NCERT Exemplar Class 12 Physics Solutions Chapter 5 Magnetism and Matter

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# NCERT Exemplar Class 12 Physics Solutions Chapter 5 Magnetism and Matter

Edited By Safeer PP | Updated on Sep 14, 2022 12:39 PM IST | #CBSE Class 12th

NCERT Exemplar Class 12 Physics solutions chapter 5 describes how the phenomena of magnetism is universal. Be it vast, distant galaxies, tiny seemingly insignificant atoms, or men and animals, all are permeated with magnetic fields from various sources. NCERT Exemplar solutions For Class 10 Physics chapter 5 answers questions like - Why does the earth's magnetic field vary from point to point in space? What is the magnetic moment associated with a solenoid? Class 12 NCERT Exemplar Physics chapter 5 solutions also explains how magnetism helps to understand the characteristics and properties of matter, the role of the forces existing between the particles within the substance in determining how the substance behaves when placed in a magnetic field, and classifying the substance based on the kind of response recorded under the influence of the magnetic field.
Also check - NCERT Solutions for Class 12 Physics

## NCERT Exemplar Class 12 Physics Solutions Chapter 5 MCQI

Question:1

A toroid of n turns, mean radius R and cross-sectional radius a carries current I. It is placed on a horizontal table taken as x-y plane. Its magnetic moment m
A. is non-zero and points in the z-direction by symmetry.
B. points along the axis of the toroid $m =m\phi$.
C. is zero, otherwise, there would be a field falling as $\frac{1}{r^{3}}$ at large distances outside the toroid.

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The answer is the option (c)
The toroid is a ring-shaped solenoid, and the magnetic field is confined inside the body of the toroid. The magnetic moment inside and outside the toroid is zero as there is no current enclosed in those spaces.

Question:2

The magnetic field of Earth can be modelled by that of a point dipole placed at the center of the Earth. The dipole axis makes an angle of $11.3^{\circ}$ with the axis of Earth. At Mumbai, declination is nearly zero.

Then,
A. the declination varies between $11.3^{\circ}$ W to $11.3^{\circ}$ E.
B. the least declination is$0^{\circ}$°.
C. the plane defined by dipole axis and Earth axis passes through Greenwich.
D. declination averaged over Earth must always be negative.

The answer is the option (a) Earth’s magnetic field is similar to a magnetic dipole and we can simulate the nature of Earth’s magnetic field by assuming a dipole at the center of Earth. The axis of the dipole is at an angle of $11.3^{\circ}$with respect to the axis of rotation.

Question:3

In a permanent magnet at room temperature
A. magnetic moment of each molecule is zero.
B. the individual molecules have a non-zero magnetic moment which is all perfectly aligned.
C. domains are partially aligned.
D. domains are all perfectly aligned

The answer is the option (d)
Permanent magnet behaves like a ferromagnetic substance at room temperature and in the absence of an external magnetic field, the domains are spread randomly. However, when put in a magnetic field, the domains are arranged to align with the external field and even when the magnet is taken out of the field, the domains stay intact.

Question:4

Consider the two idealized systems: (i) a parallel plate capacitor with large plates and small separation and (ii) a long solenoid of length L >> R, the radius of the cross-section.

In (i) E is ideally treated as a constant between plates and zero outside.
In (ii) the magnetic field is constant inside the solenoid and zero outside.
These idealized assumptions, however, contradict fundamental laws as below:

A. case (i) contradicts Gauss’s Law for electrostatic fields.
B. case (ii) contradicts Gauss’s Law for magnetic fields.
C. case (i) agrees with $\int E.dl=0$
D. case (ii) contradicts $\int H.dl=l_{en}$

The answer is the option (b)
Gauss’ Law for electrostatic field isn’t violated as electric fields don’t require to be in continuous closed paths.
$\oint_{}S E.ds=\frac{q}{\varepsilon_ 0}$
However, Gauss’ Law for magnetic field is violated as magnetic fields need to be in continuous closed paths.
$\oint_{}S B.ds=0$

Question:5

A paramagnetic sample shows a net magnetization of 8 Am–1 when placed in an external magnetic field of 0.6T at a temperature of 4K. When the same sample is placed in an external magnetic field of 0.2 T at a temperature of 16K, the magnetization will be
A. $\frac{32}{3}Am^{-1}$

B. $\frac{2}{3}Am^{-1}$
C. $6Am^{-1}$
D. $2.4Am^{-1}$

The answer is the option (b)
$X \propto \frac{B}{T}$
$X_1=8 Am^{-1} and B_1=0.6T and T_1=4K$
At $T_2=16K and B_2=0.2T$
$X_2=\frac{X_1T_1B_2}{T_2B_1}=\frac{2}{}3 Am^{-1}$

## NCERT Exemplar Class 12 Physics Solutions Chapter 5 MCQII

Question:6

S is the surface of a lump of magnetic material.
A. Lines of B are necessarily continuous across S.
B. Some lines of B must be discontinuous across S.
C. Lines of H are necessarily continuous across S.
D. Lines of H cannot all be continuous across S.

The correct answer are the options (a, d)
Magnetic field lines form continuous closed loops. Magnetic intensity varies for inside and outside the lump.

Question:7

The primary origin(s) of magnetism lies in
A. atomic currents.
B. Pauli exclusion principle.
C. polar nature of molecules.
D. intrinsic spin of the electron.

