NCERT Solutions for Exercise 2.2 Class 10 Maths Chapter 2

Q: How many exercises are there in Chapter 2?

There are 4 exercises in chapter 2 i.e. Ex 2.1, 2.2, 2.3, 2.4. practice problems from each exercise including ex 2.2 class 10 to command the concepts.

Q: What is the formula of the sum of roots of Polynomial ax² + bx + c =0?

The formula for sum of roots = α + β = -(b/a). where b and a are the coefficients of the polynomial. This formula is comprehensively covered in class 10 ex 2.2.

Q: What is the expression of finding Equation from sum and product of roots?

Ans: If sum of roots = α + β and Product of roots = α * β then x² - (α + β)x + α * β = 0 To get deeper understanding keep reading class 10 maths ex 2.2 using the pdf provided above in this article.

Q: If 2x^4 + x -3 is divided by g(x) and quotient is x² + 5x + 6, what will be the possible degree of remainder is?

considering the highest degree of f(x) is 4 taking highest degree of g(x) = 2 as mentioned, if you use simple exponent rule then degree of remainder = 4-2 = 2

Q: The graph in quadrant of the quadratic polynomial ax² + bx + c?

The graph of the given polynomial will be parabola and its orientation depends on the value of a, if a<0 then it's a downward parabola, and if a>0 then it's an upward parabola.

NCERT Solutions for Exercise 2.2 Class 10 Maths Chapter 2 - Polynomials

Edited By Ramraj Saini | Updated on Nov 02, 2023 03:15 PM IST | #CBSE Class 10th

Upcoming Event

CBSE Class 10th Exam Date : 15 Feb' 2025 - 15 Feb' 2025

NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.2 Polynomials

NCERT Solutions for class 10 maths ex 2.2 Polynomials is discussed here. These NCERT solutions are created by subject matter expert at Careers360 considering the latest syllabus and pattern of CBSE 2023-24. This exercise 2.2 Class 10 Maths is an introductory exercise that includes the concept of quadratic polynomials in x with real coefficients. Here we have the quadratic equation in form of ax² + bx + c=0 where a, b, c are real numbers with a cannot equal to zero.

Don't Miss: JEE Main & NEET 2026 Scholarship Test (Class 10): Narayana | Aakash

This Story also Contains

NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.2 Polynomials
Download PDF of NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.2 Polynomials
Access Exercise 2.2 Class 10 Maths Answers
More About NCERT Solutions for Class 10 Maths Chapter 2 Exercise 2.2
Key Features of NCERT Solutions for Class 10 Maths Chapter 2 Exercise 2.2
NCERT Solutions of Class 10 Subject Wise
Subject Wise NCERT Exemplar Solutions

NCERT Solutions for Exercise 2.2 Class 10 Maths Chapter 2 - Polynomials

In chapter 2 of Class 10 Mathematics NCERT syllabus the concept of zeroes along their relationship with the coefficients of equations is initialized. The Class 10 Maths chapter 2 exercise 2.2 lists a few practice problems on Polynomials. The Class 10th Maths chapter 2 exercise 2.2 covers the topics like sum and product of zeroes collectively in form of assumed roots/ zeroes. This chapter includes four exercises which are listed below, practice these to get in-depth understanding of concepts.

Pearson | PTE

Register now for PTE & Unlock 20% OFF : Use promo code: 'C360SPL20'. Valid till 31st DEC'24! Trusted by 3,500+ universities globally

Apply

Download PDF of NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.2 Polynomials

Download PDF

Access Exercise 2.2 Class 10 Maths Answers

Polynomials Class 10 Maths Chapter 2 Excercise: 2.2

Q1 (1) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $x ^2 - 2x -8$

Answer:

x ² - 2x - 8 = 0

x ² - 4x + 2x - 8 = 0

x(x-4) + 2(x-4) = 0

(x+2)(x-4) = 0

The zeroes of the given quadratic polynomial are -2 and 4

$\\\alpha =-2\\ \beta =4$

VERIFICATION

Sum of roots:

$\\\alpha+\beta =-2+4=2$

$\\-\frac{coefficient\ of\ x}{coefficient\ of\ x^{2}}\\ =-\frac{-2}{1}\\ =2\\=\alpha +\beta$

Verified

Product of roots:

$\\\alpha \beta =-2\times 4=-8$

$\\\frac{constant\ term}{coefficient\ of\ x^{2}}\\ =\frac{-8}{1}\\ =-8\\=\alpha \beta$

Verified

Q1 (ii) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $4s^2 - 4s + 1$

Answer:

$\\4s^2 - 4s + 1 = 0 \\4s^2 - 2s - 2s + 1 = 0 \\2s(2s-1) - 1(2s-1) = 0 \\(2s-1)(2s-1) = 0$

The zeroes of the given quadratic polynomial are 1/2 and 1/2

$\\\alpha =\frac{1}{2}\\ \beta =\frac{1}{2}$

VERIFICATION

Sum of roots:

$\\\alpha +\beta =\frac{1}{2}+\frac{1}{2}=1$

$\\-\frac{coefficient\ of\ x}{coefficient\ of\ x^{2}}\\ =-\frac{-4}{4}\\ =1\\=\alpha +\beta$

Verified

Product of roots:

$\alpha \beta =\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}$

$\\\frac{constant\ term}{coefficient\ of\ x^{2}}\\ =\frac{1}{4}\\ =\alpha \beta$

Verified

Q1 (3) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $6x ^2 - 3 -7x$

Answer:

6x ² - 3 - 7x = 0

6x ² - 7x - 3 = 0

6x ² - 9x + 2x - 3 = 0

3x(2x - 3) + 1(2x - 3) = 0

(3x + 1)(2x - 3) = 0

The zeroes of the given quadratic polynomial are -1/3 and 3/2

$\\\alpha =-\frac{1}{3}\\ \beta =\frac{3}{2}$

Sum of roots:

$\\\alpha+\beta =-\frac{1}{3}+\frac{3}{2}=\frac{7}{6}$

$\\-\frac{coefficient\ of\ x}{coefficient\ of\ x^{2}}\\ =-\frac{-7}{6}\\ =\frac{7}{6}\\=\alpha +\beta$

Verified

Product of roots:

$\\\alpha \beta =-\frac{1}{3}\times \frac{3}{2}=-\frac{1}{2}$

$\\\frac{constant\ term}{coefficient\ of\ x^{2}}\\ =\frac{-3}{6}\\ =-\frac{1}{2}\\=\alpha \beta$

Verified

Q1 (4) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $4 u^2 + 8u$

Answer: 4u ² + 8u = 0

4u(u + 2) = 0

The zeroes of the given quadratic polynomial are 0 and -2

$\\\alpha =0\\ \beta =-2$

VERIFICATION

Sum of roots:

$\\\alpha +\beta =0+(-2)=-2$

$\\-\frac{coefficient\ of\ x}{coefficient\ of\ x^{2}}\\ =-\frac{8}{4}\\ =-2\\=\alpha +\beta$

Verified

Product of roots:

$\alpha \beta =0\times-2=0$

$\\\frac{constant\ term}{coefficient\ of\ x^{2}}\\ =\frac{0}{4}\\=0\\ =\alpha \beta$

Verified

Q1 (5) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $t^2 - 15$

Answer: t ² - 15 = 0

$(t-\sqrt{15})(t+\sqrt{15})=0$

The zeroes of the given quadratic polynomial are $-\sqrt{15}$ and $\sqrt{15}$

$\\\alpha =-\sqrt{15}\\ \beta =\sqrt{15}$

VERIFICATION

Sum of roots:

$\\\alpha +\beta =-\sqrt{15}+\sqrt{15}=0$

$\\-\frac{coefficient\ of\ x}{coefficient\ of\ x^{2}}\\ =-\frac{0}{1}\\ =0\\=\alpha +\beta$

Verified

Product of roots:

$\alpha \beta =-\sqrt{15}\times \sqrt{15}=-15$

$\\\frac{constant\ term}{coefficient\ of\ x^{2}}\\ =\frac{-15}{1}\\=-15\\ =\alpha \beta$

Verified

Q1 (6) Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. $3 x^2 - x - 4$

Answer: 3x ² - x - 4 = 0

3x ² + 3x - 4x - 4 = 0

3x(x + 1) - 4(x + 1) = 0

(3x - 4)(x + 1) = 0

The zeroes of the given quadratic polynomial are 4/3 and -1

$\\\alpha =\frac{4}{3}\\ \beta =-1$

VERIFICATION

Sum of roots:

$\\\alpha +\beta =\frac{4}{3}+(-1)=\frac{1}{3}$

$\\-\frac{coefficient\ of\ x}{coefficient\ of\ x^{2}}\\ =-\frac{-1}{3}\\ =\frac{1}{3}\\=\alpha +\beta$

Verified

Product of roots:

$\alpha \beta =\frac{4}{3}\times -1=-\frac{4}{3}$

$\\\frac{constant\ term}{coefficient\ of\ x^{2}}\\ =\frac{-4}{3}\\ =\alpha \beta$

Verified

Q2 (1) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 1/4 , -1

Answer:

$\\\alpha +\beta =\frac{1}{4}\\ \alpha \beta =-1$

The required quadratic polynomial is

$\\x^{2}-(\alpha +\beta )+\alpha \beta =0\\ x^{2}-\frac{1}{4}x-1=0\\ 4x^{2}-x-4=0$

Q2 (2) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $\sqrt 2 , 1/3$

Answer:

$\\\alpha +\beta =\sqrt{2}\\ \alpha \beta =\frac{1}{3}$

$\\x^{2}-(\alpha +\beta )+\alpha \beta =0\\ x^{2}-\sqrt{2}x+\frac{1}{3}=0\\ 3x^{2}-3\sqrt{2}x+1=0$

The required quadratic polynomial is $3x^{2}-3\sqrt{2}x+1$

Q2 (3) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $0,\sqrt{5}$

Answer:

$\\\alpha +\beta =0\\ \alpha \beta =\sqrt{5}$

$\\x^{2}-(\alpha +\beta )+\alpha \beta =0\\ x^{2}-0x+\sqrt{5}=0\\ x^{2}+\sqrt{5}=0$

The required quadratic polynomial is x ² + $\sqrt{5}$ .

Q2 (4) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 1,1

Answer:

$\\\alpha +\beta =1\\ \alpha \beta =1$

$\\x^{2}-(\alpha +\beta )+\alpha \beta =0\\ x^{2}-1x+1=0\\ x^{2}-x+1=0$

The required quadratic polynomial is x ² - x + 1

Q2 (5) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. $-\frac{1}{4} , \frac{1}{4}$

Answer:

$\\\alpha +\beta =-\frac{1}{4}\\ \alpha \beta =\frac{1}{4}$

$\\x^{2}-(\alpha +\beta )+\alpha \beta =0\\ x^{2}-\left (-\frac{1}{4} \right )x+\frac{1}{4}=0\\ 4x^{2}+x+1=0$

The required quadratic polynomial is 4x ² + x + 1

Q2 (6) Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively. 4,1

Answer:

$\\\alpha +\beta =4\\ \alpha \beta =1$

$\\x^{2}-(\alpha +\beta )+\alpha \beta =0\\ x^{2}-4x+1=0\\$

The required quadratic polynomial is x ² - 4x + 1

Key Features of NCERT Solutions for Class 10 Maths Chapter 2 Exercise 2.2

NCERT 10th class maths exercise 2.2 answers are important as it covers questions from the basic form of equations comprehensively, step by step and according the latest syllabus and pattern of CBSE.
If students can solve each question of this exercise 2.2 Class 10 Maths they will be able to grasp the hit and trial concept of finding zeros of polynomial and concept of discriminant as given in Class 10th Maths chapter 2 exercise 2.2
For Class 10 final exams students may get the short answer or long answer questions from the type covered in the Class 10 Maths chapter 2 exercise 2.2. students can also study Real Numbers Class 10 Notes to revise the concepts quickly.

