NCERT Exemplar Class 12 Chemistry Solutions Chapter 2 Solutions

Access premium articles, webinars, resources to make the best decisions for career, course, exams, scholarships, study abroad and much more with

Plan, Prepare & Make the Best Career Choices

NCERT Exemplar Class 12 Chemistry Solutions Chapter 2 Solutions

Edited By Sumit Saini | Updated on Sep 16, 2022 04:11 PM IST | #CBSE Class 12th

NCERT exemplar Class 12 Chemistry solutions chapter 2 studies the formation of different types of solutions made out of combinations of two or more pure substances. This NCERT chapter mainly focuses on different kinds of liquid solutions focusing on binary compounds, their properties, and their formation and also the factors affecting them. NCERT exemplar Class 12 Chemistry chapter 2 solutions provide for different methods of showing the concentration of different solutions quantitatively as well as qualitatively. It also provides for various combinations of solid, liquid, and gas acting as solute and solvent along with examples for the same.

Latest: JEE Main high scoring chapters | JEE Main 10 year's papers

Recommended: NEET high scoring chapters

New: Aakash iACST Scholarship Test. Up to 90% Scholarship. Register Now

This Story also Contains

NCERT exemplar class 12 Chemistry solutions chapter 2: MCQ (Type 1)
Question:1
NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: MCQ (Type 2)
NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Short Answer Type
NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Matching Type
NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Assertion and Reason Type
NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Long Answer Type
Main Subtopics Covered in NCERT Exemplar Class 12 Chemistry Solutions Chapter 2 Inverse Trigonometric Functions
NCERT Exemplar Class 12 Chemistry Solutions Chapter 2 Inverse Trigonometric Functions-What will the students learn from?
NCERT Exemplar Class 12 Chemistry Solutions
NCERT Class 12 Chemistry Chapter 2 Solutions Important Topics To Cover For Exams

NCERT exemplar Class 12 Chemistry solutions chapter 2 also provides mathematical formulas for calculating the percentage, mole fraction, molarity, morality of different compounds with the help of illustrations. Class 12 Chemistry NCERT exemplar solutions chapter 2 also gives an insight into the concept of solubility of different compounds, the factors affecting the solubility such as temperature, mole fraction, and partial pressure with reference to Henry’s Law.
Also, check - NCERT Solutions for Class 12, other subjects

Apply to Aakash iACST Scholarship Test 2024

Applications for Admissions are open.

Apply Now

NCERT exemplar class 12 Chemistry solutions chapter 2: MCQ (Type 1)

Question:1

Which of the following units is useful in relating the concentration of a solution with its vapour pressure?
(i) mole fraction
(ii) parts per million
(iii) mass percentage
(iv) molality
Answer:

The answer is the option (i) Vapour pressure and the concentration (mole fraction) of solution are related. Raoult’s law states that the vapour pressure $(p_{A})$ of a component is directly proportional to the mole fraction $(x_{A})$ of the component.
$p_{x}\propto x_{A}$
where, $x_{A}=\frac{n_{A}}{n_{A}+n_{B}}$

Question:2

On dissolving sugar in water at room temperature solution feels cool to touch. Under which of the following cases dissolution of sugar will be most rapid?
(i) Sugar crystals in cold water.
(ii) Sugar crystals in hot water.
(iii) Powdered sugar in cold water.
(iv) Powdered sugar in hot water.
Answer:

The answer is the option (iv).

Dissolution is an endothermic process, which is why the solution is cool to touch. Also, powdered sugars have a higher surface area than sugar crystals which further promotes dissolution.

Question:3

At equilibrium the rate of dissolution of a solid solute in a volatile liquid solvent is __________.
(i) less than the rate of crystallisation
(ii) greater than the rate of crystallisation
(iii) equal to the rate of crystallisation
(iv) zero
Answer:

The answer is the option (iii). The rate of dissolution of solid solute is equal to the rate of crystallisation at equilibrium.

Question:4

A beaker contains a solution of a substance ‘A’. Precipitation of substance ‘A’ takes place when a small amount of ‘A’ is added to the solution. The solution is _________.
(i) saturated
(ii) supersaturated
(iii) unsaturated
(iv) concentrated
Answer:

The answer is the option (ii). Adding a small amount of solute in an already saturated solution will make the solution supersaturated and will lead to the precipitation of the solute.

Question:5

The maximum amount of a solid solute that can be dissolved in a specified amount of a given liquid solvent does not depend upon ____________.
(i) Temperature
(ii) Nature of solute
(iii) Pressure
(iv) Nature of solvent
Answer:

The answer is the option (iii). Solids don’t compress significantly on application of pressure and thus have no impact to its solubility in solvent.

Question:6

Low concentration of oxygen in the blood and tissues of people living at high altitude is due to ____________.
(i) low temperature
(ii) low atmospheric pressure
(iii) high atmospheric pressure
(iv) both low temperature and high atmospheric pressure
Answer:

The answer is the option (ii). Due to lower atmospheric pressure at high altitude, oxygen concentration is less in the blood and tissues of the people living there.

Question:7

Considering the formation, breaking and strength of hydrogen bond, predict which of the following mixtures will show a positive deviation from Raoult’s law?
(i) Methanol and acetone.
(ii) Chloroform and acetone.
(iii) Nitric acid and water.
(iv) Phenol and aniline
Answer:

The answer is the option (i). Methanol has hydrogen bonds. When acetone is mixed with it, some of the bonds break weakening the methanol-methanol interaction. This is why they exhibit a positive deviation.

Question:8

Colligative properties depend on ____________.
(i) the nature of the solute particles dissolved in solution.
(ii) the number of solute particles in solution.
(iii) the physical properties of the solute particles dissolved in solution.
(iv) the nature of solvent particles
Answer:

The answer is the option (ii). Number of solute particles determines its colligative properties.

Question:9

Which of the following aqueous solutions should have the highest boiling point?
(i) $1.0 M NaOH$
(ii) $1.0 M Na_2SO_4$
(iii) $1.0 M NH_4NO_3$
(iv) $1.0 M KNO_3$

Answer:

The answer is the option (ii). As $1.0 M Na_2SO_4$ furnishes the maximum number of ions, it should have the highest boiling poin

Question:10

The unit of ebulioscopic constant is _______________.
(i) $K kg mol^{-1} or K (molality)^{-1}$
(ii) $mol kg K^{-1} or K^{-1}(molality)$
(iii) $kg mol^{-1} K^{-1} or K^{-1}(molality)^{-1}$
(iv) $K mol kg^{-1} or K (molality)$
Answer:

The answer is the option (i)
$K_{b}=\frac{\Delta T_{b}}{m}=\frac{K}{mol kg^{-1}}$
The unit of ebullioscopic constant is $K kg mol^{-1} or K (molality)^{-1}$

Question:11

In comparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M $MgCl_2$ solution is _____________.
(i) the same
(ii) about twice
(iii) about three times
(iv) about six times
Answer:

The answer is the option (iii). Colligative properties only depend on the number of solute. While 0.01 M solution of glucose does not ionize, 0.01 M $MgCl_2$ solution ionizes to produce a single $Mg^{2+}$ ion and $2 Cl^{-}$ ions.

