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Ever wondered how delivery companies know the shortest path? How do airlines make their flight schedule work? Or how can any business company minimize the cost while maximising the profits? The answer to these real-world problems lies in Linear Programming, an interesting mathematical method for finding the optimum solution for various problems. From NCERT Class 12 Maths, the chapter Linear Programming contains the concepts of Objective Function, Decision Variables, Constraints, Feasible Region, Optimal Solutions, etc. Understanding these concepts will help the students grasp Linear Programming easily and enhance their problem-solving ability in real-world applications.
This article on NCERT notes Class 12 Maths Chapter 12 Linear Programming offers well-structured NCERT notes to help the students grasp the concepts of Linear Programming easily. Students who want to revise the key topics of Linear Programming quickly will find this article very useful. It will also boost the exam preparation of the students by many folds. These notes of Class 12 Maths Chapter 12 Linear Programming are made by the Subject Matter Experts according to the latest CBSE syllabus, ensuring that students can grasp the basic concepts effectively. NCERT solutions for class 12 maths and NCERT solutions for other subjects and classes can be downloaded from the NCERT Solutions.
Linear programming is generally defined as the technique for maximizing or minimizing a linear function of several variables, like input or output cost.
A Mountaineering equipment dealer deals in only two items–tents and rucksacks. He has Rs 50,000 for investment and has storage for compiling a maximum of 60 pieces. A tent is priced at Rs 2500 and a rucksack at Rs 500. He estimates that by selling one tent he can get a profit of Rs 250 and that from the. The sale of one rucksack earns a profit of Rs 75. So, how many tents and rucksacks should he buy with the money to maximize his total profit, assuming he can sell all the products he buys?
Here we can observe
Let us assume that he decides to buy a tent only and no rucksacks, so he can buy 50000 ÷ 2500, i.e., 20 tents. Thus, his profit can be written as: Rs (250 × 20), i.e., Rs 5000.
Suppose he chooses to buy rucksacks only and no tent. With the capital of Rs 50,000, he can buy 50000 ÷ 500, i.e., 100 rucksacks. But he can only store 60 pieces. Therefore, he can only buy 60 rucksacks, which will give a profit of Rs (60 × 75), i.e., Rs 4500.
There are other possibilities too, like he may choose to buy 10 tents and 50 rucksacks, as his storage is limited to only 60 pieces. The total profit would be calculated as Rs (10 × 250 + 50 × 75), i.e., Rs 6250, and so on.
Thus, we find that the dealer can invest his money in many different ways so that he would earn different profits by the given different investment strategies.
Now the question arises, how should he invest to get the maximum profit? For this, let us see the process mathematically.
Let x be the number of tents and y be the number of rucksacks that the dealer buys. Here, x and y must be non-negative, i.e.,
Mathematically,
2500x + 500y ≤ 50000 (investment)
or 5x + y ≤ 100 ... (3)
and x + y ≤ 60 (storage) ... (4)
Z = 250x + 75y ( objective function) ... (5)
Now, the given problems now reduce to:
Maximize Z = 250x + 75y
5x + y ≤ 100
x + y ≤ 60
x ≥ 0, y ≥ 0
Such a problem is called linear programming.
Objective function :
Let Z = ax + by be a linear function, where a, b are the constants. Linear objective function goes by the computation of the maximum or the minimum of X
Let Z = ax + by be a linear objective function. Then the variables x and y are called decision variables.
Constraints :
Constraints are the limitations or restrictions imposed on the decision variables.
Optimization problem:
A problem that asks to maximize or minimize a linear function limited to certain constraints.
Let us see a graph
5x + y ≤ 100 ... (1)
x + y ≤ 60 ... (2)
x ≥ 0 ... (3)
y ≥ 0 ... (4)
Each point in the shaded region represents a feasible choice; therefore, it is called the feasible region.
Any points outside feasible points are called infeasible points.
Optimal (feasible) solution:
Any point in the feasible region that gives the maximum or minimum value of the objective function is called an optimal solution.
Find the feasible region of the problem and find the vertices.
Find the objective function Z = ax + by. Let M and m be the largest and the smallest points of the problem
i) When the area is bounded. "M" and "m" are maximum and minimum values. If a feasible area is unbounded then
ax + by > M, no common points with the feasible region.
Manufacturing Problem: Here we describe the different types of units that should be produced in a firm
Diet Problems: Here we discuss the requirements of essential nutrients for our body.
Transportation Problem: Here we discuss the cheapest way of transporting materials from factories to different locations
This brings us to the end of the chapter.
After finishing the textbook exercises, students can use the following links to check the NCERT exemplar solutions for a better understanding of the concepts.
Students can also check these well-structured, subject-wise solutions.
Students should always analyze the latest CBSE syllabus before making a study routine. The following links will help them check the syllabus. Also, here is access to more reference books.
Important points to note:
Happy learning !!!
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