Principle Of Mathematical Induction Class 11th Notes - Free NCERT Class 11 Maths Chapter 4 notes - Download PDF

Principle Of Mathematical Induction Class 11th Notes - Free NCERT Class 11 Maths Chapter 4 notes - Download PDF

Edited By Ramraj Saini | Updated on Mar 22, 2022 04:43 PM IST

Class 11 Math chapter 4 notes are regarding Trigonometric functions. In chapter 4 we will be going through the Mathematical Induction concepts in Principle of Mathematical Induction Class 11 notes. This Class 11 Maths chapter 4 notes contains the following topics: Mathematical induction principles and a few examples.

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  1. NCERT Class 11 Math Chapter 4 Notes
  2. Significance of NCERT Class 11 Maths Chapter 4 Notes:
  3. NCERT Class 11 Notes Chapter Wise.

NCERT Class 11 Math chapter 4 notes also contain important formulas. NCERT Class 11 Math chapter 4 contains systematic explanations of topics using examples and exercises. NCERT Notes for Class 11 Math chapter 4 includes FAQ’s or frequently asked questions about the chapter. Every concept that is in CBSE Class 11 Maths chapter 4 notes is explained here in a simple and understanding way that can reach students easily.

All these concepts can be downloaded from Class 11 Maths chapter 4 notes pdf download, Principle of Mathematical Induction Class 11 notes, Class 11 Principle of Mathematical Induction notes pdf download.

Also, students can refer,

NCERT Class 11 Math Chapter 4 Notes

Mathematical Induction:

It is a mechanism, procedure, or technique to prove mathematical equations using a few principles. So as we use principles and solve these equations we call it the principles of mathematical induction.

3 steps to follow to solve using mathematical induction:

Let p(n) be a statement and n be a natural number:

Step 1 : (Basis Step)

L.H.S and R.H.S are equal for n=1 for given statement p(1).

Step 2 : (Introduction Step)

When the statement that is given is true for Assume(n=k), it should also be proved true for n=k+1 where we get LHS=RHS.

Step 3: (Conclusion Step)

Then we can state that proved Principles Of Mathematical Induction.

Let’s see an example:

Using the principles of mathematical induction prove the following statement :

1^2+2^2+3^2+4^2+..................+n^2 = \frac{n(n+1)(2n+1)}{6}

Ans:

Step 1:

Substitute n=1 in the given equation.

LHS= 1

RHS = n(n+1)(2n+1)/6 = 1 (1+1)(2(1)+1)/6 = 1 X 2 X 3/6 = 6/6 =1

Therefore LHS = RHS. Proved

Step 2:

Assume n=k for the given equation

Replace n with k

1^2+2^2+3^2+4^2+..................+k^2 = \frac{k(k+1)(2k+1)}{6}

Now we should prove it to be true for n=k+1

p(k+1)

Add (k+1)² on both sides of the equation

\\ (1^2+2^2+3^2+4^2+..................+k^2)+(k+1)^2 \\ \text{ we have been given} \ 1^2+2^2+3^2+4^2+..................+k^2 =\frac{k(k+1)(2k+1)}{6} \\ \frac{k(k+1)(2k+1)}{6} + (k+1)^2 \ \ \ \ \ ( LHS) \\ \frac{k(k+1)(2k+1)+6 (k+1)^2}{6} \ \ \ \ \ \ ( (k+1)as \ common \ term) \\ (k+1)\frac{(k(2k+1)+6 (k+1))}{6} \\

\\ (k+1) \frac{(2k^2+7k+6)}{6} \\ \frac{(k+1)(k+2)(2k+3)}{6} \\ \text{can be rearranged } \frac{(k+1)((k+1)+1)(2(k+1)+1)}{6} \\ \text{It is in the form of p(k+1)}

Hence proved from the principle of mathematical induction the given equation p(n) is true for n.

2. Using the principles of mathematical induction prove 7^n - 3^n is divisible by 4.

Ans:

Step 1:

Substitute n=1 in the given equation.

LHS = 7-3= 4 is divisible by 4.

LHS = RHS

Hence proved.

Step 2:

Assume n=k for the given equation

Replace n with k

7^k - 3^k =4d (d is some natural value)

Now we should prove it to be true for n=k+1

p(k+1)

Add (k+1) on both sides of the equation

\\ LHS =7^{k+1}-3^{k+1} \ \text{(add and subtract } 7.3^k) \\ 7^{k+1}-7.3^k+7.3^k-3^{k+1} \text{( common terms)}\\ 7(7^k-3^k) - 3^k( 7-3)\\ 7( 4d) - 4. 3^k\\ 4( 7d - 3^k)

As it is multiple of 4. So divisible by 4.

p(k+1) is true for p(k) .

Hence proved from the principle of mathematical induction the given equation p(n) is true for n.

With this topic we conclude NCERT class 11 chapter 4 notes.

The link for the NCERT textbook pdf is given below:

URL: ncert.nic.in/textbook/pdf/kemh104.pdf

Significance of NCERT Class 11 Maths Chapter 4 Notes:

NCERT Class 11 Maths chapter 4 notes will be very much helpful for students to score maximum marks in their 11 board exams. In Principle of Mathematical Induction Class 11 chapter 4 notes, we have discussed many topics: Mathematical induction principles and a few examples. NCERT Class 11 Maths chapter 4 is also very useful to cover major topics of the Class 11 CBSE Maths Syllabus.

The CBSE Class 11 Maths chapter 4 will help to understand the formulas, statements, rules in detail. This pdf also contains previous year’s questions and NCERT textbook pdf. The next part contains FAQ’s or frequently asked questions along with topic-wise explanations. These topics can be obtained by the Principle of Mathematical Induction Class 11 chapter 4 pdf download.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

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0.34\; J

Option 2)

0.16\; J

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1.00\; J

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0.67\; J

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2.45×10−3 kg

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 6.45×10−3 kg

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 9.89×10−3 kg

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12.89×10−3 kg

 

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2,000 \; J - 5,000\; J

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200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

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K/2\,

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\; K\;

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zero\;

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33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

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67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

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0.02

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3.125 × 10-2

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1.25 × 10-2

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2.5 × 10-2

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decrease twice

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increase two fold

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remain unchanged

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be a function of the molecular mass of the substance.

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6.023 × 1022

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less than 3

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more than 9

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