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NCERT Exemplar Class 12 Chemistry Solutions chapter 12 Aldehydes, Ketones and Carboxylic Acids

NCERT Exemplar Class 12 Chemistry Solutions chapter 12 Aldehydes, Ketones and Carboxylic Acids

Edited By Sumit Saini | Updated on Sep 16, 2022 05:59 PM IST | #CBSE Class 12th

In NCERT exemplar Class 12 Chemistry solutions chapter 12, students will learn about the physical properties, uses and chemical reactions of very crucial hydrocarbons like Aldehydes, Ketones, and Carboxylic Acids alongside it’s nomenclatures and various structures of the carboxyl groups easily in details etc. NCERT exemplar Class 12 Chemistry solutions chapter 12 pdf download is to be available for students. Using it they can understand the concepts better in offline mode too.

This Story also Contains
  1. NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: MCQ (Type 1)
  2. NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: MCQ (Type 2)
  3. NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Short Answer Type
  4. NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Matching Type
  5. NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Assertion and Reason Type
  6. NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Long Answer Type
  7. Major Subtopics in NCERT Exemplar Class 12 Chemistry Solutions Chapter 12 Aldehydes, Ketones and Carboxylic Acids
  8. NCERT Exemplar Class 12 Chemistry Solutions
  9. Important Topics in NCERT Exemplar Class 12 Chemistry Solutions Chapter 12

NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: MCQ (Type 1)

Question:1

Addition of water to alkynes occurs in acidic medium and the presence of \text {Hg}^{2+} ions as a catalyst. Which of the following products will be formed on addition of water to but-1-yne under these conditions.

Answer:

The answer is the option (ii) On addition of water to but-1-yne in the presence of \text {H}_{2}\text {SO}_{4} and \text {HgSO}_{4} , 2-butanone is obtained (by Markovnikoff’s rule).

Question:2

Which of the following compounds is most reactive towards nucleophilic addition reactions?

Answer:

The answer is the option (i) \text {CH}_{3}\text {CHO} (an aldehyde) is generally considered more reactive than ketones towards nucleophilic addition reactions. Ketones have 2 large substituents compared to 1 in aldehydes, that hinder the nucleophilic approach. Aldehydes are also considered more reactive because the 2 alkyl groups lead to the reduction of electrophilicity of the carbonyl carbon of ketone by releasing electron in its direction.
The reactivity order can be given as:

Question:3

The correct order of increasing acidic strength is _____________.
(i) Phenol < Ethanol < Chloroacetic acid < Acetic acid
(ii) Ethanol < Phenol < Chloroacetic acid < Acetic acid
(iii) Ethanol < Phenol < Acetic acid < Chloroacetic acid
(iv) Chloroacetic acid < Acetic acid < Phenol < Ethanol
Answer:

The answer is the option (iii) Due to formation of more stable conjugate base after removal of \text {H}^{+} phenol is more stable than the alcohol.
On the other hand, the stable conjugate base formed after removing \text {H}^{+} makes carboxylic acid more acidic than phenol.
In case chloroacetic acid, the presence of electron withdrawing chlorine group makes it more acidic compared to the acetic acid.

Question:4

Compound can be prepared by the reaction of _____________.

(i) Phenol and benzoic acid in the presence of \text {NaOH}
(ii) Phenol and benzoyl chloride in the presence of pyridine
(iii) Phenol and benzoyl chloride in the presence of \text {ZnCl}_{2}
(iv) Phenol and benzaldehyde in the presence of palladium
Answer:

The answer is the option (ii) The compound \text {C}_{6}\text {H}_{5}\text {OCOC}_{6}\text {H}_{5} can be prepared by the given below reaction. In this, the phenol is made to react with acid chloride in presence of an alkali. The alkali used is pyridine and acid chloride is benzoyl chloride.

Question:5

The reagent which does not react with both, acetone and benzaldehyde.
(i) Sodium hydrogen sulphite
(ii) Phenyl hydrazine
(iii) Fehling’s solution
(iv) Grignard reagent
Answer:

The answer is the option (iii) Fehling’s solution is the reagent that does not react with both acetone and benzaldehyde.

Question:6

Cannizaro’s reaction is not given by _____________.