Question:12

An unripe mango placed in a concentrated salt solution to prepare pickle, shrivels because _____________.
(i) it gains water due to osmosis.
(ii) it loses water due to reverse osmosis.
(iii) it gains water due to reverse osmosis.
(iv) it loses water due to osmosis.
Answer:

The answer is the option (iv). Due to osmosis, Water inside mango (lower concentration) moves outside in a concentrated salt solution (higher concentration).

Question:13

At a given temperature, osmotic pressure of a concentrated solution of a substance _____________.
(i) is higher than that at a dilute solution.
(ii) is lower than that of a dilute solution.
(iii) is same as that of a dilute solution.
(iv) cannot be compared with an osmotic pressure of a dilute solution.
Answer:

The answer is the option (i).
At a given temperature, osmotic pressure of a concentrated solution of a substance is higher than that at a dilute solution.

Question:14

Which of the following statements is false?
(i) Two different solutions of sucrose of the same molality prepared in different solvents will have the same depression in freezing point.
(ii) The osmotic pressure of a solution is given by the equation $\pi = CRT$ (where C is the molarity of the solution).
(iii) Decreasing order of osmotic pressure for 0.01 M aqueous solutions of barium chloride, potassium chloride, acetic acid and sucrose is $BaCl_2> KCl > CH_3COOH > sucrose.$
(iv) According to Raoult’s law, the vapour pressure exerted by a volatile component of a solution is directly proportional to its mole fraction in the solution.
Answer:

The answer is the option (i). Colligative properties depend on molarity of solute and the solvent. Two different solvents (with same molality of sucrose) will have different freezing points

Question:15

The values of Van’t Hoff factors for KCl, NaCl and $K_2SO_4$ , respectively, are
_____________.
(i) 2, 2 and 2
(ii) 2, 2 and 3
(iii) 1, 1 and 2
(iv) 1, 1 and 1
Answer:

The answer is the option (ii). While KCl and NaCl ionize to give 2 ions, $K_2SO_4$ gives 3 ions. So, van’t Hoff factors for KCl, NaCl and K2SO4 are 2,2 and 3 respectively

Question:16

Which of the following statements is false?
(i) Units of atmospheric pressure and osmotic pressure are the same.
(ii) In reverse osmosis, solvent molecules move through a semipermeable membrane from a region of lower concentration of solute to a region of higher concentration.
(iii) The value of molal depression constant depends on the nature of the solvent.
(iv) Relative lowering of vapour pressure is a dimensionless quantity.
Answer:

The answer is the option (ii). Solvent molecules move from a solution containing high concentration of solute to one with a low concentration of solute.

Question:17

Value of Henry’s constant K_H ____________.
(i) increases with increase in temperature.
(ii) decreases with increase in temperature.
(iii) remains constant.
(iv) first increases then decrease.
Answer:

The answer is the option (i). There is an increase in the value of Henry’s constant with increase in temperature.

Question:18

The value of Henry’s constant K_H is _____________.
(i) greater for gases with higher solubility.
(ii) greater for gases with lower solubility.
(iii) constant for all gases.
(iv) not related to the solubility of gases.
Answer:

The answer is the option (ii). Gases having a lower solubility have a higher $K_H$ .

Question:19

Consider Figure and mark the correct option.
(i) water will move from the side (A) to side (B) if a pressure lower than the osmotic pressure is applied on piston (B).
(ii) water will move from the side (B) to side (A) if a pressure greater than the osmotic pressure is applied on piston (B).
(iii) water will move from the side (B) to side (A) if a pressure equal to osmotic pressure is applied on piston (B).
(iv) water will move from the side (A) to side (B) if pressure equal to osmotic pressure is applied on the piston (A).

Answer:

The answer is the option (ii). If the piston above B applies a pressure exceeding the osmotic pressure, water will move from concentrated solution (side B) to Fresh Water (side A).

Question:20

We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentrations 0.1M, 0.01M and 0.001M, respectively. The value of Van’t Hoff factor for these solutions will be in the order______.
(i) i_A< i_B< i_C
(ii) i_A> i_B> i_C
(iii) i_A= i_B= i_C
(iv) i_A<i_B> i_C
Answer:

The answer is the option (iii). Due to complete dissociation of NaCl, the van’t Hoff factor will be the same for the three solutions.

Question:21

On the basis of information given below mark the correct option.
Information:
(A) In bromoethane and chloroethane mixture intermolecular interactions of A–A and B–B type are nearly the same as A–B type interactions.
(B) In ethanol and acetone mixture A–A or B–B type intermolecular interactions are stronger than A–B type interactions.
(C) In chloroform and acetone mixture A–A or B–B type intermolecular interactions are weaker than A–B type interactions.
(i) Solution (B) and (C) will follow Raoult’s law.
(ii) Solution (A) will follow Raoult’s law.
(iii) Solution (B) will show a negative deviation from Raoult’s law.
(iv) Solution (C) will show a positive deviation from Raoult’s law
Answer:

The answer is the option (ii). In a Bromoethane (A) and Chloroethane (B) mixture, the interactions A-A, B-B and A-B are nearly equal, so the solution will be nearly ideal and thus follow Raoult’s law.

Question:22

Two beakers of capacity 500 mL were taken. One of these beakers, labeled as “A”, was filled with 400 mL water whereas the beaker labelled “B” was filled with 400 mL of 2 M solution of NaCl. At the same temperature, both the beakers were placed in closed containers of the same material and same capacity as shown in Figure.
At a given temperature, which of the following statement is correct about the vapour pressure of pure water and that of NaCl solution.
(i) the vapour pressure in container (A) is more than that in a container (B).
(ii) the vapour pressure in container (A) is less than that in the container (B).
(iii) vapour pressure is equal in both containers.
(iv) the vapour pressure in container (B) is twice the vapour pressure in container (A).

Answer:

The answer is the option (i). Vapour pressure of container (B) is lower as NaCl being a non-volatile solute reduces the vapour pressure.

Question:23

If two liquids A and B form minimum boiling azeotrope at some specific composition then _______________.
(i) A–B interactions are stronger than those between A–A or B–B.
(ii) vapour pressure of solution increases because more number of molecules of liquids A and B can escape from the solution.
(iii) vapour pressure of solution decreases because less number of molecules of only one of the liquids escape from the solution.
(iv) A–B interactions are weaker than those between A–A or B–B.
Answer:

The answer is the option
(i) A–B interactions are stronger than those between A–A or B–B.

Question:24

4L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is _____________.
(i) 0.004
(ii) 0.008
(iii) 0.012
(iv) 0.016
Answer:

The answer is the option (iv)

$M=\frac{n}{}V=0.02 =\frac{n}{4} \;or\; n=0.08$
$M= \frac{n}{ \text{(Mass of water in Kg)} }= \frac{0.08}{}5 =0.016$

Question:25

On the basis of information given below mark the correct option.
Information: On adding acetone to methanol some of the hydrogen bonds between methanol molecules break.
(i) At specific composition, methanol-acetone mixture will form minimum boiling azeotrope and will show positive deviation from Raoult’s law.
(ii) At specific composition, methanol-acetone mixture forms maximum boiling azeotrope and will show positive deviation from Raoult’s law.
(iii) At specific composition, methanol-acetone mixture will form minimum boiling azeotrope and will show negative deviation from Raoult’s law.
(iv) At specific composition, methanol-acetone mixture will form maximum boiling azeotrope and will show negative deviation from Raoult’s law.
Answer:

The answer is the option (ii) At specific composition methanol-acetone mixture forms maximum boiling azeotrope and will show positive deviation from Raoult’s law.

