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NCERT Exemplar Class 11 Biology Solutions Chapter 15 Plant Growth and Development

NCERT Exemplar Class 11 Biology Solutions Chapter 15 Plant Growth and Development

Edited By Irshad Anwar | Updated on Apr 23, 2025 01:12 PM IST

NCERT Exemplar Class 11 Biology Solutions chapter 15: The chapter provides a deep understanding of various stages of life in plants and how certain factors affect them. The chapter covers key concepts such as plant growth phases, hormones, seed dormancy, etc. Students can refer to these explanations to improve their conceptual clarity which will help them in exams. Practising MCQ helps in exam preparation effectively. The NCERT exemplar solutions provide a variety of objective-type questions and their answers to test the application of concepts in real-life scenarios.

This Story also Contains
  1. NCERT Exemplar Class 11 Biology Chapter 15 Solutions Multiple Choice Questions
  2. NCERT Exemplar Class 11 Biology Chapter 15 Solutions -Very Short Answer Question:
  3. NCERT Exemplar Class 11 Biology Chapter 15 Solutions-Long Answer Type Questions:
  4. NCERT Exemplar Class 11 Biology Chapter 15 Solutions- Short Answer Type Questions:
  5. How do you solve Class 11 Biology Chapter 15 Solutions questions effectively?
  6. Major Topics and Subtopics in NCERT Class 11 Biology Chapter 15 Plant Growth and Development
  7. Extra MCQs from NCERT Exemplar Class 11 Biology Chapter 15
  8. NCERT Exemplar Class 11 Biology Chapter- Wise Solutions
NCERT Exemplar Class 11 Biology Solutions Chapter 15 Plant Growth and Development
NCERT Exemplar Class 11 Biology Solutions Chapter 15 Plant Growth and Development

By consistently working through these resources, studying the MCQs regularly enhances analytical thinking and accuracy in exams. Students can ensure a strong understanding of Chapter 15 and improve their overall science scores. These solutions give students an extra edge while attempting the problems given in the NCERT Class 11 Biology Book.

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NCERT Exemplar Class 11 Biology Chapter 15 Solutions Multiple Choice Questions

Different forms of questions, like MCQs, short answers, and long answers with the required diagrams, are provided below. Practising these will help you understand the pattern and these concepts easily and effectively.

Question:1

Ethylene is used for

(a) Retarding ripening of tomatoes
(b) Hastening of ripening of fruits
(c) Slowing down the ripening of apples
(d) Both b and c

Answer:
The answer is option (b) Hastening the ripening of fruits Ethylene is a naturally composed hormone within fruits and monitors the ripening of the fruit by inducing and regulating many chemical and biochemical activities.

Question:2

Coconut water contains
(a) ABA
(b) Auxin
(c) Cytokinin
(d) Gibberellin

Answer:
The answer is the option (c) Cytokinin
Coconut water hosts an abundance of cytokinin, which helps regulate cell growth and cell division.

Question:3

The effect of apical dominance can be overcome by which of the following hormones:
(a) IAA
(b) Ethylene
(c) Gibberellin
(d) Cytokinin

Answer:

The answer is the option (d) Cytokinin
During apical dominance, cytokinin antagonises the auxin and triggers outgrowth. The presence of cytokinin can induce the movement of nutrients towards the site where it is present. In lateral buds, the cytokinin present encourages growth despite the lateral buds having apical buds.

Therefore, cytokinin is antagonistic to auxin, and thus apical dominance can be overcome through the use of
cytokinin.

Question:4

Match the Following

Column IColumn II
A. IAAi) Herring sperm DNA
B. ABAii) Bolting
C. Ethyleneiii)Stomatal closure
D.GAiv) Weed-free lawns
E. Cytokinesv) Ripening of fruits


Options:
(a) A- (iv), B - (iii), C -(v), D - (ii), E- (i)
(b) A- (v), B - (iii), C -(iv), D - (ii), E- (i)
(c) A- (iv), B - (i), C -(v), D - (iii), E- (ii)
(d) A- (v), B - (iii), C -(ii), D - (i), E- (iv)

Answer:

The answer is the option (a) A- (iv), B - (iii), C -(v), D - (ii), E- (i)

Question:5

Apples are generally wrapped in waxed paper to

(a) Prevent sunlight from changing its colour
(b) Prevent aerobic respiration by checking the entry of O2
(c) Prevent ethylene formation due to injury
(d) Make the apples look attractive

Answer:
The answer is option (b) Prevent aerobic respiration by checking the entry of O2.
To avoid the ripening of the apple, in order for it to stay fresh for a much longer time, aerobic respiration is prevented because it makes the apple rot much faster.

