NCERT Class 11 Biology Chapter 13 Notes Photosynthesis In Higher Plants - Download PDF Notes

NCERT Class 11 Biology Chapter 13 Notes Photosynthesis In Higher Plants - Download PDF Notes

Edited By Irshad Anwar | Updated on Feb 09, 2024 01:01 PM IST

Photosynthesis in Higher Plants is a very important chapter of the NCERT Photosynthesis in Higher Plants from an exam point of view. The NCERT Class 11 Biology Chapter 13 notes give you a fundamental idea about how photosynthesis takes place, as given in Chapter Photosynthesis in Higher Plants. The NCERT chapter 13 Photosynthesis in Higher Plants discusses the complete process of photosynthesis and all the steps involved in it. The main topics covered in NCERT Class 11 Biology notes are definition, early experiments done for photosynthesis, where does photosynthesis take place, types of pigments involved in photosynthesis, what is light reaction, the electron transport, splitting of water, Cyclic and Non-cyclic Photo-phosphorylation, chemiosmotic hypothesis, about ATP and NADPs, the Calvin Cycle, the C4 pathway, photorespiration, and factors affecting photosynthesis. Download the CBSE Notes for Class 11 Biology, Chapter 13, PDF to use offline anywhere. Students must go through each topic in the photosynthesis in higher plants in Class 11 Notes Biology in the easiest and most effective way possible with the help of NCERT Notes for Class 11.

Class 11 Biology chapter 13 notes also cover all the important concepts related to this chapter, which are crucial for various competitive exams. Photosynthesis in Higher Plants NCERT Notes for Class 11 Biology help you revise these important concepts given in the NCERT Book in a short period of time during CBSE Board exam preparation. CBSE Class 11 Biology Chapter 13 notes will help you with quick revision. The Photosynthesis in Higher Plants chapter covers all headings of NCERT. CBSE Class 11 Biology chapter 13 notes also contain important examples that have been frequently asked in the various exams. Having revision notes and NCERT Solutions for Class 11 Biology Chapter 13 handy save you time.The NCERT Class 11 notes pdf can be downloaded through the link given below.

Also, students can refer,

NCERT Class 11 Chapter 13 Class Notes

Photosynthesis in Higher Plants

Definition of photosynthesis: It is a vital process in plants, algae, and some bacteria that converts light energy into chemical energy stored in the form of glucose. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a by-product. During photosynthesis, plants absorb CO₂. The overall chemical equation for photosynthesis can be represented as follows:

6 CO₂ + 6 H₂O + light energy → C₆H₁₂O₆ + 6 O₂

In other words, this equation can be described as the conversion of carbon dioxide and water, in the presence of light energy, into glucose and oxygen.

  • Class 11 Photosynthesis in Higher Plants notes inform us that all animals on this planet, including humans, depend on plants for their food.
  • Green plants synthesise the food they need, and all other organisms depend on them to fulfil their energy needs.
  • The green plants make food that they need through photosynthesis, and since they prepare their food on their own, they are therefore called autotrophs. Only plants exhibit autotrophic nutrition.
  • Photosynthesis in Higher plants Class 11 notes also give you two major reasons for highlighting the importance of photosynthesis:. They are the primary source of food on earth, and they also release oxygen into the atmosphere.
  • Heterotrophs are species that rely on green plants for nutrition, including humans.
  • Photosynthesis is a Physio-chemical process in which plants utilise the sun's light energy to fuel the synthesis of organic molecules such as glucose.
  • Ultimately, all living forms on earth depend on sunlight for energy.
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This chapter explores the photosynthetic machinery's structure as well as the numerous processes that turn sunlight's light energy into chemical energy.

What Do We Already Know?

  • We already know that three components, which are chlorophyll, which is the green-coloured pigment of leaves, light, and carbon dioxide are required for photosynthesis to occur.
  • In earlier classes, we also did some experiments where one leaf was partially covered with black paper, and then the other way posed to light.
  • On testing leaves for the presence of starch, it is proved that photosynthesis occurred only in the green parts of the leaves of that plant that was exposed to sunlight thus showing the importance of sunlight.
  • Another experiment that can be carried out is, if a part of a leaf of a plant is enclosed in a test tube containing some KOH solution soaked in cotton (KOH absorbs CO2), while the other half is exposed to air.
  • The arrangement is then exposed to light for a period of time.
  • Later, when the two halves of the leaf were tested for the presence of starch, it was discovered that the exposed part of the leaf that was exposed to CO2 tested positive for starch while the half that was in the tube tested negative.
  • This proves that CO2 is necessary for photosynthesis.

