NCERT Solutions for Class 10 Maths Chapter 2 Polynomials

Have you ever noticed how the path of a roller coaster, the trajectory of a football, or the economic trend predictions follow a certain pattern, that is the power of polynomials. Polynomials are not just some algebraic expression, they are one of the main pillars of mathematics. As per the latest NCERT syllabus of class 10, this chapter contains the basic concepts of polynomials like Degree of Polynomials, Zeroes of a Polynomial, Geometrical Meaning of the Zeroes of a Polynomial, and Relationship between Zeroes and Coefficients of a Polynomial. Understanding these concepts will make students more efficient in solving problems involving polynomials and will also build a strong foundation for advanced polynomial concepts.

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This Story also Contains

1. NCERT Solutions for Class 10 Maths Chapter 2 Polynomials PDF Free Download
2. NCERT Solutions for Class 10 Maths Chapter 2 Polynomials - Important Formulae
3. Class 10 Maths Chapter 2 Solutions Polynomials
4. Polynomial Class 10 Solutions - Exercise Wise
5. NCERT Solutions for Class 10 Maths: Chapter Wise
6. Importance of Solving NCERT Questions of Class 10 Maths Chapter 2
7. NCERT Solutions of Class 10 - Subject Wise
8. NCERT Exemplar solutions - Subject-wise
9. NCERT Books and NCERT Syllabus here

The NCERT solutions of Chapter 2 Polynomials, are designed by our experienced subject experts to offer a systematic and structured approach to these important concepts and help students to prepare well for exams and to gain knowledge about all the natural processes happening around them by a series of solved questions given in the NCERT textbook exercise. It covers questions from all the topics and will help you improve your speed and accuracy.

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials PDF Free Download

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NCERT Solutions for Class 10 Maths Chapter 2 Polynomials - Important Formulae

Polynomials

A polynomial $p(x)$ is an algebraic expression that can be written in the form of

$p(x)=a_n{x}^n+\dots +a_2{x}^2+a_{1}x+a_0$

Here $a_0,a_1,a_2,\dots ,a_n$ are real numbers and each power of x is a non-negative integer.

Each real number a_i is called a coefficient. The number a₀  that is not multiplied by a variable is called a constant. Each product  $a_i{x}_i$  is a term of a polynomial. The highest power of the variable that occurs in the polynomial is called the degree of a polynomial. The leading term is the term with the highest power, and its coefficient is called the leading coefficient.

Types of Polynomials

The types of polynomials based on the number of terms are

• Monomial: A monomial is a polynomial with one term. Eg. $3x$
• Binomial: A binomial is a polynomial with two terms. Eg. $3x+2y$
• Trinomial: A trinomial is a polynomial with three terms. Eg. $4x^2+3x+2y$
• Multinomial: A general term for polynomials with more than three terms. Eg. $7x^5+5x^3+3x^2+2x=1$
• Constant Polynomial: A constant polynomial is a polynomial with no variable terms but with only a constant term. Eg. $P(x)=5$
• Zero Polynomial: A polynomial with coefficients as zero. Eg. $0x^2+0x,0$

The types of polynomials based on the degree of a polynomial are

• Linear Polynomial: A polynomial with degree one. Eg. $3x+5y=5$
• Quadratic Polynomial: Polynomial with degree two. any quadratic polynomial in $x$ is of the form $a{x}^2+bx+c$, where $a,b,c$ are real numbers and $a\ne 0$. Eg. $2x^2+3x+2=0$
• Cubic Polynomial: Polynomial with degree three. The general form of a cubic polynomial is $a{x}^3+b{x}^2+cx+d$, where $a,b,c,d$ are real numbers and $a\ne 0$. Eg. $5x^3+3x^2+2x=1$
• Higher-degree polynomial: Polynomials with degree more than three. Eg. $7x^5+5x^3+3$

Zeros of a Polynomial

If a real number $k$ satisfies the given polynomial, then $k$ is the zero of that polynomial. (i.e) A real number k is the zero of the polynomial $P(x)$, if $P(k)=0$

Example: Let $P(x)=x^2-4$. Let $x=2$, then $P(x)=2^2-4=4-4=0$. Therefore, $2$ is the zero of the polynomial $P(x)$.