The correct answer are the options (a, d)
Magnetism is produced due to the movement of charged particles. Electrons revolving around the nucleus produce a current, which induces the magnetic nature of materials.

Question:8

A long solenoid has 1000 turns per meter and carries a current of 1 A. It has a soft iron core of $\mu _{r}=1000$. The core is heated beyond the Curie temperature, $T_c$.
A. The H field in the solenoid is (nearly) unchanged, but the B field decreases drastically.
B. The H and B fields in the solenoid are nearly unchanged.
C. The magnetization in the core reverses direction.
D. The magnetization in the core diminishes by a factor of about 108

The correct answer are the options (a, d)
n=1000turns m
$\mu _{r}=1000$
$H=nI=1000\times 1=1000$
$B=\mu _0 \mu _rnI=\left (\mu _0nI \right )\mu _r=K\mu _r$
$B\propto \mu_r$
Beyond Curie Temperature, ferromagnetic substance behaves like paramagnetic substance.
$(X_m)_{ferro}=10^3$
$(X_m)_{para}=10^{-5}$
Magnetisation diminishes by $10^{-8}$ times.

Question:9

The essential difference between electrostatic shielding by a conducting shell and magnetostatic shielding is due to
A. electrostatic field lines can end on charges and conductors have free charges.
B. lines of B can also end, but conductors cannot end them.
C. lines of B cannot end on any material, and perfect shielding is not possible.
D. shells of high permeability materials can be used to divert lines of B from the interior region.

The correct answer is the options (a, c, d)
Magnetic field lines always exist as continuous closed loops. High permeability magnetic materials can repel magnetic field lines to get a region devoid of the magnetic field.

Question:10

Let the magnetic field on Earth be modelled by that of a point magnetic dipole at the center of Earth. The angle of dip at a point on the geographical equator
A. is always zero.
B. can be zero at specific points.
C. can be positive or negative.
D. is bounded.

The correct answer are the options (b,c,d)
Earth’s magnetic dipole is at an angle of $11.3^{\circ}$ with respect to the axis of rotation. However, the South of dipole is near the Geographical North Pole and North of dipole is near the Geographical South Pole. Though the magnetic field created by this dipole will be zero at its equatorial plane (not the equator), it will pass the equator at two points, where the magnetic field will be zero. Angle of dip flips in sign at the equatorial plane (+ve on one side and -ve on the other)

## NCERT Exemplar Class 12 Physics Solutions Chapter 5 Very Short Answer

Question:11

A proton has spin and magnetic moment just like an electron. Why then its effect is neglected in magnetism of materials.

Magnetic moment of electron and proton are:
$M_e=\frac{eh}{4\pi m_e}$ &. $M_p=\frac{eh}{4\pi m_p}$
As $m_p >> m_e$, the Magnetic moment of proton is negligible compared to electron.

Question:12

A permanent magnet in the shape of a thin cylinder of length 10 cm has $M = 10^{6}\frac{A}{m}$ Calculate the magnetization current IM.

$M = 10^{6}\frac{A}{m}$, $l=0.1m$
IM=Magnetisation current
$M=\frac{I_M}{}l$
$I_M=M\times I=10^5A$

Question:13

Explain quantitatively the order of magnitude difference between the diamagnetic susceptibility of $N_{2}(5 \times 10^{-9})$ (at STP) and $Cu ( 10^{-5})$

$\rho_ N=\frac{28g}{22.4L}=\frac{28}{22400}gcm^{-3}$
$\rho _{Cu}=8gcm^{-3}$
$\rho _{N}\rho_{Cu}=\frac{28}{22400\times 8}=1.6\times 10^{-4}$
$\frac{x_N}{x_{Cu}}=\frac{5\times 10^{-9}}{10^{-5}}=5\times 10^{-4}$
$x=\frac{\text{Intensity of Magnetisation(M)}}{\text{Magnetising field Intensity (H)}}=\frac{\frac{\text{Magnetic moment( m)}}{\text{Volume(V)}}}{}H=\frac{m}{HV}$
$V=m'\rho$
$x=m\rho Hm'$
$x\propto \rho$
$\frac{x_{N}}{x_{Cu}}=\frac{\rho _N}{ \rho _ {Cu}}=1.6\times 10^{-4}$

Question:14

From molecular viewpoint, discuss the temperature dependence of susceptibility for diamagnetism, paramagnetism and ferromagnetism.

Diamagnetism occurs due to electron’s motion in its orbit and the external magnetic field being opposite to each other, making the net magnetism zero. Temperature does not impact the susceptibility of diamagnetism.
In paramagnetic and ferromagnetic substances, magnetism generated by electron syncs up with the external magnetic field, so there is a net increase in the magnetism. Increase in temperature disturbs the atomic alignment decreasing the susceptibility

Question:15

A ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet. (i) In which direction will it move? (ii) What will be the direction of its magnetic moment?

Both liquid nitrogen and the superconducting material are diamagnetic in nature. This does not change even when the superconducting material is dipped into liquid nitrogen. In presence of an external magnetic field, superconducting material will be repelled opposite to the direction of the magnetic field.

