NCERT Exemplar Class 11 Biology Solutions Chapter 6 Anatomy of Flowering Plants

NCERT Exemplar Class 11 Biology Solutions Chapter 6 Anatomy of Flowering Plants

Edited By Priyanka kumari | Updated on Aug 22, 2022 10:45 AM IST

In NCERT Exemplar Class 11 Biology solutions chapter 6, we will look into the anatomy of the plants. Anatomy is the study of the internal structure of a given subject. Basically, the internal structure of higher groups of plants in detail. To study any organism, we must start from scratch. In this context, NCERT exemplar solutions for Class 11 Biology chapter 6 begins its approach with the study of cells in plants. Plants have cells as the basic unit, which are then organized into tissues and in turn, the tissues form organs. The different tissues perform different functions in the organ and the organ, in turn, sticks to its unique functioning role. Everything is explained in detail in the NCERT Exemplar Class 11 Biology solutions chapter 6

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This Story also Contains
  1. NCERT Exemplar Class 11 Biology Solutions Chapter 6: Multiple Choice Questions:
  2. Very Short Answer Type Questions:
  3. Short Answer Type Questions:
  4. Long Answer Type Questions:
  5. Class 11 Biology NCERT Exemplar Solutions Chapter 6 Anatomy Of Flowering Plants- Main Subtopics:
  6. NCERT Exemplar Class 11 Biology Solutions Chapter Wise
  7. What the students will learn in NCERT Exemplar Class 11 Biology Solutions Chapter 6 Anatomy Of Flowering Plants:

Also, check NCERT Solutions for Class 11 other subjects.

NCERT Exemplar Class 11 Biology Solutions Chapter 6: Multiple Choice Questions:

Question:1

A transverse section of stem is stained first with safranin and then with fast green following the usual schedule of double staining for the preparation of a permanent slide. What would be the colour of the stained xylem and phloem?

  1. Red and green

  2. Green and red

  3. Orange and yellow

  4. Purple and orange

Answer:

Ans. The answer is the option (a) Red and green
Explanation: Xylem is coloured red with safranin because the walls of the xylem cells contain lignin which picks up the red dye of safranin and phloem is coloured green with fast green because fast green stains the dense cytoplasm and cell walls present in the phloem.

Question:2

Match the followings and choose the correct option from below

Column A

Column B

A. Meristem

(i) Photosynthesis, storage

B. Parenchyma

(ii) Mechanical support

C. Collenchyma

(iii) Actively dividing cells

D. Sclerenchyma

(iv) Stomata

E. Epidermal tissue

(v) Sclereids


Answer:

A. Meristem: It includes group or cluster of cells which remain in a continuous state of division or retain their power of division.
B. Parenchyma: It performs the function of storage of reserve food materials, storage of water in succulents, Buoyancy and gaseous exchange in water plants.
C. Collenchyma: It is the main supporting tissue in young dicotyledonous stems. The tissue has the capacity to expand and gives tensile strength to the body.
D. Sclerenchyma: It consists of thick-walled dead cells. It is of two main types: Fibres and Sclereids. Sclereids are short and possess extremely thick lamellated lignified walls with long tubular simple pits.
E. Epidermal tissue: The tissue originates from the outermost layer of the apical meristem. It has epidermis, cuticle and wax, Stomata, Trichomes. Singular of stomata is stoma. A typical stoma is microscopic and usually consists of two kidney-shaped guard cells surrounding a pore.
So, the correct answer is 'A-(iii), B-(i), C-(ii), D-(v), E-(iv)'.


Question:3

Match the following and choose the correct option from below

Column A

Column B

A. Cuticle

(i) Guard cells

B. Bulli form cells

(ii) Single-layer

C. Stomata

(iii) Waxy layer

D. Epidermis

(iv) Empty colourless cell

Options:
(a) A-(iii), B-(iv), C-(i), D-(ii)
(b) A-(i), B-(ii), C-(iii), D-(iv)
(c) A-(iii), B-(ii), C-(iv), D-(i)
(d) A-(iii), B-(ii), C-(i), D-(iv)

Answer:

Ans. The answer is the option (a) A-(iii), B-(iv), C-(i), D-(ii)
Explanation:
A- Cuticle provides a waxy layer to the epidermis of the leaves for protection.
B- Bulli form cells are large, empty and colourless epidermal cells.
C- Stomata is a guard cell as it helps in gas exchange.
D- Epidermis is a single layer of cells in plant

Question:4

Identify the simple tissue from among the following

  1. Parenchyma

  2. Xylem

  3. Epidermis

  4. Phloem

Answer:

Ans. The answer is the option (a) Parenchyma
Explanation: Parenchyma is a simple tissue as it contains one kind of cells while the others are complex tissues as they contain more than one type of cells.