Graphical Representation of Zeros of a Polynomial

For a polynomial p(x) of degree n, the graph of y = p(x) intersects the x-axis at most n points. Therefore, a polynomial p(x) of degree n has at most n zeroes.

The number of zeros of a polynomial can be found by the number of points of the graph of the polynomial intersecting with the x-axis.

Relationship Between Zeros and Coefficients of the Polynomial

Linear Polynomial:

The zero of the linear polynomial $ax+b$ = $-\frac{b}{a}$.

Quadratic Polynomial:

For the quadratic polynomial $a{x}^2+bx+c=0$ with zeros $x_1$ and $x_2$,

Sum of zeros, $x_1+x_2=-\frac{b}{a}$

Product of zeros $x_1{x}_2=\frac{c}{a}$

Cubic Polynomial:

For the quadratic polynomial $a{x}^3+b{x}^2+cx+d=0$ with zeros $x_1$, $x_2$ and $x_3$,

Sum of zeros, $x_1+x_2=-\frac{b}{a}$

Sum of product of two zeros, $x_1{x}_2+x_2{x}_3+x_3{x}_1=\frac{c}{a}$

Product of zeros $x_1{x}_2=-\frac{d}{a}$

Class 10 Maths Chapter 2 Solutions Polynomials

Polynomial Solutions Class 10 Exercise: 2.1

Q1 (1) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the numbers of zeroes of p(x), in each case.

Answer: The number of zeroes of p(x) is zero as the curve does not intersect the x-axis.

Q1 (2) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

Answer: The number of zeroes of p(x) is one as the curve intersects the x-axis only once.

Q1 (3) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

Answer: The number of zeroes of p(x) is three as the graph intersects the x-axis thrice.

Q1 (4) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

Answer: The number of zeroes of p(x) is two as the graph intersects the x-axis twice.

Q1 (5) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

Answer: The number of zeroes of p(x) is four as the graph intersects the x-axis four times.

Q1 (6) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

Answer: The number of zeroes of p(x) is three as the graph intersects the x-axis thrice.

Class 10 Maths Chapter 2 Solutions Polynomials Exercise: 2.2

Q1 (1) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $x^2-2x-8$

Answer:

x ² - 2x - 8 = 0

x ² - 4x + 2x - 8 = 0

x(x-4) +2(x-4) = 0

(x+2)(x-4) = 0

The zeroes of the given quadratic polynomial are -2 and 4

$$\begin{gathered} \alpha =-2 \\ ,\beta =4 \end{gathered}$$

VERIFICATION

Sum of roots:

$\begin{array}{rl}& \alpha +\beta =-2+4=2\\ & -\frac{\text{ coefficient of }x}{\text{ coefficient of }{x}^2}\\ & =-\frac{-2}{1}\\ & =2\\ & =\alpha +\beta \end{array}$

Verified
Product of roots:

$\begin{array}{rl}& \alpha \beta =-2\times 4=-8\\ & \frac{\text{ constant term }}{\text{ coefficient of }{x}^2}\\ & =\frac{-8}{1}\\ & =-8\\ & =\alpha \beta \end{array}$

Verified

Q1 (ii) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $4s^2-4s+1$

Answer:

$\begin{array}{rl}& 4s^2-4s+1=0\\ & 4s^2-2s-2s+1=0\\ & 2s(2s-1)-1(2s-1)=0\\ & (2s-1)(2s-1)=0\end{array}$

The zeroes of the given quadratic polynomial are $1/2$ and $1/2$

$\begin{array}{rl}& \alpha =\frac{1}{2}\\ & \beta =\frac{1}{2}\end{array}$

VERIFICATION
Sum of roots:

$\alpha +\beta =\frac{1}{2}+\frac{1}{2}=1$

$\begin{array}{rl}& -\frac{\text{ coefficient of }x}{\text{ coefficient of }{x}^2}\\ & =-\frac{-4}{4}\\ & =1\\ & =\alpha +\beta \end{array}$

Verified
Product of roots:

$\begin{array}{rl}& \alpha \beta =\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}\\ & \frac{\text{ constant term }}{\text{ coefficient of }{x}^2}\\ & =\frac{1}{4}\\ & =\alpha \beta \end{array}$