Answer:

The answer is the option (iv)
\text {CH}_{3}\text {CHO} contains 3 \alpha-hydrogens while other three compounds have no any \alpha -hydrogen. Hence, Cannizzaro’s reaction is given by them. Aldehydes without any alpha hydrogen undergo reduction and self-oxidation reaction when treated with conc. Alkali.

Question:7

Which product is formed when the compound is treated with concentrated aqueous \text {KOH} solution?


Answer:

(ii) Benzaldehyde does not have any \alpha hydrogen. When reacted with aqueous \text {KOH} solution, it gives Cannizzaro’s reaction.

Question:8


Structure of ‘A’ and type of isomerism in the above reaction are respectively.
(i) \text {Prop-1-en-2-ol, metamerism}
(ii) \text {Prop-1-en-1-ol, tautomerism}
(iii) \text {Prop-2-en-2-ol, geometrical isomerism}
(iv) \text {Prop-1-en-2-ol, tautomerism}
Answer:

The answer is the option (iv) A undergoes tautomerism to form acetone.

Question:9

Compounds A and C in the following reaction are __________.

(i) identical
(ii) positional isomers
(iii) functional isomers
(iv) optical isomers
Answer:


Thus, and \text {CH}_{3}-\text {CH}_{2}-\text {CH}_{2}\text {OH} are positional isomers.
We know that acetaldehyde when treated with Grignard reagent followed by hydrolysis gives propane 2-ol.

Question:10

Which is the most suitable reagent for the following conversion?

(i) Tollen’s reagent
(ii) Benzoyl peroxide
(iii) \text {I}_{2} and \text {NaOH} solution
(iv) \text {Sn} and \text {NaOH} solution
Answer:

The answer is the option (iii) Iodoform test is most suitable for the given reaction.

Question:11

Which of the following compounds will give butanone on oxidation with alkaline \text {KMnO}_{4} solution?
(i) \text {Butan-1-ol}
(ii) \text {Butan-2-ol}
(iii) Both of these
(iv) None of these
Answer:

The answer is the option (ii). Aldehydes, when treated with common oxidising agents get readily oxidized to carboxylic acids.

Question:12

In Clemmensen Reduction carbonyl compound is treated with _____________.
(i) \text {Zinc amalgam + HCl}
(ii) \text {Sodium amalgam + HCl}
(iii) \text {Zinc amalgam + nitric acid}
(iv) \text {Sodium amalgam + HNO}_{3}
Answer:

The answer is the option (i) Clemmensen reduction is used in the conversion of carbonyl group to \text {CH}_{2} group. In this reaction, zinc amalgam and \text {HCl} act as reagent.

NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: MCQ (Type 2)

Question:13

Which of the following compounds do not undergo aldol condensation ?

Answer:

The answer is the option (ii, iv)
Aldol condensation takes place only if \alpha hydrogen is present. In the reaction, aldehydes and ketones with 1 or more than 1 alpha hydrogen react in presence of dilute alkali to form aldol and ketol respectively.

Question:14

Treatment of compound with \text {NaOH} solution yields

(i) Phenol
(ii) Sodium phenoxide
(iii) Sodium benzoate
(iv) Benzophenone
Answer:

The answer is the option (ii, iii) We get sodium phenoxide and sodium benzoate by nucleophilic substitution reaction.

Question:15

Which of the following conversions can be carried out by Clemmensen Reduction?
(i) Benzaldehyde into benzyl alcohol
(ii) Cyclohexanone into cyclohexane
(iii) Benzoyl chloride into benzaldehyde
(iv) Benzophenone into diphenyl methane
Answer:

The answer is the option (ii, iv)
Clemmensen reduction is used in the conversion of carbonyl group of aldehydes and ketones to \text {CH}_{2} group when treated with zinc amalgam and conc. \text {HCl}. It is used to convert cyclohexanone into cyclohexane and benzophenone into diphenyl methane.

Question:16

Through which of the following reactions number of carbon atoms can be increased in the chain?
(i) Grignard reaction
(ii) Cannizaro’s reaction
(iii) Aldol condensation
(iv) HVZ reaction
Answer:

The answer is the option (i,iii) Grignard reaction is used to increase the number of carbon atom in chain. Aldol condensation increases the number of carbon atom in the chain for aldehydes and ketones.