Question:6

Growth can be measured in various ways. Which of these can be used as parameters to measure growth?

(a) Increase in cell number
(b) Increase in cell size
(c) Increase in length and weight
(d) All the above

Answer:

The answer is option (d) All the above
The growth can be in lateral or apex regions and can cause an enlargement in height or weight; all of these changes are collectively termed growth.

Question:7

The term synergistic action of hormones refers to

(a) When two hormones act together but bring about the opposite effect
(b) When two hormones act together and contribute to the same function
(c) When one hormone affects more than one function
(d) When many hormones bong about anyone's function

Answer:

The answer is option (b) When two hormones act together and contribute to the same function.

When two or more hormones function mutually to deliver a certain effect, their outcomes are called synergistic. These results can be additive or complementary.

Question:8

Plasticity in plant growth means that
(a) Plant roots are extensible
(b) Plant development is dependent on the environment
(c) Stems can extend
(d) None of the above

Answer:
The answer is option (b) Plant development is dependent on the environment.
Plants take distinct paths in response to environmental changes and different stages of life to develop various types of compositions. This entire ability is called plasticity.

Question:9

To increase sugar production in sugarcanes, they are sprayed with
(a) IAA
(b) Cytokinin
(c) Gibberellin
(d) Ethylene

Answer:

(c) Gibberellin
Explanation: Gibberellin increases the length of the stem and thus increases the amount of sugar in sugarcane.

Question:10

ABA acts antagonistically to

(a) Ethylene
(b) Cytokinin
(c) Gibberellic acid
(d) IAA

Answer:

The answer is the option (c) Gibberellic acid
ABA's function is to inhibit growth and to be antagonistic to it; the correct option should encourage and promote growth and gibberellin does, so it is the correct option.

Question:11

Monocarpic plants are those which

(a) Bear flowers with One ovary
(b) Flower once and die
(c) Bear only one flower
(d) All of the above

Answer:

The answer is option (b) Flower once and die.
Monocarpic plants are known to flower, set seeds and then die consequentially.

Question:12

The photoperiod in plants is perceived at

(a) Meristem
(b) Flower
(c) Floral buds
(d) Leaves

Answer:

The answer is the option (d)Leaves
Leaves are the primary producers and receive light energy and thus are key players in the photoperiod.

Question:3

A primary root grows from 5 cm to 19 cm in a week. Calculate the growth rate and relative growth rate over the period.

Answer:
The absolute Growth rate can be calculated as follows:
W1=W0ert
Where W1 = final Size (weight, height, number etc.)
W0 = initial Size at the beginning of the period
r = growth rate
t= time of growth
e = base of natural logarithms
Here, r is the relative growth rate
Given W1 = 19 cm
W0 = 5 cm
t =7 days
or,
Using W1 = W0 ert
Weget19=5×(2.7)7r
Then
Then 3.8=(2.7)7r
Then taking log on both sides,
log3.8=7r×log2.7
Then, 0.5798=7r×0.4314

r=0.57987×0.4314
Or r=0.1907
The relative growth rate can be calculated as follows:
r=finalsizeinitialsize
r=195
r = 3.8 cm
Absolute growth rate=0.1907
Relative growth rate 3.8cm

Question:4

Gibberellins were first discovered in Japan when rice plants were suffering from bakane (the foolish seedling disease) caused by the fungus Gibberena fujikuroi.

(a) Give two functions of this phytohormone.

(b) Which property of gibberellin caused foolish seedling disease in rice?

Answer:

(a) Two functions of the Gibberellin phytohormone are that encourage the sprouting of the seed by disruption of seed dormancy. In rosette plants, gibberellin induces the development of internodes; it encourages the process of bolting.

(b) The surplus quantity of gibberellin produced by the fungus causes foolish seedling disease in rice. The surplus of gibberellin thus induces the plants' development and hastens the growth in internodes. This thus results in the plant growing too tall and being
unable to bear its own weight.

Question:5

Gibberellins promote the formation of __________ flowers on genetically _____ plants in Cannabis, whereas ethylene promotes the formation of _________ flowers on genetically _______ plants.

Answer:
male, female, female, male

Gibberellins promote the formation of male flowers on genetically female plants in Cannabis, whereas ethylene promotes the formation of female flowers on genetically male plants.


