Have you ever wondered how large skyscrapers are designed or how the GPS tells us about our exact locations every time? To find the answer, we have to study three-dimensional geometry, where we go beyond our understanding of two-dimensional geometry to the X, Y, and Z coordinate axes. The chapter Introduction to Three-Dimensional Geometry contains the concepts of Coordinate Axes and Coordinate Planes in Three-Dimensional Space, Coordinates of a Point in Space, Distance between Two Points and its formula, and many more. These NCERT notes will help the students grasp more advanced geometry concepts easily and enhance their problem-solving ability in real-world applications.
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These NCERT notes for Class 11 Maths offer well-structured NCERT notes to help students easily grasp the concepts of three-dimensional geometry. Students who want to revise the key topics of three-dimensional geometry quickly will find this article very useful. It will also significantly boost the exam preparation of students. These NCERT Class 11 Maths Chapter 11 notes on Introduction to Three-Dimensional Geometry are prepared by subject matter experts of Careers360 following the latest NCERT syllabus, ensuring that students can grasp the basic concepts effectively. Check this NCERT article for complete syllabus coverage along with NCERT Books, Solutions, Syllabus, and Exemplar Problems with Solutions.
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Students who wish to access the Introduction to Three-Dimensional Geometry Class 11 Maths notes can click on the link below to download the entire notes in PDF.
Careers360 has prepared these Class 11 Introduction to Three Dimensional Geometry Notes to make your revision smoother and faster.
Suppose that there are two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ then the distance formula is given as
$d=\sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2+\left(z_1-z_2\right)^2}$
Suppose that there are two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ are divided into $m:n$.
The section formula is given as:
$\left(x^{\prime}, y^{\prime}, z^{\prime}\right)=\left(\frac{m x_2+n x_1}{m+n}, \frac{m y_2+n y_1}{m+n}, \frac{m z_2+n z_1}{m+n}\right)$
An equation of a plane contains three independent constants; as such, a plane is uniquely determined by three independent conditions. If we consider a plane satisfying just two given conditions, its equation will contain one arbitrary constant. If we consider a plane satisfying one given condition, its equation will contain two arbitrary constants.
We give below the equations of some well-known systems of planes:
The equation $ax + by + cz + k = 0$ represents a system of planes parallel to the plane $ax + by + cz + d = 0$,
where $d$ and $k$ are parameters.
The equation $ax + by + cz + k = 0$ represents a system of planes perpendicular to the line $\frac{x}{a} = \frac{y}{b} = \frac{z}{c}$.
The equation $a_1x + b_1y + c_1z + d_1 + λ(a_2x + b_2y + c_2z + d_2)= 0$ is a system of planes passing through the intersection of the planes
$a_1x + b_1y + c_1z + d_1 = 0$ and $a_2x + b_2y + c_2z + d_2 = 0$,
where $λ$ is a parameter.
Let there be two planes
$a_1x + b_1y + c_1z + d_1 = 0$ and $a_2x + b_2y + c_2z + d_2 = 0$
Then the angle between is given as
$\cos\theta=\left|\frac{a_1a_2+b_1b_2+c_1c_2}{\sqrt{a_1^2+b_1^2+c_1^2} \sqrt{a_2^2+b_2^2+c_2^2}}\right|$
If a straight line passes through a given point $(x_1,y_1,z_1)$ and has direction cosines $l, m, n,$ then the coordinates of any point on it satisfy the equations
$\frac{x-x_1}{l}=\frac{y-y_1}{m}=\frac{z-z_1}{n}$
The parametric vector equation of the line through a point with position vector $a$ and parallel to the vector $b$ is:
$\vec{r}=\overrightarrow{\mathrm{a}}+\lambda \vec{b}$, where $λ$ is a scalar parameter.
Given below are selected previous year question answers for NCERT Class 11 Maths Chapter 11 Introduction to Three Dimensional Geometry, collected from various examinations.
