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Probability Class 12 notes belong to the 13 chapter of NCERT. The NCERT Class 12 Maths chapter 13 notes are entirely based on the important topics required for the exam. Class 12 Maths chapter 13 notes nicely define the important formulas and their required derivations. The notes for Class 12 Maths chapter 13 helps a student to get a last-minute revision before the exam. Notes for Class 12 Maths chapter 13 is made in such a way that no students face any difficulty during their preparation. NCERT Notes for Class 12 Maths chapter 13 not only cover the NCERT notes but also covers the CBSE Class 12 Maths chapter 13 notes.
After going through Class 12 Probability notes
students can also refer to,
In general terms, probability is defined as a measurement of the uncertainty of events in random experiments. Mathematically it is the ratio of the number of outcomes to the total number of possible outcomes.
Conditional Probability
It gives us the way to find a reason for the experiment based on partial information. Let us think of such a situation that like
Thus, we can define the conditional probability that if A and B are two events of sample space S and P(A)≠0, then the probability of B after the event A has occurred is called conditional Probability.
Properties of Conditional probability
Property 1: P(F|F) = P(S|F) = 1
Property 2: If A and B are two events in the sample space S and F being an event of S such that P(F) ≠ 0, then
P((A ∪ B)|F) = P(A|F) + P(B|F) – P((A ∩ B)|F)
Property 3: P(E′|F) = 1 − P(E|F)
For Given two dependent events A and B
P(A ∩ B) = P(A) P(B | A)
The multiplication rules of probability for more than two given events are as follows
Let E, F and G are three events given in a sample space, then we have
P(E ∩ F ∩ G) = P(E) P(F|E) P(G|(E ∩ F)) = P(E) P(F|E) P(G|EF)
Similarly, this rule can be extended for four or more events.
Independent Events
We have introduced conditional probability where partial information that event B provides about event A. Now we found an interesting case where the occurrence of B does not provide information on A.
i.e. P(B|A)=P(B)
Now we can deduce that
Example:
In a dice. If M is the event in which number appears as a multiple of 3 and N be the event in which even numbers occur. So, find that event M and N are independent or not?
Solution:
We know that the sample space is S = {1, 2, 3, 4, 5, 6}
There are even numbers in event M also.
Therefore,
So,
From the above relation, we can say M and N are independent events.
Bayes’ Theorem
Bayes theorem is a theorem in the probability that is used to determine the probability of the event that is related to any event that has already occurred.
The formula is
Total Probability Theorem
Let S be a sample space associated with a random experiment. A function R: S→R is termed a random variable.
Example:
From 52 cards well-shuffled deck two cards are drawn. Find the probability for a number of aces.
Solution:
Let the number of aces be A.
Therefore, 0,1 or 2 will be the values of A.
When ace doesn’t occur
When ace occurs once
When ace occurs twice
X | 0 | 1 | 2 |
P(X) | 144/169 | 24/169 | 1/169 |
Mean of a random variable
The mean of a random variable is used to locate the middle or the average value of the random variable.
The variance of a random variable
It is the expectation of the squared deviation of a random variable from its sample mean.
Bernoulli Trails
Trials that contain only two outcomes usually referred to as ‘success’ or ‘failure’ are known as Bernoulli trials.
Example:
If there are 7 white and 9 red balls in a container 6 balls are drawn successively. Find out the trails of 6 balls from the container will be Bernoulli’s trials after each draws of the ball as replaced or not replaced in the urn.
Solution:
If the trial numbers are finite then the drawing of the ball with replacement will be the success for drawing a white ball is p = 7/16. It will be the same for all six trials. So, the balls drawing with replacements are Bernoulli trials.
If the drawing of the ball is done without replacement then the probability of success of drawing white ball will be 7/16 for the first trial, 6/15 for the second trial or if a red ball is drawn for 1st time will be 7/15 and so on. From the above statement, we can say that the success will not be the same for all the trials, so the trials are not Bernoulli trials.
Binomial Distribution
It is a type of distribution that entire up the likely values that will take one or two independent values given under a set of assumptions.
Example:
Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is at least one defective egg.
Solution:
Let X denote the number of defective eggs in the 10 eggs drawn. Since the drawing is done with replacement, the trials are Bernoulli trials. Clearly, X has the binomial distribution with
This brings us to the end of the chapter
Class 12 Probability notes will be really helpful for the revision of the entire chapter and getting a list of the important topics covered in the notes. Also, Class 12 Math chapter 13 Notes is useful for getting a glance of Class 12 CBSE Syllabuses and also for national competitive exams like BITSAT, and JEE MAINS. Class 12 Maths chapter 13 notes pdf download can be used for getting a hard copy and to prepare for the exam.
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