Careers360 Logo
How To Prepare Current Electricity For NSEP

How To Prepare Current Electricity For NSEP

Updated on Nov 07, 2022 03:38 PM IST

National Standard Examination In Physics (NSEP) is conducted every year by the Indian Association Of Physics Teachers (IAPT). Toppers of NSEP can attend Indian National Physics Olympiad (INPhO). To qualify for an exam like NSEP it is important to know every topic in the syllabus and the type of questions asked in the NSEP previous year question papers. Here we discuss the tips for how to prepare Current Electricity for NSEP

How To Prepare Current Electricity For NSEP
How To Prepare Current Electricity For NSEP

NSEP Syllabus For Current Electricity includes, Concepts of Electric Current, Drift Velocity, Mobility, resistance, Resistivity, Conductivity, Ohm's law, Colour Coding of Resistance, The Combination of Resistance, Cells and Combination, Electrical Energy and Power, Kirchoff's laws, Whetstones Bridge, Meter Bridge and Potentiometer.

Tips To Prepare Current Electricity For NSEP

  • Study all the concepts of NCERT book Class 12 Physics chapter Current Electricity.

  • Solve questions from NCERT book and NCERT exemplar.

  • Solve more circuit problems related to the combination of resistance and cells.

  • Understand how to apply Kirchoff's laws in circuits.

  • Solve questions based on whetstones bridge, meter bridge and potentiometer

    Current Electricity Important Formulas

    Drift Velocity(vd)

    1667804527945

    E- Electric Field

    T- Relaxation time

    E-charge of the electron

    m - the mass of the electron

    Resistance

    R=\rho\frac{l}{A}

    ⍴-resistivity

    l and A are the length and area of the conductor

    Resistivity

    1667804534800

    Current Division Rule

    1667804539655

    1667804531734

    1667804534186

    Combination Of Cells

    1667804538068

    i=\frac{nE}{R+nr}

    1667804539028

    1667804528355

    1667804535874

    1667804533372

    Potentiometer Application

    Comparison of emf:


    1667804536583

    \frac{E_{1}}{E_{2}}=\frac{l_{1}}{l_{2}}

    To determine the internal resistance of a cell:

    1667804537251

    r=(\frac{l_{1}-l_{2}}{l_{2}})R

    r=(\frac{E}{V}-1)R

    Wheatstone's Bridge

    1667804533735

    Balance Condition-

    \frac{P}{Q}= \frac{R}{S}

    V_{B} = V_{D}

    Meter Bridge


    1667804540661

    \frac{P}{Q}=\frac{R}{S}\Rightarrow S= \frac{(100-l)}{l}R

    NSEP Previous Year Questions

    Q-1- Two cells each of emf E and internal resistances r1 and r2 respectively are connected in series with an external resistance R. The potential difference between the terminals of the first cell will be zero when R is equal to(NSEP 2017)

    1667804529128


    Q-2- In the circuit shown R1 not equal to R2. The reading in the galvanometer is the same with switch S open or closed. Then(NSEP 2018)


    1667804530565

    (a) I1 = IG (b) I2 = IG (c) I3 = IG (d) I4 = IG


    Q-3- The effective resistance between points A and B in the circuit arrangement shown below is(NSEP 2018)

    1667804526220

    (a) 14 Ω. (b) 15 Ω. (c) 30 Ω. (d) none of the above.


    Q-4- In the circuit arrangement shown two cells supply a current I to a load resistance R = 9 Ω. One cell has an emf E1 = 9 V and internal resistance r1 = 1 Ω and the other cell has an emf E2 = 6 V and internal resistance r2 = 3 Ω. The currents are as shown. Then, (NSEP 2018- Morethan one option correct)

    1667804526864

    (a) I1 = 0.9 A and I2 = 0.5 A.

    (b) I 0.85 A.

    (c) if the cell of emf E1 is removed, current I will be smaller.

    (d) if the cell of emf E2 is removed, current I will be smaller.


    Q-5-

    If a cell of constant emf produces the same amount of heat during the same time in two independent resistors R1 and R2 when they are separately connected across the terminals of the cell, one after the other. The internal resistance of the cell is(NSEP 2019)

    1667804528690


    Q-6- Identify the rank in order from the dimmest to the brightest when all the identical bulbs are connected in the circuit as shown below.

    1667804532338

    (a) A= B > C = D (b) A= B = C = D (c) A> C > B > D (d) A= B < C = D


    Q-7- In the circuit shown if an ideal ammeter is connected between A and B then the direction of current and the current reading would be (assume I remains unchanged) (NSEP 2019)

    1667804525457

    a) B to A and Is /2 (b) A to B and Is /4 (c) B to A and Is /9 (d) B to A and Is /3


    NSEP Study Material For Current Electricity

    Previous Year NSEP Papers

    NCERT Physics book for class 12 part 1 chapter 3 Current Electricity

    NCERT Exemplar problems for Current Electricity

Articles

Back to top