Question:5

Cells of this tissue are living and show angular wall thickening. They also provide mechanical support. The tissue is

  1. Xylem

  2. Sclerenchyma

  3. Collenchyma

  4. Epidermis

Answer:

Ans. The answer is the option (c) Collenchyma
Explanation: Cells present in Xylem and Collenchyma are dead cells, and living cells may be present in the epidermis, but epidermis does not provide mechanical support.

Question:6

A conjoint and open vascular bundle will be observed in the transverse section of

  1. Monocot root

  2. Monocot stem

  3. Dicot root

  4. Dicot stem

Answer:

Ans. The answer is the option (d) Dicot stem
Explanation: Vascular bundle present in dicot stems are conjoint and open unlike in another monocot stem, root and dicot root.

Question:7

Interfascicular cambium and cork cambium are formed due to

  1. Cell division

  2. Cell differentiation

  3. Cell dedifferentiation

  4. Redifferentiation

Answer:

Ans. The answer is the option (c) Cell dedifferentiation
Explanation: Process leading to the maturation of plants is differentiation. When differentiated cells regain its capacity of cell division, the phenomenon is called dedifferentiation. The formation of interfascicular cambium and cork cambium is an example of cell dedifferentiation from fully matured/differentiated parenchyma cells.

Question:8

Phellogen and Phellem respectively denote

  1. Cork and cork cambium

  2. Cork cambium and cork

  3. Secondary cortex and cork

  4. Cork and secondary cortex

Answer:

Ans. The answer is the option (b) Cork cambium and cork
Explanation: Cork cambium or phellogen is formed in the cortex region, and phellogen differentiates into cork or phellem.

Question:9

In which of the following pairs of parts of a flowering plant is epidermis absent?

Root tip and shoot tip

  1. Shoot bud and floral bud

  2. Ovule and seed

  3. Petiole and pedicel

Answer:

Ans. The answer is the option (a) Root tip and shoot tip
Explanation: Root tip and shoot tip have meristematic cells and epidermis is absent in them.

Question:10

How many shoot apical meristems are likely to be present in a twig of a plant possessing, 4 branches and 26 leaves

  1. 26

  2. 1

  3. 5

  4. 30

  5. 4

Answer:

Ans. The answer is the option (c) 5

Explanation: Five shoot apical meristems are generally present in a twig of a plant having 4 branches and 26 leaves. Four tips are present in branches and one in the tip.

Question:11

A piece of wood having no vessels (trachea) must belong to

  1. Teak

  2. Mango

  3. Pine

  4. Palm

Answer:

Ans. The answer is the option (c) Pine
Explanation: Vessels are present in angiosperms and absent in gymnosperms, and hence, Pine is a gymnosperm and is the correct answer.

Question:12

A plant tissue, when stained, showed the presence of hemicellulose and pectin in the cell wall of its cells. The tissue represents

  1. Collenchyma

  2. Sclerenchyma

  3. Xylem

  4. Meristem

Answer:

The answer is the option (a) Collenchyma

Explanation: Collenchyma cells have depositions of cellulose, pectin, and hemicellulose.

Question:13

In conifers, fibres are likely to be absent in

  1. Secondary phloem

  2. Secondary Xylem

  3. Primary phloem

  4. Leaves

Answer:

Ans. The answer is the option (b) Secondary Xylem
Explanation: Elongated cells that are present in sclerenchyma are called fibres. Sclerenchyma is absent in secondary xylem; hence, there is an absence of fibres as well.

Question:14

When we peel the skin of a potato tuber, we remove

  1. Periderm

  2. Epidermis

  3. Cuticle

  4. Sapwood

Answer:

Ans. The answer is the option (a) Periderm
Explanation: Periderm because the potato is a modified stem and the outermost layer of the stem is a periderm.

Question:15

Answer:

The answer is the option (d) Trochodendron
Explanation: Pinus and grass are gymnosperms and therefore, do not contain sieve tubes while eucalyptus contains vessels. Trochodendron contains sieve tubes but lack vessels.

Question:16

Which one of the following cell types always divides by anticlinal cell division?