Also see-

NCERT Solutions of Class 10 Subject Wise

Subject Wise NCERT Exemplar Solutions

Frequently Asked Questions (FAQs)

1. What will be the graph of polynomial F(x) = ax² + bx + c?

The graph of the given polynomial will be Parabola but if it's upward or downward it is decided by the condition given – if a>0 the parabola is upward but if a<0 then the parabola is downward. To understanding how this is happening keep reading 10th class maths exercise 2.2 answers from the pdf provided above in this article.

2. How many exercises are there in Chapter 2?

There are 4 exercises in chapter 2 i.e. Ex 2.1, 2.2, 2.3, 2.4. practice problems from each exercise including ex 2.2 class 10 to command the concepts.

3. What is the formula of the sum of roots of Polynomial ax² + bx + c =0?

The formula for sum of roots = α + β = -(b/a). where b and a are the coefficients of the polynomial. This formula is comprehensively covered in class 10 ex 2.2.

4. What is the expression of finding Equation from sum and product of roots?

Ans: If sum of roots = α + β and Product of roots = α * β then

x² - (α + β)x + α * β = 0

To get deeper understanding keep reading class 10 maths ex 2.2 using the pdf provided above in this article.

5. If 2x^4 + x -3 is divided by g(x) and quotient is x² + 5x + 6, what will be the possible degree of remainder is?

considering the highest degree of f(x) is 4 taking highest degree of g(x) = 2 as mentioned, if you use simple exponent rule then degree of remainder = 4-2 = 2

6. The graph in quadrant of the quadratic polynomial ax² + bx + c?

The graph of the given polynomial will be parabola and its orientation depends on the value of a, if a<0 then it's a downward parabola, and if a>0 then it's an upward parabola.

7. When does quadratic equation become perfect square?

It comes under the ideal case when an Equation becomes an identity, which means When the discriminant becomes zero.

Also Read

NCERT Class 10 Maths Notes - Download Chapter Wise PDFs

The Human Eye and The Colorful world Class 10th Notes- Free NCERT Class 10 Science Chapter 11 Notes - Download PDF

NCERT Class 10 Science Chapter 14 Notes Sources Of Energy - Download PDF

Magnetic Effects of Electric Current Class 10th Notes - Free NCERT Class 10 Science Chapter 13 Notes - Download PDF

Electricity Class 10th Notes - Free NCERT Class 10 Science Chapter 12 Notes - Download PDF

Light- Reflection and Refraction Class 10th Notes- Free NCERT Class 10 Science Chapter 10 Notes - Download PDF

NCERT Syllabus for Class 10 Maths 2024-25 - Download Free PDF

NCERT Solutions for Exercise 12.3 Class 10 Maths Chapter 12 - Areas related to circles

NCERT Solutions for Exercise 12.2 Class 10 Maths Chapter 12 - Areas related to circles

NCERT Solutions for Exercise 12.1 Class 10 Maths Chapter 12 - Areas related to circles

NCERT Solutions for Class 10 Science Chapter 6 Life Processes

NCERT Solutions For Class 10 Maths Chapter 4 Quadratic Equations

NCERT Exemplar Class 10 Maths Solutions - Chapter Wise Problems with Solutions

NCERT Exemplar Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations

NCERT Exemplar Class 10 Science Solutions - Chapter Wise Problems with Solutions

Articles

BSE Telangana Hall Ticket 2025 for Regular, Private, OSSC & Vocational

Sep 10, 2024

TS SSC Result 2025, Check Telangana Class 10th Result Online @bse.telangana.gov.in

Oct 03, 2024

BSE Telangana 2025 - Telangana SSC Board Full Form, Official Website, Exam Dates, Syllabus, Result

Dec 19, 2024

Class 10 Mathematics Blueprint 2025 by CBSE: Chapter-Wise Weightage & Exam Pattern

Dec 18, 2024

CBSE Class 10 Hindi A Syllabus 2024-25 PDF - Download Chapter-Wise Curriculum/Syllabus PDF Here

Dec 17, 2024

Important Questions for Algebra CBSE Class 10 Maths Exam 2025: You Can’t Miss!

