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NCERT Solutions for Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants

NCERT Solutions for Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants

Edited By Irshad Anwar | Updated on Apr 14, 2025 04:15 PM IST | #CBSE Class 12th

NCERT Solutions Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants proves to be helpful for the students of 12th standard. NCERT Solutions explains important processes such as pollination, fertilization, and formation of seeds in easy terms. These solutions also help students understand the anatomy and functioning of various components of a flower, which is necessary to achieve maximum marks in examinations.

This Story also Contains
  1. NCERT Solutions For Class 12 Biology Sexual Reproduction in Flowering Plants
  2. Detailed NCERT Solutions for Class 12 Biology Chapter 1 (Solved Exercise)
  3. Overview of NCERT Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants
  4. Important Topics of NCERT Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants
  5. Important diagrams in Class 12 Biology Chapter 1
  6. Practice Questions for Class 12 Biology Chapter 1
  7. NCERT Solutions for Class 12 Biology: Chapter-wise
NCERT Solutions for Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants
NCERT Solutions for Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants

Correct definitions of such vital topics as microsporogenesis, megasporogenesis, and double fertilization help students to understand these terms, which are frequently requested in examinations. These answers make complex terms such as self-incompatibility and artificial hybridization simple. Constant practice using these solutions improves the confidence level of students and allows them to answer questions during exams. NCERT Solutions for Class 12 also cover the chapter with terms such as synergids, antipodals, and pollen-pistil interaction.

NCERT Solutions For Class 12 Biology Sexual Reproduction in Flowering Plants

The answers in PDF can be downloaded here:Download PDF

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Detailed NCERT Solutions for Class 12 Biology Chapter 1 (Solved Exercise)

The detailed answers to the exercise in the chapter are given below:

Q1. Name the parts of an angiosperm flower in which the development of male and female gametophytes takes place.

Answer:

In angiosperm flowers, the Gametophyte development takes place at certain sites.

  • Male gametophyte (pollen) forms within the anther's pollen sac (microsporangium).
  • Female gametophyte (embryo sac) forms inside the ovule, in the nucellus.

Q2. Differentiate between microsporogenesis and megasporogenesis. Which type of cell division occurs during these events? Name the structures formed at the end of these two events.

Answer:

Microsporogenesis and megasporogenesis are important processes in plant reproduction that have key differences. Both involve meiosis, a type of cell division.

Microsporogenesis Megasporogenesis
The process of formation of a functional haploid microspore is called microsporogenesis.The process of formation of a functional haploid microspore is called megasporogenesis.
Microsporogenesis takes place in the pollen sac of the antherMegasporogenesis takes place inside the ovule
Four functional microspores are formed as a result of microsporogenesisOnly one functional megaspore is formed as a result of megasporogenesis; the other three are degenerated
The four micropores produced as a result of microsporogenesis are arranged in a tetradThe four micropores produced as a result of megasporogenesis are arranged linearly

During microsporogenesis and megasporogenesis, meiosis occurs and results in the formation of four microspores and megaspores, respectively. Later, mitosis occurs to give rise to the microgametophyte and megagametophyte.

At the end of microsporogenesis, four functional haploid microspores are formed whereas at the end of megasporogenesis, four megaspores are formed out of which three degenerate and only one functional megaspore remains.

Q3. Arrange the following terms in the correct developmental sequence: Pollen grain, sporogenous tissue, microspore tetrad, pollen mother cell, and male gametes.

Answer:

The correct developmental sequence is as follows:

Sporogenous tissue → Pollen mother cell → Microspore tetrad → Pollen grain → male gametes

Q4. With a neat, labelled diagram, describe the parts of a typical angiosperm ovule.

Answer:

The diagram of a typical angiosperm ovule is as follows:

ovule

An ovule consists of a funicle, micropyle, integuments, nucellus, embryo sac, hilum, chalaza, etc.

