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NCERT Exemplar Class 11 Chemistry solutions chapter 1 Some Basic Concepts of Chemistry provides detailed explanations on the importance of some of the basic concepts and laws of Chemistry. These laws include Avogadro’s Law, Law of Conservation of Mass, and many more. NCERT Exemplar Class 11 Chemistry chapter 1 solutions have been drafted by the experts in such a way that anyone who goes through it gets a deep insight into the topics related to the basic terms used in Chemistry. The experts have provided solutions for numerous questions in a detailed step-by-step process to ensure understanding of the students on the various topics covered.
JEE Main Scholarship Test Kit (Class 11): Narayana | Physics Wallah | Aakash | Unacademy
NEET Scholarship Test Kit (Class 11): Narayana | Physics Wallah | Aakash | ALLEN
Scholarship Test: Vidyamandir Intellect Quest (VIQ)
Question:1
Answer:
The answer is the option (ii) Results of student A are both precise and accurate.
Explanation: First, we calculate, the average of both the readings of student A and B. Student A's average is 3.00, and student B's average is also 3.00. The correct reading of the mass is 3.00g. Therefore, both the students have gotten an average value close to the correct value and are accurate. But student A's values differ only by 0.02 and are precise while B's readings are not close to each other and differ by 0.1, and thus are not precise.
Therefore, A has the readings which are both precise and accurate.
Question:2
A measured temperature on Fahrenheit scale is 200 °F. What will this reading be on Celsius scale?
(i) 40 °C
(ii) 94 °C
(iii) 93.3 °C
(iv) 30 °C
Answer:
Question:3
What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?
(i) 4 mol L-1
(ii) 20 mol L-1
(iii) 0.2 mol L-1
(iv) 2 mol L-1
Answer:
Question:4
If 500 mL of a 5M solution is diluted to 1500 mL, what will be the molarity of the solution obtained?
(i) 1.5 M
(ii) 1.66 M
(iii) 0.017 M
(iv) 1.59 M
Answer:
Question:5
The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms?
(i) 4 g of He
(ii) 46g Na
(iii) 0.40 g of Ca
(iv) 12g He
Answer:
Question:6
If the concentration of glucose in blood is 0.9 g L-1, what will be the molarity of glucose in blood?
(i) 5 M
(ii) 50 M
(iii) 0.005 M
(iv) 0.5 M
Answer:
The answer is the option (iii) 0.005 MQuestion:7
What will be the molality of the solution containing 18.25 g of HCI gas in 500 g of water?
(i) 0.1 m
(ii) 1M
(iii) 0.5 m
(iv) 1m
Answer:
The answer is the option (iv) 1mQuestion:8
One mole of any Substance contains of Atoms/molecules of present in the 100 mL of 0.02M solution is
(i) molecules
(ii) molecules
(iii) molecules
(iv) molecules
Answer:
Question:9
What is the mass percent of carbon in carbon dioxide?
(i) 0.034%
(ii) 27.27%
(iii) 3.4%
(iv) 28.7%
Answer:
The answer is the option (ii) 27.27%
Explanation:Question:10
The empirical formula and molecular mass of a compound are and 180 g respectively. What will be the molecular formula of the compound?
(i)
(ii)
(iii)
(iv)
Answer:
The answer is the option (iii)Question:11
If the density of a solution is 3.12 g mL-1, the mass of 1.5 mL solution in significant figures is _______.
(i) 4.7g
(ii) 4680 × 10-3 g
(iii) 4.680g
(iv) 46.80g
Answer:
Question:12
Which of the following statements about a compound is incorrect?
(i) A molecule of a compound has atoms of different elements.
(ii) A compound cannot be separated into its constituent elements by physical methods of separation.
(iii) A compound retains the physical properties of its constituent elements.
(iv) The ratio of atoms of different elements in a compound is fixed.
Answer:
The answer is the option (iii) A compound retains the physical properties of its constituent elements.Question:13
Which of the following statements is correct about the reaction given below:
(i) Total mass of iron and oxygen in reactants = total mass of iron and oxygen in product therefore it follows Law of conservation of mass.
(ii) Total mass of reactants = total mass of product; therefore, Law of multiple proportions is followed.
(iii) Amount of can be increased by taking any one of the reactants (iron or oxygen) in excess.
(iv) Amount of produced will decrease if the amount of any one of the reactants (iron or oxygen) is taken in excess.
Answer:
Question:14
Which of the following reactions is not correct according to the law of conservation of mass.
(i)
(ii)
(iii)
(iv)
Answer:
The answer is the option (ii)
Explanation:
Again, following the Law of energy, the number of atoms on the reactant side should be equal to the product side. Option (ii) does not follow the rule.
Question:15
Which of the following statements indicates that Law of multiple proportion is being followed?
(i) Sample of carbon dioxide taken from any source will always have carbon and oxygen in the simple ratio 1:2,
(ii) Carbon forms two oxides namely and . where masses of oxygen which combine with fixed mass of carbon are in the simple ratio 2:1.