Question 1:
Show that the three points A (2, 3, 4), B (–1, 2, – 3) and C (– 4, 1, – 10) are collinear and find the ratio in which C divides AB.
Solution:
Given:
A(2,3,4), B(-1,2,-3) & C(-4,1,-10)
Now,
AB = $\sqrt{(2+1)^{2}+(3-2)^{2}+(4+3)^{2} }$
= $\sqrt{9+1+49 }$ = $\sqrt{59 }$
BC = $\sqrt{(-1+4)^{2}+(2-1)^{2}+(-3+10)^{2}}$
= $\sqrt{9+1+49 }$ = $\sqrt{59 }$
AC = $\sqrt{(2+4)^{2}+(3-1)^{2}+(4+10)^{2} }$
= $\sqrt{36+4+196 }$ = $2\sqrt{59}$
Now, AB + BC = $\sqrt{59}+\sqrt{59}$
= $2\sqrt{59}$
= AC
Thus, A, B & C are collinear.AC:BC = $2\sqrt{59}:\sqrt{59}$ = 2:1
Thus, C divides AB externally in the ratio 2:1.
Question 2:
What is the length of the foot of the perpendicular drawn from the point P (3, 4, 5) on the y-axis
A. $\sqrt{41}$
B. $\sqrt{34}$
C. 5
D. None of these
Solution:
The answer is the option (b)$\sqrt{ 34}$
On y-axis, x = z = 0
Thus, A = (0,4,0)
Thus, PA
= $\sqrt{ (0-3)^{2}+(4-4)^{2}+(0-5)^{2} }$
= $\sqrt{ 9+0+25 }$
= $\sqrt{ 34 }$
Hence, the correct answer is option B.
Question 3:
The distance of the point (3, 4, 5) from the origin (0, 0, 0) is
A. $\sqrt{50}$
B. 3
C. 4
D. 5
Solution:
The answer is the option (a) $\sqrt{50}$
Given: P(3,4,5) & O(0,0,0)
Thus, OP
= $\sqrt{(0-3)^{2}+(0-4)^2+(0-5)^{2} }$
= $\sqrt{9+16+25}$
= $\sqrt{50}$
Hence, the correct answer is option A.
NCERT Class 11 Maths Chapter 11 Notes play a vital role in helping students grasp the core concepts of the chapter easily and effectively, so that they can remember these concepts for a long time. Some important points of these notes are:
We at Careers360 compiled all the NCERT class 11 Maths notes in one place for easy student reference. The following links will allow you to access them.
NCERT Class 11 Maths Chapter 2 Relations and Functions Notes |
NCERT Class 11 Maths Chapter 3 Trigonometric Functions Notes |
NCERT Class 11 Maths Chapter 4 Complex Numbers and Quadratic Equations Notes |
NCERT Class 11 Maths Chapter 6 Permutation and Combinations Notes |
NCERT Class 11 Maths Chapter 11 Introduction to Three-Dimensional Geometry Notes |
NCERT Class 11 Maths Chapter 12 Limits and Derivatives Notes |
Given below are some subject-wise links for the NCERT Notes for class 11.
After finishing the textbook exercises, students can use the following links to check the NCERT exemplar solutions for a better understanding of the concepts.
Students can also check these well-structured, subject-wise solutions.
Students should always analyse the latest syllabus before making a study routine. The following links will help them check the syllabus and access some reference books.
Frequently Asked Questions (FAQs)
Direction Cosines: Cosines of the angles a line makes with the x, y, and z axes.
Direction Ratios: Proportional values representing the direction of a line in 3D space.
Students can download the Free NCERT Class 11 Maths Chapter 11 Notes PDF Introduction to Three Dimensional Geometry from the official Careers360 website.
Three Dimensional Geometry (3D Geometry) deals with the study of points, lines, and shapes in space that have three coordinates — x, y, and z.
The three axes are the x-axis, y-axis, and z-axis, which are mutually perpendicular to each other and intersect at the origin.
The origin is the point where all three axes intersect, and its coordinates are (0, 0, 0).
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