NCERT Solutions for Class 10 Maths Chapter 9 Some Applications of Trigonometry
NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry- This is an application chapter of the previous chapter. In this particular chapter, we will study some ways in which trigonometry is used in our daily life. NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry has covered the detailed explanation to each and every question. In the previous class, you have studied trigonometric ratios. Trigonometry is used in navigation, geography, construction of maps, determining the position of an island, etc. In this chapter, we will learn how trigonometry is used for finding the distances and heights and various objects, without actually measuring them. Trigonometry is one of the most ancient topics studied by scholars all over the world. In this chapter, there is only one exercise with 16 questions, based on the practical application of trigonometry. NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry are designed by the subject experts to help students in their preparation of board exams. This chapter introduces new terms like the line of sight, angle of depression and angle of elevation. NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry will give you assistance while practicing the questions of the practice exercises including optional exercise. Let's understand a few terms used in this chapter through the diagram.
The line of sight- It is an imaginary line drawn from the observer's eye to the object viewed by the observer.
The angle of elevation- The angle of elevation of an object viewed by an observer, is the angle formed by the line of sight with the horizontal level when the object is above the horizontal level,
The angle of depression- The angle of depression of an object viewed by an observer, is the angle formed by the line of sight with the horizontal level when the object is below the horizontal level.
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NCERT Solutions for Class 10 Maths Chapter 9 Some Applications of Trigonometry Excercise: 9.1
Answer:
Given that,
The length of the rope (AC) = 20 m. and
Let the height of the pole (AB) be
So, in the right triangle
By using the Sin rule
m.
Hence the height of the pole is 10 m.
Answer:
Suppose DB is a tree and the AD is the broken height of the tree which touches the ground at C.
GIven that,
, BC = 8 m
let AB = m and AD = m
So, AD+AB = DB =
In right angle triangle ,
So, the value of =
Similarily,
the value of is
So, the total height of the tree is-
= 8 (1.732) = 13.856 m (approx)
Answer:
Suppose m is the length of slides for children below 5 years and the length of slides for elders children be m.
Given that,
AF = 1.5 m, BC = 3 m, and
In triangle EAF,
The value of is 3 m.
Similarily in CDB,
the value of is = 2(1.732) = 3.468
Hence the length of the slide for children below 5 yrs. is 3 m and for the elder children is 3.468 m.
Answer:
Let the height of the tower AB is and the angle of elevation from the ground at point C is
According to question,
In the right triangle ,
the value of is = 10(1.732) = 17.32 m
Thus the height of the tower is 17.32 m
Answer:
A
Given that,
The length of AB = 60 m and the inclination of the string with the ground at point C is .
Let the length of the string AC be .
According to question,
In right triangle CBA,
The value of length of the string ( ) is = 40(1.732) = 69.28 m
Hence the length of the string is 69.28 m.
Answer:
Given that,
The height of the tallboy (DC) is 1.5 m and the height of the building (AB) is 30 m.
and
According to question,
In right triangle AFD,
So, DF =
In right angle triangle ,
EF =
So, distance walked by the boy towards the building = DF - EF =
Answer:
Suppose BC = is the height of transmission tower and the AB be the height of the building and AD is the distance between the building and the observer point (D).
We have,
AB = 20 m, BC = m and AD = m
and
According to question,
In triangle BDA,
So, = 20 m
Again,
In triangle CAD,
Answer- the height of the tower is 14.64 m
Answer:
Let the height of the pedestal be m. and the height of the statue is 1.6 m.
the angle of elevation of the top of the statue and top of the pedestal is( )and( ) respectively.
Now,
In triangle ,
therefore, BC = m
In triangle ,
the value of is m
Hence the height of the pedestal is m
Answer:
It is given that, the height of the tower (AB) is 50 m. and
Let the height of the building be m
According to question,
In triangle PBQ,
.......................(i)
In triangle ABQ,
.........................(ii)
On equating the eq(i) and (ii) we get,
therefore, = 50/3 = 16.66 m = height of the building.
Answer:
Given that,
The height of both poles are equal DC = AB. The angle of elevation of of the top of the poles are and resp.
Let the height of the poles be m and CE = and BE = 80 -
According to question,
In triangle DEC,
..............(i)
In triangle AEB,
..................(ii)
On equating eq (i) and eq (ii), we get
m
So, = 60 m
Hence the height of both poles is ( )m and the position of the point is at 60 m from the pole CD and 20 m from the pole AB.
Answer:
Suppose the is the height of the tower AB and BC = m
It is given that, the width of CD is 20 m,
According to question,
In triangle ,
............(i)
In triangle ACB,
.............(ii)
On equating eq (i) and (ii) we get:
from here we can calculate the value of and the width of the canal is 10 m.
Answer:
Let the height of the cable tower be (AB = )m
Given,
The height of the building is 7 m and angle of elevation of the top of the tower , angle of depression of its foot .
