VMC VIQ Scholarship Test
ApplyRegister for Vidyamandir Intellect Quest. Get Scholarship and Cash Rewards.
NCERT Exemplar Class 11 Physics solutions chapter 10 covers the fluidic properties of two states of matter; gas and liquid. Both of these have fluid-like properties because they can flow from one place to another, unlike solids. They do not have any particular shape, and instead, they take the shape of the container they are stored in. Fluids also act easily under any type of pressure, which will give rise to many real-world applications like barometer and manometer. All these properties have given rise to various theorems and rules, which play a major role in mechanical physics in higher education. Students can also check NCERT Class 11 Physics Solutions. In this chapter and NCERT exemplar Class 11 Physics solutions chapter 10 various topics comprising the pressure, viscosity, cohesion, and some major theorems are discussed in detail.
JEE Main Scholarship Test Kit (Class 11): Narayana | Physics Wallah | Aakash | Unacademy
NEET Scholarship Test Kit (Class 11): Narayana | Physics Wallah | Aakash | ALLEN
Scholarship Test: Vidyamandir Intellect Quest (VIQ) | ALLEN TALLENTEX
Also, check NCERT Solutions for Class 11 other subjects
Question:10.1
Answer:
The answer is the option (c)Question:10.2
Which of the following diagrams does not represent a streamline flow?
Answer:
The answer is the option (d)Question:10.3
Along a streamline
a) the velocity of a fluid particle remains constant
b) the velocity of all fluid particles crossing a given position is constant
c) the velocity of all fluid particles at a given instant is constant
d) the speed of a fluid particle remains constant
Answer:
The answer is the option (b) the velocity of all fluid particles crossing a given position is constant.Question:10.5
The angle of contact at the interface of water-glass is , ethylalcohol-glass is , mercury-glass is , and methyl iodide-glass is . A glass capillary is put in a trough containing one of these four liquids. It is observed that the meniscus is convex. The liquid in the trough is
a) water
b) ethylalcohol
c) mercury
d) methyliodide
Answer:
The answer is the option (c) Mercury.Question:10.6
For a surface molecule
a) the net force on it is zero
b) there is a net downward force
c) the potential energy is less than that of a molecule inside
d) the potential energy is more than that of a molecule inside
Answer:
The answer is the option (b) and (d)Question:10.7
Pressure is a scalar quantity because
a) it is the ratio of force to area and both force and area are vectors
b) it is the ratio of the magnitude of the force to area
c) it is the ratio of component of the force normal to the area
d) it does not depend on the size of the area chosen
Answer:
The answer is the option (c)Question:10.8
A wooden block with a coin placed on its top, floats in water as shown in figure:
The distance l and h are shown in the figure. After some time the coin falls into the water. Then
a) l decreases
b) h decreases
c) l increases
d) h increases
Answer:
The answer is the option (a) and (b)Question:10.9
With increase in temperature, the viscosity of
a) gases decreases
b) liquids increases
c) gases increases
d) liquids decreases
Answer:
The answer is the option (c) and (d)Question:10.1
Streamline flow is more likely for liquids with
a) high density
b) high viscosity
c) low density
d) low viscosity
Answer:
The answer is the option (b) and (c)Question:10.11
Answer:
Viscosity: the dragging force magnitude between two layers of a liquid per unit area, who have their velocity gradient as unity is called viscosity. This quantity just has a magnitude and no direction, and hence it is not a vector quantity.Question:10.12
Answer:
Surface tension = work done/ change in the surface areaQuestion:10.14
Answer:
The given figure has a beaker filled with water. The beaker has been placed on a weighing scale which is adjusted to zero.Question:10.15
Answer:
Question:10.17
Answer:
Question:10.19
Answer:
now,Question:10.21
a) Pressure decreases as one ascends the atmosphere. If the density of air is , what is the change in pressure dp over a differential height dh?
b) Considering the pressure p to be proportional to the density, find the pressure p at a height h if the pressure on the surface of the earth is .
c) If , and g is at what height will the pressure drop to (1/10) the value at the surface of the earth?
d) This model of the atmosphere works for relatively small distances. Identify the underlying assumption that limits the model.
Answer:
a) Let us assume that there is a packet which has a thickness of dh. In a liquid, at any point, the pressure is working in all the directions in an equal manner. The force as a result of the pressure is opposed by the buoyant force of the liquid.Question:10.22
Surface tension is exhibited by liquids due to force of attraction between molecules of the liquid. The surface tension decreases with increase in temperature and vanishes at boiling point. Given that the latent heat of vaporization for water , the mechanical equivalent of heat , density of water , Avagadro’s number and the molecular weight of water for 1 k mole.
(a) estimate the energy required for one molecule of water to evaporate.
(b) show that the inter–molecular distance for water is
(c) 1 g of water in the vapor state at 1 atm occupies 1601 cm3. Estimate the intermolecular distance at boiling
point, in the vapour state.
