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NCERT Class 11 Physics Chapter 12 Notes Thermodynamics - Download PDF

NCERT Class 11 Physics Chapter 12 Notes Thermodynamics - Download PDF

Edited By Vishal kumar | Updated on Jul 04, 2025 12:45 AM IST

Consider you put a hot cup of tea on the table- it gets cold gradually until it reaches the ambient temperature. This everyday phenomenon is subject to thermodynamics, a very interesting field of physics which concerns itself with the correlation between heat, energy, temperature and work. This topic in more detail is discussed in Class 11 Physics Chapter 11 where you will come to know how energy transfers occur and what are the dynamics that drive all this. The NCERT notes on this chapter are well prepared to provide some organized and simplified knowledge to the students on the main topics of thermodynamics. These topics not only form an essential part of real-life handlings of thermal processes but also are vital in terms of ranking well in the competitive examinations such as JEE, NEET, and board examinations such as CBSE, etc.

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This Story also Contains
  1. NCERT Notes for Class 11 Chapter 11
  2. Thermodynamics Previous year Question and Answer
  3. NCERT Class 11 Notes Chapter-Wise
NCERT Class 11 Physics Chapter 12 Notes Thermodynamics - Download PDF
NCERT Class 11 Physics Chapter 12 Notes Thermodynamics - Download PDF

This chapter discusses basic bio-thermodynamics concepts including thermal equilibrium, zeroth law, internal energy, first law of thermodynamics, second law of thermodynamics, isothermal and adiabatic processes. The Class 11 Physics notes of Chapter 11 prove quite handy to students who have to write CBSE board exams and other competitive exams such as JEE and NEET, because they can reduce important derivations and concepts into simple terms. The NCERT Class 11 Thermodynamics notes also include important ideas and definitions, key formulas and derivations, well-labeled graphs, practice questions and examples.

Also, students can refer,

NCERT Notes for Class 11 Chapter 11

Mechanics vs. Thermodynamics

  • In thermodynamics, we focus exclusively on the state of the object, evaluating macroscopic variables such as pressure, volume, and temperature. whereas, mechanics is concerned with the motion of an object, taking into account parameters such as velocity and acceleration.

Thermal Equilibrium

  • When two systems have identical temperatures, we say they are in thermal equilibrium. In mechanics, a system is considered equilibrium when its net force is zero. Equilibrium in thermodynamics refers to the stability of all macroscopic variables over time, including pressure, temperature, and volume.
  • Different Types of Equilibrium: Various types of equilibrium characterise different aspects of physical systems:
  1. Thermal equilibrium: Thermal equilibrium occurs when two systems' temperatures remain constant over time.
  2. Chemical equilibrium: Chemical equilibrium occurs when two systems' compositions remain constant over time.
  3. Mechanical equilibrium: Mechanical equilibrium occurs when two systems' pressures do not vary over time.

System and Surroundings

  • System: Any distinct part of the universe surrounded by a boundary that allows for the exchange of heat or energy.
  • Surroundings: Everything outside of the defined system that makes up the broader environment.
  • Different System Types:
  1. Open System: Characterised by the unrestricted exchange of energy and matter with its environment. An everyday example is a cup of coffee boiling in an open pan, allowing heat and water vapour to escape freely.
  2. Closed System: A closed system allows for the exchange of energy but restricts the flow of matter. A gas-filled balloon is an example of a closed system because it allows for energy transfer (thermal expansion or contraction) while maintaining a constant volume of gas.
  3. Isolated System: There is no exchange of matter or energy with the surroundings. A thermos flask is a classic example of how insulation prevents heat loss or gain, allowing the contents to remain at a constant temperature for an extended period of time.
  • Different Types of Walls:
  1. Adiabatic wall: The adiabatic wall acts as an insulating barrier, preventing heat transfer between systems. This type of wall keeps the temperatures of the interacting systems constant over time.
  2. Diathermic wall: The diathermic wall acts as a conducting barrier, allowing heat to be transferred between two systems. A diathermic wall, as opposed to an adiabatic wall, allows heat to flow through it, allowing temperature adjustments between connected systems.

