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NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants

NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants

Edited By Irshad Anwar | Updated on Apr 02, 2025 10:51 AM IST

NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants: Plant respiration is the process that allows them to use stored food to produce energy for growth and survival. Plants do not have lungs or respiratory organs like animals. During respiration, they absorb oxygen and release carbon dioxide through tiny pores known as stomata in leaves and lenticels in stems. With the help of NCERT Solutions, students can learn about these important topics more easily.

This Story also Contains
  1. NCERT Solutions For Class 11 Biology Chapter 12 Respiration in Plants PDF Download
  2. NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants Solved Exercise
  3. Respiration in Plants Overview
  4. Key Features of NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants
  5. Chapter Wise NCERT Solutions for Class 11 Biology
NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants
NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants

In NCERT Class 11 Biology Chapter 12 Respiration in Plants, students study various forms of respiration, including aerobic and anaerobic respiration. The chapter discusses how glucose breaks to release energy in the form of ATP. Learning respiration in plants is important to know how plants obtain their energy. To help students understand these concepts more clearly, Respiration in Plants NCERT Solutions for Class 11 gives step-by-step solutions to textbook problems.

NCERT Solutions For Class 11 Biology Chapter 12 Respiration in Plants PDF Download

Here is the PDF of exercise solutions to make learning easier for students:

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Also, Read

NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants Solved Exercise

The questions with detailed explanation are given below:

Q1. Differentiate between

(a) Respiration and Combustion

Answer:

Feature

Respiration

Combustion

Where it Happens

Inside living cells

Not in cells, it's a general process

What Kind of Process

A biological process

A chemical process

Energy Release

Slowly, step by step

All at once, very quickly

Energy Form

Mostly as ATP (cell's energy currency)

No ATP is made

Needs Help From

Enzymes (special proteins)

Doesn't need enzymes


Q1. Differentiate between

(b) Glycolysis and Krebs cycle

Answer:

Feature

Glycolysis

Krebs Cycle

Where it Happens

In the cell's cytoplasm

Inside the mitochondria

Pathway Shape

A straight pathway

A circular pathway

Needs Oxygen?

Happens with or without oxygen

Needs oxygen to work

What it Does

Breaks down glucose into pyruvate

Breaks down pyruvate into CO2 and water

Uses/Makes ATP

Uses a little ATP to get started

Doesn't use ATP


Q1. Differentiate between (c) Aerobic respiration and Fermentation

Answer:

Feature

Aerobic Respiration

Fermentation

Where it Happens

Inside cells

Can happen inside or outside cells

Economic Use

Not used to making things in the industry

Used to make things like wine and bread

How it Works

Uses oxygen to break down stuff

Breaks down nutrients without using oxygen

Q2. What are respiratory substrates? Name the most common respiratory substrate.

Answer: Respiratory substrates are those organic compounds which, during respiration, are being oxidized for the release of energy within living cells. Examples of common respiratory substrates are carbohydrates, proteins, fats, and organic acids. The most frequent respiratory substrate is carbohydrates.


Q3. Give the schematic representation of glycolysis.

Answer: The schematic representation of glycolysis is as follows:

Glycolysis


Q4. What are the main steps in aerobic respiration? Where does it take place?

Answer: The key steps of aerobic respiration are as follows:

  1. Glycolysis- Cytoplasm

  2. Krebs cycle- Matrix of mitochondria

  3. Electron transport system- Inner mitochondrial membrane

  4. Oxidative phosphorylation- Oxysome in the inner mitochondrial membrane.

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Q5. Give the schematic representation of an overall view of Krebs' cycle

Answer: Schematic representation of the Krebs cycle

Krebs Cycle


Q7. Distinguish between the following:

(a) Aerobic respiration and Anaerobic respiration

Answer: The difference between aerobic respiration and anaerobic respiration is given below:

Feature

Aerobic Respiration

Anaerobic Respiration

Gas Exchange

It involves the exchange of gases

The exchange of gases is absent

Oxygen Use

It uses oxygen to break the respiratory material into simple substances

It does not use oxygen for the breakdown of respiratory substrates.

Breakdown of Material

The respiratory material is completely broken

The respiratory material is partially broken

Electron Transport

It involves electron transport

Electron transport is absent


Q7. Distinguish between the following:

(b) Glycolysis and Fermentation

Answer: The difference between Glycolysis and Fermentation is given below:

Feature

Glycolysis

Fermentation

Oxygen

It is the first step of respiration, which occurs without the requirement of oxygen and is common to both aerobic and anaerobic modes of respiration

It is anaerobic respiration or respiration which does not require oxygen

Product

Glycolysis produces pyruvic acid

Fermentation produces different products such as ethanol and lactic acid.