Question:6

Classify the following plants into Long-Day plants (LDP), Short-Day plants (SDP) and Day Neutral Plants (DNP): Xanthium. Henbane (Hyoscyamus niger), Spinach, Rice, Bryophyllum, Sunflower, Tomato, Maize, Strawberry

Answer:

Long-Day plants (LDP)Short Day plants (SDP)Day Neutral Plants (DNP)
BryophyllumXanthiumSunflower
Henbane (Hyoscyamus niger)RiceTomato
SpinachStrawberryMaize


Question:7

A farmer grows cucumber plants in his field. He wants to increase the number of female flowers in them. Which plant growth regulator can be applied to achieve this?

Answer:

Ethylene
Ethylene encourages the development and increases the number of female flowers in monoecious species as it is known to be a growth regulator that has a feminising effect.

Question:8

Where are the following hormones synthesised in plants
(a) IAA
(b) Gibberellins
(c) Cytokinins

Answer:
(a) IAA is synthesised mainly in the shoot apices, primarily in the growing apices of plants. This includes the leaf primordial and developing seeds.

(b) Gibberellin hormone is synthesised in plants primarily in apical shoot buds, root tips as well as developing seeds.

(c) Cytokinin is synthesised in plants primarily in roots, endosperm region in the seeds as well as developing shoot buds and growing embryos.

Question:9

In botanical gardens and tea gardens, gardeners trim the plants regularly so that they remain bushy. Does this practice have any scientific explanation?

Answer:
Regular trimming makes the plants bushy as this growth is primarily based on the apical dominance of the plants. The apical dominance thus does not allow and in fact, prevents the growth of nearby lateral buds. This happens through the release of certain
auxins. If the shoot apex or the apical bud is removed, then the lateral buds can grow and sprout. This can lead to bushy growth.

Question:10

Light plays an important role in the life of all organisms. Name any three physiological processes in plants which are affected by light.

Answer:

The physiological processes in plants which are affected by light are: -

  • Photosynthesis,
    This is the process through which the plant manufactures its own food in the presence of sunlight by utilising inorganic substances.
  • Transpiration
    This is the process by which plants experience water loss in the form of vapour or dew formed on the leaves, primarily through the stomata. This process requires sunlight as the stomata are active and functioning only in the presence of sunlight.
  • Photoperiodism
    This process typically decides the flowering of the plant, and the number of light hours affects this growth.


Question:11

In the figure of Sigmoid growth curve given below, label segments 1, 2 and 3.

Answer:

Sigmoid growth curve

  1. Lag phase.
  2. Exponential phase and
  3. Stationary phase


Question:12

Growth is one of the characteristics of all living organisms. Do unicellular organisms also grow? If so, what are the parameters?

Answer:
Growth is a process which marks the distinction between living and non-living beings. Unicellular organisms do not experience technical growth in length or volume, unlike their multicellular counterparts. In unicellular organisms, growth is synonymous and characterised by reproduction. The process of cell synthesis divides the cell into two daughter cells.


Question:13

The rice seedlings infected with the fungus Gibberella fujikuroi are called foolish seedlings. What was the reason behind it?

Answer:

The rice seedlings infected with the fungus Gibberella fujikuroi are called foolish seedlings because the rice plants which get infected with the fungus grow excessively in length in comparison to the plant species that are not infected. The height of the plant becomes disproportionate and is too much for the plant to bear, and it cannot support the weight of the plant, which leads to the plant's death ultimately. Hence, the plant causes its own death due to the infection by the fungus and is called foolish seedlings.

NCERT Exemplar Class 11 Biology Chapter 15 Solutions-Long Answer Type Questions:

The detailed answers to the Long Answer questions are given below:

Question:1

Some varieties of wheat are known as spring Wheat While Others are called winter wheat. The former variety is sown and planted in spring, and it is harvested by the end of the same season. However, winter varieties; if planted in spring, fail to flower, or produce mature grains within a span of a flowering season. Explain, why.

Answer:

Some plants require special extrinsic conditions in order to commence the flowering stage, and one of the requirements can be a low temperature. Thus, the plants remain vegetative during the summer season and wait till they receive a low temperature to begin bearing flowers. Waiting for lower temperatures helps prevent precocious early active reproductive development. This helps the plant to gain proper maturity and develop within the vegetative state before advancing to the reproductive stage. This is called the vernalisation. Some plants have separate spring and winter varieties. For example, spring wheat is planted in the spring season and comes to flower and fruit right at the end of the season, but if the winter varieties are sown in the same season, then it will not bear flowers and fruits as compared to the spring variety.