## NCERT Exemplar Class 12 Physics Solutions Chapter 5 Short Answer

Question:16

To prove Gauss'Law $B.ds=0.$
Dipole's Magnetic moment at origin O is along the z-axis.
Assume P to be a point at a distance r from Origin and OP is at an angle θ with the z-axis.
Component of M along $OP=M\cos\theta$
Now, the magnetic field induction at P due to the dipole of moment $M \cos\theta is B$
$=\frac{\mu _0}{4\pi} 2M\frac{\cos\theta}{r^3 }\widehat{r}$
From the diagram, r is the radius of a sphere with centre at O lying in yz-plane.
An elementary area dS is taken at P $dS=r\left (r\sin \theta d\theta \right ) \widehat{r}=\left (r^2\sin\theta d\theta \right ) \widehat{r }$
$\oint B.ds=\oint \frac{\mu _{0}}{4 \pi }2M\frac{\cos \theta }{r^{3}}\widehat{r}(r^{2}\sin \theta d \theta )\widehat{r}$
$=\frac{ \frac{\mu _0}{4\pi}M}{r} \int_{0}^{2\pi }2\sin \theta \cos\theta d\theta$
$=\frac{\mu _{0}}{4\pi}\frac{ M}{r} \int_{0}^{2\pi }\sin 2\theta d\theta$
$=-\frac{\mu _{0}}{4\pi}\frac{ M}{2r} \int_{0}^{2\pi }\left ( -\frac{\cos 2 \theta }{2} \right )$
$=-\frac{\mu _{0}}{4\pi}\frac{ M}{2r}[\cos 4 \pi - \cos 0]=-\frac{\mu _{0}}{4\pi}\frac{ M}{2r} [1-1]=0$

Question:18

Suppose we want to verify the analogy between electrostatic and magnetostatic by an explicit experiment. Consider the motion of (i) electric dipole p in an electrostatic field E and (ii) magnetic dipole m in a magnetic field B. Write down a set of conditions on E, B, p, m so that the two motions are verified to be identical. (Assume identical initial conditions)

$p_E \sin \theta =\mu B \sin\theta$
$pE=\mu B$
$E=cB$
$pcB=\mu B$
$p=\mu/ c$

Question:19

A bar magnet of magnetic moment m and moment of inertia I (about center, perpendicular to length) is cut into two equal pieces, perpendicular to length. Let T be the period of oscillations of the original magnet about an axis through the mid-point, perpendicular to length, in a magnetic field B. What would be the similar period T’ for each piece?

Time period in this type of S.H.M is
$T=2\pi \sqrt{\frac{I}{MB} }$
where, T=time period
I=moment of Inertia
m=mass of magnet
B=magnetic field
$I=\frac{ml^2}{12}$
When the magnet is cut into two equal pieces, perpendicular to length the M.O.I of each piece
of magnet about an axis perpendicular to the length passing through its centre is
$I'=\frac{m/2}{12}\left (\frac{l}{2} \right )^2\times =\frac{ml^2}{12}\times \frac{1}{}8=\frac{I}{}8$
Magnetic dipole momen
t $M'=\frac{M}{}2$
Its time period of oscillation is

$T'=\frac{T}{2}$

Question:20

Use (i) the Ampere’s law for H and (ii) continuity of lines of B, to conclude that inside a bar magnet, (a) lines of H run from the N pole to S pole, while (b) lines of B must run from the S pole to N pole.

Consider a magnetic field line going through the bar magnet. We know that it must be a closed-loop.

$\int_{Q}^{P}H.dl=\int_{Q}^{P}\frac{\overrightarrow{B}}{\overrightarrow{\mu_{0}}}\overrightarrow{dl}$
B and dl are at an acute angle to each other inside the magnet.
i.e., $\int_{Q}^{P}H.dl=\int_{Q}^{P}\frac{\overrightarrow{B}}{\overrightarrow{\mu_{0}}}\overrightarrow{dl}>0$ i.e. positive
Hence, the lines of B must run from south pole S to north pole N inside the bar magnet.
According to ampere's law
$\\\oint \overrightarrow{H}.\overrightarrow{dl} =0\\\oint \overrightarrow{H}.\overrightarrow{dl} =\int_{P}^{Q}\overrightarrow{H}.\overrightarrow{dl}+\int_{Q}^{P}\overrightarrow{H}.\overrightarrow{dl}$
As $\int_{P}^{Q}\overrightarrow{H}.\overrightarrow{dl}>0 so ,\int_{Q}^{P}\overrightarrow{H}.\overrightarrow{dl}<0$ negative
If angle between H and dl is more than $90^{\circ}$, so that $\cos \theta$ is negative
(meaning that the lines run from N pole to S pole inside the bar magnet)

## NCERT Exemplar Class 12 Physics Solutions Chapter 5 Long Answer

Question:21

Verify the Ampere’s law for magnetic field of a point dipole of dipole moment $m = \widehat{m}k$. Take C as the closed curve running clockwise along (i) the z-axis from z = a > 0 to z = R; (ii) along the quarter circle of radius R and center at the origin, in the first quadrant of x-z plane; (iii) along the x-axis from x = R to x = a, and (iv) along the quarter circle of radius an and center at the origin in the first quadrant of x-z plane.

Assume the x-z plane (shown below). All points from P to Q lie on the axial line NS placed at the origin.