Early Experiments

  • In 1774 Joseph Priestly discovered oxygen and based on the experiments he hypothesised: Plants restore to the air whatever breathing animals and burning candles remove

1646805102998

An experiment performed by Joseph Priestly

  • In 1854 Julius von Sachs determined that the green parts in plants are where glucose is made and glucose is generally saved as starch.
  • T.W. Engelmann (1843–1909) conducted a remarkable experiment.
  • He separated light into its spectrum components using a prism and then lighted a green alga called Cladophora that was suspended in an anaerobic bacteria solution.
  • The microorganisms were employed to find out where O2 evolved. He discovered that germs gathered mostly in the split spectrum's blue and red light regions.
  • As a result, the first photosynthesis action spectrum was defined. It mimics the absorption spectra of chlorophyll a and b in appearance. The whole photosynthetic process for oxygen-evolving organisms was then represented by the empirical equation:

1646805102232

where [CH2O] represents a carbohydrate (e.g., glucose, a six-carbon sugar).

  • A milestone contribution to the understanding of photosynthesis was made by microbiologist Cornelius van Neill who based on his considers of purple and green microbes, illustrated that photosynthesis is a light-dependent response in which H2 from a suitable hydrogen compound i.e. H2O reduces carbon dioxide to carbohydrates.

that can be given as,

1646805102534

  • In green plants, H2O is the H2 giver and is oxidized to O2. A few life forms don't discharge O2 during photosynthesis.
  • When H2S is the Hydrogen donor for purple and green sulfur microbes, the 'oxidation' item is sulphur/Sulphate.
  • Hence, it's concluded that O2 evolved by plants(green) comes from H2O and not from CO2.

Thus, the equation of photosynthesis can be given as :

1646805101806

Site of Photosynthesis ( Where does PHOTOSYNTHESIS take place?)

  • Photosynthesis takes place in the green leaves of plants, particularly in the chloroplast of their mesophyll.

1646805102691

  • The membrane system is in charge of capturing solar energy as well as ATP and NADPH production; the reactions or sets of reactions involved are light-driven and are therefore called light reactions.
  • In the stroma, enzymes are responsible for taking CO2 and leading to the synthesis of sugar, which in turn forms starch. The reactions are not directly light-driven but dependent on the products of light reactions, i.e. ATP and NADPH, and are called Dark reactions

How Many Types of Pigments Are Involved in Photosynthesis?

  • There are four pigments in leaves: chlorophyll-a of bright or blue-green colour, chlorophyll-b of yellow-green, xanthophylls of yellow colour, and carotenoids of yellow-to yellow-orange colour.

1646805103344

Leaves show different colour pigments

We can conclude that chlorophyll is the chief pigment associated with photosynthesis.

What Is Light Reaction?

  • It includes light absorption, water splitting, oxygen release, and the formation of high-energy chemicals, i.e., ATP and NADPH.
  • Several complexes, viz., LHC, light-harvesting complexes, in which pigments are present are in Photosystem 1 (PS1) and Photosystem 2 (PS2). These are named in the order of their discovery.
  • Each photosystem has all the pigments except chlorophyll a and forms an LHS called antennae.
  • The single-molecule chlorophyll-a forms the reaction centre.
  • PS 1 has an absorption peak at 700 nm, which is referred to as P700, whereas PS 2 has an absorption peak at 680 nm, which is referred to as P680.

The Electron Transport

  • In PS2, LHC receives the light of 680 nanometers that results in the excitation of electrons, and thus they jump out of their orbit and are received by an electron acceptor that then passes it to the electron transport system.
  • Electrons are not used up and are passed to pigments of PS1 With simultaneous excitation of electrons in PS1, because of the 700 nanometer absorption of light, these electrons are passed to a molecule of energy, NADP+, resulting in the formation of NADPH and H+.

1646805102404

Electron transport showing Z scheme

This scheme is known as the Z scheme

Splitting of Water

  • The electrons that were moved from Photosystem 2 are replaced by the splitting of H2O. This creates oxygen, that is a product of photosynthesis.