Instead, the winter is planted in the autumn, and during the winter they form the seedlings. The seedlings resume their growth in the spring season and bear flowers during the summer. The winter wheat requires specific low temperatures to begin sprouting and maturing.

Question:2

It is known that some varieties of wheat are sown in autumn but are harvested around mid-summer.
(a) What could be the probable reason for this?
(b) What term is used for this promotion of flowering under low temperatures?
(c) Which plant hormone can replace the cold treatment?

Answer:
(a) These plants usually germinate and grow as seedlings throughout winter. They only resume growth when it is summer and are finally harvested around the upcoming midsummer. This is because these plants require low temperatures to bear flowers and
fruits and are able to finish their vegetative phase of growth over the period of winter and summer.
(b) This process mentioned here is called vernalisation.
(c) Gibberellin hormone can replace cold treatment effectively.

Question:3

Name a hormone which
(a) is gaseous in nature
(b) is responsible for phototropism
(c) induces femaleness in flowers of cucumber
(d) is used for killing weeds (dicots)
(e) induces flowering in long-day plants

Answer:
(a) Ethylene hormone is gaseous in nature.
(b) Auxin is responsible for phototropism.
(c) Ethylene hormone induces female characters in the flowers of cucumbers.
(d) Synthetic auxin (2,4-D) is used to kill weeds
(e) Gibberellin hormone induces flowering in long-day plants

NCERT Exemplar Class 11 Biology Chapter 15 Solutions- Short Answer Type Questions:

The detailed answers to the Short Answer questions are given below:

Question:1

Nicotiana tabacum, a Short-Day plant, when exposed to more than critical light fails to flower. Explain.

Answer:

Nicotiana tabacum is a short-day plant, and these plants require much less exposure to light than the required amount in normal plants. They demand a continuous critical dark period, which if interrupted, can affect the flowering of the plant. These plants require a photoperiod less than the generally required one and play a key role in flowering. This is due to the fact that flowering is regulated by a hormone which is present in the leaves and requires the dark photoperiod to migrate to the required places in the shoot apices.

Question:2

What are the structural characteristics of

(a) Meristematic cells near the root tip

(b) The cells in the elongation zone of the root

Answer:
(a) Meristematic cells are located in the zone, which is the growing point of the root, and in an active state of cell division. The cells are closely arranged and thin-walled and have dense protoplasm. They are essential for the growth of roots.

(b) In this zone, the cells are newly formed and lose the ability to divide, which is why they elongate and rapidly increase the length of the root. They have a large number of small vacuoles. These vacuoles fuse to form one large central vacuole. This is what
causes the cells to elongate and longitudinally grow in this region.

Question:3

Does the growth pattern in plants differ from that in animals? Do all the parts of the plant grow indefinitely? If not, name the regions of the plant, which can grow indefinitely.

Answer:

Animals and plants have different growth patterns and habits. Animals experience growth of definite, determinate form, which means they experience limited growth or stop growth after attaining maturity. Plants, on the other hand, can experience growth of definite or indefinite and indeterminate form. They can stop growing after attaining maturity of developing leaves and flowers or parts like the stem, and their branches can continue to grow. Plants experience continuous growth since they contain meristematic areas with potential for cell division, whereas animals have cell division only to replace and repair and not for the purpose of growth.

Question:4

Explain in 2-3 lines each of the following terms with the help of examples taken from different plant tissues:
(a) Differentiation
(b) De-differentiation
(c) Redifferentiation

Answer:

(a) To facilitate growth, the meristematic cells through mitotic division, divide into daughter cells. The cells ranging from the root to the shoot apical meristem are separated into different categories as they have matured and can perform specific functions. This phenomenon is called differentiation. During this phase, the cells experience critical structural modifications in the protoplasm and cell wall.

(b) Under certain conditions, the differentiated living cells can divide mitotically after recovering the ability to divide. This phenomenon is called de-differentiation. Sometimes, the de-differentiated cell may become the meristem; for example, fully differentiated parenchyma cells form the meristems and interfascicular cambium and cork cambium.

(c) The cells formed by de-differentiated cells can lose their capacity to reproduce and thus mature to perform specific functions. This is known as redifferentiation. For example, the secondary cortex and cork are prime examples as well as the cambium which de-differentiates to form the cortex.