  1. fusiform initial cells

  2. root cap

  3. protoderm

  4. phellogen

Answer:

The answer is the option (c) protoderm
Explanation: Protoderm cell divides by anticlinal cell division, unlike others.

Question:17

What is the fate of primary xylem in a dicot root showing extensive secondary growth?

  1. It is retained in the centre of the axis

  2. It gets crushed

  3. May or may not get crushed

  4. It gets surrounded by primary phloem

Answer:

The answer is the option (a) It is retained in the centre of the axis
Explanation: Primary xylem is retained in the centre of the axis while primary phloem is crushed.


Question:18

What is the fate of primary xylem in a dicot root showing extensive secondary growth?

  1. It is retained in the centre of the axis

  2. It gets crushed

  3. May or may not get crushed

  4. It gets surrounded by primary phloem

Answer:

The answer is the option (a) It is retained in the centre of the axis
Explanation: Primary xylem is retained in the centre of the axis while primary phloem is crushed.

Very Short Answer Type Questions:

Question:1

Product of photosynthesis is transported from the leaves to various parts of the plants and stored in some cell before being utilised. What are the cells/ tissues that store them?

Answer:

Food gets stored in parenchymatous cells that are present either in the stems or the roots

Question:2

Protoxylem is the first formed xylem. If the protoxylem lies next to phloem what kind of arrangement of xylem would you call it?

Answer:

If the protoxylem lies next to phloem, the arrangement is called an exarch. This arrangement can be found in roots.

Question:3

What is the function of phloem parenchyma?

Answer:

The primary function of phloem parenchyma is the storage of food and transportation of food. It also helps in storing other substances like latex and resins.

Question:4

What is present on the surface of the leaves which helps the plant prevent loss of water but is absent in roots?

Answer:

The cuticle is the waxy layer that is present on the leaves, which prevents the loss of water. The cuticles are absent in roots.

Question:5

What is the epidermal cell modification in plants which prevents water loss?

Answer:

Bulli form cells are the epidermal cell modification in plants which prevents water loss.

Question:6

What part of the plant would show the following:

  1. Radial vascular bundle

  2. Polyarch xylem

  3. Well-developed pith

Answer:

a) The radial vascular bundle is available in roots.
(b) Polyarch xylem is available in monocot root.
(c) A well-developed pith can be found in dicot stem and monocot roots.

Question:7

What are the cells that make the leaves curl in plants during water stress?

Answer:

Bulli form cells make the leaves curl in plants during water stress because there is a loss of turgor pressure in the leaves, which makes it curl.

Question:8

What constitutes the cambial ring?

Answer:

The cambial ring is a ring of cambium that is made together by interfascicular and intrafascicular cambia.

Question:9

Give one basic functional difference between phellogen and phelloderm.

Answer:

Phellogen consists of meristematic cells, whereas phelloderm is a permanent tissue made up of permanent cells.

Question:10

Arrange the following in the sequence you would find them in a plant starting from the periphery - phellem, phellogen, phelloderm.

Answer:

Phellem is the outermost layer followed by Phellogen and then Phelloderm.

Question:11

If one debarks a tree, what parts of the plant is being removed?

Answer:

Bark consists of cork, cork cambium, secondary cortex, and secondary phloem. If one debarks a tree, these parts will be removed.

Question:12

The cross-section of a plant material showed the following features when viewed under the microscope.

  1. The vascular bundles were radially arranged.

  2. Four xylem strands with exarch condition of protoxylem.

To which organ should it be assigned?

Answer:

In roots, vascular bundles are radially arranged, and the four xylem strands are arranged with exarch condition.

Question:13

What do hardwood and softwood stand for?

Answer:

Ans. Dicot angiospermic wood is called hardwood, and gymnosperm wood is called softwood.

Short Answer Type Questions:

Question:1

While eating peach or pear it is usually seen that some stone-like structures get entangled in the teeth, what are these stone-like structures called?

Answer:

Ans. While eating peach or pear, it is usually seen that entangled in teeth are called stone cells. Stone cells are a type of sclerenchyma cells.

Question:2

What is the commercial source of cork? How is it formed in the plant?

Answer:

Ans. The commercial source of cork is Quercus suber. Cork is formed from phellogen or cork cambium that is formed as secondary meristem due to dedifferentiation.