The magnetic field at a distance r is
$B=\frac{\mu _02\left |M \right |}{4\pi r^3}=\frac{\mu_0M}{2\pi r^3 }$
Along z-axis from P to Q
$\int_{P}^{Q}B.dl=\int_{P}^{Q} B.dl\cos 0^{\circ}=\int_{a}^{R}Bdz=\int_{a}^{R}\frac{\mu_{0}M}{2\pi r^3}dz=\frac{\mu _0M}{2\pi} \left (-\frac{1}{}2 \right )\left (\frac{1}{R^2}-\frac{1}{a^2} \right )=\frac{\mu _0M}{4\pi} \left (\frac{1}{a^2}-\frac{1}{R^2} \right )$
ii Along the quarter circle QS (radius R)

Consider point A to lie on the equatorial line of magnetic dipole of moment M sinθ.
Magnetic field at A is
$B_t=\frac{\frac{\mu _0}{4\pi} M\sin\theta}{R^{3}} ;dl=Rd\theta$
$B_r=\frac{\frac{\mu _0}{2\pi} m\cos \theta}{R^{3}}$
$\int_{0}^{\frac{\pi}{2}}B.dl=\int_{0}^{\frac{\pi}{2}} B_tdl\cos 0^{\circ}+ \int_{0}^{\frac{\pi}{2}} B_ r dl\cos 90^{\circ} =\int_{0}^{\frac{\pi}{2}}\frac{\mu _0m}{4\pi R^3}\sin \theta (Rd\theta )=\frac{\mu _{0}m}{4 \pi R^2} \int_{0}^{\frac{\pi}{2}}\sin\theta d\theta =\frac{\mu_{0}m}{4\pi R^2 }$
iii Along x-axis over the path ST, consider the figure given below

From the figure, every point lies on the equatorial line of the magnetic dipole.
Magnetic field induction at a point distance x from the dipole is
$B=\frac{\frac{\mu _0}{4\pi} M}{x^3 }$
$\int_{S}^{T}B.dl=\int_{R}^{a}-\frac{\mu _0M}{4\pi x^3} =0$ angle between-M and dl is $90^{\circ}$
iv Along the quarter circle TP of radius a.
Let's consider the figure given below

From case ii we get line integral of B along the quarter circle TP of radius a
is circular arc TP.
$\int B.dl=\int_{\frac{\pi}{2}}^{0} \frac{\mu _{0}}{4\pi} M\frac{\sin \theta }{a^3}ad\theta =\frac{\mu _0M}{4\pi a^2} \int_{\frac{\pi}{2}}^{0} \sin\theta d\theta =\frac{\frac{\mu _{0}}{4\pi} M}{a^2} \int_{\frac{\pi}{2}}^{0}[-\cos\theta ]$
$=-\frac{\frac{\mu _0}{4\pi} M}{a^2 }$
$\int B.dl= \int_{P}^{Q}B.dl+\int_{Q}^{S}B.dl+\int_{S}^{T}B.dl+\int_{T}^{P}B.dl$
$=\frac{\mu _0M}{4}\left [\frac{1}{a^2}-\frac{1}{R^2} \right ]+\frac{\mu _0M}{4\pi R^2}+0+\left (-\frac{\mu _0M}{4\pi R^2} \right )=0$

Question:22

What are the dimensions of χ, the magnetic susceptibility? Consider an H-atom. Guess an expression for χ, up to a constant by constructing a quantity of dimensions of χ, out of parameters of the atom: e, m, v, R and μ0. Here, m is the electronic mass, v is electronic velocity, R is Bohr radius. Estimate the number so obtained and compare with the value of $\left | x \right |\sim 10^{5}$ for many solid materials.

$X_m=\frac{I}{}H=\frac{\text{Intensity of magnetisation}}{\text{Magnetising force }}$
As I and H both have same units and dimensions, hence χ has no dimensions.
Here, χ is related with e, m, v, R and $\mu _{0}$
From Biot-Savart'slaw,
$dB=\frac{\mu _0}{4\pi} Idl\frac{\sin \theta }{r^2 }$
$\mu _0=\frac{4\pi r^2dB}{Idl\sin \theta }=\frac{4\pi r^2}{Idl \sin\theta }\times \frac{F}{qv \sin \theta }$
Dimensions of $\mu _{0}=\frac{L^2\times [MLT^{-2}]}{[QT^{-1}][L]\times 1\times Q[LT^{-1}]\times 1}=[MLQ^{-2} ]$
where Q is the dimension of charge
As χ is dimensionless, it should have no involvement of charge Q in its dimensional formula.
It will be so if μ0 and e together should have the value $\mu _0e^2$, as e has the dimensions of charge.
Let $X= \mu _0e^2 m^av^bR^c .......i$
where a, b ,c are the power of m,v and R respectively
$[M^0L^0T^0A^0T^0]=[MLA^{-2}T^{-2}]\times [A^2T^2][M]^a\times [LT^{-1}]^b\times [L]^c =[M^{1+a}L^{1+b+c}T^{-b}A^0 ]$
Equating the powers we get 0=1+a
a=-1
0=1+b+c
0=-b
b=0
1+0+c=0
c=-1
Putting values in equation i we get $X=\mu _{0}e^2m^{-1}v^2R^{-1}=\frac{\mu _0e^2}{mR }$
Here, $\mu _0=4\pi \times 10^{-7} Tm A^{-1 }$
$e=1.6\times 10^{-19} C$
$m=9.1\times 10^{-31} kg$
$R=10^{-10}m X=\left (4\pi \times 10^{-7} \right )\times \frac{(1.6\times 10^{-19})^{2}}{9.1\times 10^{-31}\times 10^{-10}}\approx 10^{-4}$

