# NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables

**NCERT Solutions for Class 10 Maths Chapter 3 PDF Download - **The name of 3rd chapter is ‘Pair of Linear Equations in Two Variables’. NCERT Class 10 maths solutions chapter 3 is an important chapter of Algebra. In NCERT solutions class 10 maths chapter 3, students will learn to solve the linear equation with two variables. Class 10 Maths chapter 3 NCERT solutions contain the answers of all exercise NCERT questions. NCERT Class 10 maths chapter 3 solutions are helpful to know the answers to the questions asked in NCERT class 10 maths book. Apart from this, by going through NCERT solutions for class 10 maths chapter 3, they will come to know about various methods of solving questions.

NCERT solutions for class 10 are also available for other subjects.

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### NCERT Solutions Class 10 Maths Chapter 3 Topics

Solving a linear equation with two variables.

Representation of linear equation in a graph.

Solutions of linear equations using the graph.

Algebraic interpretation of linear equations.

Formation of linear equations using statements.

## NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in two variables Excercise: 3.1

Answer: Let x be the age of Aftab and y be the age of his daughter

Now, According to the question,

Also,

Now, let's represent both equations graphically,

From (1), we get

So, Putting different values of x we get corresponding values of y

X | 0 | 7 | -7 |

Y | 6 | 7 | 5 |

And From (2) we get,

So, Putting different values of x we get corresponding values of y

X | 0 | 3 | 6 |

Y | -2 | -1 | 0 |

GRAPH:

Answer:

Let the price of one Bat be x and the price of one ball be y,

Now, According to the question,

From(1) we have

By putting different values of x, we get different corresponding values of y.So

X | 100 | 300 | -100 |

Y | 600 | 500 | 700 |

Now, From (2), we have,

By putting different values of x, we get different corresponding values of y.So

X | 100 | 400 | -200 |

Y | 400 | 300 | 500 |

GRAPH:

Answer:

Let, x be the cost of 1kg apple and y be the cost of 1kg grapes.

Now, According to the question,

On a day:

After One Month:

Now, From (1) we have

Putting different values of x we get corresponding values of y, so,'

X | 80 | 60 | 50 |

Y | 0 | 40 | 60 |

And From (2) we have,

Putting different values of x we get corresponding values of y, so,

X | 50 | 60 | 70 |

Y | 50 | 30 | 10 |

Graph:

## NCERT solutions for class 10 maths Chapter 3 Pair of Linear Equations in two variables Excercise: 3.2

Q1 Form the pair of linear equations in the following problems and find their solutions graphically.

Answer:

Let the number of boys is x and the number of girls is y.

Now, According to the question,

Total number of students in the class = 10, i.e.

And

the number of girls is 4 more than the number of boys,i.e.

Different points (x, y) for equation (1)

X | 5 | 6 | 4 |

Y | 5 | 4 | 6 |

Different points (x,y) satisfying (2)

X | 5 | 6 | 7 |

y | 1 | 2 | 3 |

Graph,

As we can see from the graph, both lines intersect at the point (7,3). that is x= 7 and y = 3 which means the number of boys in the class is 7 and the number of girls in the class is 3.

Q1 Form the pair of linear equations in the following problems and find their solutions graphically.

Answer:

Let x be the price of 1 pencil and y be the price of 1 pen,

Now, According to the question

And

Now, the points (x,y), that satisfies the equation (1) are

X | 3 | -4 | 10 |

Y | 5 | 10 | 0 |

And, the points(x,y) that satisfies the equation (2) are

X | 3 | 8 | -2 |

Y | 5 | -2 | 12 |

The Graph,

As we can see from the Graph, both line intersects at point (3,5) that is, x = 3 and y = 5 which means cost of 1 pencil is 3 and the cost of 1 pen is 5.

Answer:

Give, Equations,

Comparing these equations with , we get

As we can see

It means that both lines intersect at exactly one point.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means that both lines are coincident.

Q2 On comparing the ratios , and , find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident: (iii)

Answer:

Give, Equations,

Comparing these equations with , we get

As we can see

It means that both lines are parallel to each other.

Answer:

Give, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have exactly one solution and thus pair of linear equations is consistent.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have no solution and thus pair of linear equations is inconsistent.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have exactly one solution and thus pair of linear equations is consistent.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have an infinite number of solutions and thus pair of linear equations is consistent.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have an infinite number of solutions and thus pair of linear equations is consistent.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have an infinite number of solutions and thus pair of linear equations is consistent.