Thermodynamics' Zeroth Law

  • According to the Zeroth Law of Thermodynamics, if two systems are in thermal equilibrium with a third system on their own, they are also in thermal equilibrium with each other. This fundamental principle provides a foundation for defining and measuring temperature by emphasising thermal equilibrium as a transitive relation.

Thermodynamic state variables

  • Thermodynamic state variables are macroscopic quantities that define an equilibrium state in a system. These variables contain important information about the system's properties.
  • Examples of Thermodynamic State Variables:
  1. Extensive Variables: These variables are proportional to the system's size and are influenced by its mass or particle count. Examples include volume, mass, and internal energy. For example, when dealing with a larger mass system, the volume and internal energy are larger as well, demonstrating the system's size dependence.
  2. Intensive variables: Intensive variables are unaffected by the system's size. These parameters remain constant regardless of the system's mass or number of particles. Intensive variables include pressure and temperature. These variables maintain their values regardless of system size.
  • Equation of State:

The equation of state establishes a link between key variables such as pressure, mass, volume, and density, describing the state of matter when certain physical conditions are met. In the case of an ideal gas, this equation provides information about its behaviour under various conditions, making it a useful tool for understanding and predicting its state.

Consider an ideal gas, whose state equation is

PV=μRT

Here, P, V, and T are state variables, with μ = no. of moles.

Heat, Work and Internal Energy

  • Heat: Heat is the energy exchanged between a system and its surroundings when the temperature differs. This transfer occurs due to the thermal gradient, resulting in changes in the system's internal energy.
  • Work: Work occurs when a body or system moves in response to a force. Work, mathematically expressed as,

dW=PdV

Where P is the pressure of the gas in the cylinder.

  • Internal energy: The internal energy (U) of a system of molecules is the sum of their kinetic and potential energies. Internal energy, denoted by U = Ek + Ep, where Ek and Ep are the molecular kinetic and potential energies, is a macroscopic variable that is solely determined by the state of the system. It is not determined by the path taken, but rather by the energy resulting from molecular motion and configuration within the system.
  • Unlike internal energy, heat and work are not state variables. They are forms of energy transfer to a system that cause an internal energy change.

Thermodynamics First Law

  • The First Law Of Thermodynamics is synonymous with the principle of energy conservation, which states that energy cannot be created or destroyed but can be transformed into other forms.
  • According to the First Law of Thermodynamics, the change in internal energy of a closed system equals the heat added to the system minus the work done by the system on its surroundings.
  • Examples: Consider a ball dropping from a building's roof. Initially, the ball possesses potential energy at the top, which diminishes as it falls, transforming into kinetic energy. By the time it reaches the ground, the ball only has kinetic energy.
  • Mathematically,

ΔQ=ΔU+ΔW

  • For Cyclic Process

ΔQ=ΔW

Where: ΔQ is the heat provided to the system by the environment.

ΔW denotes the amount of work done by the system in relation to the environment.

And ΔU is the change in the system's internal energy.

Relation between CP and CV

  • Mayer's Formula describes the relationship between the specific heat at constant pressure (CP) and the specific heat at constant volume (CV) for an ideal gas. According to Mayer's relation, an ideal gas:

CpCV=R

Specific Heat Capacity

  • Specific heat capacity is the amount of heat required to raise the temperature of a substance per unit mass.

S=ΔQmΔT

Where,

m is the body's mass, ΔQ is the quantity of heat that a substance absorbs or rejects and ΔT stands for temperature change.

Molar Specific Heat Capacity

  • The heat capacity per mole is the amount of heat (in moles) absorbed or rejected (instead of mass m in kg) by a substance to change its temperature by one unit.

C=S/μ=ΔQ/μΔT

Where: μ= the mass of a material in moles, C is the substance's molar specific heat capacity, ΔQ is the quantity of heat that a substance absorbs or rejects and ΔT stands for temperature change.