2H2O ⟶ 4 H+ + O2 + 4e-

  • The electrons needed to replace those removed from PS 1 are provided by PS 2.
  • This splitting of H2O is associated with PS 2.

Cyclic and Non-Cyclic Photophosphorylation

  • Photophosphorylation is the synthesis of ATP from ADP and Pi in the presence of light. when PS 2 and then PS 1 act in series, non-cyclic photophosphorylation occurs; both ATP and NADPH are synthesised here, whereas
  • When only PS 1 is functional, the electron is circulated within PS 1, and phosphorylation occurs due to the cyclic flow of electrons. It takes place in stroma lamellae. It lacks the NADP reductase enzyme; here, the synthesis of ATP takes place but not of NADPH and H+.

1646805102092

Electron transport system in PS1

  • It also occurs when only light off wavelength beyond 680 nanometers are available

Chemiosmotic Hypothesis

  • The ATP synthase enzyme is made up of two parts: the F0 is introduced into the thylakoid layer and produces a transmembrane channel that allows protons to diffuse across the layer quite easily.
  • The other half, known as F1, is located on the stroma-facing side of the thylakoid membrane's exterior surface.
  • The breakdown of the gradient provides enough energy to trigger a conformational shift in the ATP synthase's F1 moiety, causing the enzyme to synthesise multiple molecules of ATP.
  • A membrane, a proton pump, a proton angle, and ATP synthase are all required for chemiosmosis.
  • Energy is used to pump protons over a membrane to make a gradient or a high concentration of protons inside the thylakoid lumen.
  • ATP synthase incorporates a channel that permits the release of protons back over the membrane; this releases sufficient energy to enact the ATP synthase chemical that catalyses the arrangement of ATP. Along with the NADPH created by the development of electrons.

Where Are The ATP And NADPH Used?

  • These are utilized in a dark reaction called the biosynthetic phase of photosynthesis, as the synthesis of food takes place here.
  • During World War II, Melvin Calvin discovered that the first carbon dioxide fixation product was a three-carbon organic acid called 3-phosphoglyceric acid, or PGA; hence, it was called the Calvin cycle.

1646805101650

C3: First CO2 fixation product is 3-C containing, PGA.

C4: First CO2 fixation product is 4-C containing OAA

The Primary Acceptor of CO2:.

In C3 plants, it's 5-C containing RuBP (ribulose bisphosphate) that combines with CO2 to produce sucrose.

The Calvin Cycle

1646805102844

i) Carboxylation: Here, carbon dioxide is utilised for the decarboxylation of RuBP which results in two molecules of 3-PGA in the presence of an enzyme named RuBP carboxylase-oxygenase, or RuBisCO, having infinity for both carbon dioxide and oxygen.

ii) Reduction: Two molecules of ATP are required for phosphorylation, and two molecules of NADPH are required for the reduction of carbon dioxide. The fixation of six molecules of carbon dioxide and six turns of cycles are required.

iii) Regeneration: Regeneration of carbon dioxide acceptor molecule RuBP requires one ATP for phosphorylation to form RuBP

In

Out

Six Carbon dioxide

One glucose

18 ATP

18 ADP + 18Pi

12 NADPH

12 NADP

The C4 Pathway

  • These have two kinds of cells: mesophyll and vascular bundles.
  • The large cells around vascular bundles are called bundle sheath cells, and leaves are set to have kranz anatomy.
  • Bundle sheath cells may have several layers containing chloroplasts and are impervious to gaseous exchange.
  • The primary carbon dioxide acceptor is the three-carbon molecule phosphoenolpyruvate (PEP) is present in the mesophyll cells.
  • The enzyme responsible is PEP carboxylase or PEP case; here, the RuBisCO enzyme is absent.
  • Here, C4 acid OAA is formed, which then forms malic acid/aspartic acid in mesophyll itself and then transported to bundle sheath cells, where C4 acids are broken down to release carbon dioxide and a three-carbon molecule.
  • Again, it is transported to mesophyll, where it forms PEP again, thus completing the cycle.

1646805103156

Hatch and slack cycle

The carbon dioxide released in the bundle sheath cells enters the C3/Calvin pathway, which is common to all plants, whether C3 or C4. The bundle sheath cells are rich in the enzyme RuBisCO but lack PEPcase. As bundle sheath cells are impermeable to carbon dioxide gas, their concentration increases.