The points (x,y) which satisfies in both equations are

X | 1 | 3 | 5 |

Y | 4 | 2 | 0 |

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have no solution and thus pair of linear equations is inconsistent.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have exactly one solution and thus pair of linear equations is consistent.

Now The points(x, y) satisfying the equation are,

X | 0 | 2 | 3 |

Y | 6 | 2 | 0 |

And The points(x,y) satisfying the equation are,

X | 0 | 1 | 2 |

Y | -2 | 0 | 2 |

GRAPH:

As we can see both lines intersects at point (2,2) and hence the solution of both equations is x = 2 and y = 2.

Answer:

Given, Equations,

Comparing these equations with , we get

As we can see

It means the given equations have no solution and thus pair of linear equations is inconsistent.

Answer:

Let be the length of the rectangular garden and be the width.

Now, According to the question, the length is 4 m more than its width.i.e.

Also Given Half Parameter of the rectangle = 36 i.e.

Now, as we have two equations, on adding both equations, we get,

Putting this in equation (1),

Hence Length and width of the rectangle are 20m and 16 respectively.

### Answer:

### Given the equation,

As we know that the condition for the intersection of lines , is ,

So Any line with this condition can be

Here,

As

the line satisfies the given condition.

### Answer:

Given the equation,

As we know that the condition for the lines , for being parallel is,

So Any line with this condition can be

Here,

As

the line satisfies the given condition.

### Answer:

Given the equation,

As we know that the condition for the coincidence of the lines , is,

So any line with this condition can be

Here,

As

the line satisfies the given condition.

### Answer:

Given, two equations,

And

The points (x,y) satisfying (1) are

X | 0 | 3 | 6 |

Y | 1 | 4 | 7 |

And The points(x,y) satisfying (2) are,

X | 0 | 2 | 4 |

Y | 6 | 3 | 0 |

GRAPH:

24151

As we can see from the graph that both lines intersect at the point (2,3), And the vertices of the Triangle are ( -1,0), (2,3) and (4,0). The area of the triangle is shaded with a green color.

## NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in two variables Excercise: 3.3

Q1 Solve the following pair of linear equations by the substitution method. (i)

Answer:

Given, two equations,

Now, from (1), we have

Substituting this in (2), we get

Substituting this value of x in (3)

Hence, Solution of the given equations is x = 9 and y = 5.

Q1 Solve the following pair of linear equations by the substitution method (ii)

Answer:

Given, two equations,

Now, from (1), we have

Substituting this in (2), we get

Substituting this value of t in (3)

Hence, Solution of the given equations is s = 9 and t = 6.

Q1 Solve the following pair of linear equations by the substitution method. (iii)

Answer:

Given, two equations,

Now, from (1), we have

Substituting this in (2), we get

This is always true, and hence this pair of the equation has infinite solutions.

As we have

,

One of many possible solutions is .

Q1 Solve the following pair of linear equations by the substitution method. (iv)

Answer:

Given, two equations,

Now, from (1), we have

Substituting this in (2), we get

Substituting this value of x in (3)

Hence, Solution of the given equations is,

.

Q1 Solve the following pair of linear equations by the substitution method. (v)

Answer:

Given, two equations,

Now, from (1), we have

Substituting this in (2), we get

Substituting this value of x in (3)

Hence, Solution of the given equations is,

.

Q1 Solve the following pair of linear equations by the substitution method. (vi)

Answer:

Given,

From (1) we have,

Putting this in (2) we get,

putting this value in (3) we get,

Hence

Q2 Solve and and hence find the value of ‘ ’ for which .

Answer:

Given, two equations,

Now, from (1), we have

Substituting this in (2), we get

Substituting this value of x in (3)

Hence, Solution of the given equations is,

Now,

As it satisfies ,

Hence Value of m is -1.

(i) The difference between the two numbers is 26 and one number is three times the other. Find them.

Answer:

Let two numbers be x and y and let the bigger number is y.

Now, According to the question,

And

Now, the substituting value of y from (2) in (1) we get,

Substituting this in (2)

Hence the two numbers are 13 and 39.

Answer:

Let the larger angle be x and smaller angle be y

Now, As we know the sum of supplementary angles is 180. so,

Also given in the question,

Now, From (2) we have,

Substituting this value in (1)

Now, Substituting this value of x in (3), we get

Hence the two supplementary angles are

Answer:

Let the cost of 1 bat is x and the cost of 1 ball is y.