Question:17

Benzophenone can be obtained by ____________.
(i) \text {Benzoyl chloride + Benzene + AlCl}_{3}
(ii) \text {Benzoyl chloride + Diphenyl cadmium}
(iii) \text {Benzoyl chloride + Phenyl magnesium chloride}
(iv) \text {Benzene + Carbon monoxide + ZnCl}_{2}
Answer:

The answer is the option (i,ii) Benzophenone can be obtained by either of benzoyl chloride + diphenylcadmium or benzoyl chloride+ benzene+ \text {AlCI}_{3} . The latter is referred to as Friedel-Craft acylation reaction.

Question:18

Which of the following is the correct representation for intermediate of nucleophilic addition reaction to the given carbonyl compound (A) :

Answer:

The answer is the option (i,ii) The 2 possible orientation of a planar molecule of carbonyl compound in case of nucleophilic attack are:

The nucleophililic attack can occur either from front or rear side.

NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Short Answer Type

Question:19

Why is there a large difference in the boiling points of \text {butanal and butan-1 -ol} ?
Answer:

There is a huge difference in the boiling points of \text {butanal and butan-1 -ol} due to the presence of intermolecular hydrogen bonding between \text {-OH} groups in alcohol.

Question:20

Write a test to differentiate between \text {pentan-2-one} and \text {pentan-3-one}.

Answer:

The answer is Idoform test. There is a \text {CH}_{3}\text {CO} group in \text {Pentan-2-one} and that is why it will give a positive iodoform test.

Question:21

Give the IUPAC names of the following compounds

Answer:

(i) \text {3-Phenylprop-2-en-1 -al}
(ii) \text {Cyclohexanecarbaldehyde}
(iii) \text {3-Oxopentan-l-al}
(iv) \text {But-2-en-l-al}

Question:22

Give the structure of the following compounds.
(i) 4-Nitropropiophenone
(ii) 2-Hydroxycyclopentanecarbaldehyde
(iii) Phenyl acetaldehyde
Answer:

Question:23

Write IUPAC names of the following structures.

Answer:

(i) \text {Ethane-1,2-dial}
(ii)\text { Benzene-1, 4-dicarbaldehyde}
(iii) \text {3-Bromobenzaldehyde}

Question:24

Benzaldehyde can be obtained from benzal chloride. Write reactions for obtaining benzal chloride and then benzaldehyde from it.
Answer:

Reactions for obtaining benzalchloride and benzaldehyde from it are:

Question:25

Name the electrophile produced in the reaction of benzene with benzoyl chloride in the presence of anhydrous \text {AlCl}_{3}. Name the reaction also.
Answer:

The electrophile produced in the reaction of benzene with benzoyl chloride in the presence of anhydrous AlCl3 is benzoylium cation. The product formed in this reaction is benzophenone. This reaction is called Friedel Craft's acylation reaction.

Question:26

Oxidation of ketones involves carbon-carbon bond cleavage. Name the products formed on oxidation of 2, 5-dimethylhexan-3-one.
Answer:

The products formed on oxidation of 2, 5-dimethylhexan-3-one are: -
2-Methylpropanoic acid
Ethanoic acid and
Methanoic acid.
3-Methylbutanoic acid

Question:27

Arrange the following in decreasing order of their acidic strength and give the reason for your answer.
\text {CH}_{3}\text {CH}_{2}\text {OH},\text {CH}_{3}\text {COOH},\text {ClCH}_{2}\text {COOH},\text {FCH}_{2}\text {COOH},\text {C}_{6}\text {H}_{5}\text {CH}_{2}\text {COOH}
Answer:

\text {FCH}_{2}\text {COOH}>\text {ClCH}_{2}\text {COOH}> \text {C}_{6}\text {H}_{5}\text {CH}_{2}\text {COOH}> \text {CH}_{3}\text {COOH}> \text {CH}_{3}\text {CH}_{2}\text {OH}
The electron-withdrawing group increase the acidity of carboxylic acids since they stabilize the conjugate base by delocalization of charge. Whereas the electron donating group decrease the acidity as the resulting conjugate base is unstable.
Higher the electronegativity, greater the acidic strength.
\left ( i.e , \text {F}>\text {Cl}>\text {C}_{6}\text {H}_{5}>\text {H} \right )

Question:28

What product will be formed on reaction of propanal with 2-methyl propanal in the presence of \text {NaOH}? What products will be formed? Write the name of the reaction also.
Answer:

On reaction of propanal with 2-methyl propanal in the presence of \text {NaOH}, aldehyde mixture is formed.