Question:3

Below is a list of plant fibres. From which part of the plant these are obtained
(a) Coir (b) Hemp (c) Cotton (d) Jute

Answer:

a) Coir is obtained from the outer coating of coconut seed
b) Hemp is obtained from the stem of Cannabis sativa plant
c) Cotton is obtained from cotton boll seeds d) Jute is obtained from the stem of the jute plant

Question:4

What are the characteristic differences found in the vascular tissue of gymnosperms and angiosperms?

Answer:

Ans. The differences between vascular tissues of gymnosperms and angiosperms are the following:

  1. Vessels are absent in the xylem of gymnosperms which is not the same case for angiosperms.

  2. Companion cells are not present in the phloem of gymnosperms but are present in the phloem of angiosperms.

Question:5

Epidermal cells are often modified to perform specialised functions in plants. Name some of them and the function they perform.

Answer:

Some of the modifications of epidermal cells and their functions are-

  1. Root hair helps in the absorbing water and important minerals for the plant.

  2. Stinging hair (trichomes) protects the plant from the physical environment.

Question:6

The lawn grass (Cyandon dactylon) needs to be mowed frequently to prevent its overgrowth. Which tissue is responsible for its rapid growth?

Answer:

Meristematic tissue is responsible for the overgrowth of the lawn grass. When grass is mowed, the apical layer is removed, which gives way to the growth of lateral branches which was obstructed by the apical buds. This makes the grass bushier.


Question:7

Plants require water for their survival. But when watered excessively, plants die. Discuss.

Answer:

Ans. Water is a necessary element for the survival of a plant. But excessive watering can lead to its death because excess water replaces the air, and there is a lack of oxygen respiration leading to the death of plant’s cells.

Question:8

A transverse section of the trunk of a tree shows concentric rings which are known as growth rings. How are these rings formed? What is the significance of these rings?

Answer:

Ans. Growth rings are formed from meristematic tissue of the cambium in dicot trees. Cambium is very active in the spring season, leading to the formation of a large number of xylary elements having wider vessel cavities. This wood is called springwood. In winters, the cambium activity is slowed down, leading to lesser xylary element with narrow vessels cavities. The wood is called latewood or autumn wood.

The two kinds of wood appear together with concentric rings known as annual rings or growth rings. These rings give an estimated age of a tree.

Question:9

Trunks of some of the aged tree species appear to be composed of several fused trunks. Is it a physiological or anatomical abnormality? Explain in detail.

Answer:

It is a case of anatomical abnormality, which is due to abnormal secondary growth caused by the abnormal positioning of meristematic tissue cambium. Sometimes in aged trees, the abnormal secondary growth produces extravascular bundles which lead to the growth of fused trunks.

Question:10

What is the difference between lenticels and stomata?

Answer:

Lenticels

Stomata

(i) These are aerating pores found in the barks or stems of plants.

(i) These are cell structures in the epidermis layers of leaves and stems.

(ii) Guard cells do not surround lenticels.

(ii) Guard cells surround the stomata.

(iii) Unregulated opening of the lenticels.

(iii) Regulated opening of the stomata.

(iv) Helps in the removal of waste.

(iv) Helps in gas exchange.


Question:11

Write the precise function of
(a) Sieve tube (b) Interfascicular cambium
(c) Collenchyma (d) Aerenchyma

Answer:

  1. Transportation of synthesised food.

  2. It helps in secondary growth.

  3. It provides mechanical support to herbaceous stem.

  4. It helps hydrophytes in facilitating buoyancy.

Question:12

The stomatal pore is guarded by two kidney-shaped guard cells. Name the epidermal cells surrounding the guard cells. How does a guard cell differ from an epidermal cell? Use a diagram to illustrate your answer.

Answer:

The epidermal cells surrounding the guard cells are called subsidiary cells. Following are the differences between guard cells and epidermal cells.

Guard Cells

Epidermal Cells

(i) Guard cells are bean or kidney-shaped.

(i) Epidermal are barrel-shaped.

(ii) Chloroplast is present in guard cells.

(ii) Epidermal cells lack chloroplast.

(iii) Guard cells are smaller.

(iii) Epidermal cells are bigger.

(iv) Thick and non-uniform cell walls are present in guard cells.

(iv) Thin and uniform cell walls are present in epidermal cells.


Question:13

Point out the differences in the anatomy of, leaf of peepal (Ficus religiosa) and maise (Zea mays). Draw the diagrams and label the differences.

Answer:

Ficus leaf

Maise leaf

(i) Ficus leaf is a dorsiventral leaf.

(i) Maise leaf is an isobilateral leaf.

