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Quadratic Equations Class 10th Notes - Free NCERT Class 10 Maths Chapter 4 Notes - Download PDF

Quadratic Equations Class 10th Notes - Free NCERT Class 10 Maths Chapter 4 Notes - Download PDF

Edited By Safeer PP | Updated on Apr 02, 2025 10:16 AM IST

Imagine after building your dream house, you need to fench that house anf for that you need the length and breadth of that house to find the biggest possible area. Quadratic equations can solve this problem. It is an integral part of Mathematics that deals with algebraic equations of degree 2. The NCERT Class 10 Maths Chapter 4 notes cover a brief outline of the chapter on quadratic equations and can be used for revision. The main topics covered in quadratic equations Class 10 notes give you the properties and roots of quadratic equations. Class 10 Maths chapter 4 notes also cover the basic equations in the chapter. Quadratic equations Class 10 notes pdf download contains all of these topics. Students can use NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations for conceptual clarity. After completing the textbook exercise, students can also refer to NCERT Exemplar Solutions for Class 10 Maths Chapter 4 Quadratic Equations for more practice purposes.

This Story also Contains
  1. Roots of a Quadratic Equation
  2. Methods to Solve Quadratic Equations
  3. Nature of Roots
  4. NCERT Class 10 Chapter Wise Notes
  5. NCERT Solutions of Class 10: Subject Wise
  6. NCERT Class 10 Exemplar Solutions for Other Subjects:

Quadratic Polynomial

A polynomial with degree 2, is a quadratic polynomial. It is in the form of

f(x) = ax2 + bx + c, where a ≠ 0

Quadratic Equation

An algebraic expression of the second degree is called a quadratic equation.

  • The standard form of a Quadratic Equation

ax2+bx+c=0

where a, b and c are the real numbers and a≠0

Roots of a Quadratic Equation

Let x = α and α be a real number. If α satisfies the quadratic equation ax2+ bx + c = 0 such that aα2 + bα + c = 0, then α is the root of the Quadratic Equation.

As quadratic polynomials have degree two, quadratic equations can have two roots. Thus, the zeros of a quadratic polynomial f(x) =ax2+bx+c is the same as the roots of the quadratic equation ax2+ bx + c= 0.

Methods to Solve Quadratic Equations

There are three methods to solve Quadratic Equations.

1. Factorization Method

In this method, divide the equation into two linear factors and equate each factor to zero to find the roots of the equation.

Step 1: Quadratic Equation in the form of ax2 + bx + c = 0.

Step 2: By factorization, we write ax2 + bx + c = 0 as (x + p) (x + q) = 0

For example-

x2- 2x - 15=0

⇒ (x+3)(x-5)=0

So, x + 3 = 0 or, x - 5 = 0

x = - 3 or x = 5

The above values of x are the two roots of the given quadratic equation.

2. Completing the Square Method

In this method, convert the equation in the square form (x + a)2 - b2 = 0 to find the roots.

Step 1: Quadratic Equation in the standard form ax2 + bx + c = 0.

Step 2: Divide both sides by a:

x2+bax+ca=0

Step 3: Transfer the constant to RHS, then add the square of the half of the coefficient of x, i.e. (b2a)2 on both the sides

x2+bax=cax2+2(b2a)x+(b2a)2=ca+(b2a)2

Step 4: Write LHS as a perfect square and simplify RHS.

(x+b2a)2=b24ac4a2

Step 5: Square root of both sides.

x+b2a=±b24ac4a2

Step 6: Constant terms are shifted to the RHS, and the value of x is calculated as there is no variable at the RHS.

x=±b24ac4a2b2a

3. Quadratic formula method

In this method, find the roots by using the quadratic formula. The quadratic formula is

x=b±b24ac2a

where a, b and c are the real numbers and b2 – 4ac is known as a discriminant.

Nature of Roots

The nature of the roots of the equation depends upon the value of D, which is called the discriminant.

Value of discriminant

Number of roots

D > 0

Two distinct real roots

D = 0

Two equal and real roots

D < 0

No real roots

NCERT Solutions of Class 10: Subject Wise

NCERT solutions are very useful to students when they attempt to solve the exercise on their own and get stuck on questions or can't understand the logic behind the question. The following links will be very helpful in that cause.

NCERT Class 10 Exemplar Solutions for Other Subjects:

During the initial stage of the preparation phase, the latest syllabus is very handy. Also, after completing the exercises from the textbooks, students can practice the exemplar exercises and read reference books. Students can use the following links for the above-mentioned purposes.

Frequently Asked Questions (FAQs)

1. What is factorization according to Class 10 Math’s chapter 4 notes?

The process by which the bracket of a quadratic equation is reduced is called factorization.

2. What is the weightage of Class 10 Quadratic Equations notes in the board examination?

Students can expect 4 to 8 marks questions from the notes for Class 10 Math’s chapter 4.

3. How many methods are there to find the roots of a quadratic equation?

In the notes for Class 10 Math’s chapter 4, four methods are discussed to find the roots of a quadratic equation.

4. How does this chapter help students?

It is evident that this chapter gives a better understanding of quadratic polynomials and helps us understand quadratic equations in a more wholesome way. Students can use Class 10 Math’s chapter 4 notes pdf download for revision

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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