Tallentex 2025 - ALLEN's Talent Encouragement Exam
ApplyRegister for Tallentex '25 - One of The Biggest Talent Encouragement Exam
NCERT exemplar Class 10 Maths solutions chapter 9 extends the learning of circles. In earlier classes, we have learned about circles; here, we will learn about tangents at any point of the circle. This chapter covers the definition of The NCERT exemplar Class 10 Maths chapter 9 solutions have been developed by our experienced Mathematics division subject matter experts to give students a quick and easy understanding of NCERT Class 10 Maths.
These Class 10 Maths NCERT exemplar chapter 9 solutions on the chapter circles are exceptionally well structured and detailed. The CBSE Syllabus for Class 10 is the building block for these NCERT exemplar Class 10 Maths solutions chapter 9.
Question:1
If radii of two concentric circles are 4 cm and 5 cm, then the length of each chord of one circle which is tangent to the other circle is
(A) 3 cm (B) 6 cm (C) 9 cm (D) 1 cm
Answer: (B) 6 cm
SolutionQuestion:2
In Figure, if ∠AOB = 125°, then ∠COD is equal to
(A) 62.5° (B) 45° (C) 35° (D) 55°
Answer: (D)
Solution
Question:3
In Figure, AB is a chord of the circle and AOC is its diameter such that ACB = 50°. If AT is the tangent to the circle at the point A, then BAT is equal to
(A) 65° (B) 60° (C) 50° (D) 40°
Answer: (C)
Solution
Question:4
From a point P which is at a distance of 13 cm from the centre O of a circle of radius 5 cm, the pair of tangents PQ and PR to the circle are drawn. Then the area of the quadrilateral PQOR is
(A) 60 cm^{2} (B) 65 cm^{2} (C) 30 cm^{2} (D) 32.5 cm^{2}
Answer:
(A) 60 cm^{2}Question:5
At one end A of a diameter AB of a circle of radius 5 cm, tangent XAY is drawn to the circle. The length of the chord CD parallel to XY and at a distance 8 cm from A is
(A) 4 cm (B) 5 cm (C) 6 cm (D) 8 cm
Answer:
(D) 8 cmQuestion:6
In Figure, AT is a tangent to the circle with centre O such that OT = 4 cm and ∠OTA = 30°. Then AT is equal to
(A) 4 cm (B) 2 cm (C) (D)
Answer: (C)
SolutionQuestion:7
In Figure, if O is the centre of a circle, PQ is a chord and the tangent PR at P makes an angle of 50° with PQ, then ∠POQ is equal to
(A) 100° (B) 80° (C) 90° (D) 75°
Answer: (A)
SolutionQuestion:8
In Figure, if PA and PB are tangents to the circle with centre O such that APB = 50°, then OAB is equal to
(A) 25° (B) 30° (C) 40° (D) 50°
Answer: (A) 25°
SolutionQuestion:9
If two tangents inclined at an angle 60° are drawn to a circle of radius 3 cm,then length of each tangent is equal to
(A) (B) 6 cm (C) 3 cm (D)
Answer:
(D)Question:10
In Figure, if PQR is the tangent to a circle at Q whose centre is O, AB is a chord parallel to PR and BQR = 70°,then AQB is equal to
( A) 20° (B) 40° (C) 35° (D) 45°
Answer:
Answer(B)Question:1
Answer:False
SolutionQuestion:2
Answer:
FalseQuestion:3
Answer:
TrueQuestion:4
Answer:
TrueQuestion:5
Answer:
TrueQuestion:6
Answer:
FalseQuestion:7
Answer:
Answer: trueQuestion:8
Answer:
FalseQuestion:9
Answer:
TrueQuestion:10
Answer:
TrueQuestion:1
Answer:
Radius = 3 cmQuestion:2
Answer:
SolutionQuestion:3
Answer:
SolutionQuestion:4
Answer:
SolutionQuestion:5
In Figure, AB and CD are common tangents to two circles of unequal radii. Prove that AB = CD.
