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NCERT exemplar Class 10 Maths solutions chapter 12 discusses the method to determine the surface area and volume of various three-dimensional objects. These three-dimensional objects can be cones, spheres, or cylinders. The NCERT exemplar Class 10 Maths solutions chapter 12 consist of detailed solutions to study and understand the NCERT class 10 Maths. These NCERT exemplar class 10 Maths chapter 12 solutions are prepared by our skilled subject matter experts with 10+ years of teaching and content development experience. The CBSE 10 Maths Syllabus acts as the outline of these NCERT exemplar Class 10 Maths solutions chapter 12.
A cylindrical pencil sharpened at one edge is the combination of
(A) a cone and a cylinder (B) frustum of a cone and a cylinder
(C) a hemisphere and a cylinder (D) two cylinders.
A Surahi is the combination of
(A) a sphere and a cylinder (B) a hemisphere and a cylinder
(C) two hemispheres (D) a cylinder and a cone.
A plumbline (sahul) is the combination of
(A) a cone and a cylinder (B) a hemisphere and a cone
(C) frustum of a cone and a cylinder (D) sphere and cylinder
The shape of a glass (tumbler) (see figure) is usually in the form of
(A) a cone (B) frustum of a cone
(C) a cylinder (D) a sphere
The shape of a gilli, in the gilli-danda game (See figure), is a combination of
(A) two cylinders (B) a cone and a cylinder
(C) two cones and a cylinder (D) two cylinders and a cone
A shuttle cock used for playing badminton has the shape of the combination of
(A) a cylinder and a sphere
(B) a cylinder and a hemisphere
(C) a sphere and a cone
(D) frustum of a cone and a hemisphere
A cone is cut through a plane parallel to its base and then the cone that is formed on one side of that plane is removed. The new part that is left over on the otherside of the plane is called
(A) a frustum of a cone (B) cone
(C) cylinder (D) sphere
A hollow cube of internal edge 22cm is filled with spherical marbles of diameter 0.5 cm and it is assumed that space of the cube remains unfilled. Then the number of marbles that the cube can accommodate is
(A) 142296 (B) 142396 (C) 142496 (D) 142596
A solid piece of iron in the form of a cuboid of dimensions , is moulded to form a solid sphere. The radius of the sphere is
(A) 21cm (B) 23cm (C) 25cm (D) 19cm
A mason constructs a wall of dimensions with the bricks each of size and it is assumed that space is covered by the mortar. Then the number of bricks used to construct the wall is
(A) 11100 (B) 11200 (C) 11000 (D) 11300
Twelve solid spheres of the same size are made by melting a solid metallic cylinder of base diameter 2 cm and height 16 cm. The diameter of each sphere is
(A) 4 cm (B) 3 cm (C) 2 cm (D) 6 cm
The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is
(A) 4950 cm^{2} (B) 4951 cm^{2} (C) 4952 cm^{2} (D) 4953 cm^{2}
A medicine-capsule is in the shape of a cylinder of diameter 0.5 cm with two hemispheres stuck to each of its ends. The length of entire capsule is 2 cm. The capacity of the capsule is
(A) 0.36 cm^{3} (B) 0.35 cm^{3} (C) 0.34 cm^{3} (D) 0.33 cm^{3}
Diameter of hemisphere = 0.5 cm
Similarly radius of cylinder = 0.25
Height = 2- 0.25 -0.25
= 2- 0.5
=1.5 cm
The total volume of capsule = volume of two hemispheres + volume of the cylinder
= 0.359cm^{3}
=0.36cm^{3} (approximate)
If two solid hemispheres of same base radius r are joined together along their bases, then curved surface area of this new solid is
(A) (B) (C) (D)
A right circular cylinder of radius r cm and height h cm (h > 2r) just encloses a sphere of diameter
(A) r cm (B) 2r cm (C) h cm (D) 2h cm
During conversion of a solid from one shape to another, the volume of the new shape will
(A) increase (B) decrease
(C) remain unaltered (D) be doubled
The diameters of the two circular ends of the bucket are 44 cm and 24 cm. The height of the bucket is 35 cm. The capacity of the bucket is
(A) 32.7 litres (B) 33.7 litres (C) 34.7 litres (D) 31.7 litres
In a right circular cone, the cross-section made by a plane parallel to the base is a
(A) circle (B) frustum of a cone
(C) sphere (D) hemisphere
Volumes of two spheres are in the ratio 64:27. The ratio of their surface areas is
(A) 3 : 4 (B) 4 : 3 (C) 9 : 16 (D) 16 : 9
Write ‘True’ or ‘False’ and justify your answer in the following:
Two identical solid hemispheres of equal base radius r cm are stuck together along their bases. The total surface area of the combination is .
