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NCERT Notes for CBSE Class 9 to 12 - Download Free PDF with Important Formulas, Examples

NCERT Notes for CBSE Class 9 to 12 - Download Free PDF with Important Formulas, Examples

Edited By Irshad Anwar | Updated on Nov 29, 2023 11:29 AM IST

NCERT Notes - Memory is crucial for students to perform well in their exams. Students need to prepare smartly to score a high percentage of marks. The key to beating performance in an academic year is to follow a regular study pattern and note down the concepts to be memorised. Careers360 CBSE Quick Revision Notes help with revision. The NCERT Notes for Quick Revision are arranged chapter-wise and can be downloaded. A revision note download option is provided to use them offline. These revision notes help students revise well for exams and also in a regular class. Once a chapter is completed from the NCERT Textbook, students should solve NCERT questions and note down the important points and formulas to revise the chapter again. NCERT point notes help with the same.

The NCERT is the council in charge of the CBSE board, a national curriculum that is used by millions of students throughout the nation. NCERT notes are the best way to revise chapters at the time of exams quickly and efficiently. The notes are crisp and short, so students can understand them quickly. All CBSE Notes are curated as per the NCERT syllabus 2023-24. NCERT short notes are provided for classes 9 to 12 Science and Mathematics subjects. All chapters from Class 9 and 10 Science and Maths and Class 11 and 12 Physics, Chemistry, Biology, and Mathematics are covered.

NCERT Notes for Class 9

NCERT Notes For Class 10

NCERT Notes for Class 11

NCERT Notes for Class 12

Along with the NCERT notes students can also refer to-

Benefits of NCERT Notes

  1. NCERT notes covered major topics of each chapter.

  2. The ncert summary notes are the best material for quick revision. Students are advised to prepare their own notes during their regular studies to get better results,

  3. These NCERT Notes have the formulas, theorems and equations related to each chapter. The necessary derivations are not addressed here. Students should prepare NCERT class notes while attending the class.

  4. The notes of NCERT are arranged in an easy manner to help students understand the concepts listed.

To prepare for the CBSE board exam or term exams for respective classes students can utilise NCERT revision notes, solutions to NCERT questions and previous year papers of the respective class. For subjects like Mathematics and Physics solving more questions are important. Previous papers, NCERT exemplar questions and class test/practise test help for the same.

Frequently Asked Question (FAQs)

1. How helps NCERT Books for the students?

NCERT Books are very helpful for all the students. The NCERT Books contains a complete solution for all doubts and it also helps for higher studies.

2. What are the subjects covered in NCERT notes Class 12?

The NCERT note for Class 12 provides for the 4 Mainly subjects namely Mathematics, Physics, Chemistry, and Biology.

3. Can NCERT notes helps to get the highers score in the CBSE board exam?

No, the NCERT notes are not sufficient for the to get good scores in the CBSE examination.NCERT notes only provide the important topics to help the students. And also NCERT notes provide the previous year's questions for the practice papers to get a higher score in the examination.

4. How can the download the NCERT syllabus?

No, the NCERT notes are not sufficient for the to get good scores in the CBSE examination.NCERT notes only provide the important topics to help the students. And also NCERT notes provide the previous year's questions for the practice papers to get a higher score in the examination.

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Get answers from students and experts

A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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