Question:29

Compound ‘A’ was prepared by oxidation of compound ‘B’ with alkaline \text {KMnO}_{4}. Compound ‘A’ on reduction with lithium aluminium hydride gets converted back to compound ‘B’. When compound ‘A’ is heated with compound B in the presence of \text {H}_{2}\text {SO}_{4} it produces the fruity smell of compound C to which family the compounds ‘A’, ‘B’ and ‘C’ belong to?
Answer:

It is given that B and A on heating together in the presence of acid produces a fruity smelling compound which is ester.

  1. Carboxylic Acid

  2. Alcohol

  3. Ester Group

Question:30

Arrange the following in decreasing order of their acidic strength. Give explanation for the arrangement.
\text {C}_{6}\text {H}_{5}\text {COOH},\text {FCH}_{2}\text {COOH},\text {NO}_{2}\text {CH}_{2}\text {COOH}
Answer:

\text {NO}_{2}\text {CH}_{2}\text {COOH}>\text {FCH}_{2}\text {COOH}>\text {C}_{6}\text {H}_{5}\text {COOH}

\text {-NO}_{2} and \text {-F} groups are electron withdrawing groups that increase the acidity due to stable nature of resulting conjugate base. Whereas the electron-donating group decrease the acidity as the resulting conjugate base is unstable.
Higher the electronegativity, greater the acidic strength.

Question:31

Alkenes and carbonyl compounds both contain a \pi bond but alkenes show electrophilic addition reactions whereas carbonyl compounds show nucleophilic addition reactions. Explain.
Answer:

In carbonyl groups, carbon acquires a partial positive charge because oxygen is more electronegative. Thus, carbonyl group is polar in nature and hence susceptible to nucleophilic addition reaction. Alkenes, on the other hand are non-polar and electron abundant; making them susceptible to electrophilic addition reaction.

Question:32

Carboxylic acids contain carbonyl group but do not show the nucleophilic addition reaction like aldehydes or ketones. Why?
Answer:

Carboxylic acid doesnt show nucleophilic substitution reaction as because of presence of lone pair atoms on O atom of OH group decreases electrophilic character of carbonyl carbon by resonance.. Hence partial positive charge decreases and therefore it doesnt show nucleophilic substitution reactions

Question:33

Identify the compounds A, B and C in the following reaction.

Answer:

  • Compound A is \text {CH}_{3}-\text {MgBr}

  • Compound B is \text {CH}_{3}-\text {COOH}

  • Compound C is \text {CH}_{3}-\text {COOCH}_{3}

Question:34

Why are carboxylic acids more acidic than alcohols or phenols although all of them have a hydrogen atom attached to an oxygen atom (-O-H)?
Answer:

Acidity depends upon the stability of the resulting conjugate base. In case of carboxylic acid, equivalent resonance structures stabilize the carboxylate ion as the negative charge is at the more electronegative oxygen atom. Phenoxide ion, conjugate base of phenol does not have equivalent resonance structure as the negative charge is on the less electronegative carbon atom.

Question:35

Complete the following reaction sequence.

Answer:

Question:36

Ethylbenzene is generally prepared by acetylation of benzene followed by reduction and not by direct alkylation. Think of a possible reason.

Answer:

The reason is formation of polysubstituted products. Friedel-craft’s acylation reaction can be used to avoid the formation of these products.

Question:37

Can Gatterman-Koch reaction be considered similar to Friedel Craft’s acylation? Discuss.
Answer:

Yes, the Gattermann-Koch reaction can be considered similar to Friedel Craft’s acylation reaction. In Gattermann-Koch reaction introduction of \text {-CHO} group to the benzene nucleus takes place by reacting \text {CO} with \text {HCl} gas. In Friedel-Crafts acylation reactions, treatment of benzene or any arene with an acid chloride in presence of anhydrous \text {AlCl}_{3} takes place. In this RCO group is introduced.

NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Matching Type

Question:38

Match the common names given in Column I with the IUPAC names given in Column II

Column I (Common names)

Column II (IUPAC names)

(i) Cinnamaldehyde

(a) Pentanal

(ii) Acetophenone

(b) Prop-2-enal

(iii) Valeraldehyde

(c) 4-Methylpent -3-en-2-one

(iv) Acrolein

(d) 3-phenylprop-2-enal

(v) Mesityl oxide

(e) 1-Phenylethanone

Answer:

(i \rightarrow d), (ii \rightarrow e), (iii \rightarrow a), (iv \rightarrow b), (v \rightarrow c)

Question:39

Match the acids given in Column I with their correct IUPAC names given in Column II.

Column I (Acids)

Column II(IUPAC names)

(i) Phthalic acid

(a) Hexane-1,6-dioic acid

(ii) Oxalic acid

(b) Benzene-1, 2-dicarboxylic acid

(iii) Succinic acid

(c) Pentane -1 , 5-dioic acid

(iv) Adipic acid

(d) Butane -1, 4-dioic acid

(v) Glutaric acid

(e) Ethane-1,2-dioic acid

Answer:

(i \rightarrow b), (ii \rightarrow e), (iii \rightarrow d), (iv \rightarrow a), (v \rightarrow c)

Question:40

Match the reactions given in Column I with the suitable reagents given in Column II.

Column I (Reactions)

Column II (Reagents)

(i) Benzophenone \rightarrow Diphenylmethane

(a) \text {LiAIH}_{4}

(ii) Benzaldehyde \rightarrow 1-Phenylethanol

(b) \text {DIBAL-H}

(iii) Cyclohexanone \rightarrow Cyclohexanol

(c) \text {Zn (Hg)}/\text {Conc.HCl}

(iv) Phenyl benzoate \rightarrow Benzaldehyde

(d) \text {CH}_{3}\text {MgBr}

Answer:

(i \rightarrow c), (ii \rightarrow d), (iii \rightarrow a), (iv \rightarrow b)

Question:41

Match the example given in Column I with the name of the reaction in Column II

Column I (Examples)

Column II (Reaction)

(i)

(a)

Friedel-Crafts acylation

(ii)

(b)

HVZ reaction

(iii)

(c)

Aldol condensation

(iv)

(d)

Cannizzaro's reaction

(v)

(e)

Rosenmund's reduction

(vi)

(f)

Stephen's reaction


Answer:

(i \rightarrow e), (ii \rightarrow d), (iii \rightarrow a), (iv \rightarrowb), (v \rightarrow f), (vi \rightarrow c)

NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Assertion and Reason Type

Question:42

In the following question a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: Formaldehyde is a planar molecule.
Reason: It contains \text {sp}^{2} hybridised carbon atom.
(i) Assertion and reason both are correct and the reason is the correct explanation of assertion.
(ii) Assertion and reason both are wrong statements.
(iii) The assertion is a correct statement but the reason is the wrong statement.
(iv) The assertion is a wrong statement but the reason is the correct statement.
(v) Assertion and reason both are correct statements but the reason is not the correct
explanation of assertion.

Answer:

The answer is the option (i). Formaldehyde contains sp^{2} hybridized carbon atom. That is why it is a planar molecule. Both the assertion and reason are correct, and reason is correct explanation of assertion.

Question:43

In the following question a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: Compounds containing \text {-CHO} group are easily oxidised to corresponding carboxylic acids.
Reason: Carboxylic acids can be reduced to alcohols by treatment with \text {LiAlH}_{4}
(i) Assertion and reason both are correct and the reason is the correct explanation of assertion.
(ii) Assertion and reason both are wrong statements.
(iii) The assertion is a correct statement but the reason is the wrong statement.
(iv) The assertion is a wrong statement but the reason is the correct statement.
(v) Assertion and reason both are correct statements but the reason is not the correct
explanation of assertion

Answer:

The answer is the option (v). Due to high electronegativity of oxygen, carbonyl group in aldehydes are a strong electron-withdrawing group. This weakens the C-H bond in aldehydes. Even a weak oxidizing agent can oxidize the aldehydes into the corresponding carboxylic acids.