  • Funicle - It is the stalk of the ovule which connects the ovule to the placenta. Funicle is short and multicellular.
  • Hilum - It is the point where the funicle connects the main body of the ovule.
  • Integuments - These are the layers that surround the ovule. There can be an outer integument and an inner integument. The main function of integuments is to protect the inner tissues.
  • Micropyle - The opening which is present at the top of integuments is called micropyle. The main function of the micropyle is to allow the entry of the pollen tube into the ovule.
  • Nucellus - Integuments surround parenchymatous tissue, which constitutes the main body of the ovule and is called nucellus. The primary function of the nucellus is to provide nutrition to the developing embryo.
  • Chalaza - The swollen part of the ovule present opposite to the micropyle is called chalaza.
  • Embryo sac - It is present in the nucellus, and it contains a female gamete called an egg.

Q5. What is meant by the monosporic development of female gametophytes?

Answer:

Monosporic development is a particular process in the development of the female gametophyte.

  • It signifies that the female gametophyte (embryo sac) develops from one functional megaspore.
  • The megaspore develops into the embryo sac through mitotic divisions.

Q6. With a neat diagram, explain the 7-celled, 8-nucleate nature of the female gametophyte.

Answer:

The diagram of 7-celled 8-nucleate embryo sacs of plants is as follows:

7- celled 8- nucleate embryo sacs

The female gametophyte of plants is formed from a single functional megaspore with the help of four unequal mitotic divisions. These mitotic divisions give rise to 8 nuclei. Later, these nuclei assemble into 7 cells. To both chalazal and micropylar ends, three cells each move. The three cells at the chalaza are called antipodal cells, while those at the micropylar end constitute the egg apparatus. The egg apparatus includes two larger cells called synergid, while the egg is the smallest cell that acts as a female gamete.

Two nuclei migrate to the centre,e and together they form a single cell called the central cell. This central cell consists of two nuclei called polar nuclei. Thus, the mature embryo sac possesses 7 cells ( 3 antipodal cells, 2 synergid cells, 1 egg cell and 1 central cell) and 8 nuclei ( 3 antipodal cells, 2 synergid cells, 1 egg cell and 2 central cells).

Q7. What are chasmogamous flowers? Can cross-pollination occur in cleistogamous flowers? Give reasons for your answer.

Answer:

Flowers can be of two types, i.e. chasmogamous flowers or cleistogamous flowers.

  • Chasmogamous flowers are open flowers which have their anthers and stigma exposed.
  • These flowers facilitate cross-pollination.
  • On the other hand, cleistogamous flowers are closed flowers whose anthers and stigmas are not exposed.
  • Since these flowers do not open at all, only self-pollination occurs in these and cross-pollination is never seen.

Thus. Cross-pollination cannot occur in cleistogamous flowers.

Q8. Mention two strategies evolved to prevent self-pollination in flowers.

Answer:

Self-pollination refers to the transfer of pollen grains from the anther of a flower to the stigma of the same flower. Continuous self-pollination can reduce the variations in the progeny and cause a reduction in vigour and vitality. Thus, plants have developed certain mechanisms to avoid self-pollination and ensure cross-pollination. The two mechanisms to prevent self-pollination are as follows:

  1. Self-sterility or self-incompatibility - In this mechanism, the pollen grains of a flower do not germinate on the stigma of the same flower. This occurs due to the presence of some self-sterile genes. This mechanism is genetic.
  2. Dichogamy- In this method, the timing of maturation of anthers and stigmas of a bisexual flower is different to prevent self-pollination.

Protandry- Anthers mature earlier than the stigma of the same flower. So, even if the pollens fall on these stigmas, they are unable to germinate. E.g. sunflower, Salvia.

Protogyny- Stigmas mature earlier than anthers and get pollinated by mature pollen grains of other flowers. E.g. Mirabilis jalapa.

Q9. What is self-incompatibility? Why does self-pollination not lead to seed formation in self-incompatible species?

Answer:

Self-incompatibility refers to the genetic inability of fully functional pollen grains and ovules to produce viable seeds.

  • This is mainly due to the presence of S or self-genes.
  • If these genes are present in pollen as well as ovules, they will not be able to produce viable seeds.
  • Self-pollination does not lead to the formation of seeds in self-incompatible species due to the presence of certain chemical substances that block the germination of pollen grains on the stigma and also obstruct their passage to the ovary.