Now, According to the question,

Now, From (1) we have

Substituting this value of y in (2)

Now, Substituting this value of x in (3)

Hence, The cost of one bat is 500 Rs and the cost of one ball 50 Rs.

Answer:

Let the fixed charge is x and the per km charge is y.

Now According to the question

And

Now, From (1) we have,

Substituting this value of x in (2), we have

Now, Substituting this value in (3)

Hence, the fixed charge is 5 Rs and the per km charge is 10 Rs.

Now, Fair For 25 km :

Hence fair for 25km is 255 Rs.

Answer:

Let the numerator of the fraction be x and denominator of the fraction is y

Now According to the question,

Also,

Now, From (1) we have

Substituting this value of y in (2)

Substituting this value of x in (3)

Hence the required fraction is

Answer:

Let x be the age of Jacob and y be the age of Jacob's son,

Now, According to the question

Also,

Now,

From (1) we have,

Substituting this value of x in (2)

Substituting this value of y in (3),

Hence, Present age of Jacob is 40 years and the present age of Jacob's son is 10 years.

## NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in two variables Excercise: 3.4

Q1 Solve the following pair of linear equations by the elimination method and the substitution method :

Answer:

Elimination Method:

Given, equations

Now, multiplying (1) by 3 we, get

Now, Adding (2) and (3), we get

Substituting this value in (1) we, get

Hence,

Substitution method :

Given, equations

Now, from (1) we have,

substituting this value in (2)

Substituting this value of x in (3)

Hence,

Q1 Solve the following pair of linear equations by the elimination method and the substitution method :

Answer:

Elimination Method:

Given, equations

Now, multiplying (2) by 2 we, get

Now, Adding (1) and (3), we get

Putting this value in (2) we, get

Hence,

Substitution method :

Given, equations

Now, from (2) we have,

substituting this value in (1)

Substituting this value of x in (3)

Hence,

Answer:

Elimination Method:

Given, equations

Now, multiplying (1) by 3 we, get

Now, Subtracting (3) from (2), we get

Putting this value in (1) we, get

Hence,

Substitution method :

Given, equations

Now, from (2) we have,

substituting this value in (1)

Substituting this value of x in (3)

Hence,

Answer:

Elimination Method:

Given, equations

Now, multiplying (2) by 2 we, get

Now, Adding (1) and (3), we get

Putting this value in (2) we, get

Hence,

Substitution method :

Given, equations

Now, from (2) we have,

substituting this value in (1)

Substituting this value of x in (3)

Hence,

Answer:

Let the numerator of the fraction be x and denominator is y,

Now, According to the question,

Also,

Now, Subtracting (1) from (2) we get

Putting this value in (1)

Hence

And the fraction is

Answer:

Let the age of Nuri be x and age of Sonu be y.

Now, According to the question

Also,

Now, Subtracting (1) from (2), we get

putting this value in (2)

Hence the age of Nuri is 50 and the age of Nuri is 20.

Answer:

Let the unit digit of the number be x and 10's digit be y.

Now, According to the question,

24323

Also

Now adding (1) and (2) we get,

now putting this value in (1)

Hence the number is 18.

Answer:

Let the number of Rs 50 notes be x and the number of Rs 100 notes be y.

Now, According to the question,

And

Now, Subtracting(1) from (2), we get

Putting this value in (1).

Hence Meena received 10 50 Rs notes and 15 100 Rs notes.

Answer:

Let fixed charge be x and per day charge is y.

Now, According to the question,

And

Now, Subtracting (2) from (1). we get,

Putting this in (1)

Hence the fixed charge is 15 Rs and per day charge is 3 Rs.

## NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in two variables Excercise: 3.5

### Answer:

Given, two equations,

Comparing these equations with , we get

As we can see,

Hence, the pair of equations has no solution.

### Answer:

Given, two equations,

Comparing these equations with , we get

As we can see,

Hence, the pair of equations has exactly one solution.

By Cross multiplication method,

### Answer:

Given the equations,

Comparing these equations with , we get

As we can see,

Hence, the pair of equations has infinitely many solutions.

### Answer:

Given the equations,

Comparing these equations with , we get

As we can see,

Hence, the pair of equations has exactly one solution.