Question:5

Auxins are growth hormones capable of promoting cell elongation. They have been in horticulture to promote growth, flowering, and rooting. Write a line to explain the meaning of the following terms related to auxins.
(a) Auxin precursors
(b) Anti-auxins
(c) Synthetic auxins

Answer:
(a) Auxin precursors are the raw substances utilised in the process of initial making and synthesis of auxins. For example- IAA's auxin precursor is tryptophan.
(b) Anti-auxins are compound substances which restrict the action of auxins. For example, TIBA and p-chlorophenoxy isobutyric acid (PCIB).
(c) Synthetic auxins are auxins which are artificially synthesised and do not occur naturally in plants. For example, 2:4-D, NAA.

Question:6

The role of ethylene and abscisic acid is both positive and negative. Justify this statement.

Answer:

Both ethylene and abscisic acid have positive and negative effects.
Positive Effects of Ethylene:

  • Ethylene acts as a hormone which induces apical dominance and encourages horizontal growth
  • It interrupts the dormancy of seeds and buds
  • Ethylene aids in the initiation of the root
  • Ethylene also helps in the ripening of certain fruits

Negative Effects of Ethylene:

  • Ethylene causes the abscission of leaves because it hastens the senescence of leaves
  • Ethylene delays longitudinal development in the plant
  • Ethylene extends the dormancy of lateral buds

Positive Effects of Abscisic Acid:

  • Helps reduce water loss in the form of transpiration
  • Induces flowering in short-day plants
  • In certain plants such as Rosen, abscisic acid encourages parthenocarpic development as well as the rooting of stem-cutting
  • Helps plants form resistance to environmental stress
  • Promotes root initiation in certain plants

Negative Effects of Abscisic Acid:

  • Encourages the abscission of flowers and fruits and induces leaf senescence.
  • Inhibits and slows down the cambial activity
  • Retards the effect and functioning of growth hormones.
  • Promotes dormancy in seeds and

Question:7

While experimenting, why do you think it is difficult to assign any effect seen to any single hormone?

Answer:

Plant hormones mostly work together, complementary to each other. Plant hormones can have both synergistic and antagonistic interactions which affect the plant tissues. A single hormone can have multiple effects, while multiple hormones can target and aim to achieve just one effect. Therefore it can be exceedingly difficult to identify one single hormone according to its particular effect on plant metabolism and system. Moreover, plant hormones function in the presence of a lot of extrinsic factors which are needed for the reaction. Thus, it is difficult to assign any effect seen to any single hormone.

Question:8

What is the mechanism underlying the phenomenon by which the terminal/apical bud suppresses the growth of lateral buds? Suggest measures to overcome this phenomenon.

Answer:
This phenomenon by which the terminal/apical bud suppresses the growth of the lateral buds is called apical dominance. On removal of the apical bud, the lateral buds are allowed to sprout, which produces bushy growth. The apical bud restricts the growth of the lateral buds through the release of certain auxins. Thus the auxin causing apical dominance can be countered with cytokinin. This attracts nutrients and helps the lateral buds to grow by acting as an antagonistic.

Question:9

In animals, there are special glands secreting hormones, whereas there are no glands in plants. Where are plant hormones formed? How are the hormones translocated to the site of activity?

Answer:
Plant hormones are produced by individual cells in the regions where they are essential to the plants. To take an example, auxin is synthesised in the cells where there are growing apices. The vascular system of plants is where plant hormones are translocated through. Other examples include the Abscisic acid produced in many parts of plants, which is transported through diffusion and transport channels.

Question:10

Many discoveries in science have been accidental. This is true for plant hormones also. Can you justify this statement by giving an example? Also, what term is used for such accidental findings?

Answer:

Various plant hormones and other scientific research have been led by accidental means. Gibberellin was discovered accidentally, and Charles Darwin and his son Francis Darwin accidentally came across the auxin. They noticed that coleoptiles of canary grass reacted to unilateral illumination through growth in the direction of light. After some time, F W Went separated auxin from coleoptiles of oat seedlings.

The term used for accidental discovery is 'serendipity'

Question:11

To get carpet-like grass lawns are mowed regularly. Is there any scientific for this?

Answer:

Ans. Mowing regularly means the trimming of the apical parts of the plant, which thus causes the sprouting and faster growth of lateral branches. Thus apical dominance is prevented and restricts the longitudinal growth of the plant. Since the apices are removed, the auxins released due to the apical buds inhibit the lateral buds from getting mobilised and encourage the growth of lateral branches. This helps in maintaining carpet-like lawns.

Question:12

In a slide showing different types of cells can you identify which type of the cell may be meristematic and the one which is incapable of dividing and how?