Q10. What is the bagging technique? How is it useful in a plant breeding programme?

Answer:

The bagging technique is a tool used in plant breeding. Bagging refers to covering emasculated flowers with the help of butter paper or plastic bags to avoid contamination of the stigma of these flowers with undesired pollens.

  • This technique is used during artificial hybridisation experiments.
  • This technique is useful in breeding programmes because it prevents contamination of stigma with unwanted pollens.
  • So, through this technique, we can allow the breeding of species according to our needs and obtain superior species.

Q11. What is triple fusion? Where and how does it take place? Name the nuclei involved in triple fusion.

Answer:

A pollen grain produces two male gametes. Out of these, one male gamete fuses with the egg cell and produces a zygote. The second male gamete fuses with the two polar nuclei of the central cell to produce the primary endosperm nucleus. Since this fusion includes three haploid nuclei, it is called triple fusion.

  • The process of triple fusion occurs in the central cell of the embryo sac.
  • The pollen tube delivers one nucleus to the egg cell while the other one migrates to the centre and fuses polar nuclei.

In triple fusion, two polar nuclei and one male gamete are involved.

Q12. Why do you think the zygote is dormant for some time in a fertilised ovule?

Answer:

The zygote starts developing into an embryo only when a certain amount of endosperm has developed. This is because endosperm provides nourishment to the developing embryo. Thus, a zygote remains dormant in a fertilised ovule till the endosperm has developed.

Q13(a). Differentiate between:

(a) hypocotyl and epicotyl

Answer:

The differences between hypocotyl and epicotyl are as follows:

Hypocotyl Epicotyl
This is the portion of the embryo present below the cotyledon.This is the portion of the embryo present above the cotyledon.
Hypocotyl ends in radicleEpicotyl ends into plumule

Q13(b) . Differentiate between:

(b) coleoptile and coleorrhiza

Answer:

The differences between coleoptile and coleorhiza are as follows:

ColeoptileColeorrhiza
Coleoptile refers to the protective covering that surrounds the plumuleColeorrhiza is the sheath that surrounds the radicle and root cap
This sheath can come out of the soil, become green and perform photosynthesis.Coleorrhiza remains in the soil only.

Q13(c) . Differentiate between:

(c) integument and testa

Answer:

The differences between integument and testa are as follows:

Integument Testa
It is a ppre-fertilisationstructure that covers the ovuleIt is a post-fertilisation structure that covers the seed
The integument is a thin layer consisting of living cellsTesta is a thick coat consisting of dead cells
The integument arises from ChalazaTesta is derived from the integuments

Q13(d). Differentiate between:

(d) perisperm and pericarp

Answer:

The differences between the perisperm and pericarp are as follows:

PerispermPericarp
Perisperm refers to the residual persistent nucellusThe pericarp is the wall of the fruit derived from the ovary wall
Perisperm is non-functional to the seedThe function of the pericarp is the protection of the inside structures
It is dryIt is fleshy.

Q14. Why is an apple called a false fruit? Which part(s) of the flower forms the fruit?

Answer:

The fruits are formed from the ovary of a flower after fertilisation.

  • Such fruits that develop from the ovary are called true fruits.
  • On the other hand, fruits formed from any part of the flower other than the ovary are called false fruits.
  • Apple is called a false fruit because it develops from the thalamus and not from the ovary.
  • The parts of flowers that take part in fruit formation are the ovary, thalamus, etc.

Q15. What is meant by emasculation? When and why does a plant breeder employ this technique?

Answer:

The process of removal of anthers from the flower with the help of forceps without affecting the female reproductive parts is called emasculation. This technique is used by plant breeders to allow suggestive breeding between plants to produce plants with desired seeds. Hence, it can be used to prevent self-pollination or cross-pollination according to the needs of the breeder.


Q16. If one can induce parthenocarpy through the application of growth substances, which fruits would you select to induce parthenocarpy and why?