By Cross multiplication method,

### Answer:

Given equations,

As we know, the condition for equations to have an infinite solution is

So, Comparing these equations with, , we get

From here we get,

Also,

Now, Subtracting (2) from (1) we get

Substituting this value in (1)

Hence, .

Q2 (ii) For which value of k will the following pair of linear equations have no solution?

### Answer:

Given, the equations,

As we know, the condition for equations to have no solution is

So, Comparing these equations with, , we get

From here we get,

Hence, the value of K is 2.

Q3 Solve the following pair of linear equations by the substitution and cross-multiplication methods :

### Answer:

Given the equations

By Substitution Method,

From (1) we have

Substituting this in (2),

Substituting this in (3)

Hence .

By Cross Multiplication Method

### Answer:

Let the fixed charge be x and the cost of food per day is y,

Now, According to the question

Also

Now subtracting (1) from (2),

Putting this value in (1)

Hence, the Fixed charge is Rs 400 and the cost of food per day is Rs 30.

### Answer:

Let numerator of a fraction be x and the denominator is y.

Now, According to the question,

Also,

Now, Subtracting (1) from (2) we get,

Putting this value in (2) we get,

Hence, the fraction is

.

### Answer:

Let the number of right answer and wrong answer be x and y respectively

Now, According to the question,

And

Now, subtracting (2) from (1) we get,

Putting this value in (1)

Hence the total number of question is

### Answer:

Let the speed of the first car is x and the speed of the second car is y.

Let's solve this problem by using relative motion concept,

the relative speed when they are going in the same direction= x - y

the relative speed when they are going in the opposite direction= x + y

The given relative distance between them = 100 km.

Now, As we know,

Relative distance = Relative speed * time .

So, According to the question,

Also,

Now Adding (1) and (2) we get

putting this in (1)

Hence the speeds of the cars are 40 km/hour and 60 km/hour.

### Answer:

Let be the length of the rectangle and be the width,

Now, According to the question,

Also,

By Cross multiplication method,

Hence the length and width of the rectangle are 17 units and 9 units respectively.

## NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in two variables Excercise: 3.6

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations:

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

By Cross Multiplication method,

And Hence,

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations:

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

By Cross Multiplication method,

So,

.

And hence

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations:

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

By Cross Multiplication method,

And Hence,

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations:

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

Multiplying (1) by 3 we get

Now, adding (2) and (3) we get

Putting this in (2)

Now,

Hence,

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations: (v)

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

By Cross Multiplication method,

And Hence,

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations:

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

By Cross Multiplication method,

And Hence,

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations:

(vii)

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

By Cross Multiplication method,

Now,

And,

Adding (3) and (4) we get,

Putting this value in (3) we get,

And Hence,

Q1 Solve the following pairs of equations by reducing them to a pair of linear equations:

### Answer:

Given Equations,

Let,

Now, our equation becomes

And

Now, Adding (1) and (2), we get

Putting this value in (1)

Now,

And

Now, Adding (3) and (4), we get

Putting this value in (3),

Hence,

### Answer:

Let the speed of Ritu in still water be x and speed of current be y,

Let's solve this problem by using relative motion concept,

the relative speed when they are going in the same direction (downstream)= x +y

the relative speed when they are going in the opposite direction (upstream)= x - y

Now, As we know,

Relative distance = Relative speed * time .

So, According to the question,

And,

Now, Adding (1) and (2), we get

Putting this in (2)

Hence,

Hence Speed of Ritu in still water is 6 km/hour and speed of the current is 4 km/hour

### Answer:

Let the number of days taken by woman and man be x and y respectively,

The proportion of Work done by a woman in a single day

The proportion of Work done by a man in a single day

Now, According to the question,

Also,

Let,

Now, our equation becomes

And

By Cross Multiplication method,

So,

### Answer:

Let the speed of the train and bus be u and v respectively

Now According to the question,

And

Let,

Now, our equation becomes

And

By Cross Multiplication method,

And Hence,

Hence the speed of the train and bus are 60 km/hour and 80 km/hour respectively.

## NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in two variables Excercise: 3.7

Answer:

Let the age of Ani be , age of Biju be ,

Case 1: when Ani is older than Biju

age of Ani's father Dharam:

and

age of his sister Cathy :

Now According to the question,

Also,

Now subtracting (1) from (2), we get,

putting this in (1)

Hence the age of Ani and Biju is 19 years and 16 years respectively.

Case 2:

And

Now Adding (3) and (4), we get,

putting it in (3)

Hence the age of Ani and Biju is 21 years and 24 years respectively.