Answer:

The presence of the following characteristics would indicate meristematic cells in the slides showing different types of cells:

(a) Thin cellulose wall
(b) Dense cytoplasm with a large nucleus
(c) Cells displaying cell division, like mitosis and other various stages.
(d) Smaller-sized vacuoles or even negligible vacuoles.

If the above features are absent, then it can be determined that the cells are incapable of division.

Question:13

A rubber band stretches and reverts to its original position. Bubble gum stretches, but it does not return to its original position.

Is there any difference between the two processes? Discuss it with respect to plant growth.

[Hint: Elasticity (reversible) plasticity (irreversible)]

Answer:

Referring to an experiment with oat coleoptile, the auxin hormone induces the shoot tip tending in the direction of the light source. This process is irreversible and is known as plasticity. It is the plant's ability to adjust to the surrounding environmental
conditions. While, if weight is attached to the coleoptile segment, the weight causes bending and thus stretches the plant. If the weight is removed, the shoot of the plant returns to the original position meaning that this change is reversible. This is known as elasticity.

Question:14

Label the diagram

(a) This is which part of a dicotyledonous plant?

(b) If we remove part I from the plant, what will happen?

Answer:

(a) This diagram displays the shoot apex of the dicotyledonous plant.
Shoot apex

(b) Removal of the shoot apex will prevent apical dominance. This will, in turn, help in the growth of lateral branches.


Question:15

Both animals and plants grow. Why do we say that growth and differentiation in plants are open and not so in animals? Does this statement hold true for sponges also?

Answer:
The growth of a plant can be said to be indeterminate. This is because a part of a plant can grow infinitely, i.e. always growing and forming new organs to replace the older ones. This is not the case for animals. Animal growth is limited and stops after a certain age when they mature. This is why one can say that the growth and differentiation in plants and animals are different.

The sponges can be said to be an exception in the animal kingdom. This is because they are the animals which show a cellular level of organisation. They depict the characteristics of open-ended growth but cannot be called one since they cannot grow beyond a certain size.

Question:16

Define parthenocarpy. Name the plant hormone used to induce parthenocarpy.

Answer:

Parthenocarpy is the process of formation and development of fruits that occurs without the use of any kind of fertilisation. The fruit produced by this process does not contain seeds. Fruits such as pear, banana, pineapple, and some varieties of papaya are parthenocarpic fruits. In order to induce parthenocarpy, auxins, cytokinin and gibberellins are utilised.

Question:17

While eating watermelons, all of us wish it were seedless. As a plant physiologist can you suggest any method by which this can be achieved?

Answer:

To have seedless watermelons, there needs to be a cross-hybridisation that occurs between a tetraploid female parent and a diploid male. This results in a triploid plant which has three sets of chromosomes. This particular genome thus produces the watermelon to not contain seeds.

Question:18

A gardener finds more broad-leaved dicot weeds growing in his lawns. What can be done to get rid of the weeds efficiently?

Answer:
The weed can be effectively eliminated by using weedicides. One can use the 2:4- D and 2:4: 5-T which do not affect mature monocotyledons. This is a synthetic auxin and is widely used by farmers but is to be used with caution and restraint so as to not hamper the crops.

Question:19

On germination a seed first produces shoots with leaves, flowers appear later,
(a) Why do you think this happens?
(b) How is this advantageous to the plant?

Answer:

(a) On germination of the seed, shoots with leaves are produced at first as the plant is gradually entering the vegetative growth phase of the plant. The leaves begin to manufacture food, and the photoperiod follows to determine the flowering of the plant.
The leaves are produced to regulate the process of photosynthesis and produce food, which could be utilised in sexual reproduction. This marks the beginning of the important flowering process as well.

(b) The vegetative phase marks immense growth and aids the plant to gain maturity. Then the process of reproduction commences, and flowering also occurs. The vegetative phase is necessary to prepare the plant for the upcoming process and for it to develop the necessary structures for it. Thug, the vegetative phase of growth is necessary for the survival of the plant species. The flowering phase depends on this phase to provide for nourishment.

How do you solve Class 11 Biology Chapter 15 Solutions questions effectively?

To solve the Plant Growth and Development questions effectively, follow these simple steps:

  1. Understand growth, differentiation, and plant growth regulators as main concepts from the textbook.
  2. Revise germination, photoperiodism, and vernalization as main processes through brief notes.
  3. Practice all NCERT and exemplar questions with step-by-step detailed solutions for clarity.
  4. Draw and label diagrams to improve understanding of plant structure and developmental stages.
  5. Clarify doubts and review regularly to improve retention and application abilities.