(ii) Stomata are found in the lower epidermis region of the leaf.

(ii) Stomata are found in both upper and lower epidermis regions of the leaf.

(iii) Mesophyll cells are differentiated into spongy and palisade cells.

(iii) Mesophyll consists of only spongy cells.

(iv) It lacks bulliform cells.

(iv) It consists of bulliform cells.


Question:14

Palm is a monocotyledonous plant, yet it increases in girth. Why and how?

Answer:

Ans. Palm tree shows secondary growth which is due to the repeated division of parenchymatous cells which causes an increase in the girth of the stem.

Long Answer Type Questions:

Question:1

The arrangement of ovules within the ovary is known as placentation. What does the term placenta refer to? Draw various types of placentation in flower, as seen in T.S. and V.S.

Answer:

The placenta is soft tissues to which the ovules are attached. It found in the inner ovary wall. The arrangement of ovules inside the ovary is called placentation. Placentation can be of different types like marginal placentation, basal, parietal, axile and free central placentation. In marginal one, a ridge kind of structure is formed between the placenta and the ovary. The ovules are arranged on this ridge in two rows: example- pea. In basal one, the placenta is formed at the lower region of the ovary. Only a single ovule is attached to the placenta: example- sunflower. In parietal one, the ovules are attached in the inner wall of the ovary or in the peripheral area in two chambers, example- mustard. In axile placentation, the ovules develop in the central axis in a multilocular ovary, example- tomato. In free central placentation, the ovules develop in central axis but in a unilocular ovary, example- primrose.



Question:2

Deciduous plants shed their leaves during hot summer or in autumn. This process of shedding of leaves is called abscission, apart from physiological changes what anatomical mechanism is involved in the abscission of leaves.

Answer:

Shedding of leaves in plants is known as abscission of leaves. Apart from physiological changes, anatomical changes are also involved in the shedding of leaves.

Some anatomical changes are –

1. Formation of an abscission zone, also known as a separation zone, at the base of the petiole in deciduous trees. This zone is made up a weak top layer and a bottom layer. In the autumn season, the bottom layer expands, breaking the cells of the top layer, which allows the leaf to shed.

2. Excess loss of chlorophyll can also attribute to the falling of the leaves.

3. Hormonal change can also occur in deciduous trees due to excess secretion of abscisic acid, which stimulates the process of abscission.

The abscission zone is also called the separation zone. It is formed at the base of the petiole. It is composed of a top layer and a bottom layer. The cells in the top layer have weak cell walls. The bottom layer expands in winter and breaks the cell walls of the top layer. This results in shedding of leaves.

Question:3

Is Pinus an evergreen tree? Comment.

Answer:

Ans. Pinus is not a deciduous tree because it does not shed its leaves in any particular season. It is an evergreen tree because it has leaves throughout the year and the leaves shed throughout the year and grow back. This is because Pinus trees have thicker cuticles and sunken stomata that reduces the loss of water, helping it to grow leaves throughout the year.

Question:4

Assume that a pencil box held in your hand represents a plant cell. In how many possible planes can it be cut? Indicate these cuts with the help of line drawings.

Answer:

It can be cut vertically, horizontally and diagonally. If a plant cell is cut in two equal halves, it can be cut in bilateral symmetry. If a plant is cut in different planes, it will result in radial symmetry. Therefore, it can be cut either in a single plane or different plane.

Question:5

Each of the following terms has some anatomical significance. What do these terms mean? Explain with the help of line diagrams.

  1. Plasmadesmoses/ Plasmodesmata

  2. Middle lamella

  3. Secondary wall

Answer:

. (a) Plasmodesmata are channels that directly connect the cytoplasm of one plant cell to another. It helps in establishing communication and transportation of food and other important minerals from one plant cell to another.

(b) Middle lamella consists of pectin which acts as a glueing agent helping in holding cell walls of two adjacent cells together.


(c) Secondary walls are composed of cellulose, lignin and hemicellulose, which provides strength to the plant and protects it from any mechanical stress.

Question:6

Distinguish between the following:
(a) Exarch and endarch condition of protoxylem
(b) Stele and vascular bundle
(c) Protoxylem and metaxylem
(d) Interfasicular cambium and intrafasicular cambium
(e) Open and closed vascular bundles
(f) Stem hair and root hair

Answer:

Ans. (a) Endarch is a protoxylem condition that occurs in the stem of a plant when the protoxylem is arranged in the centre and the metaxylem is arranged at the periphery of the stem. Exarch is a protoxylem condition that occurs in the roots of a plant. In this, the protoxylem lies at the periphery, and the metaxylem is arranged in the centre. This arrangement is called the exarch.