(iii) When magnesium burns in oxygen, the amount of magnesium taken for the reaction is equal to the amount of magnesium in magnesium oxide formed.
(iv) At constant temperature and pressure 200 mL of hydrogen will combine with 100 mL oxygen to produce 200 mL of water vapour.
Answer:
Question:16
One mole of oxygen gas at STP is equal to ________
(i) molecules of oxygen
(ii) atoms of oxygen
(iii) 16 g of oxygen
(iv) 32 g of oxygen
Answer:
The answer are the options (i) and (iv)Question:17
Sulphuric acid reacts with sodium hydroxide as follows :
When 1L of 0.1M sulphuric acid solution is allowed to react with 1L of 0. 1M sodium hydroxide solution, the amount of sodium sulphate and its molarity in the solution obtained is
(i) 0.1 mol L-1
(ii) 7.10 g
(iii) 0.025 mol L-1
(iv) 3.55 g
Answer:
Question:18
Which of the following pairs have the same number of atoms ?
(i) 16 g of (g) and 4 g of (g)
(ii) 16 g of and 44 g of
(iii) 28 g of and 32 g of
(iv) 12 g of C (s) and 23 g of Na(s)
Answer:
The answer are the options (iii) and (iv)Question:19
Which of the following solutions have the same concentration?
(i) 20 g of NaOH in 200 mL of solution
(ii) 0.5 mole of KCl in 200 mL of solution
(iii) 40 g of NaOH in 100 mL of solution
(iv) 20 g Of KOH in 200 mL of solution
Answer:
The answer are the options (i) and (ii) mol of NaOH
(ii) Molar concentration Of NaOH
as 200 mL = 0.2 L
Molar concentration of KCl =
Question:20
16 g of oxygen has same of molecules as in
(i) 16 g of CO
(ii) 28 g of
(iii) 14 g of
(iv)) 1.0 g of
Answer:
Question:21
Which of the following terms are unitless?
(i) Molality
(ii) Molarity
(iii) Mole fraction
(iv) Mass percent
Answer:
The answer are the options (iii) and (iv)Question:22
One of the Statements of Dalton 's atomic theory is given below; "Compounds are formed when atoms of different elements combine in a fixed ratio". Which of the following laws is not related to this statement?
(i) Law of conservation of mass
(ii) Law Of definite proportions
(iii) Law of multiple proportions
(iv) Avogadro's Law
Answer:
The answer are the options (i) and (iv)Question:23
What will be the mass of one atom of C-12 in grams?
Answer:
Question:24
How many significant figures should be present in the answer of the following calculations?
Answer:
has 2 significant figures.Question:25
What is the symbol for SI unit of mole? How is the mole defined?
Answer:
Question:26
What is the difference between molality and molarity?
Answer:
Question:27
Calculate the mass percent of calcium, phosphorus and oxygen in calcium Phosphate;
Answer:
Question:28
Answer:
The Law being obeyed in this experiment is Gay Lussac's Law of Gaseous Volumes. The Law states, gases react with each other in a simple ratio by volume, provided the gases are maintained at a constant temperature and pressure.Question:29
Answer:
(a) Yes, the statement is true.Question:30
Calculate the average atomic mass of hydrogen using the following data:
Isotope | % Natural Abundance | Molar Mass |
1H | 99.985 | 1 |
2H | 0.015 | 2 |
Answer:
Average atomic mass =Question:31
Given that 65.3 g of Zn reacts with HCI to form 22.7 of H2(g)Question:32
The density of 3 molal solutions of NaOH is 1.110 g mL-1 . Calculate the molarity of the solution.
Answer:
Question:34
As per information given in the question, Mass of NaOH = 4gQuestion:35
Answer:
Question:36
Column I | Column II |
A. 88 g of CO2 | a. 0.25 mol |
B. 6.022 x 1023 molecules of H2O | b. 2 mol |
C. 5.6 litres of O2 at STP | c. 1 mol |
D. 96 g of O2 | d. 6.022 x 1023 molecules |
E. 1 mole of any gas | e. 3 mol |
Answer:
i) – b
ii) – c
iii) – a
iv) - e
v) – d
Question:37
Match the following physical quantities with units
Column I (Physical) | Column II (Unit) |
(i) Molarity | a. g mL-1 |
(ii) Mole fraction | b. mol |
(iii) Mole | c. Pascal |
(iv) Molality | d. Unitless |
(v) Pressure | e. mol L-1 |
(vi) Luminous intensity | f. Candela |
(vii) Density. | g. mol kg-1 |
(viii) Mass | h. N m-1 |
i. kg |
Answer:
(i) – eQuestion:38
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): The empirical mass of ethene is half of its molecular mass.
Reason (R): The empirical formula represents the simplest whole number ratio of various atoms present in a compound.
(i) Both A and R are true, and R is the correct explanation of A.
(ii) A is true but R is false.
(iii) A is false but R is true.
(iv) Both A and R are false.