NADH Production

It produces two molecules of NADH per glucose molecule

It uses NADH produced during glycolysis.


Q7. Distinguish between the following:

(c) Glycolysis and Citric acid Cycle

Answer: The difference between Glycolysis and Citric acid Cycle is given below:

Feature

Glycolysis

Citric Acid Cycle

Location

It takes place inside the cytoplasm

It takes place in mitochondria

Function

It is the first step of respiration in which glucose is broken down to the level of pyruvate.

It is the second step of respiration wherein an active acetyl group is broken down completely


Q8. What are the assumptions made during the calculation of the net gain of ATP?

Answer: The assumptions used while calculating the net gain of ATP are as follows:

  1. It is supposed that different steps of aerobic respiration like glycolysis, TCA cycle, and ETS follow one after the other in a regular pathway.

  2. The NADH formed during glycolysis is transported into the mitochondria in order to receive oxidative phosphorylation.

  3. The glucose molecule is taken to be the sole substrate and it is assumed that no other molecule goes into the pathway at intermediate stages.

  4. The intermediates formed in respiration are not used for any other purpose.

Q9. Discuss "The respiratory pathway is an amphibolic pathway."

Answer: The respiratory pathway is an amphibolic pathway because it includes both the breakdown (catabolism) and the synthesis (anabolism) of molecules. Carbohydrates, fats, and proteins are broken into their simpler forms such as glucose, fatty acids, glycerol, and amino acids before respiration. Molecules of the respiratory pathway, such as acetyl CoA, are also utilised for the synthesis of fatty acids and proteins.


Q10. Define RQ. What is its value for fats?

Answer: The respiratory quotient (RQ) is defined as the ratio of the volume of CO2 evolved to the volume of O2 consumed during respiration. The value of the respiratory quotient depends on the type of respiratory substrate. The value of RQ for various respiratory substrates is as follows:

  1. Carbohydrates- 1

  2. Fat - 0.7

  3. Organic acids- more than 1

  4. Proteins - less than 1


Q11. What is oxidative phosphorylation?

Answer: Oxidative phosphorylation is the process of generating ATP through the use of energy released from respiration during the oxidation of NADH and FADH2. The process is facilitated by the presence of the enzyme ATP synthase, which is a component of the electron transport system (ETS). In this process, oxidation-reduction reactions build up a proton gradient. There are two components of ATP synthase: F0 and F1. The F0 component is located in the membrane and has a passage for protons, whereas the F1 component is where ADP and inorganic phosphate get converted into ATP. One ATP molecule is produced for every two protons passing through the F0-F1 complex.


Q12. What is the significance of step-wise release of energy in respiration?

Answer: The respiration process occurs stepwise, involving steps such as glycolysis, the TCA cycle, ETS, and oxidative phosphorylation. The synthesis of ATP during respiration is also in every phase. The products obtained in one step of respiration serve as the substrate of the other pathway. Different molecules generated during respiration are also engaged in other biochemical processes. Various respiratory substrates enter and leave the pathway when needed. The ATP also gets used wherever needed, and the rate of reactions of enzymes is also regulated. Hence, step-by-step release of energy increases the efficiency of the system in extracting as well as storing energy.


Respiration in Plants Overview

Class 11 Biology students need to learn about plant respiration, which is now discussed in Chapter 12 of the CBSE Syllabus 2025-26. Cellular respiration is discussed in this chapter, where plants break down food to release energy for growth and development. NCERT Solutions for Chapter 12 gives answers to important questions regarding glycolysis, fermentation, and aerobic respiration. In contrast to animals, plants use stomata and lenticels for gas exchange rather than specialised respiratory organs. The respiratory process in plants is amphibolic, where it includes anabolism as well as catabolism, and the respiratory quotient (RQ) differs according to the food. The respiration in plants class 11 solutions provide clear explanations and make the topic easy to understand.

The important topics and subtopics of Respiration in Plants Class 11 are given below:

12.1

Do Plants Breathe?

12.2

Glycolysis

12.3

Fermentation

12.4

Aerobic Respiration

12.4.1

Tricarboxylic Acid Cycle (Krebs Cycle)

12.4.2

Electron Transport System (ETS) and Oxidative Phosphorylation

12.5

The Respiratory Balance Sheet

12.6

Amphibolic Pathway

12.7

Respiratory Quotient

Key Features of NCERT Solutions for Class 11 Biology Chapter 12 Respiration in Plants

  • NCERT Solutions for Class 11 Biology are in NCERT textbook style.
  • Respiration in Plants class 11 solutions give direct answers to all textbook questions in the same sequence.
  • A helpful resource for students of CBSE to prepare themselves for examinations.
  • Chapter 12 class 11 biology solutions answers are composed in the most basic and understandable manner.
  • Helps students in testing and refining their knowledge of the subject.
  • In a downloadable version for instant and offline use

NCERT Solutions for Class 11: Subject-wise

Chapter Wise NCERT Solutions for Class 11 Biology

Below mentioned are the Chapterwise solutions:


Check the NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. What are the important topics covered in NCERT Solutions for Class 11 Biology Chapter 12?