Also, Read NCERT Solution subject-wise

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Major Topics and Subtopics in NCERT Class 11 Biology Chapter 15 Plant Growth and Development

The topics and subtopics of the chapter are given below-

  • 15.1 Growth
  • 15.1.1 Plant growth generally is indeterminate
  • 15.1.2 Growth is measurable
  • 15.1.3 Phases of Growth
  • 15.1.4 Growth Rates
  • 15.1.5 Conditions for Growth
  • 15.2 Differentiation, Dedifferentiation and Redifferentiation
  • 15.3 Development
  • 15.4Plant Growth Regulators
  • 15.4.1 Characteristics
  • 15.4.2 The discovery of plant growth regulators
  • 15.4.3 Physiological Effects of Plant Growth Regulators
  • 15.4.3.1 Auxins
  • 15.4.3.2 Gibberellins
  • 15.4.3.3 Cytokinins
  • 15.4.3.4 Ethylenes
  • 15.4.3.5 Abscisic Acid

NCERT Exemplar Class 11 Solutions for other subjects



Extra MCQs from NCERT Exemplar Class 11 Biology Chapter 15

Here are some extra questions along with their answers to help you practice and strengthen your understanding of the chapter Plant Growth and Development:

  1. Ethylene is primarily responsible for:
    a) Delaying fruit ripening
    b) Hastening fruit ripening
    c) Promoting seed dormancy
    d) Stimulating root growth
    Answer: b) Hastening fruit ripening

  2. Which plant hormone is commonly found in coconut water?
    a) Auxin
    b) Cytokinin
    c) Gibberellin
    d) Abscisic acid
    Answer: b) Cytokinin

  3. Apical dominance can be overcome by the application of:
    a) Auxin
    b) Cytokinin
    c) Ethylene
    d) Gibberellin
    Answer: b) Cytokinin

  4. Gibberellins are used commercially to:
    a) Increase sugar content in sugarcane
    b) Promote leaf fall
    c) Induce seed dormancy
    d) Cause fruit ripening
    Answer: a) Increase sugar content in sugarcane

  5. Plasticity in plant growth refers to:
    a) The ability of plants to grow only in fixed patterns
    b) Dependence of plant development on environmental conditions
    c) Rigid growth irrespective of environment
    d) Growth limited to roots only
    Answer: b) Dependence of plant development on environmental conditions.

Also Check NCERT Books and NCERT Syllabus here

Additional topics for NEET from Class 11 Science Chapter 15

Learning other topics of Plant Growth and Development is important to NEET since the test not only questions basic concepts but also provides greater insights into plant hormones, growth phases, and physiological processes. Learning these additional topics clarifies growth regulation mechanisms, interactions between hormones, and influences of the environment on plants, which are regularly asked in NEET, hence enhancing your problem-solving ability and test preparedness.

TopicWhy Important for NEET?
Detailed roles and types of plant hormones (auxins, gibberellins, cytokinins, ethylene, ABA)Essential for understanding growth regulation and responses
Mechanism of action of plant growth regulatorsHelps answer application and experimental questions
Photoperiodism and vernalizationImportant for questions on flowering and plant adaptation
Seed dormancy and germination factorsFrequently asked in NEET for developmental biology
Apical dominance and its hormonal controlClarifies shoot growth patterns and hormone balance
Bioassays of plant hormones (e.g., Avena curvature test)Useful for experimental design and concept questions
Plant growth phases (lag, log, stationary)Helps in understanding growth patterns and kinetics
Role of hormones in fruit development and ripeningImportant for applied biology and agriculture-related questions
Interaction of environmental factors with plant growthNEET often includes environment-growth related questions
Tissue culture and plant regeneration basicsIncreasingly relevant for biotechnology-related questions

