NCERT Notes for CBSE Class 9 to 12 - Download Free PDF with Important Formulas, Examples

Edited By Irshad Anwar | Updated on Nov 29, 2023 11:29 AM IST

NCERT Notes - Memory is crucial for students to perform well in their exams. Students need to prepare smartly to score a high percentage of marks. The key to beating performance in an academic year is to follow a regular study pattern and note down the concepts to be memorised. Careers360 CBSE Quick Revision Notes help with revision. The NCERT Notes for Quick Revision are arranged chapter-wise and can be downloaded. A revision note download option is provided to use them offline. These revision notes help students revise well for exams and also in a regular class. Once a chapter is completed from the NCERT Textbook, students should solve NCERT questions and note down the important points and formulas to revise the chapter again. NCERT point notes help with the same.

This Story also Contains

NCERT Notes for Class 9
NCERT Notes For Class 10
NCERT Notes for Class 11
NCERT Notes for Class 12
Benefits of NCERT Notes

The NCERT is the council in charge of the CBSE board, a national curriculum that is used by millions of students throughout the nation. NCERT notes are the best way to revise chapters at the time of exams quickly and efficiently. The notes are crisp and short, so students can understand them quickly. All CBSE Notes are curated as per the NCERT syllabus 2023-24. NCERT short notes are provided for classes 9 to 12 Science and Mathematics subjects. All chapters from Class 9 and 10 Science and Maths and Class 11 and 12 Physics, Chemistry, Biology, and Mathematics are covered.

NCERT Notes for Class 9

NCERT Notes for Class 9 Science

NCERT Notes for Class 9 Maths

NCERT Notes For Class 10

NCERT Notes for Class 10 Science

NCERT Notes for Class 10 Maths

NCERT Notes for Class 11

NCERT Notes for Class 11 Maths	NCERT Notes for Class 11 Physics
NCERT Notes for Class 11 Chemistry	NCERT Notes for Class 11 Biology

NCERT Notes for Class 12

NCERT Notes for Class 12 Maths	NCERT Notes for Class 12 Physics
NCERT Notes for Class 12 Chemistry	NCERT Notes for Class 12 Biology

Along with the NCERT notes students can also refer to-

NCERT Solutions	NCERT Exemplar Solutions
NCERT Solution Class 9	NCERT Solution Class 10
NCERT Solution Class 11	NCERT Solution Class 12

Benefits of NCERT Notes

NCERT notes covered major topics of each chapter.
The ncert summary notes are the best material for quick revision. Students are advised to prepare their own notes during their regular studies to get better results,
These NCERT Notes have the formulas, theorems and equations related to each chapter. The necessary derivations are not addressed here. Students should prepare NCERT class notes while attending the class.
The notes of NCERT are arranged in an easy manner to help students understand the concepts listed.

To prepare for the CBSE board exam or term exams for respective classes students can utilise NCERT revision notes, solutions to NCERT questions and previous year papers of the respective class. For subjects like Mathematics and Physics solving more questions are important. Previous papers, NCERT exemplar questions and class test/practise test help for the same.

NCERT Syllabus	NCERT Books
NCERT Books for Class 9	NCERT Syllabus Class 9
NCERT Books for Class 10	NCERT Syllabus Class 10
NCERT Books for Class 11	NCERT Syllabus Class 11
NCERT Books for Class 12	NCERT Syllabus Class 12

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Popular Questions

A block of mass 0.50 kg is moving with a speed of 2.00 ms^-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up ? Fat supplies 3.8×10⁷J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 ms⁻² :

Option 1)

2.45×10⁻³ kg

Option 2)

6.45×10⁻³ kg

Option 3)

9.89×10⁻³ kg

Option 4)

12.89×10⁻³ kg

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

A particle is projected at 60⁰ to the horizontal with a kinetic energy $K$ . The kinetic energy at the highest point

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

In the reaction,

$2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, $Mg_{3}(PO_{4})_{2}$ will contain 0.25 mole of oxygen atoms?

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol^-1) is

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t²) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m² , the number of rotations made by the pulley before its direction of motion if reversed, is