Question:23

Assume the dipole model for earth’s magnetic field B which is given by BV = vertical component of magnetic field
$=\frac{\mu _{0}}{ 4 \pi}\frac{2m \cos \theta }{r^{3}}$

BH = Horizontal component of magnetic field
$=\frac{\mu _{0}}{ 4 \pi}\frac{ \sin \theta m }{r^{3}}$
$\theta = 90^{\circ}$– latitude as measured from magnetic equator.
Find loci of points for which (i) B is minimum; (ii) dip angle is zero; and (iii) dip angle is $\pm 45^{\circ}$

$(a)B_v=\mu _{0}2m\frac{\cos \theta}{ 4\pi r^3 }$
$B_H=\frac{\mu _{0}}{4 \pi}\frac{m\sin \theta}{ r^{3} }$
These are the components of B to a net magnetic field will be
$B=\sqrt{B_v^2+ B_H^2}=\frac{\mu_{0}m}{4\pi r^3}[3\cos 2 \theta +1]^{\frac{1}{}2}$
From the above equation, the value of B is minimum, if
$\cos \theta =\frac{\pi}{}2$
$\theta =\frac{\pi}{}2$
Thus, B is minimum at the magnetic equator.
(b) Angle of dip
$\tan \delta =\frac{B_v}{B_H}=\frac{\mu _{0}}{4 \pi }\frac{.2m \frac{\cos \theta }{r^3}}{\frac{\mu _{0}}{4\pi }\sin \theta .\frac{m}{r^{3}}} =2\cot \theta .........i$
$\tan \delta =2\cot \theta$
For dip angle is zero $\tan \delta =0$
$\cot \theta =0 , \theta =\frac{\pi}{}2$
For this value of θ angle of dip is vanished. It means that locus is again magnetic equator.

(c)

$tan \delta =\frac{B_v}{B_H}$

Angle of dip

$\delta =\pm 45^{\circ}$
$\frac{ B_v}{B_H}=tan \pm 45^{\circ}$
$\frac{ B_v}{B_H}=1$
$2 \cot \theta =1$
$\tan \theta =\frac{1}{}2$
$\theta =\tan ^{-1}({\frac{1}{}2})$
Thus, $\theta =\tan ^{-1}({\frac{1}{}2})$ is the locus.

Question:24

The angle of declination is zero on the plane formed by the dipole axis and Earth’s axis of rotation. So, the angle of declination is 0 at P.
The angle of dip is zero on the magnetic equator. So, point Q has an angle of dip 0 and the angle of declination 11.3°.

Question:25

There are two current carrying planar coils made each from identical wires of length L. $C_1$ is circular (radius R) and $C_2$ is square (side a). They are so constructed that they have the same frequency of oscillation when they are placed in the same uniform B and carry the same current. Find an in terms of R.

For $C_1$,
length=L
number of turns per unit length
$n_1=\frac{L}{2\pi R}$
For $C_2$
side=a
perimeter=L
number of turns per unit length
$n_2=\frac{L}{4a}$

Let Magnetic moment of $C_1$ be $m_1=n_1iA_1$ where i is the current in the coil and
Magnetic moment of $C_{2}$ be $m_2=n_2iA_2$ where i is the current in the coil
$m_1=L.i.\pi .\frac{R^2}{2\pi R } ; m_2=\frac{L}{4a}.i.a^2$
$m_1=\frac{LiR}{2 } ; m_2=\frac{Lia}{4}$
Moment of inertia of $C_1=I_1=\frac{MR^2}{}2$
Moment of inertia of$C_2=I_2=\frac{Ma^2}{12}$….ii where M is the mass of coil
Frequency of $C_1=f_1=2\pi \sqrt{\frac{I_1}{m_1B}}$…iii
Frequency of$C_2=f_2=2\pi \sqrt{\frac{I_2}{m_2B}}$….iv
According to problem, $f_{1}=f_{2}$
$2\pi \sqrt{\frac{I_1}{m_1B}} =2\pi \sqrt{\frac{I_2}{m_2B}}$
$\frac{I_1}{m_1}=\frac{I_2}{m_2} or \frac{m_2}{m_1}=\frac{I_2}{I_1}$
On substituting the values from eqn i, ii, iiiand iv we get
$Lia.\frac{2}{4 \times LiR}=Ma^{2}.\frac{2}{12 MR^2}$
$\frac{ a}{2R}=\frac{a^2}{6R^2 }$
$3R=a$
Thus, the value of a is 3R.

In a nutshell, NCERT Exemplar Class 12 Physics solutions chapter 5 explores the laws and derivations concerning magnetism and matter and earths magnetic field. NCERT Exemplar Class 12 Physics solutions chapter 5 pdf download is available for students. The NCERT solutions provided on this page will help understand all the relevant and vital concepts comprehensively and also aid in preparing for the 12 boards and competitive exams.