According to question,
In triangle ,
since DB = CE = 7 m
In triangle ,
Thus, the total height of the tower equal to
Answer:
Given that,
The height of the lighthouse (AB) is 75 m from the sea level. And the angle of depression of two different ships are and respectively
Let the distance between both the ships be m.
According to question,
In triangle ,
.............(i)
In triangle ,
.............(ii)
From equation (i) and (ii) we get;
Hence, the distance between the two ships is approx 55 m.
Answer:
Given that,
The height of the girl is 1.2 m. The height of the balloon from the ground is 88.2 m and the angle of elevation of the balloon from the eye of the girl at any instant is ( ) and after some time .
Let the distance travelled by the balloon from position A to position D during the interval.
AB = ED = 88.2 - 1.2 =87 m
Now, In triangle ,
In triangle ,
Thus, distance traveled by the balloon from position A to D
m
Answer:
Let be the height of the tower (DC) and the speed of the car be . Therefore, the distance (AB)covered by the car in 6 seconds is 6 m. Let time required to reach the foot of the tower. So, BC =
According to question,
In triangle ,
..........................(i)
In triangle ,
...................(ii)
Put the value of in equation (i) we get,
Hence, from point B car take 3 sec to reach the foot of the tower.
Answer:
Let the height of the tower be m.
we have PB = 4m and QB = 9 m
Suppose , so
According to question,
In triangle ,
..............(i)
In triangle ,
.....................(ii)
multiply the equation (i) and (ii), we get
Hence the height of the tower is 6 m.
NCERT solutions for class 10 maths chapter wise
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | |
Chapter 3 | NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in Two Variables |
Chapter 4 | NCERT solutions for class 10 maths chapter 4 Quadratic Equations |
Chapter 5 | NCERT solutions for class 10 chapter 5 Arithmetic Progressions |
Chapter 6 | |
Chapter 7 | NCERT solutions for class 10 maths chapter 7 Coordinate Geometry |
Chapter 8 | NCERT solutions for class 10 maths chapter 8 Introduction to Trigonometry |
Chapter 9 | NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | NCERT solutions for class 10 chapter maths chapter 12 Areas Related to Circles |
Chapter 13 | NCERT solutions class 10 maths chapter 13 Surface Areas and Volumes |
Chapter 14 | |
Chapter 15 |
NCERT solutions of class 10 subject wise
How to use NCERT Solutions for class 10 maths chapter 9 Some Applications of Trigonometry ?
- Before coming to this chapter, please ensure that you have completed the previous chapter.
Read the conceptual theory given in the NCERT textbook and have a look over some examples present in the textbook.
Once you complete the above points then you can jump to the practice exercises available in the NCERT textbook.
While practicing the questions in practice exercises, you can use NCERT solutions for class 10 maths chapter 9 Some Applications of Trigonometry.
When you have done the practice exercise then the best thing to make your concepts strong is the last 5 year papers.
Keep working hard & happy learning!
Frequently Asked Question (FAQs) - NCERT Solutions for Class 10 Maths Chapter 9 Some Applications of Trigonometry
Question: Does CBSE provides the solutions of NCERT class 10 ?
Answer:
No, CBSE doesn’t provided NCERT solutions for any class or subject.
Question: Where can I find the complete solutions of NCERT class 10 maths ?
Answer:
Here you will get the detailed NCERT solutions for class 10 maths by clicking on the link.
Question: How does the NCERT solutions are helpful in CBSE board exam?
Answer:
In CBSE board exam most of the questions are directly asked from NCERT textbook, so must know NCERT very well. In NCERT solutions, you will get are detailed solutions provided by the experts who knows how best to answer in the board exam in order to get good marks.
Question: Which is the official website of NCERT ?
Answer:
NCERT official is the official website of the NCERT where you can get NCERT textbooks and syllabus from class 1 to 12.
Question: What is the weightage of the chapter application of trigonometry in CBSE board exam ?
Answer:
Two chapters trigonometry and applications of trigonometry has 12 marks weightage in 10 board final exam.
Question: How many chapters are there in the class 10 maths ?
Answer:
There are 15 chapters in the class 10 maths NCERT. Chapter 1- Real Numbers, Chapter 2- Polynomials, Chapter 3- Pair of Linear Equations in Two Variables, Chapter 4- Quadratic Equations, Chapter 5- Arithmetic Progressions, Chapter 6- Triangles, Chapter 7- Coordinate Geometry, Chapter 8- Introduction to Trigonometry, Chapter 9- Some Applications of Trigonometry, Chapter 10- Circles, Chapter 11- Constructions, Chapter 12- Areas Related to Circles, Chapter 13- Surface Areas and Volumes, Chapter 14- Statistics, Chapter 15- Probability are the chapters in the NCERT class 10 maths.