NCERT Solutions for Class 10 Maths Chapter 9 Some Applications of Trigonometry
NCERT Solutions for Class 10 Maths Chapter 9 - Some Applications of Trigonometry is the 9th chapter of Maths which deals with the applications of trigonometry in our daily life. NCERT Class 10 maths solutions for chapter 9 consist of the answers to each question given in the 9th chapter of NCERT class 10 maths book. There is only one exercise in NCERT chapter 9 Class 10 Maths which contain 16 questions. In these NCERT solutions for Class 10 Maths chapter 9, students will learn how trigonometry is used for finding the distances and heights and various objects, without actually measuring them.
NCERT solutions for Class 10 Maths chapter 9 are designed by the subject experts to help students in their preparation of board exams. Also, check NCERT solutions for Class 6 to 12.
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Also Refer,
- NCERT Notes For Class 10 Mathematics Chapter Some Applications of Trigonometry
- NCERT Exemplar Solutions For Class 10 Mathematics Chapter Trigonometry
NCERT Solutions for Class 10 Maths Chapter 9 - All Exercises
NCERT Solutions for Class 10 Maths Chapter 9 Some Applications of Trigonometry Excercise: 9.1
Answer:
Given that,
The length of the rope (AC) = 20 m. and
Let the height of the pole (AB) be
So, in the right triangle
By using the Sin rule
m.
Hence the height of the pole is 10 m.
Answer:
Suppose DB is a tree and the AD is the broken height of the tree which touches the ground at C.
GIven that,
, BC = 8 m
let AB = m and AD = m
So, AD+AB = DB =
In right angle triangle ,
So, the value of =
Similarily,
the value of is
So, the total height of the tree is-
= 8 (1.732) = 13.856 m (approx)
Answer:
Suppose m is the length of slides for children below 5 years and the length of slides for elders children be m.
Given that,
AF = 1.5 m, BC = 3 m, and
In triangle EAF,
The value of is 3 m.
Similarily in CDB,
the value of is = 2(1.732) = 3.468
Hence the length of the slide for children below 5 yrs. is 3 m and for the elder children is 3.468 m.
Answer:
Let the height of the tower AB is and the angle of elevation from the ground at point C is
According to question,
In the right triangle ,
the value of is = 10(1.732) = 17.32 m
Thus the height of the tower is 17.32 m
Answer:
A
Given that,
The length of AB = 60 m and the inclination of the string with the ground at point C is .
Let the length of the string AC be .
According to question,
In right triangle CBA,
The value of length of the string ( ) is = 40(1.732) = 69.28 m
Hence the length of the string is 69.28 m.
Answer:
Given that,
The height of the tallboy (DC) is 1.5 m and the height of the building (AB) is 30 m.
and
According to question,
In right triangle AFD,
So, DF =
In right angle triangle ,
EF =
So, distance walked by the boy towards the building = DF - EF =
Answer:
Suppose BC = is the height of transmission tower and the AB be the height of the building and AD is the distance between the building and the observer point (D).
We have,
AB = 20 m, BC = m and AD = m
and
According to question,
In triangle BDA,
So, = 20 m
Again,
In triangle CAD,
Answer- the height of the tower is 14.64 m
Answer:
Let the height of the pedestal be m. and the height of the statue is 1.6 m.
the angle of elevation of the top of the statue and top of the pedestal is( )and( ) respectively.
Now,
In triangle ,
therefore, BC = m
In triangle ,
the value of is m
Hence the height of the pedestal is m
Answer:
It is given that, the height of the tower (AB) is 50 m. and
Let the height of the building be m
According to question,
In triangle PBQ,
.......................(i)
In triangle ABQ,
.........................(ii)
On equating the eq(i) and (ii) we get,
therefore, = 50/3 = 16.66 m = height of the building.
Answer:
Given that,
The height of both poles are equal DC = AB. The angle of elevation of of the top of the poles are and resp.
Let the height of the poles be m and CE = and BE = 80 -
According to question,
In triangle DEC,
..............(i)
In triangle AEB,
..................(ii)
On equating eq (i) and eq (ii), we get
So, = 60 m
Hence the height of both poles is ( )m and the position of the point is at 60 m from the pole CD and 20 m from the pole AB.