Answer:

The fruits formed as a result of parthenocarpy are generally seedless. Hence, for parthenocarpy, we can select fruits which have a lot of seeds in them. Such fruits include watermelon, orange, muskmelon, lemon, etc. So we can select watermelon to induce parthenocarpy because by this method we can have seedless watermelons.

Q17. Explain the role of the tapetum in the formation of the pollen-grain wall.

Answer:

The tapetum is the nutritive innermost layer of the microsporangium that provides nutrition to the developing microspores. The role of the tapetum in the formation of the pollen grain wall is as follows:

  • Tapetum secretes ubisch granules required for the formation of sporopollenin in the exine (outer wall) of the pollen grain
  • Tapetum also secretes pollen kit substances required for the formation of the pollen grain wall

Q18 . What is apomixis, and what is its importance?

Answer:

The process of development of seeds from diploid cells of nucellus tissue without the process of fertilisation is called apomixis. This process is a form of asexual reproduction that mimics sexual reproduction. Apomixis is very commonly seen in grasses.

Importance of apomixis

  • Apomixis is used by horticulturists to produce hybrid seeds.
  • Apomixis leads to the formation of infection-free embryos.
  • Apomixis can be used to produce multiple embryos at a time.
  • Apomictic embryos are genetically similar to their parent plants. For this reason, they can be used to conserve specific characteristics in crop plants.

NCERT Solutions for Class 12- Subject-wise

How do you solve NCERT Class 12 Biology Chapter 1 questions effectively?

To effectively solve Sexual Reproduction in Flowering Plants questions, follow these steps:

  1. Be aware of the structure of a flower, including reproductive organs like stamens and pistils.
  2. Gain information about the nature of pollination (self and cross-pollination) as well as their vectors.
  3. Note events like pollen-pistil interaction, double fertilization, and post-fertilization events.
  4. Keep in mind terms like microsporogenesis, megasporogenesis, and embryo sac development.
  5. Practice flower, pollen grain, and ovule structure diagrams for clarity.
  6. Rephrase the significance of seed dispersal and fruit formation for clarity in concepts.
  7. Try previous year questions and sample papers for practice in depth.

Overview of NCERT Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants

This chapter is all about flowers giving rise to new flowers. We will be talking about flower parts, how pollen and eggs are formed, and how they come together to form seeds and fruits. It's a romance between flowers!

1. Flower Parts

Flowers have different parts, including:

  • Sepals: The green ones that cover the flower bud.

  • Petals: The colourful ones that bring insects in.

  • Stamens: The male ones, which form pollen.

  • Carpels: The female parts, where the eggs are contained.

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2. Pollen Development

  • Microsporogenesis: Development of the pollen grains within the stamen.

  • Pollen grains have two layers:

  1. Exine: The hard outer wall to covers the pollen.

  2. Intine: Soft inner wall.

  • Two cells within the pollen grain: one which will develop sperm and the other that enables the pollen to travel.

  • Tapetum is a food-providing layer for developing pollen grains.

3. Egg Formation

  • Megasporogenesis: The formation of the egg within the ovule (carpel structure).

  • A cell becomes a megaspore, which forms the embryo sac (where the egg is found).

  • The embryo sac is specially organized with 7 cells and 8 nuclei.

4. Pollination

  • Pollination is the transfer of pollen from the stamen to the carpel.

  • There are two primary types:

  1. Self-pollination: Pollen falls on the same flower.

  2. Cross-pollination: Pollen falls on another flower.

  • Pollination is accomplished by various agents like insects, wind, and water.

5. Production of Flower (Fertilization)

  • Fertilization is the joining of sperm from the pollen and the egg.

  • Double fertilization occurs in flowering plants:

  • One sperm fuses with the egg to produce the embryo.

  • The second sperm fuses with two other nuclei to produce the endosperm (food for the embryo).

6. Seed Development

  • After fertilization, the ovule is converted into a seed.

  • The endosperm supplies the embryo with nourishment.

  • Seeds can be dormant or germinate in good conditions.

7. Fruit Development

  • After fertilization, the ovary becomes a fruit.

  • True fruits develop from the ovary.

  • False fruits develop from other floral parts (e.g., the apple).