  • At constant pressure, molar specific heat capacity (CP): The equivalent molar specific heat capacity at constant pressure is called molar specific heat capacity at constant pressure if the gas is retained at constant pressure during the heat transfer (CP).
  • At constant volume, the molar specific heat capacity (CV): The equivalent molar specific heat capacity at constant volume is called molar specific heat capacity at constant volume if the volume of the gas is maintained during the heat transfer (CV).

Isothermal Processes

  • An Isothermal Process is defined as the condition in which the temperature of a system undergoing a thermodynamic process remains constant throughout. In other words, during an isothermal process, the system's other thermodynamic variables change (such as pressure, volume, or internal energy), but the temperature remains constant.
  • The equation for an ideal gas undergoing an isothermal process describes the relationship between pressure (P), volume (V), and temperature (T):

PV=constant

This means that the product of pressure and volume for an ideal gas remains constant as long as the process takes place at the same temperature. A hyperbolic curve is commonly used to represent the behaviour of an isothermal process on a pressure-volume (PV) diagram.

  • Graphically,

C:\Users\GOD IS GREAT\Pictures\53eddb47-a86c-40af-967a-72bc4d8121e52705281370954061303.png

Points in the Graph of the Isothermal Process:

  • Isotherms are curves on the pressure-volume (P-V) graph that form during an isothermal process. These isotherms have a hyperbolic shape.
  • The slope of an isothermal curve on the P-V graph:

tanθ=dPdV=PV

  • The area between the isothermal curve and the volume axis on the P-V graph represents the work done during the isothermal process.
  • The magnitude of work done in the isothermal process:

W=nRTloge(VfVi)=2.303nRTlog10(VfVi)W=nRTloge(PiPf)=2.303nRTlog10(PiPf)

Adiabatic Processes

  • An Adiabatic process is a thermodynamic process in which no heat is exchanged between the system and its surroundings. In other words, the system is thermally isolated, which prevents heat from entering or leaving the system.
  • Equations of Adiabatic process:

PVγ=constant; whereγ=CPCVTVγ1=constantT1V1γ1=T2V2γ1orTV1γTγPγ1=constantT1γP11γ=T2γP21γorTPγ1γorPTγγ1

Isochoric Processes

  • Isochoric Process refers to a thermodynamic process in which the system's volume remains constant while other variables, such as pressure and temperature, vary. Because the volume is constant in an isochoric process, no work is done to or by the gas.

ΔW =0

Isobaric Processes

  • The term "Isobaric Process" is derived from the combination of "iso," meaning the same, and "baric," which refers to pressure. In an isobaric process, pressure remains constant throughout the operation, whereas volume and temperature may fluctuate.

W=μR(V2V1)
ΔQ=ΔU+μR(T2T1)

Cyclic Processes

  • The process by which the system returns to its original condition.

ΔU = 0

This means that the entire amount of heat absorbed is equal to the amount of work done by the system.

Heat Engines

  • A Heat Engine is a device that allows heat to be supplied and absorbed by placing a body in alternating contact with hot and cold bodies.
  • A heat engine, to put it simply, is a mechanism that turns thermal energy into mechanical energy.

Thermodynamics' Second Law

  • The Second Law Of Thermodynamics states that any spontaneous process will inevitably result in an increase in the total entropy (S) of the universe. Simply put, this law states that the entropy of an isolated system does not decrease over time.
  • Under certain conditions, such as thermodynamic equilibrium or a reversible process, the total entropy of a system and its surroundings remains constant. The Law of Increased Entropy is an alternative term for the second law, emphasising the tendency of systems to progress towards greater disorder over time.