Verified

Q1 (3) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $6x^2-3-7x$

Answer:

6x ² - 3 - 7x = 0

6x ² - 7x - 3 = 0

6x ² - 9x + 2x - 3 = 0

3x(2x - 3) + 1(2x - 3) = 0

(3x + 1)(2x - 3) = 0

The zeroes of the given quadratic polynomial are -1/3 and 3/2

$\begin{array}{rl}& \alpha =-\frac{1}{3}\\ & \beta =\frac{3}{2}\end{array}$

Sum of roots:

$\begin{array}{rl}& \alpha +\beta =-\frac{1}{3}+\frac{3}{2}=\frac{7}{6}\\ & -\frac{\text{ coefficient of }x}{\text{ coefficient of }{x}^2}\\ & =-\frac{-7}{6}\\ & =\frac{7}{6}\\ & =\alpha +\beta \end{array}$

Verified

Product of roots:

$\begin{array}{rl}& \alpha \beta =-\frac{1}{3}\times \frac{3}{2}=-\frac{1}{2}\\ & \frac{\text{ constant term }}{\text{ coefficient of }{x}^2}\\ & =\frac{-3}{6}\\ & =-\frac{1}{2}\\ & =\alpha \beta \end{array}$

Verified

Q1 (4) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $4u^2+8u$

Answer: 4u ² + 8u = 0

4u(u + 2) = 0

The zeroes of the given quadratic polynomial are 0 and -2

$\begin{array}{rl}& \alpha =0\\ & \beta =-2\end{array}$

VERIFICATION
Sum of roots:

$\begin{array}{rl}& \alpha +\beta =0+(-2)=-2\\ & -\frac{\text{ coefficient of }x}{\text{ coefficient of }{x}^2}\\ & =-\frac{8}{4}\\ & =-2\\ & =\alpha +\beta \end{array}$

Verified
Product of roots:

$\alpha \beta =0\times -2=0$

$\begin{array}{rl}& \frac{\text{ constant term }}{\text{ coeff ficient of }{x}^2}\\ & =\frac{0}{4}\\ & =0\\ & =\alpha \beta \end{array}$

Verified

Q1 (5) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $t^2-15$

Answer: t ² - 15 = 0

$(t-\sqrt{15})(t+\sqrt{15})=0$

The zeroes of the given quadratic polynomial are $-\sqrt{15}$ and $\sqrt{15}$

$\begin{array}{rl}& \alpha =-\sqrt{15}\\ & \beta =\sqrt{15}\end{array}$

VERIFICATION
Sum of roots:

$\begin{array}{rl}& \alpha +\beta =-\sqrt{15}+\sqrt{15}=0\\ & -\frac{\text{ coefficient of }x}{\text{ coefficient of }{x}^2}\\ & =-\frac{0}{1}\\ & =0\\ & =\alpha +\beta \end{array}$

Verified

Product of roots:

$\begin{array}{rl}& \alpha \beta =-\sqrt{15}\times \sqrt{15}=-15\\ & \frac{\text{ constant term }}{\text{ coefficient of }{x}^2}\\ & =\frac{-15}{1}\\ & =-15\\ & =\alpha \beta \end{array}$

Verified

Q1 (6) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $3x^2-x-4$

Answer: 3x ² - x - 4 = 0

3x ² + 3x - 4x - 4 = 0

3x(x + 1) - 4(x + 1) = 0

(3x - 4)(x + 1) = 0

The zeroes of the given quadratic polynomial are 4/3 and -1

$\begin{array}{rl}& \alpha =\frac{4}{3}\\ & \beta =-1\end{array}$

VERIFICATION
Sum of roots:

$\begin{array}{rl}& \alpha +\beta =\frac{4}{3}+(-1)=\frac{1}{3}\\ & -\frac{\text{ coefficient of }x}{\text{ coefficient of }{x}^2}\\ & =-\frac{-1}{3}\\ & =\frac{1}{3}\\ & =\alpha +\beta \end{array}$

Verified

Product of roots:

$\begin{array}{rl}& \alpha \beta =\frac{4}{3}\times -1=-\frac{4}{3}\\ & \frac{\text{ constant term }}{\text{ coefficient of }{x}^2}\\ & =\frac{-4}{3}\\ & =\alpha \beta \end{array}$