Question:26

K_H value for Ar(g), CO₂(g), HCHO (g) and CH₄(g) are 40.39, 1.67, $1.83\times 10^{-5}$ and 0.413 respectively.
Arrange these gases in the order of their increasing solubility.
(i) $HCHO < CH_4< CO_2 < Ar$
(ii) $HCHO < CO_2< CH_4< Ar$
(iii) $Ar < CO_2< CH_4< HCHO$
(iv) $Ar < CH_4 < CO_2 < HCHO$
Answer:

The answer is the option (iii) Solubility decreases with increasing value of KH. The increasing order of solubility of the gases is as follows: $Ar < CO_2< CH_4< HCHO$

NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: MCQ (Type 2)

Question:27

Which of the following factor(s) affect the solubility of a gaseous solute in the a fixed volume of liquid solvent?
(a) nature of solute (b) temperature (c) pressure
(i) (a) and (c) at constant T
(ii) (a) and (b) at constant P
(iii) (b) and (c) only
(iv) (c) only

Answer:

The answer is the option (i, ii) solubility of a gaseous solute depends on nature of solute, pressure and temperature.

Question:28

Intermolecular forces between two benzene molecules are near to same strength as those between two toluene molecules. For a mixture of benzene and toluene, which of the following are not true?
(i) $\Delta _{mix} H = zero$
(ii) $\Delta _{mix} V = zero$
(iii) These will form a minimum boiling azeotrope.
(iv) These will not form the ideal solution.
Answer:

The answer is the option (iii, iv) As interactions in a Benzene and Toluene solution are nearly identical, they will form an ideal solution.
$\Delta _{mix} H = 0$ , $\Delta _{mix} V =0$

Question:29

Relative lowering of vapour pressure is a colligative property because _____________.
(i) It depends on the concentration of a non-electrolyte solute in a solution and does not depend on the nature of the solute molecules.
(ii) It depends on a number of particles of electrolyte solute in a solution and does not depend on the nature of the solute particles.
(iii) It depends on the concentration of a non-electrolyte solute in solution as well as on the nature of the solute molecules.
(iv) It depends on the concentration of an electrolyte or nonelectrolyte solute in solution as well as on the nature of solute molecules.

Answer:

The answer is the option (i, ii) Nature of solute particles is not a factor in determining the relative lowering of vapour pressure. It is only affected by the number of solute particles (non-electrolyte and electrolyte solutes)

Question:30

Van’t Hoff factor i is given by the expression _____________.
(i) i = Normal molar mass/Abnormal molar mass
(ii) i = Abnormal molar mass/ Normal molar mass
(iii) i= Observed colligative property/calculated colligative property
(iv) i = Calculated colligative property/ Observed colligative property
Answer:

The answer is the option (i,iii)
$i=\frac{\text{Normal molar mass}}{\text{Abnormal molar mass}}\; or\; i=\frac{\text{Observed colligative property}}{\text{Calculated colligative property}}$

Question:31

Isotonic solutions must have the same _____________.
(i) solute
(ii) density
(iii) elevation in boiling point
(iv) depression in freezing point

Answer:

The answer is the option (ii, iii)

Isotonic solutions must have the same
(ii) density
(iii) elevation in boiling point

Question:32

Which of the following binary mixtures will have the same composition in the liquid and vapour phase?
(i) Benzene – Toluene
(ii) Water-Nitric acid
(iii) Water-Ethanol
(iv) n-Hexane – n-Heptane

Answer:

The answer is the option (ii, iii) Water-Nitric acid and Water-Ethanol solutions have the same composition in liquid and vapour phases

Question:33

In isotonic solutions ________________.
(i) solute and solvent both are same.
(ii) osmotic pressure is the same.
(iii) solute and solvent may or may not be same.
(iv) a solute is always the same solvent may be different.
Answer:

The answer is the option (ii, iii) Osmotic pressure is the same for isotonic solutions.

Question:34

For a binary ideal liquid solution, the variation in total vapour pressure versus the composition of the solution is given by which of the curves?

Answer:

The answer is the option (i,iv) for ideal solution.
$p_1 \propto x_1$ and $p_2 \propto y_2$

Question:35

Colligative properties are observed when _____________.
(i) a non-volatile solid is dissolved in a volatile liquid.
(ii) a non-volatile liquid is dissolved in another volatile liquid.
(iii) a gas is dissolved in non-volatile liquid.
(iv) a volatile liquid is dissolved in another volatile liquid.
Answer:

The answer is the option (i, ii) Colligative properties can be observed on dissolution of a non-volatile solid or liquid in a volatile liquid

NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Short Answer Type

Question:36

Components of a binary mixture of two liquids A and B were being separated by distillation. After some time, separation of components stopped and the composition of the vapour phase became the same as that of a liquid phase. Both the components started coming in the distillate. Explain why this happened.
Answer:

As the composition of both the liquid and vapour phase is same and both components are coming in the distillate, this implies that they have formed an azeotropic mixture.

Question:37

Explain why on the addition of 1 mol of NaCl to 1 litre of water, the boiling point of water increases, while the addition of 1 mol of methyl alcohol to one litre of water decreases its boiling point.
Answer:

Boiling point of water increases on addition of NaCl, as it is a non-volatile solute and, hence, reduces the vapour pressure of water and increase thew boiling point. Unlike NaCl, Methyl alcohol is more volatile than water and thus increases the vapour pressure of water and reduces the boiling point.

Question:38

Explain the solubility rule “like dissolves like” in terms of intermolecular forces that exist in solutions.
Answer:

“Like dissolves like” means that a solute dissolves in a solvent if their intermolecular interactions are similar. In other words, we can say that polar solutes can dissolve in polar solvents and non-polar solutes can dissolve in non-polar solvents.

Question:39

Concentration terms such as mass percentage, ppm, mole fraction and molality are independent of temperature, however, molarity is a function of temperature. Explain.
Answer:

$\text{Molarity}=\frac{\text{number of moles of solute}}{\text{Volume of solution in litres} }$
Since, molarity is dependent on volume of the solution, it changes with temperature. The other concentration terms like mass percentage, ppm, mole fraction, molality involve moles or mass of components which are independent of temperature.

Question:40

What is the significance of Henry’s Law constant K_H?
Answer:

According to Henry’s law:
$p=K_H\times x$
$K_H=\frac{p}{}x$
Solubility of gas in a liquid decreases with increasing Henry’s law constant.

Question:41

Why are aquatic species more comfortable in cold water in comparison to warm water?
Answer:

For a given pressure, as the temperature decreases, the solubility of oxygen in water increases. This means that cold sea water has higher concentration of oxygen and aquatic species thrive more in cold water.

Question:42

(a) Explain the following phenomena with the help of Henry’s law.
(i) A painful condition known as bends.
(ii) Feeling of weakness and discomfort in breathing at high altitude.
(b) Why soda water bottle kept at room temperature fizzes on opening?
Answer:

(a)

Deep sea divers require compressed air for breathing under water, which has both $N_2$ and $O_2$ . In atmospheric conditions, $N_2$ isn’t soluble in blood, but at higher pressure (as you go deeper into the ocean, the pressure increases) it starts dissolving. When the diver comes back up, the pressure decreases and $N_2$ comes out of the body, leaving behind bubbles in the blood stream, which restrict the flow of blood affecting nerve impulses. In worse cases, these bubbles can burst the capillaries and not let $O_2$ reach the tissues. This condition, known as bends, is very painful and can even be life-threatening.
In lower pressure (at higher altitudes), $O_2$ exhibits a lower partial pressure, resulting in lower oxygen concentration in blood and tissues. This condition is known as anoxia and leads to climbers becoming weak and losing ability to think clearly.