Question:44

In the following question a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: The \alpha-hydrogen atom in carbonyl compounds is less acidic.
Reason: The anion formed after the loss of the \alpha-hydrogen atom is resonance stabilised.
(i) Assertion and reason both are correct and the reason is the correct explanation of assertion.
(ii) Assertion and reason both are wrong statements.
(iii) The assertion is a correct statement but the reason is the wrong statement.
(iv) The assertion is a wrong statement but the reason is the correct statement.
(v) Assertion and reason both are correct statements but the reason is not the correct
explanation of assertion
Answer:

The answer is the option (iv). The \alpha -hydrogen atom in carbonyl compounds is more acidic. Carboxylic acids on dissociation in water give resonance stabilized carboxylate anions and hydronium ion.

Question:45

In the following question a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: Aromatic aldehydes and formaldehyde undergo Cannizaro reaction.
Reason: Aromatic aldehydes are almost as reactive as formaldehyde.
(i) Assertion and reason both are correct and the reason is the correct explanation of assertion.
(ii) Assertion and reason both are wrong statements.
(iii) The assertion is a correct statement but the reason is the wrong statement.
(iv) The assertion is a wrong statement but the reason is the correct statement.
(v) Assertion and reason both are correct statements but the reason is not the correct
explanation of assertion.
Answer:

The answer is the option (iii). Aromatic aldehydes and formaldehyde do not have a-hydrogen and thus undergo Cannizzaro’s reaction. Aldehydes with no alpha hydrogen atom undergo oxidation and reduction reaction when treated with conc. Alkali.

Question:46

In the following question a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form a silver mirror.
Reason: Both, aldehydes and ketones contain a carbonyl group.
(i) Assertion and reason both are correct and the reason is the correct explanation of assertion.
(ii) Assertion and reason both are wrong statements.
(iii) The assertion is a correct statement but the reason is the wrong statement.
(iv) The assertion is a wrong statement but the reason is the correct statement.
(v) Assertion and reason both are correct statements but the reason is not the correct
explanation of assertion.
Answer:

The answer is the option (iv) Aldehyde and ketones both have carbonyl group but only the former undergoes reaction with Tollen’s reagent to give silver mirror.

NCERT Exemplar Class 12 Chemistry Solutions Chapter 12: Long Answer Type

Question:47

An alkene ‘A’ (Molecular formula C_{5}H_{10}) on ozonolysis gives a mixture of two compounds ‘B’ and ‘C’. Compound ‘B’ gives positive Fehling’s test and also forms iodoform on treatment with I_{2} and NaOH. Compound ‘C’ does not give Fehling’s test but forms iodoform. Identify the compounds A, B and C. Write the reaction for ozonolysis and formation of iodoform from B and C.
Answer:

As compound B turns up with a positive result for Fehling’s test, it is an aldehyde. It also gives a positive result to the iodoform test, which implies that it has a \text {-COCH}_{3} group. Compound C with a positive iodoform test and negative Fehling’s test, is a ketone.


Question:48

An aromatic compound ‘A’ (Molecular formula C_{8}H_{8}O) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. Compound ‘A’ does not give Tollens or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula C_{7}H_{6}O_{2}), which is also formed along with the yellow compound in the above reaction. Identify A, B and C and write all reactions involved.

Answer:

Molecular formula of the compound in question is C_{8}H_{8}O. It is given that ‘A’ does not give Tollens’ or Fehling’s test, making it a ketone. Since we get positive test with 2, 4-DNP and iodoform test, It means it is methyl ketone.

Question:49

Write down functional isomers of a carbonyl compound with molecular formula C_{3}H_{6}O. Which isomer will react faster with HCN and why? Explain the mechanism of the reaction also. Will the reaction lead to the completion with the conversion of whole reactant into product at reaction conditions? If a strong acid is added to the reaction mixture what will be the effect on concentration of the product and why?
Answer:

C_{3}H_{6}O_{} will have following isomer.

Compound 1 (Propanal) is more susceptible to a reaction with HCN as carbon atom in carbonyl group acquires more positive charge than carbon atom in compound 2 (propan-2-one). Moreover, there is much less static hindrance in compound 1 compared to compound 2.
Equilibrium is established in this reaction as it is reversible in nature. Addition of an acid hinders the formation of CN- ion and thus, can stop the reaction.