The important topics covered in NCERT Solutions for Class 11 Biology Chapter 12 include:

  • Do Plants Breathe?

  • Glycolysis

  • Fermentation

  • Aerobic Respiration

  • The Respiratory Balance Sheet

  • Amphibolic Pathway

  • Respiratory Quotient.

2. What are the benefits of respiration in plants ncert pdf?
  • NCERT is the basis of your studies.
  • All respiration-related answers are available in the NCERT book. The Class 11 NCERT PDF of respiration in plants will make you get good marks in exams.
  • The NCERT solutions of respiration in plants are helpful for competitive exams such as NEET. 
  • Learning Class 11 Biology Chapter 12 NCERT solutions will increase your knowledge.
  • To obtain good marks, stick to the NCERT syllabus and practice the exercises in the textbook. As additional practice, see NCERT Exemplar.
3. What are the important topics of respiration in plants ncert?

These are the important topics of ncert respiration in plants:

  • Glycolysis  
  • Fermentation  
  • Aerobic Respiration  
  • Tricarboxylic Acid Cycle  
  • Electron Transport System (ETS) and Oxidative Phosphorylation  
  • The Respiratory Balance Sheet  
  • Amphibolic Pathway  
  • Respiratory Quotient 
4. What is oxidative phosphorylation given in chapter 12 biology class 11 ncert solutions?

Oxidative phosphorylation is the synthesis of energy-rich ATP  molecules with the help of energy liberated during oxidation of reduced coenzymes ( NADH and FADH2 ) produced in respiration. TH enzyme required for the synthesis is called ATP synthase. It is the fifth complex of ETS. During this process, a number of oxidation-reduction reactions occur and lead to the generation of a proton gradient. 

5. How does aerobic and anaerobic respiration differ in plants?

Aerobic respiration in plants occurs in the presence of oxygen, fully oxidizing glucose into CO₂ and H₂O, primarily in mitochondria, with a high energy output. Anaerobic respiration occurs without oxygen, partially breaking down glucose into ethanol and CO₂, mainly in the cytoplasm, with a lower energy output.

6. What is glycolysis, and where does it occur in plant cells?

Glycolysis is the process by which glucose is converted into pyruvate. It occurs in the cytoplasm of plant cells and is a common pathway for both aerobic and anaerobic respiration.

7. Explain the Krebs cycle in respiration with key steps.

The Krebs cycle (or citric acid cycle) occurs in the mitochondrial matrix and involves the breakdown of acetyl-CoA into CO₂, NADH, FADH₂, and ATP. Key steps include:

  • Decarboxylation: Acetyl-CoA enters the cycle by combining with oxaloacetate to form citrate.
  • Isomerization: Citrate is converted into isocitrate.
  • Oxidation: Isocitrate is oxidized to form α-ketoglutarate, producing NADH and CO₂.
  • Decarboxylation: α-Ketoglutarate is converted into succinyl-CoA, releasing another CO₂ and producing NADH.
  • Oxidation: Succinyl-CoA is converted into succinate, producing FADH₂.
  • Oxidation: Succinate is converted into fumarate, producing FADH₂.
  • Hydration: Fumarate is hydrated to form malate.
  • Oxidation: Malate is oxidized to form oxaloacetate, producing NADH.
8. How is electron transport system (ETS) involved in plant respiration?

The electron transport system (ETS) is crucial in aerobic respiration, occurring in the mitochondrial inner membrane. It uses electrons from NADH and FADH₂ to generate a proton gradient, which drives ATP synthesis through oxidative phosphorylation.

9. What are the end products of fermentation in plants?

The end products of fermentation (anaerobic respiration) in plants are primarily ethanol and carbon dioxide.

10. Why is the respiratory quotient (RQ) important in plant respiration?

The respiratory quotient (RQ) is important because it helps determine the type of substrate being respired and the efficiency of respiration. An RQ of 1 indicates carbohydrate respiration, while values less than 1 suggest fat or protein respiration.

11. What is the role of ATP in respiration, and how is it synthesized?

ATP is the primary energy currency of the cell. It is synthesized through substrate-level phosphorylation in glycolysis and oxidative phosphorylation in the electron transport chain.

12. How does the mitochondria function as the powerhouse of the cell in plants?

Mitochondria are the powerhouses of the cell because they generate most of the ATP during aerobic respiration through the Krebs cycle and electron transport chain.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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