(b) $CO_2$ isn’t very soluble in soft drinks at atmospheric pressure. So, to dissolve $CO_2$ in soft drinks, soda bottles are sealed under high pressure. However, when the bottle is opened, the pressure decreases suddenly and excess $CO_2$ fizzes out.

Question:43

Why is the vapour pressure of an aqueous solution of glucose lower than that of water?
Answer:

In pure liquid water, molecules of water cover the entire surface. When a non-volatile solute is dissolved in water, it replaces part of the surface water molecules. As a result, the number of solvent molecules which can escape also gets reduced and thus, the vapour pressure of the solution reduces.

Question:44

How does sprinkling of salt help in clearing the snow-covered roads in hilly areas? Explain the phenomenon involved in the process.
Answer:

Salt is spread over snow covered roads to lower water’s freezing point enough to melt the ice (snow). This leads to the snow melting away and clearing the road.

Question:45

What is a “semi-permeable membrane”?

Answer:

Semipermeable membrane are membranes which only permit the flow of solvent molecules, but not the solute molecules. Only the solvent molecules move across the semipermeable membrane during osmosis and Reverse osmosis.

Question:46

Give an example of a material used for making semipermeable membrane for carrying out reverse osmosis.
Answer:

For carrying out reverse osmosis cellulose acetate, potassium ferrocyanide, etc. are used as semipermeable membrane.

NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Matching Type

Question:47

Match the items given in Column I and Column II.

Column I	Column II
(i) Saturated solution	(a) Solution having the same osmotic pressure at a given temperature as that of the given solution
(ii) Binary solution	(b) A solution whose osmotic pressure is less than that of another.
(iii) Isotonic solution	(c) Solution with two components.
(iv)Hypotonic solution	(d) A solution which contains the maximum amount of solute that can be dissolved in a given amount of solvent at a given temperature.
(v) Solid solution	(e) A solution whose osmotic pressure is more than another.
(vi) Hypertonic solution	(f) A solution in the solid phase

ALLEN NEET Coaching

Ace your NEET preparation with ALLEN Online Programs

Apply

Aakash iACST Scholarship Test 2024

Get up to 90% scholarship on NEET, JEE & Foundation courses

Apply

Answer:

(i —> d), (ii —> c); (iii—> a); (iv —> b), (v —> f); (vi —> e)
i.Saturated solution: It is a solution where no more of the solute can be dissolved at the given temperature and pressure.
ii.Binary solution: It is a solution with two components.
iii.Isotonic solution: It is a solution having same osmotic pressure at a given temperature as that of given solution.
iv.Hypotonic solution: It is a solution whose osmotic pressure is lesser than that of a given solution.
v,Solid solution: It is a solution in solid phase.
vi.Hypertonic solution: It is a solution whose osmotic pressure is greater than that of a given solution

Question:48

Match the items given in Column I with the type of solutions given in Column II.

Column I	Column II
(i) Soda water	(a) A solution of the gas in solid
(ii) Sugar solution	(b) A solution of the gas in gas
(iii) German silver	(c) A solution of solid in liquid
(iv) Air	(d) A solution of solid in solid
(v) Hydrogen gas in palladium	(e) A solution of the gas in liquid
	(f) A solution of liquid in solid

Answer:

(i → e), (ii → c), (iii → d); (iv → b), (v → a)
i. Soda water: A solution of gas in $(CO_2)$ liquid(soft drink)
ii. Sugar solution: A solution of solid (sugar) in liquid (water)
iii. German silver: It is an alloy of Cu, Zn and Ni and a solid solution of solid in solid.
iv. Air: A solution of gas igas. Air is a mixture of various gases.
v. Hydrogen gas in palladium: Hydrogen gas in palladium is used as a reducing agent and is an example of solution of gas in solid.

Question:49

Match the laws given in Column I with expressions given in Column II.

Column I	Column II
(i) Raoult’s law	(a) $\Delta T_f= K_fm$
(ii) Henry’s law	(b) $\pi = CRT$
(iii) Elevation of boiling point	(c) $p = x_{1}P_1^0+ x_{2}P_2^0$
(iv) Depression in freezing point	(d) $\Delta T_b= K_bm$
(v) Osmotic pressure	(e) $p = K_H.x$

Answer:

(i) → (c) (ii) → (e) (iii) → (d) (iv) → (a) (v) → (b)
i.Raoult’s law: $p = x_{1}P_1^0+ x_{2}P_2^0$
ii. Henry’s law: $p = K_H.x$
iii. Elevation of boiling point: $\Delta T_b= K_bm$
iv. Depression in freezing point: $\Delta T_f= K_fm$
v. Osmotic pressure: $\pi = CRT$

Question:50

Match the terms given in Column I with expressions given in Column II.

Column I	Column II
(i) Mass percentage	(a) $\frac{Number \;of\; moles\; of\; the\; solute\; component}{Volume\; of \;solution \;in \; litres}$
(ii) Volume percentage	(b) $\frac{Number \;of \;moles\; of\; a\; component}{Total\; number\; of\; moles\; of\; all\; the\; components}$
(iii) Mole fraction	(c) $\frac{Volume\; of\; the\; solute\; component\; in \;solution}{Total\; volume \;of solution\;}\times 100$
(iv) Molality	(d) $\frac{Mass\; of\; the\; solute\; component\; in \;solution}{Total \;mass \;of \;the\; solution}\times 100$
(v) Molarity	(e) $\frac{Number\; of \;moles \;of\; the\; solute\; components}{Mass\; of \;solvent \;in\; kilograms}\times 100$

Answer:

(i → d), (ii → c), (iii →b), (iv → e), (v →a)

NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Assertion and Reason Type

Question:51

In the following questions, a statement of Assertion (A) followed by a statement of
Reason (R) is given. Choose the correct answer out of the following choices:
(a) Assertion and reason both are correct statements and reason is the correct explanation for Assertion.
(b) Assertion and reason both are correct statements but reason is not the correct explanation for Assertion.
(c) Assertion is correct statement but reason is wrong.
(d) Assertion and reason both are incorrect.
(e) Assertion is wrong but reason is correct.
Assertion (A): Molarity of a solution in liquid state changes with temperature.
Reason (R): The volume of a solution changes with change in temperature.
Answer:

The answer is the option (a) Molarity depends on volume, which changes with temperature. Hence, molarity also changes with change in temperature.

Question:52

In the following questions, a statement of Assertion (A) followed by a statement of
Reason (R) is given. Choose the correct answer out of the following choices:
(a) Assertion and reason both are correct statements and reason is the correct explanation for Assertion.
(b) Assertion and reason both are correct statements but reason is not the correct explanation for Assertion.
(c) Assertion is correct statement but reason is wrong.
(d) Assertion and reason both are incorrect.
(e) Assertion is wrong but reason is correct.
Assertion (A): When methyl alcohol is added to water, boiling point of water increases.
Reason (R): When a volatile solute is added to a volatile solvent, elevation in boiling point is observed.
Answer:

The answer is the option (d) Addition of a volatile solute to a volatile solvent increases vapour pressure and decreases boiling point. Methyl alcohol and water interaction are an example of the same.