Write ‘True’ or ‘False’ and justify your answer in the following :
A solid cylinder of radius r and height h is placed over other cylinder of same height and radius. The total surface area of the shape so formed is
Write ‘True’ or ‘False’ and justify your answer in the following :
A solid cone of radius r and height h is placed over a solid cylinder having same base radius and height as that of a cone. The total surface area of the combined solid is
Write ‘True’ or ‘False’ and justify your answer in the following :
A solid ball is exactly fitted inside the cubical box of side a. The volume of the ball is
Write ‘True’ or ‘False’ and justify your answer in the following:
The volume of the frustum of a cone is where h is vertical height of the frustum and are the radii of the ends.
Write ‘True’ or ‘False’ and justify your answer in the following:
The capacity of a cylindrical vessel with a hemispherical portion raised upward at the bottom as shown in the Figure is
Write ‘True’ or ‘False’ and justify your answer in the following:
An open metallic bucket is in the shape of a frustum of a cone, mounted on a hollow cylindrical base made of the same metallic sheet. The surface area of the metallic sheet used is equal to curved surface area of frustum of a cone + area of circular base + curved surfacearea of cylinder
How many shots each having a diameter of 3 cm can be made from a cuboidal lead solid of dimensions
Answer 84The barrel of a fountain pen, cylindrical in shape, is 7 cm long and 5 mm in diameter. A full barrel of ink in the pen is used upon writing 3300 words on average. How many words can be written in a bottle of ink containing one-fifth of a litre?
3300 words can be written with 0.001375 L of ink
So with 1L of ink 3300/0.001375 words can be written=2400000
So with 1/5th of a litter 2400000/5 words can be written=48000
NCERT exemplar Class 10 chapter 12 Maths solutions covers the following topics:
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These Class 10 Maths NCERT exemplar chapter 12 solutions emphasise finding out curved surface area, total surface area, and volume of various three-dimensional objects such as cones, cylinders, and spheres. These calculations and learning will be helpful in Physics and Maths of higher classes and are essential for both medical and engineering aspirants. The expressive nature of these solutions provides the students a perfect environment to attempt and practice Surface Areas and Volumes based practice problems. The Class 10 Maths NCERT exemplar solutions chapter 12 Surface Areas and Volumes consist of plenty of practice problems, making the student prepared for NCERT Class 10 Maths, RD Sharma Class 10 Maths, RS Aggarwal Class 10 Maths et cetera.
NCERT exemplar Class 10 Maths solutions chapter 12 pdf download is a free-to-use feature that provides the students with the facility to study the NCERT exemplar Class 10 Maths chapter 12 in an offline environment.
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 |
Ice cream cones can be seen as a combination of a hemisphere and a cone in simplified form. We know the volume of cone and volume of the hemisphere, so we can find out its complete volume.
We can find out the volume of sharpened pencil by assuming it as a combination of cylinder and a cone.
The chapter Surface Areas and Volumes is vital for Board examinations as it holds around 8-10% weightage of the whole paper.
It is highly suggested that students practice and study every topic covered in NCERT exemplar Class 10 Maths solutions chapter 12 to score high in Surface Areas and Volumes.
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
Yes, you can definitely apply for diploma courses after passing 10th CBSE. In fact, there are many diploma programs designed specifically for students who have completed their 10th grade.
Generally, passing 10th CBSE with a minimum percentage (often 50%) is the basic eligibility for diploma courses. Some institutes might have specific subject requirements depending on the diploma specialization.
There is a wide range of diploma courses available in various fields like engineering (e.g., mechanical, civil, computer science), computer applications, animation, fashion design, hospitality management, and many more.
You can pursue diplomas at various institutions like:
Hi,
Yes, you can get admission for a diploma course if you are a 10th passed out student. The basic eligibility criteria to get enrolled into a Diploma course is to secure minimum of 50% in your 10th boards. Although, several institutions can ask for specific subject requirements.
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