Aakash Repeater Courses
ApplyTake Aakash iACST and get instant scholarship on coaching programs.
Have you ever tried solving quadratic equations like $x^2+1=0$? Then you will find $x^2=-1$. Is it possible that the square of a real number is $-1$? The answer lies in this chapter. From NCERT Class 12 Maths, the chapter Complex Numbers and Quadratic Equations contains the concepts of Complex Numbers, Algebra of Complex Numbers, The Modulus and the Conjugate of a Complex Number, Argand Plane and Polar Representation, etc. These concepts will help the students grasp more advanced complex number topics easily and will also enhance their problem-solving ability in real-world applications.
This article on NCERT notes Class 12 Maths Chapter 4 Complex Numbers and Quadratic Equations offers well-structured NCERT notes to help the students grasp the concepts of Complex Numbers easily. Students who want to revise the key topics of Complex Numbers and Quadratic Equations quickly will find this article very useful. It will also boost the exam preparation of the students by many folds. These notes of NCERT Class 12 Maths Chapter 4 Complex Numbers and Quadratic Equations are made by the Subject Matter Experts according to the latest CBSE syllabus, ensuring that students can grasp the basic concepts effectively. NCERT solutions for class 12 maths and NCERT solutions for other subjects and classes can be downloaded from the NCERT Solutions.
A complex number is defined as the combination of real and imaginary numbers.
Example: $3+4i$
Here, $3$ is real and $4i$ is the imaginary part.
Here is $i =\sqrt{(-1)}$, then we can say that $i^2 = -1$
Addition Of Two Complex Numbers
Let $x=a+ib$ and $y=c+id$
Therefore, $x+y= (a+c) +i(b+d)$
Properties
The closure law: The sum of two complex numbers is also a complex number
The commutative law $x+y=y+x$
The associative law $(x+y)+z=x+(y+z)$
Difference Of Two Complex Numbers
Let $x=a+ib$ and $y=c+id$
Therefore $x-y= x+(-y)$
Multiplication of Two Complex Numbers
Let $x=a+ib$ and $y=c+id$
Therefore, $xy=ac-bd+i(ad+bc)$
Properties
The closure law. The multiplication of two complex numbers is also a complex number
The commutative law $xy=yx$
The associative law $(xy)z=x(yz)$
The distributive law $x(y+z) = xy+xz$ and $(x+y)z=xz+yz$
Division Of Two Complex Numbers
Let $x=a+ib$ and $y=c+id$
Therefore $\frac{x}{y}$ = $x.(\frac{1}{y})$
In general, any integer k
$i^{4 k}=1, i^{4 k+1}=i, i^{4 k+2}=-1, i^{4 k+3}=-i$
The square roots of a negative real number
$i^2=-1, \text { and }(-i)^2=i^2=-1$
If $x=a+i b$, then $|x|=\sqrt{a^2+b^2}$
Properties
$|x y|=|x||y|$
$|\frac{x}{y}|=\frac{|x|}{|y|}$
$(xy)'=x'y'$
$(x±y)’=x’±y’$
$(\frac{x}{y})’=\frac{x’}{y’}$
The complex number $a+ib$ corresponding to ordered pairs $(a, b)$ can also be represented geometrically in the XY plane.
In the Argand plane, the modulus of a complex number $a+ib =\sqrt{(a^2+b^2)}$ is the distance from the origin to the point.
We note that the point P is uniquely determined by the ordered pair of real numbers $(r, θ),$ called the polar coordinates of the point P.
We get $a=r\cosθ, b=r\sinθ,$ thus $x=r(\cosθ +i \sin θ)$
Example:
Express the following in the form $\mathrm{a}+\mathrm{ib}: i^{-35}$
Solution : $i^{-35}=\frac{1}{i^{35}}=\frac{1}{\left(i^2\right)^{17} i}=\frac{1}{-i} × \frac{i}{i}=i$
The equation that consists of the highest power in the polynomial is 2.
Let $ax^2+bx+c=0$ be a quadric equation then its discriminant is
$D=b^2-4ac$
Let us assume that $D<0$
Then $x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a}$
Example:
Solve $x^2+x+1=0$
Solution:
Here, $b^2-4ac=1^2-4×1×1=-3<0$
$\begin{aligned} & \text { Therefore } x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} \\ &= \frac{-1 \pm \sqrt{1^2-4 × 1 × 1}}{2 × 1}=\frac{-1 \pm \sqrt{3} i}{2}\end{aligned}$
This concludes the chapter.
NCERT Class 11 Maths Chapter 3 Notes play a vital role in helping students grasp the core concepts of the chapter easily and effectively, so that they can remember these concepts for a long time. Some important points of these notes are:
After finishing the textbook exercises, students can use the following links to check the NCERT exemplar solutions for a better understanding of the concepts.
Students can also check these well-structured, subject-wise solutions.
Students should always analyze the latest CBSE syllabus before making a study routine. The following links will help them check the syllabus. Also, here is access to more reference books.
Happy learning !!!
Take Aakash iACST and get instant scholarship on coaching programs.
This ebook serves as a valuable study guide for NEET 2025 exam.
This e-book offers NEET PYQ and serves as an indispensable NEET study material.
As per latest syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
As per latest syllabus. Chemistry formulas, equations, & laws of class 11 & 12th chapters
As per latest 2024 syllabus. Study 40% syllabus and score upto 100% marks in JEE