Question:53

In the following questions, a statement of Assertion (A) followed by a statement of
Reason (R) is given. Choose the correct answer out of the following choices:
(a) Assertion and reason both are correct statements and reason is the correct explanation for Assertion.
(b) Assertion and reason both are correct statements but reason is not the correct explanation for Assertion.
(c) Assertion is correct statement but reason is wrong.
(d) Assertion and reason both are incorrect.
(e) Assertion is wrong but reason is correct.
Assertion (A): When NaCl is added to water, a depression in freezing point is observed.
Reason (R): The lowering of vapour pressure of a solution causes depression in the freezing point.
Answer:

The answer is the option (a) Addition of a non-volatile solute to a volatile solvent decreases vapour pressure and increases boiling point.

Question:54

In the following questions, a statement of Assertion (A) followed by a statement of
Reason (R) is given. Choose the correct answer out of the following choices:
(a) Assertion and reason both are correct statements and reason is correct explanation for Assertion.
(b) Assertion and reason both are correct statements but reason is not the correct explanation for Assertion.
(c) Assertion is correct statement but reason is wrong statement.
(d) Assertion and reason both are incorrect statements.
(e) Assertion is wrong statement but reason is correct statement.
Assertion (A): When a solution is separated from the pure solvent by a semipermeable membrane, the solvent molecules pass through it from pure solvent side to the solution side.
Reason (R): Diffusion of solvent occurs from a region of high concentration solution to a region of low concentration solution
Answer:

The answer is the option (b) Assertion and reason both are correct statements but reason is not the correct explanation for Assertion.

NCERT Exemplar Class 12 Chemistry Solutions Chapter 2: Long Answer Type

Question:55

Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?
(i) w/w (mass percentage)
(ii) x (mole fraction)
(iii) V/V (volume percentage)
(iv) M (Molarity)
(v) w/V (mass by volume percentage)
(vi) m (Molality)
(vii) ppm (parts per million)
Answer:

$\text{w/w(Mass percentage)}=\frac{\text{Mass of component in the solution}}{\text{Total mass of the solution}}\times 100$
$\text{V/V(Volume percentage)}=\frac{\text{Volume of component in the solution}}{\text{Total volume of the solution}}\times 100$
$\text{w/V (mass by Volume percentage)}=\frac{\text{Mass of the solute}}{\text{Total volume of the solution}}\times 100$
$\text{ppm (parts per million)}=\frac{\text{Number of parts of component}}{\text{Total number of parts of all components}}\times 10^{6}$
$\text{x( Mole fraction)}=\frac{\text{Number of moles of component}}{\text{Total number of moles of all components}}$
$\text{M (Molarity)}=\frac{\text{Moles of solute}}{\text{Volume of the solution in litre}}$
$\text{m (Molality)}=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}$

JEE Main Highest Scoring Chapters & Topics

Just Study 40% Syllabus and Score upto 100%

Download EBook

Mass percentage, ppm, mole fraction and molality are only dependent on mass or number of moles making them independent of temperature changes.

Question:56

Using Raoult’s law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions.
(a) $CHCl_3(l) \; \text{and} \;CH_2Cl_2(l)$
(b) $NaCl(s)\; \text{and}\;H_{2}O(l)$
Answer:

$p=p_A^ox_A+p_B^ox_B$
Where, $p_A^o,p_B^o$ are the vapour pressure of pure components (A) and (B)
And $x_{A}\text{and }x_{B}$ are the mole fractions of the components in the solution.

(b) On dissolving in water, the vapour pressure lowers. Vapour pressure of solution is:
$p=p^ox_A$
Where $x_{A}$ =mole fraction of solvent
$p^{0}$ =vapour pressure of pure solvent
p=vapour pressure of solution
Similarly,
$\frac{\Delta p}{p^o}=x_B$
$\Delta p=p^o-p$
$x_{B}$ =mole fraction of solute

Question:57

Explain the terms ideal and non-ideal solutions in the light of forces of interactions operating between molecules in liquid solutions.
Answer:

Ideal solutions: They obey Raoult’s law irrespective of the concentration. For an ideal solution,
$\Delta _{mix}H=0, \Delta _{mix}V=0$
$\text{A-B interactions}\approx \text{A-A interactions and B-B interactions}$
Non-ideal solutions: They don’t follow Raoult’s law over the entire range of concentration
Positive deviations: Vapour pressure is higher than the calculated values
$\Delta _{mix}H=+ve, \Delta _{mix}V=+ve$
A-B interactions < A-A interactions and B-B interactions
Negative deviations: Vapour pressure is lower than the calculated values
$\Delta _{mix}H=-ve, \Delta _{mix}V=-ve$
A-B interactions>A-A interactions and B-B interactions

Question:58

Why is it not possible to obtain pure ethanol by fractional distillation? What general name is given to binary mixtures which show deviation from Raoult’s law and whose components cannot be separated by fractional distillation? How many types of such mixtures are there?
Answer:

Azeotropes are solutions which have the same compositions of components in both the liquid and vapour phase and boil at a constant temperature. The components cannot be separated by fractional distillation as they have the same boiling point. There are two types of azeotropes

Minimum boiling azeotropes: They show large positive deviation from Raoult’s law (A-B interactions are weaker than A-A and B-B interactions), e.g., ethanol-water mixture
Maximum boiling azeotropes: They show large negative deviation from Raoult’s law (A-B interactions are stronger than A-A and B-B interactions) e.g., solution having composition 68% HNO₃ and 32% water by mass.

Question:59

When kept in water, raisin swells in size. Name and explain the phenomenon involved with the help of a diagram. Give three applications of the phenomenon.
Answer:

Raisins swell in water due to osmosis. Water moves from a place of lower concentration (Water holder) to higher concentration (Raisin) through the skin of raisin which acts as a semipermeable membrane.

Applications of the phenomenon

Water moves from soil to plant roots partly due to osmosis.
Preservation of meat against bacterial action by adding salt.
Preservation of fruits against bacterial action by adding sugar. Bacterium in canned fruit loses water through the process of osmosis, shrivels, and dies.
Reverse osmosis is used for desalination of water.

Question:60

Discuss biological and industrial importance of osmosis.
Answer:

Some of the biological and industrial importance of osmosis are as follows-

Osmosis is responsible for the circulation of water to all the body parts of animals
Water moves from soil to plant roots partly due to osmosis. Concentration of cell sap inside the root hair cells is higher compared to that of water present in the soil.
Water circulation inside the plant body from root to treetop is also because of osmosis.
Osmosis helps in growth of plants and germination of seeds.
Due to endosmosis, Red Blood Cells burst when they are placed in water.
Osmosis controls various functions of plants, e.g., stretching of leaves and flowers, opening, and closing of flowers.
Salt and sugar in pickles prevent the growth of bacteria and fungi by osmosis and thus, act as preservatives.
Endosmosis is responsible for the swelling of dead bodies under water.
Dried fruits and vegetables swell and return to their original form when placed in water. It is also due to the endosmosis of water.
Edema: Tissues become puffy when a person intakes an excess amount of salt.