## Main Subtopics - NCERT Exemplar Class 12 Physics Solutions Chapter 5 Magnetism and Matter

• Introduction
• The Bar Magnet
• The magnetic field lines
• Bar magnet as an equivalent solenoid
• The dipole in a uniform magnetic field
• The electrostatic analogue
• Magnetism And Gauss's Law
• The Earth's Magnetism
• Magnetic declination and dip
• Magnetisation And Magnetic Intensity
• Magnetic Properties Of Materials
• Diamagnetism
• Paramagnetism
• Ferromagnetism
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## NCERT Exemplar Class 12 Physics Chapter Wise Links

 Chapter 1 Electric Charges and Fields Chapter 2 Electrostatic Potential and Capacitance Chapter 3 Current Electricity Chapter 4 Moving Charges and Magnetism Chapter 6 Electromagnetic Induction Chapter 7 Alternating Current Chapter 8 Electromagnetic Waves Chapter 9 Ray Optics and Optical Instruments Chapter 10 Wave Optics Chapter 11 Dual Nature of Radiation and Matter Chapter 12 Atoms Chapter 13 Nuclei Chapter 14 Semiconductor Electronics Chapter 15 Communication Systems

## What will the students learn in NCERT Exemplar Class 12 Physics Solutions Chapter 5?

.Understanding magnetism is required to answer questions like- Why are some materials magnetic and others not? And why do several substances become magnetised by a field, whereas others remain unaffected? Magnetic materials act as the protagonist in industrial success and technological growth. They have a wide range of uses in the generation of power, transmission and communication, analogue and electronic devices such as clocks or digital wristwatches, scientific and medical equipment, sensors, therapy and delivery. NCERT Exemplar Class 12 Physics chapter 5 solutions discusses the usage of magnets and magnetism

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1. How many questions are solved in the solutions?

The NCERT exemplar Class 12 Physics solutions chapter 5 provided by us will have all the 25 questions of the main exercise.

2. How will these questions and solutions help?

These questions are solved in the most simple and explanative way so that one can grasp the topic. This will help in understanding the basics and how to solve questions in exams.

3. What all crucial topics are covered in magnetism and matter?

This chapter covers various important topics like properties of bar magnet, diamagnetism, ferromagnetism and paramagnetism and earths magnetism etc. These topics are highly crucial from both boards and entrance exam POV.

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#### Goa Board Secondary School Certificate Examination

Exam Date:19 April,2024 - 19 April,2024

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### Questions related to CBSE Class 12th

Have a question related to CBSE Class 12th ?

Hello aspirant,

The purpose of graphic design extends beyond the brand's look. Nevertheless, by conveying what the brand stands for, it significantly aids in the development of a sense of understanding between a company and its audience. The future in the field of graphic designing is very promising.

Thank you

Hope this information helps you.

hello,

Yes you can appear for the compartment paper again since CBSE gives three chances to a candidate to clear his/her exams so you still have two more attempts. However, you can appear for your improvement paper for all subjects but you cannot appear for the ones in which you have failed.

Good Luck

Hello dear,

If you was not able to clear 1st compartment and now you giving second compartment so YES, you can go for your improvement exam next year but if a student receives an improvement, they are given the opportunity to retake the boards as a private candidate the following year, but there are some requirements. First, the student must pass all of their subjects; if they received a compartment in any subject, they must then pass the compartment exam before being eligible for the improvement.

As you can registered yourself as private candidate for giving your improvement exam of 12 standard CBSE(Central Board of Secondary Education).For that you have to wait for a whole year which is bit difficult for you.

Positive side of waiting for whole year is you have a whole year to preparing yourself for your examination. You have no distraction or something which may causes your failure in the exams. In whole year you have to stay focused on your 12 standard examination for doing well in it. By this you get a highest marks as a comparison of others.

Believe in Yourself! You can make anything happen

All the very best.

Hello Student,

I appreciate your Interest in education. See the improvement is not restricted to one subject or multiple subjects  and  we cannot say if improvement in one subject in one year leads to improvement in more subjects in coming year.

You just need to have a revision of all subjects what you have completed in the school. have a revision and practice of subjects and concepts helps you better.

All the best.

Hi,

You just need to give the exams for the concerned two subjects in which you have got RT. There is no need to give exam for all of your subjects, you can just fill the form for the two subjects only.

A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

 Option 1) Option 2) Option 3) Option 4)

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

 Option 1) 2.45×10−3 kg Option 2)  6.45×10−3 kg Option 3)  9.89×10−3 kg Option 4) 12.89×10−3 kg

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

 Option 1) Option 2) Option 3) Option 4)

A particle is projected at 600   to the horizontal with a kinetic energy . The kinetic energy at the highest point

 Option 1) Option 2) Option 3) Option 4)

In the reaction,

 Option 1)   at STP  is produced for every mole   consumed Option 2)   is consumed for ever      produced Option 3) is produced regardless of temperature and pressure for every mole Al that reacts Option 4) at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, will contain 0.25 mole of oxygen atoms?

 Option 1) 0.02 Option 2) 3.125 × 10-2 Option 3) 1.25 × 10-2 Option 4) 2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

 Option 1) decrease twice Option 2) increase two fold Option 3) remain unchanged Option 4) be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

 Option 1) Molality Option 2) Weight fraction of solute Option 3) Fraction of solute present in water Option 4) Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

 Option 1) twice that in 60 g carbon Option 2) 6.023 × 1022 Option 3) half that in 8 g He Option 4) 558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

 Option 1) less than 3 Option 2) more than 3 but less than 6 Option 3) more than 6 but less than 9 Option 4) more than 9

Database professionals use software to store and organise data such as financial information, and customer shipping records. Individuals who opt for a career as data administrators ensure that data is available for users and secured from unauthorised sales. DB administrators may work in various types of industries. It may involve computer systems design, service firms, insurance companies, banks and hospitals.