Reversible and Irreversible Process

  • Reversible Process: A thermodynamic process is considered reversible if it can be reversed, restoring the system and its surroundings to their original states while causing no net change in the universe. Reversible processes allow the system to transition from an initial state to a final state and then seamlessly reverse back to the initial state. Examples include isothermal expansion and compression, as well as electrolysis.
  • Irreversible Process: Irreversible processes are those that cannot be reversed in any practical way. Irreversible processes typically happen quickly. Examples include plastic deformation, combustion, diffusion, and water flow downhill. Irreversible processes cause an increase in entropy and lack reversibility.

Carnot Engine

  • The Carnot Engine was named after the scientist Carnot.
  • It's a reversible heat engine that can operate at two different temperatures.
  • It achieves a level of efficiency that no other engine can match.
  • Processes in a Carnot engine's cycle

Any heat engine's basic function is to transfer heat Q1 from a hot reservoir at temperature T1 to a cool reservoir at temperature T2.

It is isothermal expansion because the system absorbs heat. At temperature T1, the engine absorbs heat Q1.

Inside the engine, an adiabatic process occurs, causing the temperature of the engine to rise from T1 to T2, but with no heat flow.

Isothermal contraction occurs as the system releases heat. At temperature T2, the engine produces heat Q2.

An adiabatic process occurs once more, changing the system's temperature from T2 to T1.

Isothermal expansion, followed by the adiabatic process, and then isothermal contraction, followed by the adiabatic process, make up one cycle of the Carnot engine.

This will continue to happen.

  • The efficiency of Carnot engine is given by:-

η=WQ1Q2=1T2T1

Thermodynamics Previous year Question and Answer

Q1: An ideal gas undergoes isothermal process from some initial state I to final state f. Choose the correct alternatives

a) dU = 0

b) dQ = 0

c) dQ = dU

d) dQ = dW

Answer:

Since the process is isothermal ΔT=0 or T is constant
For an ideal gas, dU=Change in internal energy=nCvdT
dT=0; Thus dU=0

dQ=dU+dWdQ=dW

Hence, the answers are the options (a) and (d) only.

Q2: An ideal gas undergoes cyclic process ABCDA as shown in given P-V diagram (Figure). The amount of work done by the gas is:

Answer:

Let us take the PV diaaram, in this figure we have work done in the process of ABCD is equal to the area of the rectangle in ABCDA.
work done in the process of ABCD= area of the rectangle in ABCDA.
work done in the process of ABCD=AB×BC
work done in the process of ABCD=(3VoVo)×(2PoPo)
work done in the process of ABCD=2Vo×Po
work done in the process of ABCD=2VoPo
Here we can see that the process is in an anti-clockwise direction, therefore;
work done in the process of ABCD=2VoPo

Q3: An ideal gas undergoes four different processes from the same initial state (Figure). Four processes are adiabatic, isothermal, isobaric and isochoric. Out of 1, 2, 3 and 4 which one is adiabatic

.

Answer:

For curve4pressure is constant, so this is an isobaric process.

$

\text{For curve 1 , volume is constant, so it is an isochoric process. Between curves 3 and 2 , curve 2 is steeper, so it is adiabatic and 3 is isothermal.}

$

NCERT Class 11 Notes Chapter-Wise

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Frequently Asked Questions (FAQs)

1. Is Thermodynamics significant in JEE and NEET?

It is, in fact, very important chapter as far as JEE and NEET are concerned because it acts as a foundation to several conceptual and numerical questions on heat, energy, and the efficiency of a system.

2. What is thermodynamics in 11 th Physics?

Thermodynamics is a part of physics that concerns the correlation between heat, work and energy. it discusses the transfer of energy in a system and surrounding.

3. What is the role of NCERT notes in this chapter?

The NCERT notes provide well-written explanations, essential formulas, derivations and diagram-based revision for last-minute revision

4. In exams, do derivations matter in this chapter?

Devices such as ACs, engines, other power plants, and even biological metabolism in organisms are based on thermodynamics.

5. What is the relevance of thermodynamics in the technological world?

The Second Law of Thermodynamics Asserts that a hot object will naturally give heat to a cold object until both are at the same temperature.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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