Question:61

How can you remove the hard calcium carbonate layer of the egg without damaging its semipermeable membrane? Can this egg be inserted into a bottle with a narrow neck without distorting its shape? Explain the process involved.
Answer:

This can be achieved as under:

Take a mineral acid solution and put an egg inside it and leave it for 2 hours. Most of the outer shell will dissolve. Remove any remaining part with your fingers.
Take a saturated solution (hypertonic) and lace the egg in it for 3 hours. Egg’s size reduces as the egg shrivels due to osmosis.
Place the egg in a bottle with a narrow neck and fill water (hypotonic) in it. The egg will regain its shape.

Question:62

Why is the molar mass determined by measuring a colligative property in case of some solutes abnormal? Discuss it with the help of Van’t Hoff factor.
Answer:

Abnormal molecular masses are shown by the compounds which dissociate/associate in the solvent.

Association: Colligative properties depend on the number of particles in a solution. Certain compounds like benzoic acid or ethanoic acid dimerise in benzene due to hydrogen bonding resulting in the reduction of the number of particles and thus, solutes show lower colligative property.
Dissociation: Similarly, certain compounds like electrolytes (NaCl, KCl) etc dissociate into ions, increasing the number of particles, and thus, show higher value of colligative property.

Van’t Hoff introduced a factor to account for association or dissociation, known as Van’t Hoff factor.
$i=\frac{\text{Expected molar mass}}{\text{Abnormal molar mass}}$
$=\frac{\text{Observed colligative property}}{\text{Calculated colligative property}}$
$=\frac{\text{Total number of moles of particles after association or disaasociation}}{\text{Total number of moles of particles before association or disaccioation}}$

NCERT exemplar Class 12 Chemistry solutions chapter 2 provided here for the NCERT Books are very useful and detailed from the point of view of aiding practice, preparation and working for Board exams as well as the JEE Main exams. Students can also use NCERT exemplar Class 12 Chemistry solutions chapter 2 PDF download as and when needed.

Main Subtopics Covered in NCERT Exemplar Class 12 Chemistry Solutions Chapter 2 Inverse Trigonometric Functions

Types of Solutions
Expressing Concentration of Solutions
Solubility
Solubility of a Solid in a Liquid
Solubility of a Gas in a Liquid
Vapour Pressure of Liquid Solutions
Vapour Pressure of Liquid-Liquid Solutions
Raoult’s Law as a special case of Henry’s Law
Vapour Pressure of Solutions of Solids in Liquids
Ideal and Non- ideal Solutions
Ideal Solutions
Non-ideal Solutions
Colligative Properties and Determination of Molar Mass
Relative Lowering of Vapour Pressure
Elevation of Boiling Point
Depression of Freezing Point
Osmosis and Osmotic Pressure
Reverse Osmosis and Water Purification
Abnormal Molar Masses

JEE Main high scoring chapters and topics

As per latest 2024 syllabus. Study 40% syllabus and score upto 100% marks in JEE

Apply

NEET previous year papers with solutions

Solve NEET previous years question papers & check your preparedness

Apply

NCERT Exemplar Class 12 Chemistry Solutions Chapter 2 Inverse Trigonometric Functions-What will the students learn from?

The students will be able to understand the formation of different types of solutions and their properties that can be easily related to various solutions around us. They will also be able to understand and express the concentration of different solutions with the help of different methods provided by going through NCERT exemplar solutions for Class 12 Chemistry chapter 2. The students will learn to calculate the concentration, percentage, morality, molality, etc. of different compounds and also the factors affecting them by solving NCERT exemplar Class 12 Chemistry solutions chapter 2. It will also give an insight into the solubility of different solutions and the effect of temperature on these solutions. The students will also learn about Henry’s law and Raoult’s law to establish a relationship between different properties of solid and knowledge about colligative properties of solid.

NCERT Exemplar Class 12 Chemistry Solutions

Chapter 1 Solid State

Chapter 3 Electrochemistry

Chapter 4 Chemical Kinetics

Chapter 5 Surface Chemistry

Chapter 6 General Principles and Processes of Isolation of Elements

Chapter 7 The p-Block Elements

Chapter 8 The d & f Block Elements

Chapter 9 Coordination Compounds

Chapter 10 Haloalkanes and Haloarenes

Chapter 11 Alcohols, Phenols, and Ethers

Chapter 12 Aldehydes, Ketones, and Carboxylic Acids

Chapter 13 Amines

Chapter 14 Biomolecules

Chapter 15 Polymers

Chapter 16 Chemistry in Everyday Life

NCERT Class 12 Chemistry Chapter 2 Solutions Important Topics To Cover For Exams

NCERT exemplar Class 12 Chemistry solutions chapter 2 also establishes different relationships between different properties of different combinations and their reliability on one another such as Raoult’s law that helps to determine the vapour pressure of distinguished components of any solution with the help of Dalton’s law of partial pressure, etc. for liquid-liquid and solid-liquid solutions.

NCERT exemplar Class 12 Chemistry chapter 2 solutions also covers a brief description on various properties of solutions depending on the number of solute particles also known as colligative properties with relation to the boiling point, vapour pressure, mole fraction, freezing point, osmotic pressure, temperature and much more.

Class 12 Chemistry NCERT exemplar solutions chapter 2 also talks about various azeotropes formed from such solutions and the process of water purification through reverse osmosis.

NCERT Exemplar Class 12 Solutions

NCERT Exemplar Class 12 Mathematics Solutions

NCERT Exemplar Class 12 Physics Solutions

NCERT Exemplar Class 12 Biology Solutions

Check NCERT Solutions for Class 12 Chemistry

Chapter 1	The Solid State
Chapter 2	Solutions
Chapter 3	Electrochemistry
Chapter 4	Chemical Kinetics
Chapter 5	Surface chemistry
Chapter 6	General Principles and Processes of isolation of elements
Chapter 7	The P-block elements
Chapter 8	The d and f block elements
Chapter 9	Coordination compounds
Chapter 10	Haloalkanes and Haloarenes
Chapter 11	Alcohols, Phenols, and Ethers
Chapter 12	Aldehydes, Ketones and Carboxylic Acids
Chapter 13	Amines
Chapter 14	Biomolecules
Chapter 15	Polymers
Chapter 16	Chemistry in Everyday life

Must read NCERT Solution subject wise

Read more NCERT Notes subject wise

Also Check NCERT Books and NCERT Syllabus here:

Frequently Asked Question (FAQs)

1. Q: Can I download the solutions for this chapter?

Ans: Yes, you can go on the link on the page for easy NCERT exemplar Class 12 Chemistry solutions chapter 2 pdf download.

2. Q: Who prepares these solutions?

Ans: The NCERT exemplar Class 12 Chemistry chapter 2 solutions are prepared by us. We are a team of experts in Chemistry who provide solutions by referring advanced level books.

3. Q: Are these solutions helpful for board examinations?

Ans: Yes, these solutions are designed and completely reliable for you to study for you board exammations.

4. Q: How many times should one read the solutions?

Ans: One can read as many times as they like until they are well acquainted with topics and have cleared the concept to solve questions.

