NCERT Solutions for Exercise 2.1 Class 10 Maths Chapter 2 - Polynomials

NCERT Solutions for Exercise 2.1 Class 10 Maths Chapter 2 - Polynomials

Edited By Ramraj Saini | Updated on Nov 02, 2023 02:04 PM IST | #CBSE Class 10th

NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.1 Polynomials

NCERT solution for class 10 maths ex 2.1 are discussed here. This exercise deals with graphs including the meaning of graphs, the number of times it intersects the x-axis i.e. zeroes. These These NCERT Solutions for exercises are created by expert team at Careers360 considering the need of students, latest syllabus and pattern of CBSE 2023-24 and comprehensively covering whole questions and answers. If you really struggling with questions then keep reading this by the end of this you will be in-depth understanding of the 10th class maths exercise 2.1 answers.

According to general graph theory, each intersection with the x-axis of the graph indicates one zero of the Polynomial. A straight line parallel to the x-axis has no solution. A straight line parallel to y-axis has one solution. This chapter includes four exercise which are listed below, students should practice these problems to command the concepts.

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Download PDF of NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.1 Polynomials

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Access Exercise 2.1 Class 10 Maths Answers

Polynomials Class 10 Maths Chapter 2 Exercise: 2.1

Q1 (1) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the numbers of zeroes of p(x), in each case.

1635918537229

Answer: The number of zeroes of p(x) is zero as the curve does not intersect the x-axis.

Q1 (2) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918562539

Answer: The number of zeroes of p(x) is one as the graph intersects the x-axis only once.

Q1 (3) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918572380


Answer: The number of zeroes of p(x) is three as the graph intersects the x-axis thrice.

Q1 (4) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918582058

Answer: The number of zeroes of p(x) is two as the graph intersects the x-axis twice.

Q1 (5) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918596067

Answer: The number of zeroes of p(x) is four as the graph intersects the x-axis four times.

Q1 (6) The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case

1635918606641

Answer: The number of zeroes of p(x) is three as the graph intersects the x-axis thrice.

More About NCERT Solutions for Class 10 Maths Exercise 2.1

This ex 2.1 class 10 Maths - Graph theory emphasizes knowing the various states of the graph resembling the characteristic of the polynomial. The NCERT solutions for Class 10 Maths exercise 2.1 mainly focused on the concept number of zeroes or solutions of the polynomial determined through its graph. The concepts discussed in class 10 maths ex 2.1 questions and answers are important for competitive exams such as Boards and JEE, therefore practice them to command these concepts.

Key Features of NCERT Solutions for Class 10 Maths Exercise 2.1

  • NCERT solutions for Class 10 Maths exercise 2.1 assist students in resolving and reviewing all of the exercises questions.
  • If you go over the NCERT answer for Class 10th Maths chapter 2 exercise 2.1 properly, you will be able to gain more marks and will be able to do well in maths in examinations.
  • 10th class maths exercise 2.1 answers, is based on basic concepts of graphs namely the number of zeroes represented by the graphs. students can also study Real Numbers Class 10 Notes to revise the concepts quickly.

Also see-

NCERT Solutions of Class 10 Subject Wise

Subject Wise NCERT Exemplar Solutions

Frequently Asked Questions (FAQs)

1. What is the graph representation of polynomials according to NCERT syllabusClass 10 Maths?

Graph representation of a polynomial is plotting the values of x against the evaluated values of y and then analyzing the characteristics of the graphs whether it has no solution, one solution, two solutions or infinite solution etc depending upon how many times the graph intersects the x-axis.

2. What is meant by the zero of the polynomial?

The value of x for which the polynomial becomes zero. 

3. How are the graphs plotted?

Consider y=P(x) be any polynomial equation. To plot in the graph evaluate the value of y for each value of x and find ordered pair such as (considered value of x , evaluated value of y) plot it in the graph against the cartesian plane(a cartesian plane is a plane consisting of x-axis and y-axis).

4. Which graph represents the polynomial with infinite zeros?

 The graph in which there is a straight line coincident with the x-axis, it represents the graph with infinite solutions.

5. Which graph represents the polynomial with no solution?

Any graph which does not intersect the x-axis represents the graph with no solution.

6. Is the degree of the polynomial always equal to the number of zeroes?

No, it is not necessary.

For eg: A quadratic graph that does not intersect the x-axis has degree 2 but has 0 zeroes.

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Hello Aspirant,  Hope your doing great,  your question was incomplete and regarding  what exam your asking.

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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