Answer:
Suppose the is the height of the tower AB and BC = m
It is given that, the width of CD is 20 m,
According to question,
In triangle ,
............(i)
In triangle ACB,
.............(ii)
On equating eq (i) and (ii) we get:
from here we can calculate the value of and the width of the canal is 10 m.
Answer:
Let the height of the cable tower be (AB = )m
Given,
The height of the building is 7 m and angle of elevation of the top of the tower , angle of depression of its foot .
According to question,
In triangle ,
since DB = CE = 7 m
In triangle ,
Thus, the total height of the tower equal to
Answer:
Given that,
The height of the lighthouse (AB) is 75 m from the sea level. And the angle of depression of two different ships are and respectively
Let the distance between both the ships be m.
According to question,
In triangle ,
.............(i)
In triangle ,
.............(ii)
From equation (i) and (ii) we get;
Hence, the distance between the two ships is approx 55 m.
Answer:
Given that,
The height of the girl is 1.2 m. The height of the balloon from the ground is 88.2 m and the angle of elevation of the balloon from the eye of the girl at any instant is ( ) and after some time .
Let the distance travelled by the balloon from position A to position D during the interval.
AB = ED = 88.2 - 1.2 =87 m
Now, In triangle ,
In triangle ,
Thus, distance traveled by the balloon from position A to D
m
Answer:
Let be the height of the tower (DC) and the speed of the car be . Therefore, the distance (AB)covered by the car in 6 seconds is 6 m. Let time required to reach the foot of the tower. So, BC =
According to question,
In triangle ,
..........................(i)
In triangle ,
...................(ii)
Put the value of in equation (i) we get,
Hence, from point B car take 3 sec to reach the foot of the tower.
Answer:
Let the height of the tower be m.
we have PB = 4m and QB = 9 m
Suppose , so
According to question,
In triangle ,
..............(i)
In triangle ,
.....................(ii)
multiply the equation (i) and (ii), we get
Hence the height of the tower is 6 m.
NCERT Solutions for Class 10 Maths for Other Chapters
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | Some Applications of Trigonometry |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 |
Subject wise NCERT Exemplar solutions
Know more about NCERT Solutions for Class 10 Maths Chapter 9
As per NCERT Application of Trigonometry Class 10, Trigonometry is one of the most ancient topics studied by scholars all over the world. Ch 9 Maths Class 10 introduces new terms like the line of sight, angle of depression and angle of elevation. NCERT solutions for Class 10 Maths chapter 9 will give you assistance while practising the questions of the exercises 9.1.
The main topics covered in the application of trigonometry class 10
9.1 Introduction: This section introduces the concept of how trigonometry is used in everyday life, and how it was first developed for use in astronomy. The chapter will also look at how trigonometry can be used to find heights and distances without directly measuring them.
9.2 Heights and Distances: This topic delves into the concepts of line of sight, angle of deviation, angle of elevation, and angle of depression, and demonstrates how to solve problems using trigonometric ratios.
9.3 Summary: This section provides a summary of the key points covered in the chapter, helping students to focus on the most important concepts.
Let's understand a few terms used in Some Applications of Trigonometry Class 10 Chapter through the diagram.
The line of sight- It is an imaginary line drawn from the observer's eye to the object viewed by the observer.
The angle of elevation- The angle of elevation of an object viewed by an observer, is the angle formed by the line of sight with the horizontal level when the object is above the horizontal level,
The angle of depression- The angle of depression of an object viewed by an observer, is the angle formed by the line of sight with the horizontal level when the object is below the horizontal level.
How to use NCERT Solutions for Class 10 Maths Chapter 9?
Before coming to this Class 10 Chapter 9, please ensure that you have completed the previous chapter Introduction to Trigonometry.
Read the conceptual theory given in the NCERT textbook and have a look over some examples present in the textbook for the deeper understanding of the topics.
Once you complete the above points then you can jump to the practice exercises available in the NCERT book.