Verified

Q2 (1) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 1/4 , -1

Answer:

$\begin{array}{rl}& \alpha +\beta =\frac{1}{4}\\ & \alpha \beta =-1\end{array}$

The required quadratic polynomial is

$\begin{array}{rl}& x^2-(\alpha +\beta )x+\alpha \beta =0\\ & x^2-\frac{1}{4}x-1=0\\ & 4x^2-x-4=0\end{array}$

Q2 (2) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $\sqrt{2},1/3$

Answer:

$\begin{array}{rl}& \alpha +\beta =\sqrt{2}\\ & \alpha \beta =\frac{1}{3}\\ & x^2-(\alpha +\beta )x+\alpha \beta =0\\ & x^2-\sqrt{2}x+\frac{1}{3}=0\\ & 3x^2-3\sqrt{2}x+1=0\end{array}$

The required quadratic polynomial is $3x^2-3\sqrt{2}x+1$

Q2 (3) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $0,\sqrt{5}$

Answer:

$\begin{array}{rl}& \alpha +\beta =0\\ & \alpha \beta =\sqrt{5}\\ & x^2-(\alpha +\beta )x+\alpha \beta =0\\ & x^2-0x+\sqrt{5}=0\\ & x^2+\sqrt{5}=0\end{array}$

The required quadratic polynomial is x ² + $\sqrt{5}$ .

Q2 (4) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 1,1

Answer:

$\begin{array}{rl}& \alpha +\beta =1\\ & \alpha \beta =1\\ & x^2-(\alpha +\beta )x+\alpha \beta =0\\ & x^2-1x+1=0\\ & x^2-x+1=0\end{array}$

The required quadratic polynomial is x ² - x + 1

Q2 (5) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $-\frac{1}{4},\frac{1}{4}$

Answer:

$\begin{array}{rl}& \alpha +\beta =-\frac{1}{4}\\ & \alpha \beta =\frac{1}{4}\\ & x^2-(\alpha +\beta )x+\alpha \beta =0\\ & x^2-(-\frac{1}{4})x+\frac{1}{4}=0\\ & 4x^2+x+1=0\end{array}$

The required quadratic polynomial is 4x ² + x + 1

Q2 (6) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 4,1

Answer:

$\begin{array}{rl}& \alpha +\beta =4\\ & \alpha \beta =1\\ & x^2-(\alpha +\beta )x+\alpha \beta =0\\ & x^2-4x+1=0\end{array}$

The required quadratic polynomial is x ² - 4x + 1

Polynomial Class 10 Solutions - Exercise Wise

Here are the exercise-wise links for the NCERT class 10 chapter 2 Polynomial:

• Polynomials Class 10 Exercise 2.1
• Polynomials Class 10 Exercise 2.2
• Polynomials Class 10 Exercise 2.3
• Polynomials Class 10 Exercise 2.4

NCERT Solutions for Class 10 Maths: Chapter Wise

Importance of Solving NCERT Questions of Class 10 Maths Chapter 2

• Solving these NCERT questions will help students understand the basic concepts of Polynomials easily.
• Students can practice various types of questions which will improve their problem-solving skills.
• These NCERT exercises cover all the important topics and concepts so that students can be well-prepared for various exams.
• By solving these NCERT Polynomials problems students will get to know about all the real-life applications of Polynomials.

NCERT Solutions of Class 10 - Subject Wise

Students can use the following links to check the solution of maths and science-related questions in-depth.

• NCERT solutions for Class 10 Maths
• NCERT solutions for Class 10 Science

NCERT Exemplar solutions - Subject-wise

After completing the NCERT textbooks, students should practice exemplar exercises for a better understanding of the chapters and clarity. The following links will help students to find exemplar exercises.

• NCERT Exemplar Class 10th Maths
• NCERT Exemplar Class 10th Science

NCERT Books and NCERT Syllabus here

Here are some useful links for NCERT books and the NCERT syllabus for class 10:

• NCERT Books Class 10 Maths
• NCERT Syllabus Class 10 Maths
• NCERT Books Class 10
• NCERT Syllabus Class 10