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Sequences And Series Class 11th Notes - Free NCERT Class 11 Maths Chapter 9 notes - Download PDF

Sequences And Series Class 11th Notes - Free NCERT Class 11 Maths Chapter 9 notes - Download PDF

Edited By Komal Miglani | Updated on Apr 08, 2025 09:03 AM IST

In our daily life, we often notice patterns, like the number of steps we walk each day increasing by a fixed number of steps on subsequent days, or if the salary of a person is multiplied by a fixed value every year. These are examples of sequences and series. A sequence is simply a list of numbers in a specific order, and a series is the total you get when you add up the numbers in a sequence. NCERT notes for Class 11 Maths Chapter 9 give a detailed explanation of Arithmetic Progression (AP), where the same number is added each time, and Geometric Progression (GP), where each number is multiplied by the same value. You’ll also learn how to find any term in the pattern and how to calculate the total of all terms. The NCERT Class 11 Maths chapter 9 notes are entirely based on the useful topics of the series and sequence.

This Story also Contains
  1. NCERT Class 11 Maths Chapter 9 Notes
  2. Arithmetic Progression (A.P)
  3. Arithmetic Mean
  4. Geometric Progression (G.P)
  5. Geometric Mean (G.M.)
  6. Sum To n Terms Of Special Series
  7. NCERT Class 11 Notes Chapter Wise
  8. Subject Wise NCERT Exemplar Solutions
  9. Subject Wise NCERT Solutions
  10. NCERT Books and Syllabus
  11. Importance of NCERT Class 11 Math Chapter 9 Notes

A Class 11 Maths chapter 9 note helps a student to revise the key concepts before the exam. NCERT Notes for Class 11 Maths chapter 9 covers Arithmetic progression, geometric progression, arithmetic mean, geometric mean, and the relation between the arithmetic mean and geometric mean as per the latest syllabus.

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NCERT Class 11 Maths Chapter 9 Notes

Sequence

The general definition is arranging something in a particular order.

Generally, we write the terms of a sequence by a1,a2,a3,an,, etc., the subscripts define the position of the term. The nth term defines the nth position of the sequence.
From the above sentences, we can say that a function whose domain is the set of natural numbers or a subset of it can be defined as a sequence. A functional notation can be used for an is a(n)

Series

Let a1,a2,a3,an,, be a given sequence. Then, the expression a1+a2+a3+.+an is known as a series.

The sum of the following series is denoted by ∑an is a(n).

Arithmetic Progression (A.P)

Let the sequence be

a1,a2,a3,an called an AP when the difference between an and an+1 is d
Thus an can be written as an=a+(n1)d
Let the sequence a1+a2+..+an
Then the summation is Sn=(n2)[2a+(n1)d]

Example:

If the 1,5,9,13… sequence is an A.P., what will be the nth term in the sequence?

Solution:

Given, sequence 1,5,9,13 . . . . . . .

Difference between the numbers, d =(139)=4

The nth term will be,

an=1+(n1)4an=1+4n4an=4n3

Arithmetic Mean

If the two given numbers are p and q. Insert the number F between p and q so that p, F, and q are in arithmetic progression. If F is the arithmetic mean of p and q numbers. Then we will have,

Fp=qFF+F=p+q2F=p+qF=p+q2

If the terms of an A.P. are increased, decreased, multiplied, or divided by the same constant, they remain in A.P.
If a1,a2,a3 are in A.P. with common difference d, then
(i) a1±k,a2±k,a3±k, are also in A.P with common difference d.
(ii) a1k,a2k,a3k, are also in A.P with common difference dk(k0). and a1k,a2k,a3k are also in A.P. with common difference dk(k0).
If a1,a2,a3 and b1,b2,b3 are two A.P., then
(i) a1±b1,a2±b2,a3±b3, are also in A.P
(ii) a1b1,a2b2,a3b3, and a1b1,a2b2,a3b3, are not in A.P.

If a1,a2,a3 and an are in A.Ps, then
(i) a1+an=a2+an1=a3+an2=
(ii) ar=ark+ar+k2k,0knr
(iii) If nth  term of any sequence is linear expression in n, then the sequence is an A.P.
(iv) If sum of n terms of any sequence is a quadratic expression in n, then sequence is an A.P.

Geometric Progression (G.P)

Let us consider the following sequences:

2, 4, 8, 16, .…..

1/9, -1/27, 1/81, -1/243, ......

Let the sequence be a1,a2,a3,.an called a GP when the difference in the ratio between an and an+1 is r by letting a1=a, we obtain a geometric progression,a, ar, ar 2, ar 3,..

General Term Of A G.P

The general term of GP is an=arn1

Sum to n terms of a G.P

Sn=a+ar+ar2++arn1Sn=a(1rn)(1r)

Geometric Mean (G.M.)

The formula for GM is

G=√ab

(i) If the terms of a G.P. are multiplied or divided by the same non-zero constant (k0), they remain in G.P.

If a1,a2,a3,, are in G.P., then a1k,a2k,a3k, and a1k,a2k,a3k, are also in G.P. with same common ratio, in particularly if a1,a2,a3, are in G.P., then 1a1,1a2,1a3, are also in G.P.
(ii) If a1,a2,a3, and b1,b2,b3, are two G.P.s, then a1b1,a2b2,a3b3, and a1b1,a2b2,a3b3, are also in G.P.
(iii) If a1,a2,a3, are in A.P. (ai>0i), then xa1,xa2,xa3,, are in G.P. (x>0)

(iv) If a1,a2,a3,,an are in G.P., then a1an=a2an1=a3an2=

Relationship Between A.M. and G.M

A=(a+b)/2 and G=√(ab)

The relation is A ≥ G.

Sum To n Terms Of Special Series

1+2+3+.+n (sum of first n natural numbers) k=n(n+1)212+22+32+.+n2 (sum of squares of the first n natural numbers) k=n(n+1)(2n+1)613+23+33++n3 (sum of cubes of the first n natural numbers) k=[n(n+1)2]2

NCERT Class 11 Notes Chapter Wise


Subject Wise NCERT Exemplar Solutions

After finishing the textbook exercises, students can use the following links to check the NCERT exemplar solutions for a better understanding of the concepts.

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Subject Wise NCERT Solutions

Students can also check these well-structured, subject-wise solutions.

NCERT Books and Syllabus

Students should always analyze the latest CBSE syllabus before making a study routine. The following links will help them check the syllabus. Also, here is access to more reference books.

Importance of NCERT Class 11 Math Chapter 9 Notes

Class 11 Sequence and series notes cover all important topics of the chapter. Class 11 Math chapter 9 notes are based on the Class 11 CBSE Maths Syllabus. So, it will help students to get a detailed and compact knowledge of the chapter.

  • NCERT notes are very important to strengthen your key concepts in order to perform well in exams. Students must try to solve all the NCERT problems, including miscellaneous exercises, and if needed, refer to the NCERT Solutions for Class 11 Maths Chapter 9 Sequence and Series
  • Students are advised to go through the NCERT Class 12 Maths Chapter 9 Notes before solving the questions.
  • These NCERT notes are very useful for boosting your exam preparation and quick revision.

Happy learning !!!

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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