NCERT Exemplar Class 11 Biology Chapter- Wise Solutions

The NCERT exemplar chapter-wise solutions for class 11 biology are given below-

NCERT Exemplar Solutions for Class 11 Biology Chapter 1 The Living World
NCERT Exemplar Solutions for Class 11 Biology Chapter 2 Biological Classification
NCERT Exemplar Solutions for Class 11 Biology Chapter 3 Plant Kingdom
NCERT Exemplar Solutions for Class 11 Biology Chapter 4 Animal Kingdom
NCERT Exemplar Solutions for Class 11 Biology Chapter 5 Morphology of Flowering Plants
NCERT Exemplar Solutions for Class 11 Biology Chapter 6 Anatomy of Flowering Plants
NCERT Exemplar Solutions for Class 11 Biology Chapter 7 Structural Organisation in Animals
NCERT Exemplar Solutions for Class 11 Biology Chapter 8 Cell The Unit of Life
NCERT Exemplar Solutions for Class 11 Biology Chapter 9 Biomolecules
NCERT Exemplar Solutions for Class 11 Biology Chapter 10 Cell Cycle and Cell Division
NCERT Exemplar Solutions for Class 11 Biology Chapter 11 Transport in Plants
NCERT Exemplar Solutions for Class 11 Biology Chapter 12 Mineral Nutrition
NCERT Exemplar Solutions for Class 11 Biology Chapter 13 Photosynthesis in Higher Plants
NCERT Exemplar Solutions for Class 11 Biology Chapter 14 Respiration in Plants
NCERT Exemplar Solutions for Class 11 Biology Chapter 16 Digestion and Absorption
NCERT Exemplar Solutions for Class 11 Biology Chapter 17 Breathing and Exchange of Gases
NCERT Exemplar Solutions for Class 11 Biology Chapter 18 Body Fluids and Circulation
NCERT Exemplar Solutions for Class 11 Biology Chapter 19 Excretory Products and their Elimination
NCERT Exemplar Solutions for Class 11 Biology Chapter 20 Locomotion and Movement
NCERT Exemplar Solutions for Class 11 Biology Chapter 21 Neural Control and Coordination
NCERT Exemplar Solutions for Class 11 Biology Chapter 22 Chemical Coordination and Integration





The NCERT Class 11 Biology Exemplar Solutions provide well-written explanations that are written by subject experts and help the student remember everything with ease. Solving these questions helps to strengthen their understanding and increase their confidence in exams.

















Frequently Asked Questions (FAQs)

1. How are these questions solved by the teachers?

   Teachers use the chapters and the given information along with their practical knowledge to solve the questions in a more detailed way.


2. Who can benefit from these NCERT Exemplar Class 11 Biology Solutions Chapter 15 ?

 Those students who are preparing for their board exams or are preparing for the entrance exam or both can make the most from these NCERT Exemplar Class 11 Biology Solutions Chapter 15.

 

3. How to download these NCERT Exemplar Class 11 Biology Chapter 15 Solutions?

One can download the NCERT Exemplar Class 11 Biology Solutions Chapter 15 as a web page file in the browser.

4. What one can learn from this NCERT Exemplar Class 11 Biology Chapter 15 Solutions?

Students will learn about plants growth, differentiation, dedifferentiation, growth regulators, vernalisation and photoperiodism.

5. What is seed dormancy, and how can it be broken?

Seed dormancy is a state where viable seeds fail to germinate even under favorable conditions, acting as a survival mechanism that prevents germination in unsuitable environments. Dormancy can be broken by various methods, including scarification, stratification, and specific environmental conditions.

6. How does gibberellin promote seed germination?

Gibberellins promote seed germination by breaking dormancy, stimulating the synthesis of hydrolytic enzymes like amylase, and mobilizing stored nutrients, ultimately enabling the embryo to grow.

7. Why is abscisic acid called a stress hormone?

Abscisic acid (ABA) is called a "stress hormone" because its synthesis and release are strongly stimulated by environmental stresses like drought and waterlogging, and it plays a crucial role in enabling plants to tolerate these abiotic stresses. 

8. How does temperature affect seed germination?

Temperature plays a crucial role in seed germination, with optimal temperatures being essential for the process, while extreme temperatures can negatively impact or even inhibit it.

9. What is the significance of photoperiodism in flowering plants?

Photoperiodism, the plant's response to the length of day and night, is crucial for regulating flowering and other developmental processes, enabling plants to adapt to seasonal changes and optimize their reproductive success.

10. How does ethylene regulate fruit ripening?

Ethylene, a naturally produced plant hormone, plays a crucial role in fruit ripening by acting as a signal to initiate and regulate a series of physiological and biochemical changes, including softening, color changes, and flavour development.

11. What are the different phases of plant growth?

Plant growth progresses through distinct phases: meristematic (cell division), elongation (cell enlargement), and maturation (cell differentiation).

12. How do internal and external factors influence plant growth?

Plant growth is influenced by both internal (genetic and hormonal) and external (environmental) factors, with the interplay of these factors determining a plant's development and characteristics.

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Upcoming School Exams

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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