(d) During vaporisation a molecule overcomes a force F, assumed constant, to go from an inter-molecular distance d to d ′ . Estimate the value of F where d=3.1x10-10m
(e) Calculate , which is a measure of the surface tension.
Answer:
a)Question:10.23
Answer:
The amount of pressure outside a balloon is lesser than the amount of pressure inside the balloon.
{: surface tension, R: balloon’s radius}
Where, V is the volume of balloon and ni is number of moles of gas in the balloon
R is the gas constant, Ti is the temperature
= Mass of balloon (Mi)/Molecular mass (Ma)
-------------(1)
In the same way,
According to principal of floatation, , here W is the weight which the balloon lifts
If the mass displaced by balloon is M0 and Ma is the mass inside or outside of the balloon
---------------(2)
Hence from (1) and (2) we can write,
Ma = 79% N2 + 21%O2
+ Pressure due to ST of membrane
The NCERT questions from the main exercise and additional exercise are solved by our team of teachers. These solutions are exhaustive and effective in a better learning process. Students can easily download these solutions in PDF format for future reference and practice. Simply click on the download link of NCERT exemplar Class 11 Physics solutions chapter 10 pdf download and the file will get downloaded to the device for offline use.
Also, Read NCERT Solution subject wise -
Also, check NCERT Notes subject wise -
The chapter on mechanical properties of fluids covers every property that makes the fluid act in a certain way under various factors like pressure, temperature, etc. in this chapter a student will learn in detail about the pressure and thrust in the liquid. The Class 11 Physics NCERT exemplar solutions chapter 10 covers two most crucial laws in fluid dynamics, called Pascal's law and Archimedes principle. These two laws explain how the fluid acts and reacts under pressure. One explains pressure distribution and one about fluid displacement.
This chapter also covers the equation of continuity of fluids passing through a cross-section and energy of liquids. Students will also learn about Bernoulli's theorem which tells about non-pressurized streamline flow in which the liquid will produce the same potential energy, pressure energy, and kinetic energy from NCERT Exemplar Class 11 Physics solutions chapter 10. Some of the other topics covered are surface tension, critical velocity, angle of contact, Torricelli's theorem, etc. Learning these topics, one will be one step closer to finding a better explanation in fluid dynamics applications like changing weather patterns, moving tectonic plates and ocean currents, etc.
The Class 11 Physics NCERT exemplar solutions chapter 10 covers various characteristics of fluids like viscosity, surface tension, terminal velocity, surface energy, critical velocity, magnus effect, etc. these topics are covered to give a basic idea of how fluids react under pressure in various circumstances and how to measure the changes.
The learners will learn some of the basic yet major laws, theorems, and equations like Archimedes's principle, Pascal's law, Bernoulli's theorem, Torricelli's theorem, Stoke's law, Reynolds number, Poiseuille's equation, and equation of continuity.
The NCERT Exemplar Class 11 Physics solutions chapter 10 also cover some of the major applications of fluid dynamics like barometer and manometer and cover how they work and where they are used. This will make the students aware of real-world applications in Physics.
Chapter 1 | Physical world |
Chapter 2 | Units and Measurement |
Chapter 3 | Motion in a straight line |
Chapter 4 | Motion in a Plane |
Chapter 5 | Laws of Motion |
Chapter 6 | Work, Energy and Power |
Chapter 7 | System of Particles and Rotational motion |
Chapter 8 | Gravitation |
Chapter 9 | Mechanical Properties of Solids |
Chapter 10 | Mechanical Properties of Fluids |
Chapter 11 | Thermal Properties of Matter |
Chapter 12 | Thermodynamics |
Chapter 13 | Kinetic Theory |
Chapter 14 | Oscillations |
Chapter 15 | Waves |
Students can get a clear and better idea about the topics, and the theorems explained in the chapter and how they have to answer the questions in the exam.
From this chapter, all the questions mentioned in the MCQ and short and long answer type questions are solved in complete detail in NCERT exemplar class 11 physics chapter 10 solutions.
Yes, these NCERT exemplar class 11 physics solutions chapter 10 are highly useful for those who are preparing for the entrance exams. One can make use of these solutions to understand questions in more depth.
Application Date:09 September,2024 - 14 November,2024
Application Date:09 September,2024 - 14 November,2024
Admit Card Date:04 October,2024 - 29 November,2024
Admit Card Date:04 October,2024 - 29 November,2024
Register for Vidyamandir Intellect Quest. Get Scholarship and Cash Rewards.
As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
As per latest 2024 syllabus. Chemistry formulas, equations, & laws of class 11 & 12th chapters
Accepted by more than 11,000 universities in over 150 countries worldwide
Register now for PTE & Unlock 20% OFF : Use promo code: 'C360SPL20'. Valid till 15th NOV'24! Trusted by 3,500+ universities globally
As per latest 2024 syllabus. Study 40% syllabus and score upto 100% marks in JEE