RBSE 12th Physics Question Paper 2025 PDF (8 March)- Exam Analysis, Answer Key

RBSE 12th Physics Question Paper 2025 was successfully conducted on 8 March 2025 which was scheduled from 8:30 am to 11:45 am, by following the latest syllabus and exam pattern. The RBSE class 12th Physics paper was held as per the scheduled date by the Rajasthan Board of Secondary Education (RBSE). RBSE 12th physics paper had a moderate level of difficulty. Students found the paper well-balanced, with a mix of conceptual and numerical questions. Students can download the RBSE Class 12th physics question paper 2025 and answer keys to assess their performance.

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The RBSE Class 12th Physics paper is important for students who are preparing for competitive exams like JEE Main and NEET. With the help of this article, students can check the detailed analysis and RBSE 12th physics answer key. Based on the RBSE Physics Questions Paper 2025, students can check and evaluate their answers.

RBSE 12th Physics Question Paper 2025: Highlights

Highlights of RBSE class 12th Physics paper 2025 are given below table:

RBSE 12th Physics Question Paper 2025 PDF

Students can download the detailed solution pdf link by Clicking on the link given below:

RBSE 12th Physics Answer Key and Solution 2025

Students can match their answer with the correct answer of the RBSE class 12 physics paper which is given below. Stay updated on this page for detailed solutions and answer keys.

RBSE Class 12 Physics Answer Key SS-40

Question 1 :
The question asks for the SI unit of electric flux.
Electric flux $\left({\mathrm{\Phi }}_E\right)$ is given by:

$${\mathrm{\Phi }}_E=E\cdot A$$

where:
- $E$ is the electric field with SI units of $N/C$ (Newton per Coulomb),
- $A$ is the area with SI units of $m^2$ (square meters).

Thus, the SI unit of electric flux is:

$$N\cdot m^2/C$$

From the given options, the correct answer is:
(अ) or (A) $N\cdot C^{-1}\cdot m^2$.

Question 2 :
The question is based on Coulomb's Law, which states that the force $F$ between two point charges is given by:

$$F=\frac{k{q}_1{q}_2}{r^2}$$

where:
- $k$ is Coulomb's constant,
- $q_1$ and $q_2$ are the magnitudes of the charges,
- $r$ is the distance between the charges.

Initially, the force is given as $F$ when the distance is $r$ :

$$F=\frac{k{q}_1{q}_2}{r^2}$$

Now, if the distance is increased to $2r$, the new force $F^{\prime }$ will be:

$$\begin{array}{rl}{F}^{\prime }& =\frac{k{q}_1{q}_2}{(2r{)}^2}\\ F^{\prime }& =\frac{k{q}_1{q}_2}{4r^2}\\ F^{\prime }& =\frac{F}{4}\end{array}$$

Thus, the correct answer is (स) $\frac{F}{4}$.

Question 3 :

- The $10\mathrm{\Omega }$ resistor is in the middle of a balanced Wheatstone bridge, so no current flows through it. We can ignore it.

- The left and right pairs of $5\mathrm{\Omega }$ resistors are in series:

$$5\mathrm{\Omega }+5\mathrm{\Omega }=10\mathrm{\Omega }$$

- These two $10\mathrm{\Omega }$ resistances are in parallel:

$$R_{\mathrm{eq}}=\frac{10\mathrm{\Omega }\times 10\mathrm{\Omega }}{10\mathrm{\Omega }+10\mathrm{\Omega }}=5\mathrm{\Omega }$$

from Ohm's Law,
- Given voltage $=\mathbf{2}\mathbf{V}$, total resistance $=\mathbf{5}\mathbf{\Omega }$.
- Current, $I=\frac{V}{R}=\frac{2}{5}A$.

The current is $\frac{2}{5}A$, so the correct choice is:
ब) $\frac{2}{5}A$.

RBSE Class 12 Physics Question Paper 2025 Exam Analysis

The question paper was very well-structured and had everything prescribed in the curriculum and the blueprint of the topic. Those students who had a clear understanding of the topics as well as regularly practiced our test paper and numerical questions, could easily handle this paper.

By reading this article, students can download RBSE 12th physics question paper PDF 2025 which will help to know the structure of the exam pattern of questions paper and level. Also, students can check the RBSE class 12 physics answer key to match their answers and calculate the final score.

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