Photorespiration

  • RuBisCO, which is the most abundant enzyme in the world, is characterised by the fact that it can bind with O2 as well as CO2.

1646805101481

  • In C3 plants, some O2 binds with RuBisCO resulting in the formation of phosphoglycerate and phosphoglycolate in a pathway called photorespiration. In this pathway, there is no synthesis of sugar and ATP/NADPH therefore it's called a wasteful process
  • In C4 plants, photorespiration does not occur; therefore, they have more productivity.

Factors Affecting Photosynthesis

  • The rate of photosynthesis depends on both internal and external factors.
  • Internal factors like the number, size, age, Orientation of leaves, chloroplasts, etc., and internal factors like CO2 concentration, Temperature, water, etc.
  • When several factors affect any biochemical process, Blackman's (1905) Law of Limiting Factors comes into effect, i.e., if a chemical process is influenced by more than one factor at that point, its rate will be decided by the factor that is closest to its minimal value, which is called the limiting factor. It's the figure that specifically influences the method if the amount is changed.

Light

  • Light is used as 10% of incident sunlight. At low intensity, it's directly proportional to CO2 fixation.
  • At higher intensities, other factors become limiting.
  • An increase in light beyond a limit causes the breakdown of chlorophyll and, thus, a decrease in photosynthesis.

Carbon Dioxide Concentration

  • It's the major limiting factor, as carbon dioxide is very low in the atmosphere, ranging from 0.03% to 0.04%, increase in concentration up to 0.05% can cause an increase in the rate of photosynthesis

Temperature

  • The dark reactions that are enzymatic are temperature-controlled.
  • C4 plants respond to higher temperatures, and they also show higher rates of photosynthesis, whereas C3 plants are found to show a lower temperature optimum.

Water

  • Water stress causes the stomata to close, thereby reducing carbon dioxide availability, and it makes leaves wilt, thereby reducing surface area.

Chapter-Wise NCERT Class 11 Notes Biology

Significance of NCERT Class 11 Biology Chapter 13 Notes:

Class 11 Biology chapter 13 notes will assist you in revising the chapter and gaining an understanding of the main subjects addressed. These class 11 Photosynthesis in Higher Plants notes are also beneficial for covering the main themes of the CBSE Biology Syllabus in Class 11 as well as for competitive exams such as AIPMT, AIIMS, NEET, and others. The Class 11 Biology chapter 13 notes pdf download can be utilised for offline preparation.

Subject Wise NCERT Exemplar Solutions

Subject Wise NCERT Solutions

Frequently Asked Questions (FAQs)

1. Can C3 and C4 plants be differentiated from outside?

photosynthesis in Higher plants Class 11 notes state that by looking at a plant it can't be told whether a plant is C3 or C4. It can be told after seeing its anatomy. We can distinguish between C3 and C4 plants by their areas of growth also.

2. Why are C4 plants highly productive?

In accordance with CBSE class 11 Biology chapter 13 notes, This is so because the bundle sheath cells of these C4 plants are impervious to gas-like CO2 and thus there is a huge concentration of CO2 at that place RuBisCO combines with that CO2 to reduce it and form food.

3. Differentiate between the C3 pathway and the C4 pathway according to NCERT Class 13 Biology chapter 13 notes.


C3 pathway

C4 pathway

  1. The first Carbon dioxide fixation product is PGA

  1. The first Carbon dioxide fixation product is OAA

  1. Photorespiration takes place

2. Photorespiration does not take place

  1. Productivity is thus less

3. Productivity is thus more.


4. Differentiate between the anatomy of C3 and C4 plants as per NCERT notes for Class 11 Biology Chapter 13.

Ans:- 

Anatomy of C3

Anatomy of C4

  1. Vascular bundles are not having layers of cells

  1. Vascular bundles are having a layer of cells called bundle sheath cells

  1. mesophyll lack PEP

2. Mesophyll lack RuBisCO

  1. Vascular bundles lack RuBisCO

3. Vascular bundle lack PEP


5. RuBisCO is an enzyme that acts both as a carboxylase and oxygenase. Why does it carry out more Carboxylation in C4 plants?

According to Photosynthesis in Higher plants Class 11 notes, This is so because vascular bundles are having bundle sheath cells that are impervious to Carbon dioxide.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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