Dec 17, 2024

Class 10 Science Weightage 2024-25 Blueprint by CBSE, Chapter-Wise Weightage, Marking Scheme

Dec 09, 2024

CBSE Date Sheet 2025 Class 10th OUT; Download CBSE 10th Exam Time Table PDF

Dec 06, 2024

Upcoming School Exams

Bihar Open Board 10th Examination

Application Date:11 November,2024 - 10 January,2025

Admit Card

Result

Bihar Open Board 12th Examination

Application Date:11 November,2024 - 10 January,2025

Admit Card

Result

National Means Cum-Merit Scholarship

Admit Card Date:27 November,2024 - 22 December,2024

Eligibility Criteria

Application Process

Exam Pattern

Madhya Pradesh State Open School 12th Examination

Admit Card Date:13 December,2024 - 06 January,2025

Admit Card

Result

Gujarat Board Higher Secondary School Certificate

Late Fee Application Date:13 December,2024 - 22 December,2024

Exam Pattern

Result

Admit Card

View All School Exams

Certifications By Top Providers

My SQL Basics

Via Great Learning

Full-Stack Web Development

Via Masai School

Business Analytics Foundations

Via PW Skills

Digital Banking Business Model

Via State Bank of India

Full-Stack Android Development

Via Masai School

Machine Learning with Python a Practical Introduction

Via IBM

1115 courses

816 courses

394 courses

295 courses

Harvard University, Cambridge

98 courses

University of Michigan, Ann Arbor

83 courses

IT & Software

Teaching and Academics

Programming and Development

Health, Fitness and Medicine

Business and Management

Engineering and Architecture

General Management

Financial Management

Environmental Studies

History

Psychology

Artificial Intelligence

Explore Top Universities Across Globe

University of Essex, Colchester

Wivenhoe Park Colchester CO4 3SQ

University College London, London

Gower Street, London, WC1E 6BT

The University of Edinburgh, Edinburgh

Old College, South Bridge, Edinburgh, Post Code EH8 9YL

University of Bristol, Bristol

Beacon House, Queens Road, Bristol, BS8 1QU

University of Delaware, Newark

Newark, DE 19716

University of Nottingham, Nottingham

University Park, Nottingham NG7 2RD

Exams Required to Study in USA: GMAT, GRE, SAT, ACT, IELTS, PTE

9 min ⋆ Dec 19, 2024 06:12 AM IST

Countries Tightened Visa Rules for International Students in 2025

9 min ⋆ Dec 19, 2024 06:12 AM IST

PR in France for Indian and International Students 2025

11 min ⋆ Dec 19, 2024 05:12 AM IST

PR in USA for Indian Students in 2025

8 min ⋆ Dec 19, 2024 05:12 AM IST

Cheapest and Affordable Universities in France for International Students in 2025

12 min ⋆ Dec 19, 2024 05:12 AM IST

Study in Singapore for Indian Students in 2025

12 min ⋆ Dec 19, 2024 05:12 AM IST

Related E-books & Sample Papers

CBSE Class 10 Social Science Sample Paper with Solution 2024-25 PDF

589+ Downloads

CBSE Class 10 Mathematics (Standard) Sample Paper with Solution 2024-25 PDF

367+ Downloads

CBSE Class 10 Mathematics (Basic) Sample Paper with Solution 2024-25 PDF

187+ Downloads

CBSE Class 10 Hindi B Sample Paper with Solution 2024-25 PDF

90+ Downloads

CBSE Class 10 Hindi A Sample Paper with Solution 2024-25 PDF

61+ Downloads

CBSE Class 10 English (Language & Literature) Sample Paper with Solution 2024-25 PDF

86+ Downloads

Questions related to CBSE Class 10th

Have a question related to CBSE Class 10th ?