  • Parthenocarpy is the development of fruits without fertilization (seedless fruit).

8. Plant Breeding

  • Plant breeders employ methods such as emasculation (deflowering and removal of anthers) and bagging (enclosing the flower) for controlling pollination and developing novel plant varieties.

9. Special Cases

  • Apomixis: A special form of asexual reproduction whereby seeds are developed without fertilization.

  • Polyembryony: When a seed has more than one embryo.

Important Topics of NCERT Class 12 Biology Chapter 1 Sexual Reproduction in Flowering Plants

Some important topics are given below:

Topic

Description

Flower Parts

Sepals, petals, stamens, carpels, and their functions in reproduction.

Pollen Formation

Microsporogenesis: the development of pollen grains in the stamen, including the role of the tapetum.

Egg Formation

Megasporogenesis: the development of the embryo sac and egg inside the ovule.

Pollination

The transfer of pollen from the stamen to the carpel, including types (self, cross) and agents.

Fertilization

Double fertilization: the fusion of sperm with the egg and the formation of the endosperm.

Seed Development

The development of the ovule into a seed, including the role of the endosperm and the processes of dormancy and germination.

Fruit Development

The development of the ovary into a fruit, including true fruits, false fruits, and parthenocarpy.

Plant Breeding

Techniques such as emasculation and bagging used to control pollination and create new plant varieties.

Apomixis/Polyembryony

Asexual reproduction through seeds and the formation of multiple embryos in a single seed.

ParthenocarpyThe development of fruit without fertilization, resulting in seedless fruits.

Important diagrams in Class 12 Biology Chapter 1

Here are some important diagrams from Sexual Reproduction in Flowering Plants:

  1. Longitudinal Section of a Flower
    This diagram shows the internal structure of a flower, highlighting reproductive organs such as stamens and pistils.Longitudinal Section of a Flower
  2. Transverse Section of a Young Anther
    This diagram shows the detailed structure of an anther, including microsporangia where pollen grains are formed.detailed structure of an anther
  3. Microsporogenesis (Pollen Grain Tetrad Formation)
    A sequence showing the development of microspores into pollen grains through meiosis.Microsporogenesis
  4. Stages of Double Fertilization
    Diagram showing how one sperm fertilizes the egg while another forms the endosperm.Double Fertilization

Practice Questions for Class 12 Biology Chapter 1

Question 1: What is emasculation, and why is it practiced?

Answer: Emasculation means excising the anthers or the stamens of a bisexual flower so that artificial hybridization would not result in self-pollination.

Question 2: What is double fertilization in flowering plants?

Answer: Double fertilization refers to two fusion processes: one where one sperm unites with the egg and gives rise to a zygote and another where yet another unites with the polar nuclei and develops into the endosperm.

Question 3: What are the advantages of sexual reproduction in plants

Answer: Sexual reproduction ensures genetic diversity, promotes evolution, and enhances plant versatility.

Question 4: Define apomixis and compare it to sexual reproduction.

Answer: Apomixis is asexual seed growth without fertilization to yield genetically similar offspring, which is the opposite of sexual reproduction by recombination of genetics.

Question 5: Name the male and female floral reproductive structures.

Answer: Male is stamen (filament + anther) and female is pistil (stigma + style + ovary).

NCERT Solutions for Class 12 Biology: Chapter-wise

Below mentioned are the Chapterwise solutions:

A clear understanding of photosynthesis by NCERT solutions is quite beneficial to the students as it provides a fundamental understanding of plant life and ecological activities. Understanding fundamental concepts such as the light-dependent and light-independent reactions, and the crucial functions of chlorophyll and enzymes, not only prepares students for exams but also enhances their concept of the sophisticated mechanisms sustaining life on Earth. Through these NCERT solutions, the students gain a firm foundation, which improves their educational skills and develops an ongoing sense of inquiry towards nature.

NCERT Exemplar Class 12 Solutions

Frequently Asked Questions (FAQs)

1. What is sexual reproduction in flowering plants according to NCERT Class 12 Biology?

Sexual reproduction in flowering plants involves the fusion of male and female gametes, resulting in a diploid zygote. This process occurs within flowers, specifically through pollination, fertilization, and subsequent seed development

2. What are the important topics which are mentioned in NCERT solution for class 12 biology chapter 1 sexual reproduction in flowering plants?

