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Complex Numbers And Quadratic Equations Class 11th Notes - Free NCERT Class 11 Maths Chapter 5 notes - Download PDF

Complex Numbers And Quadratic Equations Class 11th Notes - Free NCERT Class 11 Maths Chapter 5 notes - Download PDF

Updated on Apr 07, 2025 09:08 AM IST

Have you ever tried solving quadratic equations like x2+1=0? Then you will find x2=1. Is it possible that the square of a real number is 1? The answer lies in this chapter. From NCERT Class 12 Maths, the chapter Complex Numbers and Quadratic Equations contains the concepts of Complex Numbers, Algebra of Complex Numbers, The Modulus and the Conjugate of a Complex Number, Argand Plane and Polar Representation, etc. These concepts will help the students grasp more advanced complex number topics easily and will also enhance their problem-solving ability in real-world applications.

This Story also Contains
  1. NCERT Class 11 Maths Chapter 4 Notes
  2. Importance of NCERT Class 11 Maths Chapter 3 Notes:
  3. NCERT Class 11 Notes Chapter Wise
  4. Subject-Wise NCERT Exemplar Solutions
  5. Subject-Wise NCERT Solutions
  6. NCERT Books and Syllabus

This article on NCERT notes Class 12 Maths Chapter 4 Complex Numbers and Quadratic Equations offers well-structured NCERT notes to help the students grasp the concepts of Complex Numbers easily. Students who want to revise the key topics of Complex Numbers and Quadratic Equations quickly will find this article very useful. It will also boost the exam preparation of the students by many folds. These notes of NCERT Class 12 Maths Chapter 4 Complex Numbers and Quadratic Equations are made by the Subject Matter Experts according to the latest CBSE syllabus, ensuring that students can grasp the basic concepts effectively. NCERT solutions for class 12 maths and NCERT solutions for other subjects and classes can be downloaded from the NCERT Solutions.

NCERT Class 11 Maths Chapter 4 Notes

Complex Number

A complex number is defined as the combination of real and imaginary numbers.

Example: 3+4i

Here, 3 is real and 4i is the imaginary part.

Here is i=(1), then we can say that i2=1

Algebra Of Complex Numbers

Addition Of Two Complex Numbers

Let x=a+ib and y=c+id

Therefore, x+y=(a+c)+i(b+d)

Properties

  • The closure law: The sum of two complex numbers is also a complex number

  • The commutative law x+y=y+x

  • The associative law (x+y)+z=x+(y+z)

Difference Of Two Complex Numbers
Let x=a+ib and y=c+id

Therefore xy=x+(y)

Multiplication of Two Complex Numbers
Let x=a+ib and y=c+id

Therefore, xy=acbd+i(ad+bc)

Properties

  • The closure law. The multiplication of two complex numbers is also a complex number

  • The commutative law xy=yx

  • The associative law (xy)z=x(yz)

  • The distributive law x(y+z)=xy+xz and (x+y)z=xz+yz

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Division Of Two Complex Numbers

Let x=a+ib and y=c+id

Therefore xy = x.(1y)

Power of i

In general, any integer k

i4k=1,i4k+1=i,i4k+2=1,i4k+3=i

The square roots of a negative real number

i2=1, and (i)2=i2=1

The Modulus And The Conjugate Of A Complex Number

If x=a+ib, then |x|=a2+b2

Properties

  1. |xy|=|x||y|

  2. |xy|=|x||y|

  3. (xy)=xy

  4. (x±y)=x±y

  5. (xy)=xy

Argand Plane And Polar Representation

The complex number a+ib corresponding to ordered pairs (a,b) can also be represented geometrically in the XY plane.

In the Argand plane, the modulus of a complex number a+ib=(a2+b2) is the distance from the origin to the point.

Polar Representation Of A Complex Number

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We note that the point P is uniquely determined by the ordered pair of real numbers (r,θ), called the polar coordinates of the point P.

We get a=rcosθ,b=rsinθ, thus x=r(cosθ+isinθ)

Example:

Express the following in the form a+ib:i35
Solution : i35=1i35=1(i2)17i=1i×ii=i

Quadratic Equation

The equation that consists of the highest power in the polynomial is 2.

Let ax2+bx+c=0 be a quadric equation then its discriminant is

D=b24ac

Let us assume that D<0

Then x=b±b24ac2a

Example:

Solve x2+x+1=0

Solution:

Here, b24ac=124×1×1=3<0

 Therefore x=b±b24ac2a=1±124×1×12×1=1±3i2

This concludes the chapter.

Importance of NCERT Class 11 Maths Chapter 3 Notes:

NCERT Class 11 Maths Chapter 3 Notes play a vital role in helping students grasp the core concepts of the chapter easily and effectively, so that they can remember these concepts for a long time. Some important points of these notes are:

  • Effective Revision: These notes provide a detailed overview of all the important theorems and formulas, so that students can revise the chapter quickly and effectively.
  • Clear Concepts: With these well-prepared notes, students can understand the basic concepts effectively. Also, these notes will help the students remember the key concepts by breaking down complex topics into simpler and easier-to-understand points.
  • Time Saving: Students can look to save time by going through these notes instead of reading the whole lengthy chapter.
  • Exam Ready Preparation: These notes also highlight the relevant contents for various exams, so that students can get the last-minute minute very useful guidance for exams.

NCERT Class 11 Notes Chapter Wise

Subject-Wise NCERT Exemplar Solutions

After finishing the textbook exercises, students can use the following links to check the NCERT exemplar solutions for a better understanding of the concepts.

Subject-Wise NCERT Solutions

Students can also check these well-structured, subject-wise solutions.

NCERT Books and Syllabus

Students should always analyze the latest CBSE syllabus before making a study routine. The following links will help them check the syllabus. Also, here is access to more reference books.

Happy learning !!!

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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