Answer:
SolutionQuestion:6
In Figure, AB and CD are common tangents to two circles of unequal radii.
In above question, if radii of the two circles are equal, prove that AB = CD.
Answer:
SolutionQuestion:7
In Figure, common tangents AB and CD to two circles intersect at E. Prove that AB = CD.
Answer:
SolutionQuestion:8
Answer:
SolutionQuestion:9
Prove that the tangents drawn at the ends of a chord of a circle make equal angles with the chord.
Answer:
SolutionQuestion:10
Answer:
SolutionQuestion:1
If a hexagon ABCDEF circumscribe a circle, prove that AB + CD + EF = BC + DE + FA.
Answer:
SolutionQuestion:2
Answer:
SolutionQuestion:3
Answer:
Question:4
Answer:
SolutionQuestion:5
Answer:
4.8 cmQuestion:6
Answer:
SolutionQuestion:7
Answer:
Solution
In the given figure PQ and PR are two tangents drawn from an external point P.
PQ = PR [ lengths of tangents drawn from on external point to a circle are equal]
[ angels opposite to equal sides are equal]
In PQR
[ sum of angels of a triangle is 180°]
SR||OP (Given)
[Alternate interior angles]
Also [Alternate segment angles]
In QRS
Question:8
Answer:
SolutionQuestion:9
Answer:
SolutionQuestion:10
Answer:
SolutionQuestion:11
Answer:
AnswerQuestion:12
Answer:
Given :
Here [ PC is tangent]
Question:13
Answer:
AnswerThese Class 10 Maths NCERT exemplar chapter 9 solutions provide an extension to the learning of circles done in Class 9. The chapter discusses tangents at any point of the circle along with the theorems such as the perpendicular tangent theorem. The chapter on Circles can be better understood and practiced using these NCERT exemplar Class 10 Maths chapter 9 solutions Circles and will be enough to solve other books such as A textbook of Mathematics by Monica Kapoor, NCERT Class 10 Maths, RD Sharma Class 10 Maths, RS Aggarwal Class 10 Maths et cetera.
NCERT exemplar Class 10 Maths solutions chapter 9 pdf download is a free and valuable feature. It provides the students with a pdf download facility to refer to the solutions in an offline environment while studying NCERT exemplar Class 10 Maths chapter 9.
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 |
From any point inside the circle, we can never draw a tangent to the circle.
Therefore, the answer to this question will be zero
From any point outside the circle, we can draw two tangents to the circle.
These two tangents will have equal lengths.
Circles is an important chapter for Board examinations as it carries around 6-8% weightage of the whole paper.
Generally, we get MCQ, Fill in the blanks, Short answer, and Long answer questions with a distribution of 1 question for each type. A thorough study and practice from NCERT exemplar Class 10 Maths solutions chapter 9 can help you score maximum marks for the same.
Hello
The Sadhu Ashram in Aligarh is located in Chhalesar . The ashram is open every day of the week, except for Thursdays . On Mondays, Wednesdays, and Saturdays, it's open from 8:00 a.m. to 7:30 p.m., while on Tuesdays and Fridays, it's open from 7:30 a.m. to 7:30 p.m. and 7:30 a.m. to 6:00 a.m., respectively . Sundays have varying hours from 7:00 a.m. to 8:30 p.m. . You can find it at Chhalesar, Aligarh - 202127 .
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
Register for Tallentex '25 - One of The Biggest Talent Encouragement Exam
As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
As per latest 2024 syllabus. Chemistry formulas, equations, & laws of class 11 & 12th chapters
Accepted by more than 11,000 universities in over 150 countries worldwide
Register now for PTE & Unlock 10% OFF : Use promo code: 'C360SPL10'. Limited Period Offer!
As per latest 2024 syllabus. Study 40% syllabus and score upto 100% marks in JEE