Also Read

NCERT Class 12 Physics Chapter 9 Notes Ray Optics and Optical Instruments - Download PDF

NCERT Class 12 Physics Chapter 8 Notes Electromagnetic Waves - Download PDF

NCERT Class 12 Physics Chapter 7 Notes Alternating Current - Download PDF

NCERT Class 12 Physics Chapter 6 Notes Electromagnetic Induction - Download PDF

NCERT Class 12 Physics Chapter 5 Notes Magnetism and Matter - Download PDF

NCERT Class 12 Physics Chapter 4 Notes Moving Charges and Magnetism - Download PDF

NCERT Books for Class 12 Hindi 2024 - Download chapter wise PDFs here

NCERT Books for Class 12 Biology 2024 - Download Free PDF

NCERT Books for Class 12 Chemistry 2024 - Download Free Pdf

NCERT Book for Class 12 Maths 2024 - Download Free PDF

NCERT Book for Class 12 Physics 2024 - Download Free PDF

NCERT Books for Class 12 - Download All Subjects PDFs Here

NCERT Syllabus for Class 12 English 2024 - Download Syllabus PDF

NCERT Syllabus for Class 12 2024 (All Subjects) - Download PDF Here

NCERT Syllabus for Class 6 to 12 (2023-24) - All Subjects PDF Download

NCERT Solutions for Miscellaneous Exercise Chapter 7 Class 12 - Integrals

NCERT Solutions for Exercise 4.1 Class 11 Maths Chapter 4 - Principle of Mathematical Induction

NCERT Solutions for Class 12 Biology - Check CBSE 12 Biology NCERT Chapterwise Solution

NCERT Solutions for Class 12 Maths Chapter 11 Three Dimensional Geometry

NCERT Solutions for Class 12

NCERT Solutions for Class 12 Maths (Updated 2023-24)

NCERT Exemplar Class 12 Physics Solutions Chapter 8 Electromagnetic Waves

Articles

UP Board 12th Result 2024 Out, Check UPMSP Inter Result 2024 @upresults.nic.in

Apr 20, 2024

UP Board 12th Toppers List 2024, Check UPMSP Inter Toppers Names, Marks, and Rank

Apr 20, 2024

UP Board 12th Marksheet 2024, Download UPMSP Inter Marksheet 2024 Here

Apr 20, 2024

UP Board Compartment Result 2024 for Class 10th & 12th @upmsp.edu.in

Apr 20, 2024

UP Board 12th Grading System 2024, Check Marking System Here

Apr 20, 2024

CBSE Class 12 Physical Education Syllabus 2024-25 (New Released) : Download PDF

Apr 17, 2024

CBSE Result DigiLocker 2024 - Download 10th, 12th Result via DigiLocker Login, Passing & Migration Certificate

Apr 15, 2024

5 min ⋆ Sep 28, 2023

Study Help

Cancer Treatment: Why Chemotherapy Does Not Suit All Patients

Mock Test

Admit Card

View All School Exams

Certifications By Top Providers

Artificial Intelligence Projects

Via Great Learning

Introduction to Web Development with HTML CSS JavaScript

Via IBM

Full-Stack Web Development

Via Masai School

Digital Banking Business Model

Via State Bank of India

Business Analytics Foundations

Via PW Skills

Python Fundamentals for Beginners

Via Great Learning

1110 courses

789 courses

328 courses

136 courses

Harvard University, Cambridge

98 courses

IBM

86 courses

IT & Software

Teaching and Academics

Programming and Development

Health, Fitness and Medicine

Business and Management

Engineering and Architecture

General Management

Financial Management

History

Environmental Studies

Cloud Computing

Law

Explore Top Universities Across Globe

University of Essex, Colchester

Wivenhoe Park Colchester CO4 3SQ

University College London, London

Gower Street, London, WC1E 6BT

The University of Edinburgh, Edinburgh

Old College, South Bridge, Edinburgh, Post Code EH8 9YL

University of Bristol, Bristol

Beacon House, Queens Road, Bristol, BS8 1QU

University of Nottingham, Nottingham

University Park, Nottingham NG7 2RD

Lancaster University, Lancaster

Bailrigg, Lancaster LA1 4YW

Top Benefits of Studying in New Zealand 2024 - Low Cost, Top Universities, Visa Free Travel, Job Opportunities

6 min ⋆ Mar 01, 2024 12:03 PM IST

Top MBBS Colleges in Asian Countries - Course Details, Tuition Fees, Eligibility

5 min ⋆ Mar 01, 2024 11:03 AM IST

Countries to Study Abroad for Indians other than Canada

6 min ⋆ Feb 28, 2024 07:02 AM IST

TOEFL Reading Section: Strategies for Effective Preparation

5 min ⋆ Mar 01, 2024 10:03 AM IST

TOEFL Preparation Time 2024: How To Prepare For TOEFL?

4 min ⋆ Mar 01, 2024 10:03 AM IST

IELTS General Training Preparation 2024 - Tips, Strategies & Practice

5 min ⋆ Mar 01, 2024 06:03 AM IST

Related E-books & Sample Papers

CBSE Class 11, 12 Physics Syllabus 2024-25

232+ Downloads

CBSE Class 11, 12 Economics Syllabus 2024-25

76+ Downloads

CBSE Class 11, 12 Sociology Syllabus 2024-25

108+ Downloads

CBSE Class 11, 12 Sanskrit (Elective) Syllabus 2024-25

31+ Downloads

CBSE Class 11, 12 Sanskrit (Core) Syllabus 2024-25

8+ Downloads

CBSE Class 11, 12 Psychology Syllabus 2024-25

33+ Downloads

Questions related to CBSE Class 12th

Have a question related to CBSE Class 12th ?

I am interested in graphic designing and coding. how do I make a career .which stream should I go.what engineering subject to take

Hello aspirant,

The purpose of graphic design extends beyond the brand's look. Nevertheless, by conveying what the brand stands for, it significantly aids in the development of a sense of understanding between a company and its audience. The future in the field of graphic designing is very promising.

There are various courses available for graphic designing. To know more information about these courses and much more details, you can visit our website by clicking on the link given below.

https://www.careers360.com/courses/graphic-designing-course

Thank you

Hope this information helps you.

Read Complete Answer

Sajal Trivedi 29 January,2024

i couldn't clear 1st compartment (which held in August 2022) cbse class 12th so can I give improvement in all subjects which to be held on March 2023. tell me a solution i need more than 75% in class 12th

hello,

Yes you can appear for the compartment paper again since CBSE gives three chances to a candidate to clear his/her exams so you still have two more attempts. However, you can appear for your improvement paper for all subjects but you cannot appear for the ones in which you have failed.

I hope this was helpful!

Good Luck

Read Complete Answer

Upasana Barman 24 August,2022

i was not able to clear 1st compartment and now I have to give 2nd compartment so can I give improvement exam next year? plz tell me very much tensed(cbse class 12th)

Hello dear,

If you was not able to clear 1st compartment and now you giving second compartment so YES, you can go for your improvement exam next year but if a student receives an improvement, they are given the opportunity to retake the boards as a private candidate the following year, but there are some requirements. First, the student must pass all of their subjects; if they received a compartment in any subject, they must then pass the compartment exam before being eligible for the improvement.

As you can registered yourself as private candidate for giving your improvement exam of 12 standard CBSE(Central Board of Secondary Education).For that you have to wait for a whole year which is bit difficult for you.

Positive side of waiting for whole year is you have a whole year to preparing yourself for your examination. You have no distraction or something which may causes your failure in the exams. In whole year you have to stay focused on your 12 standard examination for doing well in it. By this you get a highest marks as a comparison of others.

Believe in Yourself! You can make anything happen

All the very best.