sadhu ashram ramgart road aligarh

If you're looking for directions or steps to reach Sadhu Ashram on Ramgart Road in Aligarh, here’s how you can get there:

Steps to Reach Sadhu Ashram, Ramgart Road, Aligarh:

Starting Point:
- Determine your starting point in Aligarh or the nearby area.
Use Google Maps:
- Open Google Maps on your phone or computer.
- Enter "Sadhu Ashram, Ramgart Road, Aligarh" as your destination.
- Follow the navigation instructions provided by Google Maps.
By Local Transport:
- Auto-rickshaw/Taxi: Hire an auto-rickshaw or taxi and inform the driver about your destination. Most local drivers should be familiar with Sadhu Ashram.
- Bus: Check if there are any local buses that operate on Ramgart Road. Ask the bus conductor if the bus stops near Sadhu Ashram.
Landmarks to Look For:
- As you approach Ramgart Road, look for local landmarks that might help you confirm you’re on the right path, such as known shops, temples, or schools nearby.
Ask for Directions:
- If you're unsure, ask locals for directions to Sadhu Ashram on Ramgart Road. It's a known location in the area.
Final Destination:
- Once you reach Ramgart Road, Sadhu Ashram should be easy to spot. Look for any signage or ask nearby people to guide you to the exact location.

If you need detailed directions from a specific location or more information about Sadhu Ashram, feel free to ask

Read Complete Answer

sai raja 01 September,2024

show the previous year exams ?

Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.

Read Complete Answer

SWETCHCHA MISKA 10 July,2024

as an icse student in class 10 is above 80 percent good enough to get into commerce in 11th cbse

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

Read Complete Answer

Manasvini Gupta 23 July,2024

i had cleared 10th from cbse in 2022 2 years ago now i wish to apply for 12th as private candidate in 2025. can i do so?

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

Read Complete Answer

Ashvadha 03 July,2024

i had cleared 10th in 2022 from cbse can i apply for 12th as private candidate this year?

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.

Read Complete Answer

sadafreen356 03 July,2024

View All

Stay up-to date with CBSE Class 10th News

Download Careers360 App

All this at the convenience of your phone

Regular Exam Updates
Best College Recommendations
College & Rank predictors
Detailed Books and Sample Papers
Question and Answers

Scan and download the app

Central Board of Secondary Education Class 10th Examination

Applications Open

Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

Option 1) less than 3	Option 2) more than 3 but less than 6
Option 3) more than 6 but less than 9	Option 4) more than 9

NCERT Solutions for Exercise 2.2 Class 10 Maths Chapter 2 - Polynomials

NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.2 Polynomials

Pearson | PTE

Download PDF of NCERT Solutions For Class 10 Maths Chapter 2 Exercise 2.2 Polynomials

Access Exercise 2.2 Class 10 Maths Answers

More About NCERT Solutions for Class 10 Maths Chapter 2 Exercise 2.2

Key Features of NCERT Solutions for Class 10 Maths Chapter 2 Exercise 2.2

NCERT Solutions of Class 10 Subject Wise

Subject Wise NCERT Exemplar Solutions

Frequently Asked Questions (FAQs)

Also Read

Articles

Upcoming School Exams

Certifications By Top Providers

Explore Top Universities Across Globe

Related E-books & Sample Papers

Questions related to CBSE Class 10th

Steps to Reach Sadhu Ashram, Ramgart Road, Aligarh:

Popular CBSE Class 10th Questions

Colleges After 12th

JEE Main Important Physics formulas

JEE Main Important Chemistry formulas

TOEFL ® Registrations 2024

Pearson | PTE

JEE Main high scoring chapters and topics

JEE Main Important Mathematics Formulas

Stay up-to date with CBSE Class 10th News

Explore on Careers360

NCERT Solutions

NCERT Exemplars

NCERT Books

NCERT Notes

CBSE

CBSE Class 10

CBSE Class 12th

CISCE Board 10th

IMO

IEO

NSO

NMMS

NVS

JNVST

Schools By Medium

By Ownership

By City

By State

Download Careers360 App

All this at the convenience of your phone

Scan and download the app