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A career as ethical hacker involves various challenges and provides lucrative opportunities in the digital era where every giant business and startup owns its cyberspace on the world wide web. Individuals in the ethical hacker career path try to find the vulnerabilities in the cyber system to get its authority. If he or she succeeds in it then he or she gets its illegal authority. Individuals in the ethical hacker career path then steal information or delete the file that could affect the business, functioning, or services of the organization.

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GIS officer work on various GIS software to conduct a study and gather spatial and non-spatial information. GIS experts update the GIS data and maintain it. The databases include aerial or satellite imagery, latitudinal and longitudinal coordinates, and manually digitized images of maps. In a career as GIS expert, one is responsible for creating online and mobile maps.

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The invention of the database has given fresh breath to the people involved in the data analytics career path. Analysis refers to splitting up a whole into its individual components for individual analysis. Data analysis is a method through which raw data are processed and transformed into information that would be beneficial for user strategic thinking.

Data are collected and examined to respond to questions, evaluate hypotheses or contradict theories. It is a tool for analyzing, transforming, modeling, and arranging data with useful knowledge, to assist in decision-making and methods, encompassing various strategies, and is used in different fields of business, research, and social science.

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Individuals who opt for a career as geothermal engineers are the professionals involved in the processing of geothermal energy. The responsibilities of geothermal engineers may vary depending on the workplace location. Those who work in fields design facilities to process and distribute geothermal energy. They oversee the functioning of machinery used in the field.

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If you are intrigued by the programming world and are interested in developing communications networks then a career as database architect may be a good option for you. Data architect roles and responsibilities include building design models for data communication networks. Wide Area Networks (WANs), local area networks (LANs), and intranets are included in the database networks. It is expected that database architects will have in-depth knowledge of a company's business to develop a network to fulfil the requirements of the organisation. Stay tuned as we look at the larger picture and give you more information on what is db architecture, why you should pursue database architecture, what to expect from such a degree and what your job opportunities will be after graduation. Here, we will be discussing how to become a data architect. Students can visit NIT Trichy, IIT Kharagpur, JMI New Delhi

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Individuals who opt for a career as a remote sensing technician possess unique personalities. Remote sensing analysts seem to be rational human beings, they are strong, independent, persistent, sincere, realistic and resourceful. Some of them are analytical as well, which means they are intelligent, introspective and inquisitive.

Remote sensing scientists use remote sensing technology to support scientists in fields such as community planning, flight planning or the management of natural resources. Analysing data collected from aircraft, satellites or ground-based platforms using statistical analysis software, image analysis software or Geographic Information Systems (GIS) is a significant part of their work. Do you want to learn how to become remote sensing technician? There's no need to be concerned; we've devised a simple remote sensing technician career path for you. Scroll through the pages and read.

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Data are collected and examined to respond to questions, evaluate hypotheses or contradict theories. It is a tool for analyzing, transforming, modeling, and arranging data with useful knowledge, to assist in decision-making and methods, encompassing various strategies, and is used in different fields of business, research, and social science.

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A Safety Manager is a professional responsible for employee’s safety at work. He or she plans, implements and oversees the company’s employee safety. A Safety Manager ensures compliance and adherence to Occupational Health and Safety (OHS) guidelines.

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For an individual who opts for a career as an actor, the primary responsibility is to completely speak to the character he or she is playing and to persuade the crowd that the character is genuine by connecting with them and bringing them into the story. This applies to significant roles and littler parts, as all roles join to make an effective creation. Here in this article, we will discuss how to become an actor in India, actor exams, actor salary in India, and actor jobs.

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A career as radio jockey has a lot to offer to deserving candidates. If you want to know more about a career as radio jockey, and how to become a radio jockey then continue reading the article.

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The word “choreography" actually comes from Greek words that mean “dance writing." Individuals who opt for a career as a choreographer create and direct original dances, in addition to developing interpretations of existing dances. A Choreographer dances and utilises his or her creativity in other aspects of dance performance. For example, he or she may work with the music director to select music or collaborate with other famous choreographers to enhance such performance elements as lighting, costume and set design.

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A career as social media manager involves implementing the company’s or brand’s marketing plan across all social media channels. Social media managers help in building or improving a brand’s or a company’s website traffic, build brand awareness, create and implement marketing and brand strategy. Social media managers are key to important social communication as well.

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Photography is considered both a science and an art, an artistic means of expression in which the camera replaces the pen. In a career as a photographer, an individual is hired to capture the moments of public and private events, such as press conferences or weddings, or may also work inside a studio, where people go to get their picture clicked. Photography is divided into many streams each generating numerous career opportunities in photography. With the boom in advertising, media, and the fashion industry, photography has emerged as a lucrative and thrilling career option for many Indian youths.

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An individual who is pursuing a career as a producer is responsible for managing the business aspects of production. They are involved in each aspect of production from its inception to deception. Famous movie producers review the script, recommend changes and visualise the story.

They are responsible for overseeing the finance involved in the project and distributing the film for broadcasting on various platforms. A career as a producer is quite fulfilling as well as exhaustive in terms of playing different roles in order for a production to be successful. Famous movie producers are responsible for hiring creative and technical personnel on contract basis.