(b) Stele comprises the major part of the root and stem. Stele consists of the vascular bundles,pericycle and the pith. The vascular bundle is a part of stele consisting of xylem and phloem-types of complex tissues.

(c) There are two kinds of primary xylem- protoxylem and metaxylem. The primary xylem which formed earlier and is smaller in size is the protoxylem and the one which is formed later and is larger in size is called metaxylem.

(d) In dicot stems, the cambium cells that are present in between of the primary xylem and primary phloem is called the intrafascicular cambium whereas the interfascicular cambium is formed by the adjoining medullary cells with the intrafascicular cambium. This meristematic form is the interfascicular cambium.

(e) A closed vascular bundle is the one which lacks cambium and therefore, cannot perform secondary growth where an opened vascular bundle is the one which has cambium, and it can very well perform secondary growth.

(f) Stem hairs are trichomes that grow on stems. Trichomes are multicellular epidermal cells, and these can be branched or unbranched and soft or rigid. These protect plants form physical dangers and also help in preventing much loss of water. Root hairs are unicellular epidermal cells present in the roots of the plants. Root hairs help in absorbing water and important minerals from the soil for the growth of the plant.

Questions related to all the topics are detailed in the NCERT Exemplar Class 11 Biology Solutions Chapter 6, which will be helpful for board exam and competitive exam as well. Students can access the NCERT exemplar class 11 Biology solutions chapter 6 pdf download function for the best learning experience.

Class 11 Biology NCERT Exemplar Solutions Chapter 6 Anatomy Of Flowering Plants- Main Subtopics:

  • The Tissues
  • Meristematic Tissues
  • Permanent Tissues
  • Simple Tissues
  • Complex Tissues
  • The Tissue System
  • Epidermal Tissue System
  • The Ground Tissue System
  • The Vascular Tissue System
  • Anatomy of Dicotyledonous and Monocotyledonous Plants
  • Dicotyledonous Root
  • Monocotyledonous Root
  • Dicotyledonous Stem
  • Monocotyledonous Stem
  • Dorsiventral (Dicotyledonous) Leaf
  • Isobilateral (Monocotyledonous) Leaf
  • Secondary Growth
  • Vascular Cambium
  • Formation of cambial ring
  • Activity of the cambial ring
  • Spring wood and autumn wood
  • Heartwood and sapwood
  • Cork Cambium
  • Secondary Growth in Roots

NCERT Exemplar Class 11 Biology Solutions Chapter Wise

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What the students will learn in NCERT Exemplar Class 11 Biology Solutions Chapter 6 Anatomy Of Flowering Plants:

A detailed study of Class 11 Biology NCERT exemplar solutions chapter 6 will enable the students to have a good understanding of the different internal features. A plant is made up of several tissues which are broadly classified into Meristematic Tissues and Permanent Tissues. The students will also learn how food is assimilated and transported and how water and minerals and phosphates are transported.

Further in NCERT exemplar Class 11 Biology chapter 6 solutions, they will learn the internal differences in monocotyledon and dicotyledon plants. They will also be made aware of the concepts of xylem and phylum and how wood is secondary xylem. NCERT Exemplar Class 11 Biology solutions chapter 6 will help students studying in class 11 as well as to general readers who are interested in botany.

NCERT Exemplar Class 11 Solutions

Check Chapter-Wise Solutions of Questions Given in Book:

Also, Read NCERT Solution subject wise

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Frequently Asked Questions (FAQs)

1. What all topics are included in the NCERT Exemplar Class 11 Biology Solutions Chapter 6?

This chapter covers all the crucial topics like xylem, phloem, vascular cambium, cork cambium, secondary growth in roots etc.

2. How many questions are solved?

In total 12 questions are solved which are mentioned in the main exercise of the chapter in these NCERT Exemplar Class 11 Biology solutions chapter 6.

3. Are these questions in the chapter solved in simple language?

Yes, these questions in the exercise are mentioned with complete detail in the easiest language and with illustrative diagrams.

4. Is NCERT Exemplar Class 11 Biology Chapter 6 Solutions helpful for an entrance exam?

Anatomy of plants is a major chapter that is part of the entrance exam syllabus, and thus understanding NCERT questions and answers will help in solving MCQs in a better way.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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