Answer:

Let the amount of money the first person and the second person having is x and y respectively

Noe, According to the question.

Also

Multiplying (2) by 2 we get,

Now adding (1) and (3), we get

Putting this value in (1)

Thus two friends had 40 Rs and 170 Rs respectively.

Answer:

Let the speed of the train be v km/h and the time taken by train to travel the given distance be t hours and the distance to travel be d km.

Now As we Know,

Now, According to the question,

Now, Using equation (1), we have

Also,

Adding equations (2) and (3), we obtain:

Substituting the value of x in equation (2), we obtain:

Putting this value in (1) we get,

Hence the distance covered by train is 600km.

Answer:

Let the number of rows is x and the number of students in a row is y.

Total number of students in the class = Number of rows * Number of students in a row

Now, According to the question,

Also,

Subtracting equation (2) from (1), we get:

Substituting the value of y in equation (1), we obtain:

Hence,

The number of rows is 4 and the Number of students in a row is 9.

Total number of students in a class

:

Hence there are 36 students in the class.

Q5 In a , . Find the three angles.

Answer:

Given,

Also, As we know that the sum of angles of a triangle is 180, so

Now From (1) we have

Putting this value in (2) we have

Putting this in (3)

And

Hence three angles of triangles

Answer:

Given two equations,

And

Points(x,y) which satisfies equation (1) are:

X | 0 | 1 | 5 |

Y | -5 | 0 | 20 |

Points(x,y) which satisfies equation (1) are:

X | 0 | 1 | 2 |

Y | -3 | 0 | 3 |

GRAPH:

As we can see from the graph, the three points of the triangle are, (0,-3),(0,-5) and (1,0).

Q7 Solve the following pair of linear equations: (i)

Answer:

Given Equations,

Now By Cross multiplication method,

Q7 Solve the following pair of linear equations: (ii)

Answer:

Given two equations,

Now By Cross multiplication method,

Q7 Solve the following pair of linear equations: (iii)

Answer:

Given equation,

Now By Cross multiplication method,

Q7 Solve the following pair of linear equations: (iv)

Answer:

Given,

And

Now, Subtracting (1) from (2), we get

Substituting this in (1), we get,

.

Hence,

Q7 Solve the following pair of linear equations: (v)

Answer:

Given Equations,

As we can see by adding and subtracting both equations we can make our equations simple to solve.

So,

Adding (1) and )2) we get,

Subtracting (2) from (1) we get,

Now, Adding (3) and (4) we get,

Putting this value in (3)

Hence,

Q8 ABCD is a cyclic quadrilateral (see Fig. 3.7). Find the angles of the cyclic quadrilateral.

Answer:

As we know that in a quadrilateral the sum of opposite angles is 180 degrees.

So, From Here,

Also,

Multiplying (1) by 3 we get,

Now,

Subtracting, (2) from (3) we get,

Substituting this value in (1) we get,

Hence four angles of a quadrilateral are :

### NCERT Solutions for Class 10 Maths for Other Chapters

Chapter No. | Solution Link |

Chapter 1 | |

Chapter 2 | |

Chapter 3 | NCERT solutions for class 10 maths chapter 3 |

Chapter 4 | |

Chapter 5 | |

Chapter 6 | |

Chapter 7 | |

Chapter 8 | |

Chapter 9 | |

Chapter 10 | |

Chapter 11 | |

Chapter 12 | |

Chapter 13 | |

Chapter 14 | |

Chapter 15 |

### Features of NCERT Class 10 Maths Solutions Chapter 3

The questions and their answers given in Chapter 3 Class 10 Maths NCERT solutions are very interesting and important for board and competitive exams.

NCERT solutions for class 10 maths chapter 3 will help to boost preparation for all of the examinations.

Many real-life situations can be formulated using Mathematical equations given in this chapter 3 NCERT Class 10 Maths solutions.

For example, consider the statement "cost of 1 Kg Apple and 2Kg orange is 120 and the cost of 3 Kg Apple and 1 Kg orange is 210". The statement can be formulated using the Mathematical equation, for this consider the cost of Apple as x and that of orange as y. Then we can write two equations as x+2y=120 and 3x+y=210.

### Subject-wise NCERT Solutions of Class 10

### How to use NCERT Solutions for Class 10 Maths Chapter 3?

Follow the given tips to make the most of NCERT solutions Class 10 Maths Chapter 3 PDF download:

NCERT solutions Class 10 Maths Chapter 3 are the most important tool when you are appearing for board examinations. 90% paper of CBSE board examinations, directly come from the NCERT.

