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NCERT Class 10 Maths chapter 5 notes based on arithmetic progression, in which general form of A.P and common difference are included. The chapter arithmetic progression Class 10 notes also include the arithmetic mean and the sum of n terms of an A.P.
The NCERT Class 10 chapter 1 notes include important formulas. CBSE Class 10 Maths chapter 1 notes contain systematic explanations of topics using examples and exercises. The important terms and techniques related to A.P. have also been included in CBSE Class 10 Maths chapter 1 notes. All these topics can be easily available and are downloaded from Class 10 Maths chapter 1 notes pdf download.
Also, students can refer,
Sequence: This is the ordered list of numbers.
Arithmetic progression: The list of numbers is made in such a way that each term is having a common difference in between them and the comment difference is constant, that is adding a fixed number will proceed to the next term.
Lets suppose a is the first term and d is the common difference in between the terms.
Now, here a1=a
a2=a1+d= a + d
a2=a2+d= a + d + d = a + 2d
a3=a3+d= a + 2d + d = a + 3d
………
…………..
Moving further in the same way for “n” terms.
an=a +(n-1) d
Which is the nth term of an A.P. where;
a is the first term of an A.P.
n will be the number of terms and;
d is a common difference.
Now here in this scenario to get the value; considering the sum of first n terms of an A. P. is Sn.
Where,we can write the sum as follows:
Sn= (a) first term + (a+ d) second term + (a + 2d) third term +( a + 3d) third term………(1)
By putting the value of the product of ‘terms and the common difference we can write the series as:
Sn= (a +(n-1) d) +( a +(n-2) d) +(a +(n-3) d)+….+…. ………….(2)
Adding both the equation we get;
2Sn= n [2a +(n-1) d]
Sn=0.5n[2a +(n-1) d];
Where l = [a +(n-1) d]
So we can write the above equation is as follows.
Sn=0.5n[a+l]
Points to remember:
For calculating the Nth term of an AP=Sn-Sn-1
The sum of n positive integer will be calculated as Sn=n(n+1)/2
For n odd positive integers sum will be calculated as n2
For n even positive integers sum will be calculated as n(n+1)
It should be noted that if in case constant is added or subtracted or multiplied to each and every term in an AP then we get the sequence which is also followed up with a new AP.
It should also be kept in mind that when each and every term of an AP is divided by a non-zero quantity then we get the result of a sequence of new AP.
Arithmetic Progression Class 10 Notes will help to understand the formulas, statements, rules in detail. Also, this NCERT Class 10 Maths chapter 5 also contains previous year’s questions and NCERT TextBook pdf. It also contains FAQs or frequently asked questions along with topic-wise explanations. Class 10 Maths chapter 5 notes help to understand the concept of Sequence of Arithmetic progression as well as the general formula related to it.
Let the sequence is taken as 12, 18, 24, …..96.
Here, a=12 , d=18-12=6, and last term an=96
nth term=a +(n-1) d
12+(n-1)6 = 96
(n-1)6=96-12=84
n=15
sum=0.5n(n+1)=5(11)=55
The given sequence 1, 3, 5... is an ap
sum=0.5n(a+l)=0.5x7(1+13)=49
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