Answer:
Question:39
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): One atomic mass unit is defined as one twelfth of the mass of one carbon- 12 atom.
Reason (R) : Carbon-12 isotope is the most abundant isotope of carbon and has been Chosen as standard.
(i) Both A and R are true, and R is the Correct explanation Of A.
(ii) Both A and R are true, but R is not the correct explanation of A
(iii) A is true but R is false.
(iv) Both A and R are false.
Answer:
The answer is the option (ii) Both A and R are true, but R is not the correct explanation of A.Question:40
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): Significant figures for 0.200 is 3 whereas for 200 it is 1.
Reason (R): Zero at the end or right of a number are significant provided they are not on the right side of the decimal point.
(i) Both A and R are true and R is correct explanation of A.
(ii) Both A and R are true but R is not a correct explanation of A.
(iii) A is true but R is false.
(iv) Both A and R are false.
Answer:
Question:41
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): Combustion Of 16 g Of methane, gives 18 g Of water.
Reason (R): In the combustion of methane. water is one of the products.
(i) Both A and R are true but R is not the Correct explanation Of A.
(ii) A is true but R is false.
(iii) A is false but R is true.
(iv) Both A and R are false.
Answer:
Question:42
Answer:
Question:43
Answer:
Number of moles of HCI=Question:44
Answer:
The Law of multiple proportions states that "If two elements can combine to form more than one compound, the mass of element combines with the fixed mass of the other element and is in the ratio of small whole numbers." For example, hydrogen reacts with oxygen to form water andQuestion:45
Answer:
Applying the Law of multiple proportionsStudents preparing for their examinations can make use of the NCERT Exemplar Class 11 Chemistry solutions chapter 1 PDF download feature to download a PDF to prepare for their exams, as it covers many important topics which are asked in the competitive exams. NCERT Exemplar solutions for Class 11 Chemistry chapter 1 includes the following topics:
Importance of Chemistry
Nature of matter
Properties of matter and their measurement
The International System of Units (S.I)
Mass and weight
Uncertainty in measurement
Scientific notation
Significant figures
Dimensional Analysis
Laws of Chemical Combinations
Law of conservation of mass
Law of definite proportions
Law of Multiple Proportions
Gay-Lussac’s Law
Avogadro law
Dalton Atomic Theory
Atomic and Molecular masses
Average atomic Mass
Formula mass
Mole Concept and Molar Mass
Percentage composition
Empirical Formula
Stoichiometry and stoichiometric calculations
Limiting Reagents
Reactions in solutions
Through NCERT Exemplar Class 11 Chemistry solutions chapter 1 Some Basic Concepts of Chemistry students will learn the basic properties of matter and also about the various S.I units that can be used. All the laws and theories such as Dalton’s Atomic Theory and Avogadro Law among others have been explained in a detailed way to form a good base for the students. The students will also get to learn and solve numerical based on topics such as molecular weight, mass concentration, and mole concept among others which will be helpful if they are preparing for competitive exams and also for their class 12.
Chapter 3 Classification of Elements and Periodicity in Properties |
Chapter 12 Organic Chemistry – Some Basic Principles and Techniques |
Here are the important topics that the students must specifically learn in this chapter:
The students will get to learn about the various parameters to denote the strength of the solution such as Molarity, Normality, Molality and their important relations. The related numerical and their solutions are given in Class 11 Chemistry NCERT Exemplar solutions chapter 1.
NCERT Exemplar Class 11 Chemistry solutions chapter 1 also introduces important concepts such as Dilution law, Equivalence concept, and Stoichiometry and has exercises for the revision of students.
Students will study various laws of chemical combination like Law of Multiple Proportion, Law of Definite proportion.
Chapter-1 - Some Basic Concepts of Chemistry
Chapter-2 - Structure of Atom
Chapter-3 - Classification of Elements and Periodicity in Properties
Chapter-4 - Chemical Bonding and Molecular Structure
Chapter-5 - States of Matter
Chapter-6 - Thermodynamics
Chapter-7 - Equilibrium
Chapter-8 - Redox Reaction
Chapter-9 - Hydrogen
Chapter-10 - The S-Block Elements
Chapter-11 - The P-Block Elements
Chapter-12 - Organic chemistry- some basic principles and techniques
Chapter-14 - Hydrocarbons
Chapter-15 - Environmental Chemistry
Read more NCERT Solution subject wise -
Also, Read NCERT Notes subject wise -
Also Check NCERT Books and NCERT Syllabus here:
Yes, the concepts are given in an easy and detailed way for the readers to understand better.
It is an important chapter from the competition point of view. The questions regarding molarity, molality etc. are frequently asked.
For a better understanding of any concept/ chapter, one should solve all the exercises given. It helps in self-evaluation.
Yes, NCERT Exemplar Solutions for Class 11 Chemistry Chapter 1 covers all the important topics.
Application Date:09 September,2024 - 14 November,2024
Application Date:09 September,2024 - 14 November,2024
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Admit Card Date:04 October,2024 - 29 November,2024
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