Tallentex 2025 - ALLEN's Talent Encouragement Exam
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The multiplication table of 56 provides multiples of 56 up to 10 times, aiding in the quick verification of multiplication problems. It can be built using multiplication or repeated addition of 56 and is a useful tool for improving maths speed and accuracy.
The phrase 'Table of 56' refers to the result of adding 56 by itself 'n' times. Additionally, the table of 56 can also be written by multiplying 56 by natural numbers starting from 1.
Fifty-Six times One is equal to Fifty-Six
Fifty-Six times Two is equal to One Hundred And Twelve
Fifty-Six times Three is equal to One Hundred And Sixty-Eight
Fifty-Six times Four is equal to Two Hundred And Twenty-Four
Fifty-Six times Five is equal to Two Hundred And Eighty
Fifty-Six times Six is equal to Three Hundred And Thirty-Six
Fifty-Six times Seven is equal to Three Hundred And Ninety-Two
Fifty-Six times Eight is equal to Four Hundred And Forty-Eight
Fifty-Six times Nine is equal to Five Hundred And Four
Fifty-Six times Ten is equal to Five Hundred And Sixty
Here is a graphic to help you comprehend the multiplication table of 56:
56 | × | 1 | = | 56 |
56 | × | 2 | = | 112 |
56 | × | 3 | = | 168 |
56 | × | 4 | = | 224 |
56 | × | 5 | = | 280 |
56 | × | 6 | = | 336 |
56 | × | 7 | = | 392 |
56 | × | 8 | = | 448 |
56 | × | 9 | = | 504 |
56 | × | 10 | = | 560 |
56 | × | 11 | = | 616 |
56 | × | 12 | = | 672 |
56 | × | 13 | = | 728 |
56 | × | 14 | = | 784 |
56 | × | 15 | = | 840 |
56 | × | 16 | = | 896 |
56 | × | 17 | = | 952 |
56 | × | 18 | = | 1008 |
56 | × | 19 | = | 1064 |
56 | × | 20 | = | 1120 |
1. Find the value of 56 x 5 + 10.
Solution:
\begin{equation}
56 \times 5 + 10
= (56 \times 5) + 10 [BODMAS\; \; rule]
= 280 + 10
= 290
\end{equation}
2. If 19 notebooks are bought by Sam for Rs. 1064. Then what is the cost of each notebook?
Solution: Given,
Number of notebooks bought = 19
Cost of 15 notebooks = Rs. 1064
Cost of each notebook =
\begin{equation}
1064/19 = 56
\end{equation}
Therefore, each notebook will cost Rs. 56.
3. Each of the 45 folders contains 56 sheets of paper. What is the total number of sheets of paper?
Solution:
If one folder has 56 sheets of pages, we can easily calculate how many total sheets of paper there are by using the following table:
\begin{equation}
45 \times 56=2520
\end{equation}
2520 is the total number of sheets of paper in 45 folders.
4. The capacity of a drum is 56 litres of milk. How much milk can be collected in eight drums of this size?
Solution: The total litres of milk
\begin{equation}
56 \times 8 = 448
\end{equation}
448 litres of milk can be collected in 8 drums of this capacity.
5. A customer buys 4 kg of sugar every day. How many kilos of sugar will the customer buy in 56 days?
Solution:
If the customer goes to the market every day and buys 4 kg of sugar, we can easily calculate how much sugar he will buy in 56 days by doing the following:
\begin{equation}
56 \times 4= 220
\end{equation}
220 kgs of sugar will be bought in total after 56 days.
5. There are twelve erasers in a box. How many erasers are in 56 boxes?
Solution: With the help of 56 tables we will get to know
\begin{equation}
56 \times 12= 672
\end{equation}
There are 672 erasers in 56 boxes.
The first ten multiples of 56 are 56, 112, 168, 224, 280, 336, 392, 448, 504, and 560. Adding the multiples,
\begin{equation}
56 + 112 + 168 + 224 + 280 + 336 + 392 + 448 + 504 + 560 = 3080.
\end{equation}
Thus, the sum is 3080.
The Least Common Multiple (LCM) is a technique for determining the least common multiple of two or more integers. A common multiple is a number that is the product of two or more numbers.
The least common factor or multiple of any two or more supplied integers is denoted by LCM.
There are just a few multiples of 56: 56, 112, 168, 224.....
There are just a few multiples of 28: 28, 56, 84, 112...
The sum of the common multiple of 56 and 28 is 56.
As a result, the LCM of 56 and 28 is 56.
56 is a composite number as it has more than two factors, which include 1, 2, 4, 7, 8, 14, 28, and 56. A prime number is a natural number greater than one that cannot be computed by multiplying two smaller natural numbers.
The factors of 56 are 1, 2, 4, 7, 8, 14, 28, and 56.
Sum =
\begin{equation}
1 + 2 + 4 + 7+8+14+28+56 = 120
\end{equation}
Therefore, 120 is the required sum.
Now, we need to find the average of the given factors.
Since, Average = (Sum of all values)/(Total number of values)
Hence,
Average =
\begin{equation}
120/8 = 15
\end{equation}
Thus, 15 is the required average.
56 is not a perfect square number, which means it does not have a natural integer as its square root. In decimal notation, the square root of 56 is represented as
\sqrt{56} = 7.483
The square root of 56 cannot be expressed as a p/q fraction, indicating that it is an irrational number.
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