NCERT Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Notes - Download PDF Notes

NCERT Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Notes - Download PDF Notes

Edited By Irshad Anwar | Updated on May 02, 2024 04:45 PM IST

A pair of linear equations in two variables is a very important chapter of the NCERT Pair of Linear Equations in Two Variables from an exam point of view. The NCERT Class 10 Maths Chapter 3 notes provide you with different methods of solving a pair of linear equations. The main topics covered in the NCERT Class 10 Maths notes are the graphical method of solving a pair of linear equations, the algebraic method of solving a pair of linear equations, the substitution method, and the elimination method. Download the CBSE Notes for Class 10 Maths, Chapter 3, PDF to use offline anywhere. Students must go through each topic in pair of linear equations in two variables Class 10 Notes Maths, in the easiest and most effective way possible with the help of NCERT Notes for Class 10.

This Story also Contains
  1. Pair of Linear Equations in Two Variables Class 10 Notes Maths Chapter 3
  2. Parallel Line
  3. 2. Intersecting Line
  4. 3. Coinciding Line
  5. Significance of NCERT Class 10 Maths Chapter 3 Notes

Class 10 Maths chapter 3 notes also cover all the important concepts that are useful in various competitive exams. Pair of linear equations in two variables NCERT Notes Class 10 Maths helps you revise all major concepts given in the NCERT Book in no time during Class 10 CBSE Board exam preparation. CBSE Class 10 Maths Chapter 3 notes will help you with quick revision. Pair of linear equations in two variables Chapter 3 maths class 10 Notes covers all headings of the NCERT book. CBSE Class 10 Maths Chapter 3 notes also contain important examples that have been frequently asked in the various exams. Having revision notes and NCERT Solutions for Class 10 Maths Chapter 3 handy is beneficial to save you time. The NCERT Class 10 notes PDF can be downloaded through the link given below.

Also, students can refer to:

Pair of Linear Equations in Two Variables Class 10 Notes Maths Chapter 3

  1. Parallel Line

Suppose that there are two lines are given as

1643953833921


Then these two lines are parallel only if

1643953833309


Then it is called a parallel line.

For Example: Consider the following equations:

1643953833677



1643953834110


From the graph, it is clear that there is no solution.

2. Intersecting Line

Suppose that there are two lines are given as

1643954092499


Then these two lines intersect only if

1643954093931


Then it is called an intersecting line.

For example: Consider the following equations:

1643954093711

1643954094319

From the graph, it is clear that there is only one intersecting point so one solution is possible.

3. Coinciding Line

Suppose that there are two lines are given as

1643953914202



Then these two lines coincide only if

1643953915346



Then it is called a coinciding line.

For example: Consider the following equations:

1643953915629

1643953915973

From the graph, it is clear that there are an infinite number of points so infinitely many solutions are possible.

Chapter Wise Class 10 Notes Maths

Significance of NCERT Class 10 Maths Chapter 3 Notes

Pair of Linear Equations in Two Variables Class 10 Notes will help you understand the formulas, statements, and rules in detail. Notes for Class 10 Maths, Chapter 3, also contain previous year’s questions and NCERT Textbook PDF. Pair of Linear Equations in Two Variables Class 10 Notes PDF download can be used to prepare in offline mode. Class 10 Pair of Linear Equations in Two Variables contains FAQs, or frequently asked questions, along with a topic-wise explanation.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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