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In a career as a copywriter, one has to consult with the client and understand the brief well. A career as a copywriter has a lot to offer to deserving candidates. Several new mediums of advertising are opening therefore making it a lucrative career choice. Students can pursue various copywriter courses such as Journalism, Advertising, Marketing Management. Here, we have discussed how to become a freelance copywriter, copywriter career path, how to become a copywriter in India, and copywriting career outlook.

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In a career as a vlogger, one generally works for himself or herself. However, once an individual has gained viewership there are several brands and companies that approach them for paid collaboration. It is one of those fields where an individual can earn well while following his or her passion.

Ever since internet costs got reduced the viewership for these types of content has increased on a large scale. Therefore, a career as a vlogger has a lot to offer. If you want to know more about the Vlogger eligibility, roles and responsibilities then continue reading the article.

3 Jobs Available
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For publishing books, newspapers, magazines and digital material, editorial and commercial strategies are set by publishers. Individuals in publishing career paths make choices about the markets their businesses will reach and the type of content that their audience will be served. Individuals in book publisher careers collaborate with editorial staff, designers, authors, and freelance contributors who develop and manage the creation of content.

3 Jobs Available
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Careers in journalism are filled with excitement as well as responsibilities. One cannot afford to miss out on the details. As it is the small details that provide insights into a story. Depending on those insights a journalist goes about writing a news article. A journalism career can be stressful at times but if you are someone who is passionate about it then it is the right choice for you. If you want to know more about the media field and journalist career then continue reading this article.

3 Jobs Available
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Individuals in the editor career path is an unsung hero of the news industry who polishes the language of the news stories provided by stringers, reporters, copywriters and content writers and also news agencies. Individuals who opt for a career as an editor make it more persuasive, concise and clear for readers. In this article, we will discuss the details of the editor's career path such as how to become an editor in India, editor salary in India and editor skills and qualities.

3 Jobs Available
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Individuals who opt for a career as a reporter may often be at work on national holidays and festivities. He or she pitches various story ideas and covers news stories in risky situations. Students can pursue a BMC (Bachelor of Mass Communication), B.M.M. (Bachelor of Mass Media), or MAJMC (MA in Journalism and Mass Communication) to become a reporter. While we sit at home reporters travel to locations to collect information that carries a news value.

2 Jobs Available
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Are you searching for a Corporate Executive job description? A Corporate Executive role comes with administrative duties. He or she provides support to the leadership of the organisation. A Corporate Executive fulfils the business purpose and ensures its financial stability. In this article, we are going to discuss how to become corporate executive.

2 Jobs Available
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A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.

2 Jobs Available
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Welding Engineer Job Description: A Welding Engineer work involves managing welding projects and supervising welding teams. He or she is responsible for reviewing welding procedures, processes and documentation. A career as Welding Engineer involves conducting failure analyses and causes on welding issues.

5 Jobs Available
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A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product.

A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.

3 Jobs Available
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3 Jobs Available

A QA Lead is in charge of the QA Team. The role of QA Lead comes with the responsibility of assessing services and products in order to determine that he or she meets the quality standards. He or she develops, implements and manages test plans.

2 Jobs Available
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A Structural Engineer designs buildings, bridges, and other related structures. He or she analyzes the structures and makes sure the structures are strong enough to be used by the people. A career as a Structural Engineer requires working in the construction process. It comes under the civil engineering discipline. A Structure Engineer creates structural models with the help of computer-aided design software.

2 Jobs Available
##### Process Development Engineer

The Process Development Engineers design, implement, manufacture, mine, and other production systems using technical knowledge and expertise in the industry. They use computer modeling software to test technologies and machinery. An individual who is opting career as Process Development Engineer is responsible for developing cost-effective and efficient processes. They also monitor the production process and ensure it functions smoothly and efficiently.

2 Jobs Available
##### AWS Solution Architect

An AWS Solution Architect is someone who specializes in developing and implementing cloud computing systems. He or she has a good understanding of the various aspects of cloud computing and can confidently deploy and manage their systems. He or she troubleshoots the issues and evaluates the risk from the third party.

4 Jobs Available

An Azure Administrator is a professional responsible for implementing, monitoring, and maintaining Azure Solutions. He or she manages cloud infrastructure service instances and various cloud servers as well as sets up public and private cloud systems.

4 Jobs Available
##### Computer Programmer

Careers in computer programming primarily refer to the systematic act of writing code and moreover include wider computer science areas. The word 'programmer' or 'coder' has entered into practice with the growing number of newly self-taught tech enthusiasts. Computer programming careers involve the use of designs created by software developers and engineers and transforming them into commands that can be implemented by computers. These commands result in regular usage of social media sites, word-processing applications and browsers.

3 Jobs Available
##### Product Manager

A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.

3 Jobs Available
##### Information Security Manager

Individuals in the information security manager career path involves in overseeing and controlling all aspects of computer security. The IT security manager job description includes planning and carrying out security measures to protect the business data and information from corruption, theft, unauthorised access, and deliberate attack

3 Jobs Available
##### Automation Test Engineer

An Automation Test Engineer job involves executing automated test scripts. He or she identifies the project’s problems and troubleshoots them. The role involves documenting the defect using management tools. He or she works with the application team in order to resolve any issues arising during the testing process.

2 Jobs Available