Read Complete Answer

Mayankjha.student2007 23 August,2022

if i am giving improvement in one subject this year, will i be able to give improvement in more subjects next year?

Hello Student,

I appreciate your Interest in education. See the improvement is not restricted to one subject or multiple subjects and we cannot say if improvement in one subject in one year leads to improvement in more subjects in coming year.

You just need to have a revision of all subjects what you have completed in the school. have a revision and practice of subjects and concepts helps you better.

All the best.

Read Complete Answer

Nuthalapati Vyshnavi 21 August,2022

I got an RT for 2 subjects, so do I have to give exams for all the subjects in the coming year or just the 2. pls help me

Hi,

You just need to give the exams for the concerned two subjects in which you have got RT. There is no need to give exam for all of your subjects, you can just fill the form for the two subjects only.

Read Complete Answer

Muskan Dhalwal 17 August,2022

View All

Popular CBSE Class 12th Questions

A block of mass 0.50 kg is moving with a speed of 2.00 ms^-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up ? Fat supplies 3.8×10⁷J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 ms⁻² :

Option 1)

2.45×10⁻³ kg

Option 2)

6.45×10⁻³ kg

Option 3)

9.89×10⁻³ kg

Option 4)

12.89×10⁻³ kg

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

A particle is projected at 60⁰ to the horizontal with a kinetic energy $K$ . The kinetic energy at the highest point

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

In the reaction,

$2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, $Mg_{3}(PO_{4})_{2}$ will contain 0.25 mole of oxygen atoms?

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol^-1) is

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t²) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m² , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1) less than 3	Option 2) more than 3 but less than 6
Option 3) more than 6 but less than 9	Option 4) more than 9

Data Administrator

Database professionals use software to store and organise data such as financial information, and customer shipping records. Individuals who opt for a career as data administrators ensure that data is available for users and secured from unauthorised sales. DB administrators may work in various types of industries. It may involve computer systems design, service firms, insurance companies, banks and hospitals.

4 Jobs Available

Bio Medical Engineer

The field of biomedical engineering opens up a universe of expert chances. An Individual in the biomedical engineering career path work in the field of engineering as well as medicine, in order to find out solutions to common problems of the two fields. The biomedical engineering job opportunities are to collaborate with doctors and researchers to develop medical systems, equipment, or devices that can solve clinical problems. Here we will be discussing jobs after biomedical engineering, how to get a job in biomedical engineering, biomedical engineering scope, and salary.

4 Jobs Available

Ethical Hacker

A career as ethical hacker involves various challenges and provides lucrative opportunities in the digital era where every giant business and startup owns its cyberspace on the world wide web. Individuals in the ethical hacker career path try to find the vulnerabilities in the cyber system to get its authority. If he or she succeeds in it then he or she gets its illegal authority. Individuals in the ethical hacker career path then steal information or delete the file that could affect the business, functioning, or services of the organization.

3 Jobs Available

GIS Expert

GIS officer work on various GIS software to conduct a study and gather spatial and non-spatial information. GIS experts update the GIS data and maintain it. The databases include aerial or satellite imagery, latitudinal and longitudinal coordinates, and manually digitized images of maps. In a career as GIS expert, one is responsible for creating online and mobile maps.

3 Jobs Available

Data Analyst

The invention of the database has given fresh breath to the people involved in the data analytics career path. Analysis refers to splitting up a whole into its individual components for individual analysis. Data analysis is a method through which raw data are processed and transformed into information that would be beneficial for user strategic thinking.

Data are collected and examined to respond to questions, evaluate hypotheses or contradict theories. It is a tool for analyzing, transforming, modeling, and arranging data with useful knowledge, to assist in decision-making and methods, encompassing various strategies, and is used in different fields of business, research, and social science.

3 Jobs Available

Geothermal Engineer

Individuals who opt for a career as geothermal engineers are the professionals involved in the processing of geothermal energy. The responsibilities of geothermal engineers may vary depending on the workplace location. Those who work in fields design facilities to process and distribute geothermal energy. They oversee the functioning of machinery used in the field.

3 Jobs Available

Database Architect

If you are intrigued by the programming world and are interested in developing communications networks then a career as database architect may be a good option for you. Data architect roles and responsibilities include building design models for data communication networks. Wide Area Networks (WANs), local area networks (LANs), and intranets are included in the database networks. It is expected that database architects will have in-depth knowledge of a company's business to develop a network to fulfil the requirements of the organisation. Stay tuned as we look at the larger picture and give you more information on what is db architecture, why you should pursue database architecture, what to expect from such a degree and what your job opportunities will be after graduation. Here, we will be discussing how to become a data architect. Students can visit NIT Trichy, IIT Kharagpur, JMI New Delhi.

3 Jobs Available

Remote Sensing Technician

Individuals who opt for a career as a remote sensing technician possess unique personalities. Remote sensing analysts seem to be rational human beings, they are strong, independent, persistent, sincere, realistic and resourceful. Some of them are analytical as well, which means they are intelligent, introspective and inquisitive.

Remote sensing scientists use remote sensing technology to support scientists in fields such as community planning, flight planning or the management of natural resources. Analysing data collected from aircraft, satellites or ground-based platforms using statistical analysis software, image analysis software or Geographic Information Systems (GIS) is a significant part of their work. Do you want to learn how to become remote sensing technician? There's no need to be concerned; we've devised a simple remote sensing technician career path for you. Scroll through the pages and read.

3 Jobs Available

Budget Analyst

Budget analysis, in a nutshell, entails thoroughly analyzing the details of a financial budget. The budget analysis aims to better understand and manage revenue. Budget analysts assist in the achievement of financial targets, the preservation of profitability, and the pursuit of long-term growth for a business. Budget analysts generally have a bachelor's degree in accounting, finance, economics, or a closely related field. Knowledge of Financial Management is of prime importance in this career.

4 Jobs Available

Data Analyst

3 Jobs Available

Underwriter

An underwriter is a person who assesses and evaluates the risk of insurance in his or her field like mortgage, loan, health policy, investment, and so on and so forth. The underwriter career path does involve risks as analysing the risks means finding out if there is a way for the insurance underwriter jobs to recover the money from its clients. If the risk turns out to be too much for the company then in the future it is an underwriter who will be held accountable for it. Therefore, one must carry out his or her job with a lot of attention and diligence.

3 Jobs Available

5 Jobs Available

The word “choreography" actually comes from Greek words that mean “dance writing." Individuals who opt for a career as a choreographer create and direct original dances, in addition to developing interpretations of existing dances. A Choreographer dances and utilises his or her creativity in other aspects of dance performance. For example, he or she may work with the music director to select music or collaborate with other famous choreographers to enhance such performance elements as lighting, costume and set design.

2 Jobs Available

A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.

2 Jobs Available

Welding Engineer

5 Jobs Available

QA Manager

4 Jobs Available

Quality Controller

A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product.

A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.

3 Jobs Available

An AWS Solution Architect is someone who specializes in developing and implementing cloud computing systems. He or she has a good understanding of the various aspects of cloud computing and can confidently deploy and manage their systems. He or she troubleshoots the issues and evaluates the risk from the third party.

4 Jobs Available

Azure Administrator

An Azure Administrator is a professional responsible for implementing, monitoring, and maintaining Azure Solutions. He or she manages cloud infrastructure service instances and various cloud servers as well as sets up public and private cloud systems.