Question:50

When liquid ‘A’ is treated with a freshly prepared ammoniacal silver nitrate solution, it gives bright silver mirror. The liquid forms a white crystalline solid on treatment with sodium hydrogen sulphite. Liquid ‘B’ also forms a white crystalline solid with sodium hydrogen sulphite but it does not give test with ammoniacal silver nitrate. Which of the two liquids is aldehyde? Write the chemical equations of these reactions also.
Answer:

Since liquid A forms a bright silver mirror when treated with ammoniacal AgNO_{3} solution it is an aldehyde.
In the same way, liquid ‘B’ must be a methyl ketone for it does not give test with ammoniacal AgNO_{3} solution.
Chemical equations for these reactions are :

Also, check NCERT solutions for class 12, other subjects.

Studying the chapter “Aldehydes, Ketones and Carboxylic Acids” from Class 12 Chemistry NCERT exemplar solutions chapter 12 will not only help you to write IUPAC names of different ketones, aldehydes, and carboxylic acids, but will also help you to remember these for future.

Major Subtopics in NCERT Exemplar Class 12 Chemistry Solutions Chapter 12 Aldehydes, Ketones and Carboxylic Acids

  • Nomenclature and Structure of Carbonyl Group
  • Preparation of Aldehydes and Ketones
  • Physical Properties of Aldehydes and Ketones
  • Chemical Reactions of Aldehydes and Ketones
  • Uses of Aldehydes and Ketones
  • Structure of Carboxyl Group
  • Nomenclature of Carboxyl Group
  • Methods of Preparation of Carboxylic Acids
  • Physical Properties of Carboxylic Acids
  • Chemical Reactions of Carboxylic Acids
  • Uses of Carboxylic Acids
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NCERT Exemplar Class 12 Chemistry Solutions

Important Topics in NCERT Exemplar Class 12 Chemistry Solutions Chapter 12

- The physical properties and chemical reactions of very important hydrocarbons (from exams point of view) is talked about in detail

- Students will also learn about nomenclatures and various structures of different carboxyl groups with their detailed diagrams provided by Class 12 Chemistry NCERT exemplar solutions chapter 12, which again is very crucial from exam point of view.

- Studying from NCERT exemplar Class 12 Chemistry solutions chapter 12 will help students to understand the concept better

NCERT Exemplar Class 12 Solutions

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Frequently Asked Question (FAQs)

1. What will the students learn from NCERT Exemplar Class 12 Chemistry solutions chapter 12?

Students will learn about physical properties, uses and chemical reactions of very crucial hydrocarbons like Aldehydes, Ketones, and Carboxylic Acids alongside it’s nomenclatures and various structures of the carboxyl groups and the IUPAC names  of different ketones, aldehydes, and carboxylic acids.

2. Who prepared these Chapter 12 solutions?

Our Chemistry teachers prepared these NCERT Class 12 exemplar solutions for chapter 12.

3. What are the topics covered in NCERT Class 12 Chemistry Exemplar solution chapter 12?

There are the topics covered in NCERT Class 12 Chemistry exemplar solution chapter 12

  • Nomenclature and Structure of Carbonyl Group
  • Preparation of Aldehydes and Ketones
  • Physical Properties of Aldehydes and Ketones
  • Chemical Reactions of Aldehydes and Ketones
  • Uses of Aldehydes and Ketones
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Questions related to CBSE Class 12th

Have a question related to CBSE Class 12th ?
i have taken admission in clg after my campartment exam in chemistry along with the neet 2025 preperation but unfortunately i again got campartment after doing all this preparation i got 15 marks only now I can't able to think what should I do next.

You can use them people also used problem

Read Complete Answer
Divyan 06 August,2024
i scored 84 percent in cbse 2 years ago.Am i eligible for medhavi scholarship if give 12th again after 2 drop years and will got 75+ in mpboard

Hi,

The Medhavi National Scholarship Program, under the Human Resources & Development Mission (HRDM), offers financial assistance to meritorious students through a scholarship exam. To be eligible, candidates must be between 16 and 40 years old as of the last date of registration and have at least passed the 10th grade from a recognized board. Higher qualifications, such as 11th/12th grade, graduation, post-graduation, or a diploma, are also acceptable.