Now you have done the NCERT solutions for class 10 maths chapter 3 and learned the approach to solving questions in the step by step method.

After covering NCERT solutions for class 10 maths chapter 3 you should target the past year papers of CBSE board examinations. The previous year papers will cover the rest 10% part of the class 10 board exams.

## Frequently Asked Question (FAQs) - NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables

**Question: **What is the weightage of the 3rd chapter for CBSE board exam?

**Answer: **

CBSE doesn't provide the marks distributions chapter-wise but it provides the total weightage of a unit (upto 4-5 chapters). As per CBSE the total weightage of algebra (4 chapters) carry a weightage of 20 marks in the final board exam.

**Question: **Where can I find the complete NCERT class 10 solutions Maths chapter 3?

**Answer: **

You will get the detailed NCERT solutions for class 10 maths chapter 3 from this page.

**Question: **What are the important topics of class 10 Maths chapter 3?

**Answer: **

Formation of linear equations using statements, algebraic interpretation of linear equations, solving a linear equation with two variables, representation of linear equation in a graph, and solutions of linear equations using the graph are important topics from this chapter.

**Question: **How are NCERT Class 10 Maths solutions of chapter 3rd helpful in the board exam ?

**Answer: **

Class 10 Maths chapter 3 NCERT solutions are not only important when you stuck while solving the problems but you will get new ways to solve the problems. So, it will help you to know various methods of solving linear equations.

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CBSE Class 10 Sample Papers 2021- Download CBSE sample papers ...

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## Questions related to CBSE Class 10th

### Board cbse class 10 Is cancelled and promote all student please sir because of corona do not study

Hello aspirant,

No CBSE and ICSE board didn't not cancelled the 10th and 12th exam.

As they had declared that 10th and 12th class exam will not be cancelled and students will have to give it in offline mode in this pandemic also.

Hope this helps you

All the best for your future

### CBSE class 10th malayalam can someone please tell me a good one

Hello Dear,

Malayalam is the mother tongue of those who have their roots in Kerala. It is one of the Dravidian languages that has similarities in words with its other contemporary languages such as Tamil and Telugu. People who speak Malayalam are referred to as Mallus. You can download the previous year papers from the link below:

https://school.careers360.com/download/sample-papers/cbse-10th-class-malayalam-solved-sample-paper-2021

Good Luck

### When will the Karnataka NTSE Stage 1 Merit list(i.e people who have cleared stage-1) and the cut off come out?

**DSERT, Karnataka**has

**released**the

**NTSE Karnataka 2021 Result stage 1**on

*March 9, 2021*on their

**official website**(

*dsert.kar.nic.in*). It is available in the form of

**district-wise marks lists**, consisting of

*registration numbers and marks of all students.*

**Along with the NTSE stage 1 result, cutoff and merit list of selected candidates is also released.**

The students those who have

**cleared**the

*stage 1 exam*are

**eligible**to seat for the

*stage 2 exam*which is going to be held on

**June 13, 2021**. The

**scholarship**will be given to the students who will

**pass**the

*stage 2 examination.*

To know more about

**NTSE Karnataka Important Dates, Cut-off, Scholarship**visit :

**https://www.google.com/amp/s/school.careers360.com/articles/ntse-karnataka-result/amp**

**Hope it helps**

**Thank You !!!**

### Age criteria to appear in class 10 CBSE exam

Hello Bishal

According to guidelines of CBSE, minimum age to appear for class x must be 14 years. There is no upper limit to appear for class x cbse board.

A candidate can appear for maximum three attempts.

Some candidates give private exams or sometimes students fail in standard ix then they privately appear for class x then their age must be more than 14 years. Sometimes students appear for x class after one year gap of passing class ix then also their age would be 15 or 16 as there is no upper limit age.

### My child is supposed to make another attempt at compartment exam of 10th cbse Missed last date for applying. since the boards are postponed to May 4th can I pay her fees and apply now.

Hello sir I'm sorry to inform you but now you're not eligible to fill the registration form as last date to fill the registration Form was 9th December 2020. Yes examination gets postponed to May but portal to fill the registration form is not open , in case if the registration form portal will open again you can fill the registration form and make the payment.

Feel free to comment if you've any doubt

Good luck