While practicing the questions in practice exercises, you can use NCERT solutions for Class 10 Maths chapter 9 to know how to solve, what is the final answer and so on.
When you have done the practice exercise then the best thing to make your concepts strong is the last 5 years CBSE class 10 question papers and the NCERT exemplar problems.
Keep working hard & happy learning!
NCERT Solutions for Class 10 for other subjects.
Also Check NCERT Books and NCERT Syllabus here
Frequently Asked Question (FAQs) - NCERT Solutions for Class 10 Maths Chapter 9 Some Applications of Trigonometry
Question: What are the benefits of studying the class 10 maths applications of trigonometry solutions?
Answer:
Some of the benefits of studying NCERT Solutions for application to trigonometry class 10 include the ability to calculate heights and distances of objects without direct measurement and a better understanding of trigonometry-based questions. This knowledge will aid students in answering questions related to trigonometry and performing well in class tests and CBSE exams.
Question: How does the NCERT solutions are helpful in CBSE board exam?
Answer:
In CBSE board exam most of the questions are directly asked from NCERT textbook, so students must know topics in the NCERT syllabus very well. In NCERT class 10 maths book. , you will get are detailed solutions provided by the experts who knows how best to answer in the board exam in order to get good marks. Students can practice more questions from NCERT Exemplar.
Question: Are the NCERT Solutions for Class 10 Maths Chapter 9 sufficient for CBSE ex
Answer:
It is important to thoroughly study and practice all the questions in the NCERT Solutions for trigonometry applications class 10. Once you have completed all the questions, you can supplement your learning by consulting other reference materials and the questions provided in the NCERT Exemplar textbooks.
Question: Where can one find the applications of trigonometry class 10 ncert solutions?
Answer:
Some applications of trigonometry class 10 ncert solutions can be downloaded for free in PDF format from the Craerrs360 website. These NCERT solutions can also find above in this article. Students can practice them to score well in the exam. Also, students can download the application of trigonometry pdf format to study offline.
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Questions related to CBSE Class 10th
my sons dob is 13/02/2009 is hi eligible for 10th board exam in 2024,,from cbse. olz reply me
The eligibility age criteria for class 10th CBSE is 14 years of age. Since your son will be 15 years of age in 2024, he will be eligible to give the exam.
can Hindi marks be replace with IT 402(additional subject) in CBSE class 10th board
That totally depends on what you are aiming for. The replacement of marks of additional subjects and the main subject is not like you will get the marks of IT on your Hindi section. It runs like when you calculate your total percentage you have got, you can replace your lowest marks of the main subjects from the marks of the additional subject since CBSE schools goes for the best five marks for the calculation of final percentage of the students.
However, for the admission procedures in different schools after 10th, it depends on the schools to consider the percentage of main five subjects or the best five subjects to admit the student in their schools.
i got less marks in maths can it get replaced by additional hindi in cbse
Replacement of marks of additional subjects and your main course subject is not like they will swap the marks you got in Hindi and Mathematics on your marksheet. It works like if you calculate the total percentage you got in your class, you can take the marks of your additional subject to consider in place of the subject you have got the least marks in. CBSE schools consider this method only to release the merit list of their students.
If you're in 10th and aiming to get admission in 11th in any school, it depends on the schools if they consider your main five subject marks or the best five subject marks for the admission.
If you're in 12th and are trying for different colleges to get in, it depends on your course which you wish to study further and also some criterias and eligibility of the colleges. In most cases for general courses, colleges take the best three or best four subjects marks consideration for the admission process.
So, good luck.
when will cbse term 2 result will declare please tale
Hello,
Central Board of Secondary Education will declare term 2 CBSE exam result 2022 for Class 10 in the third week of July. Please keep an eye on the official website or the link below for the latest information. Students need to enter their CBSE board roll number and other details to check term 2 cbseresults.nic.in 2022 Class 10 results. The board had announced the CBSE Class 10 results 2022 for term 1 on March 11, 2022.
cbse 10 claas bord result check now
Hello Aspirant,
Class 10 cbse results are not out yet. It is expected to be declared on 23rd of July. Keep checking the official website of cbse.
Good luck.