To apply, download the Medhavi App from the Google Play Store, sign up, and read the detailed notification about the scholarship exam. Complete the registration within the app, take the exam from home using the app, and receive your results within two days. Following this, upload the necessary documents and bank account details for verification. Upon successful verification, the scholarship amount will be directly transferred to your bank account.

The scholarships are categorized based on the marks obtained in the exam: Type A for those scoring 60% or above, Type B for scores between 50% and 60%, and Type C for scores between 40% and 50%. The cash scholarships range from Rs. 2,000 to Rs. 18,000 per month, depending on the exam and the marks obtained.

Since you already have a 12th-grade qualification with 84%, you meet the eligibility criteria and can apply for the Medhavi Scholarship exam. Preparing well for the exam can increase your chances of receiving a higher scholarship.

Read Complete Answer
Yuvan 01 September,2024
i upload 12th board result screenshot in ncweb form from the cbse site so it is valid

hello mahima,

If you have uploaded screenshot of your 12th board result taken from CBSE official website,there won,t be a problem with that.If the screenshot that you have uploaded is clear and legible. It should display your name, roll number, marks obtained, and any other relevant details in a readable forma.ALSO, the screenshot clearly show it is from the official CBSE results portal.

hope this helps.

Read Complete Answer
Ashvadha 12 July,2024
Kya mujhe class 12 ka important question milega jo exam mai per year puche jate hai

Hello Akash,

If you are looking for important questions of class 12th then I would like to suggest you to go with previous year questions of that particular board. You can go with last 5-10 years of PYQs so and after going through all the questions you will have a clear idea about the type and level of questions that are being asked and it will help you to boost your class 12th board preparation.

You can get the Previous Year Questions (PYQs) on the official website of the respective board.

I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.

Read Complete Answer
kumardurgesh1802 10 July,2024
I have completed my 12th with arts cbse. I want to repeat my 12th with pcmb. How to become a private candidate and what are deadline to be able to appear in 2025 exam?

Hello student,

If you are planning to appear again for class 12th board exam with PCMB as a private candidate here is the right information you need:

  • No school admission needed! Register directly with CBSE. (But if you want to attend the school then you can take admission in any private school of your choice but it will be waste of money)
  • You have to appear for the 2025 12th board exams.
  • Registration for class 12th board exam starts around September 2024 (check CBSE website for exact dates).
  • Aim to register before late October to avoid extra fees.
  • Schools might not offer classes for private students, so focus on self-study or coaching.

Remember , these are tentative dates based on last year. Keep an eye on the CBSE website ( https://www.cbse.gov.in/ ) for the accurate and official announcement.

I hope this answer helps you. If you have more queries then feel free to share your questions with us, we will be happy to help you.

Good luck with your studies!

Read Complete Answer
kumardurgesh1802 10 July,2024
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Popular CBSE Class 12th Questions

A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

 Option 2)

0.16\; J
Option 3)

1.00\; J

 Option 4)

0.67\; J
Read More

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

 Option 2)

 6.45×10−3 kg
Option 3)

 9.89×10−3 kg

 Option 4)

12.89×10−3 kg

 
Read More

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

 Option 2)

200 \, \, J - 500 \, \, J
Option 3)

2\times 10^{5}J-3\times 10^{5}J

 Option 4)

20,000 \, \, J - 50,000 \, \, J
Read More

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

 Option 2)

\; K\;
Option 3)

zero\;

 Option 4)

K/4
Read More

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

 Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced
Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

 Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .
Read More

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

 Option 2)

3.125 × 10-2
Option 3)

1.25 × 10-2

 Option 4)

2.5 × 10-2
Read More

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

 Option 2)

increase two fold
Option 3)

remain unchanged

 Option 4)

be a function of the molecular mass of the substance.
Read More

With increase of temperature, which of these changes?

Option 1)

Molality

 Option 2)

Weight fraction of solute
Option 3)

Fraction of solute present in water

 Option 4)

Mole fraction.
Read More

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

 Option 2)

6.023 × 1022
Option 3)

half that in 8 g He

 Option 4)

558.5 × 6.023 × 1023
Read More

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

 Option 2)

more than 3 but less than 6
Option 3)

more than 6 but less than 9

 Option 4)

more than 9
Read More

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