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NCERT Solutions for Miscellaneous Exercise Chapter 8 Class 12 - Application of Integrals

NCERT Solutions for Miscellaneous Exercise Chapter 8 Class 12 - Application of Integrals

Edited By Komal Miglani | Updated on May 08, 2025 02:31 PM IST | #CBSE Class 12th

Integrals are an inseparable part of calculus, which can solve real-world problems related to areas and volumes by summing up infinitely many small pieces to make a whole. The application of integrals delves into the aspect of how integrals can be used to solve problems related to real-life scenarios. The miscellaneous exercise of the chapter, Application of Integrals, combines all the key concepts covered in the chapter, so that the students can enhance their understanding by a comprehensive review of the entire chapter and get better at problem-solving. This article on the NCERT Solutions for Miscellaneous Exercise of Class 12, Chapter 8 - Application of Integrals, offers detailed and easy-to-understand solutions for the exercise problems, so that students can strengthen their understanding of the application of integrals. For syllabus, notes, exemplar solutions and PDF, refer to this link: NCERT.

This Story also Contains
  1. Application of Integrals Class 12 Chapter 8 Miscellaneous: Exercise
  2. Topics covered in Chapter 8, Application of Integrals: Miscellaneous Exercise
  3. NCERT Solutions Subject Wise
  4. NCERT Exemplar Solutions Subject Wise
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Application of Integrals Class 12 Chapter 8 Miscellaneous: Exercise

Question 1: Find the area under the given curves and given lines:

(i) y=x2,x=1,x=2 and x -axis

Answer:

The area bounded by the curve y=x2,x=1,x=2 and x -axis
1594728126741
The area of the required region = area of ABCD
=12ydx=12x2dx=[x33]12=73
Hence the area of shaded region is 7/3 units

Question 1: Find the area under the given curves and given lines:

(ii) y=x4,x=1,x=5 and x -axis

Answer:

The area bounded by the curev y=x4,x=1,x=5 and x -axis

1594728286834
The area of the required region = area of ABCD
=15ydx=12x4dx=[x55]12=62515=624.8
Hence the area of the shaded region is 624.8 units


Question 2: Sketch the graph of y=|x+3| and evaluate 60|x+3|dx.

Answer:

y=|x+3|

the given modulus function can be written as

x+3>0

x>-3

for x>-3

y=|x+3|=x+3

x+3<0

x<-3

For x<-3

y=|x+3|=-(x+3)

1654760706138

Integral to be evaluated is

60|x+3|dx=63(x3)dx+30(x+3)dx=[x223x]63+[x22+3x]30=(92+9)(18+18)+0(929)=9

Question 3: Find the area bounded by the curve y=sinx between x=0 and x=2π .

Answer:

The graph of y=sinx is as follows

1654760755958

We need to find the area of the shaded region

ar(OAB)+ar(BCD)

=2ar(OAB)

=2×0πsinxdx=2×[cosx]0π=2×[(1)(1)]=4

The bounded area is 4 units.




Question 4: Choose the correct answer.

Area bounded by the curve y=x3 , the x -axis and the ordinates x=2 and x=1 is

(A) 9 (B) 154 (C) 154 (D) 174

Answer:

1654765098486

Hence the required area

=21ydx

=21x3dx=[x44]21

=[x44]20+[x44]01

=[0(2)44]+[140]

=4+14=154

Therefore the correct answer is B.

Question 5: Choose the correct answer.

T he area bounded by the curve y=x|x| , x -axis and the ordinates x=1 and x=1 is given by

(A) 0 (B) 13 (C) 23 (D) 43

[ Hint : y=x2 if x>0 and y=x2 if x<0 . ]

Answer:

The required area is

201x2dx=2[x33]01=23 units


Also Read,

Topics covered in Chapter 8, Application of Integrals: Miscellaneous Exercise

The main topics covered in class 12 maths chapter 8 of Application of Integrals, Miscellaneous Exercise are:

  • Area under curves: In this topic, we will calculate the area between a curve and the coordinate axes in a specific interval. For example, the area under the curve y=f(x), between two points on the X axis, as x=a and x=b, can be found using definite integrals as: A=abf(x)dx.
  • Area between two curves: This topic deals with the area between two curves. Let f(x) and g(x) be two curves in the interval [a,b], then the area can be found using the formula, Area =ab[f(x)g(x)]dx.
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NCERT Solutions Subject Wise

Below are some useful links for subject-wise NCERT solutions for class 12.

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As per latest 2024 syllabus. Maths formulas, equations, & theorems of class 11 & 12th chapters

NCERT Exemplar Solutions Subject Wise

Here are some links to subject-wise solutions for the NCERT exemplar class 12.

Frequently Asked Questions (FAQs)

1. How many questions are there in Miscellaneous exercise Chapter 8 ?

There are 19 questions total in Miscellaneous exercise Chapter 8.

2. Can we find an area without using integrals ?

Simple figures like triangle, circle etc. can be tackled without integration but not the complex ones. 

3. Are questions repeated in the examination from this Chapter ?

Yes, in the Board exam the questions are repeated every year. 

4. What is the level of questions asked from this Chapter ?

Moderate level questions are asked from this Chapter. 

5. Can one skip Miscellaneous exercise ?

No, as it has some good questions, miscellaneous exercise must be done. 

6. What is the time it will take to complete for the first time ?

It will take around 5-6 hours to complete for the first time.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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