These are the important topics which are mentioned in NCERT solutions for class 12 biology chapter 1 sexual reproduction in flowering plants:   

  • Flower - A Fascinating Organ of Angiosperms  
  • Pre - Fertilisation: Structures and Events  
  • Stamen, Microsporangium and Pollen Grain  
  • The Pistil, Megasporangium (ovule) and Embryo sac  
  • Pollination  
  • Double Fertilization  
  • Post - Fertilisation: Structures and Events  
  • Endosperm  
  • Embryo  
  • Seed  
  • Apomixis And Polyembryony 
3. Why you should use NCERT solutions for class 12 biology chapter 1 sexual reproduction in flowering plants?
  • NCERT is the base, especially for CBSE students.  
  • In NCERT solutions for class 12 biology chapter 1 sexual reproduction in flowering plants, you will get all the answers to this chapter and it will help you to score good marks in the exam.  
  • This will also help you to score good marks in competitive exams like NEET.  
  • NCERT solutions also help you in your 12th board exam.  
  • class 12 biology ch 1 ncert solutions sexual reproduction in flowering plants will also boost up your knowledge.  
  • To Score Well in the examination, follow NCERT syllabus and exercise given in the NCERT Book. To practice more problems, students can refer to NCERT exemplar  
4. What are the difference between coleoptile and coleorrhiza given in class 12 biology chapter 1?

The differences between coleoptile and coleorrhiza given in class 12 biology ch 1 ncert solutions are as follows:  

  Coleoptile  
  Coleorrhiza  
Coleoptile refers to the protective covering that surrounds plumule  
Coleorrhiza is the sheath that surrounds the radicle and root cap  
This sheath can come out of the soil, become green and perform photosynthesis.  
Coleorrhiza remains in the soil only.  
5. How does pollination occur in flowering plants as explained in NCERT?

In flowering plants, pollination, as described in NCERT, is the transfer of pollen grains from the anther (male part) to the stigma (female part) of a flower, enabling fertilization and seed development.

6. What are the different types of pollination mentioned in NCERT Class 12 Biology Chapter 1?

In NCERT Class 12 Biology Chapter 1, "Sexual Reproduction in Flowering Plants," discusses two main types of pollination: self-pollination (autogamy and geitonogamy) and cross-pollination (xenogamy), with autogamy occurring within the same flower and geitonogamy between different flowers on the same plant.

7. How does seed formation occur in plants according to NCERT?

According to NCERT, seed formation in flowering plants (angiosperms) begins with pollination, followed by fertilization where a male gamete fuses with a female gamete, resulting in a zygote that develops into an embryo within the ovule, which then matures into a seed. 

8. Why is double fertilization unique to angiosperms?

Double fertilization, where one sperm fuses with the egg to form a zygote and another fuses with two polar nuclei to form endosperm, is unique to angiosperms (flowering plants) because this process is crucial for their reproductive success, specifically for seed and fruit development.

9. What are the different types of ovules found in flowering plants?

Flowering plants exhibit different ovule types based on their orientation and curvature, including orthotropous, anatropous, campylotropous, amphitropous, and circinotropous ovules.

10. How does pollen-pistil interaction take place in sexual reproduction?

Pollen-pistil interaction, crucial for sexual reproduction in flowering plants, involves a series of events from pollen deposition on the stigma to the formation of the pollen tube and fertilization, including pollen recognition, germination, and tube growth. 

11. What is the structure and function of an embryo sac in plants?

The embryo sac, or female gametophyte, is a crucial structure in flowering plants, residing within the ovule, and plays a vital role in reproduction by facilitating fertilization and embryo development.

12. How does artificial hybridization help in plant breeding?

Artificial hybridization in plant breeding allows breeders to control pollination and cross-pollinate plants. They breed with specific desirable traits, leading to improved crop varieties with traits like disease resistance, higher yield, or better quality.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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