CBSE Class 12th Exam Date:17 Feb' 26 - 17 Feb' 26
Assume that a student is trying to find the rate at which a cup of hot coffee cools down in a specific environment. The change in temperature with time is a practical application of differential equations. Differential equations allow us to understand and predict changes in quantity, an essential component of physics, biology, engineering, and economics.
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The NCERT solutions for Class 12 Maths Chapter 9 Exercise 9.1 solutions are designed to provide students with the basics of differential equations—equations involving derivatives. Designed by expert teachers of Careers360, these solutions are as per the new CBSE 2025-26 curriculum and are designed to lead the students to the creation of strong fundamentals. All the NCERT solutions for Class 12 Maths Chapter 9, exercise 9.1 have been presented in a simple, step-by-step manner to enable students to understand the logic of each solution. Some additional sample problems from the NCERT book have been provided, detailing the thought process of each of these problems. These exercises, along with practice, enable one to not only learn mathematics but gain confidence to deal with board exams as well as competitive exams such as the JEE. NCERT solutions provide a great mentor to enable one to master the chapter and acquire conceptual clarity.
This material provides easy solutions to all the questions of Exercise 9.1 of Differential Equations. The PDF can be downloaded by the students for practice and enhancement of the chapter for board and competitive exams.
Question:1 Determine order and degree (if defined) of differential equation $\frac{\mathrm{d} ^4y}{\mathrm{d} x^4} +\sin(y''')=0$
Answer:
Given function is
$\frac{\mathrm{d} ^4y}{\mathrm{d} x^4} +\sin(y''')=0$
We can rewrite it as
$y^{''''}+\sin(y''') =0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{''''}$
Therefore, the order of the given differential equation $\frac{\mathrm{d} ^4y}{\mathrm{d} x^4} +\sin(y''')=0$ is 4
Now, the given differential equation is not a polynomial equation in its derivatives
Therefore, it's a degree is not defined
Question:2 Determine order and degree (if defined) of differential equation $y' + 5y = 0$
Answer:
Given function is
$y' + 5y = 0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{'}$
Therefore, the order of the given differential equation $y' + 5y = 0$ is 1
Now, the given differential equation is a polynomial equation in its derivatives and its highest power raised to y ' is 1
Therefore, it's a degree is 1.
Answer:
Given function is
$\left(\frac{\mathrm{d} s}{\mathrm{d} t} \right )^4 + 3s \frac{\mathrm{d}^2 s}{\mathrm{d} t^2} = 0$
We can rewrite it as
$(s^{'})^4+3s.s^{''} =0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $s^{''}$
Therefore, the order of the given differential equation $\left(\frac{\mathrm{d} s}{\mathrm{d} t} \right )^4 + 3s \frac{\mathrm{d}^2 s}{\mathrm{d} t^2} = 0$ is 2
Now, the given differential equation is a polynomial equation in its derivatives and power raised to s '' is 1
Therefore, it's a degree is 1
Question:4 Determine order and degree (if defined) of differential equation.
$\left(\frac{d^2y}{dx^2} \right )^2 + \cos\left(\frac{dy}{dx} \right )= 0$
Answer:
Given function is
$\left(\frac{d^2y}{dx^2} \right )^2 + \cos\left(\frac{dy}{dx} \right )= 0$
We can rewrite it as
$(y^{''})^2+\cos y^{''} =0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{''}$
Therefore, the order of the given differential equation $\left(\frac{d^2y}{dx^2} \right )^2 + \cos\left(\frac{dy}{dx} \right )= 0$ is 2
Now, the given differential equation is not a polynomial equation in its derivatives
Therefore, it's a degree is not defined
Question:5 Determine order and degree (if defined) of differential equation.
$\frac{d^2y}{dx^2} = \cos 3x + \sin 3x$
Answer:
Given function is
$\frac{d^2y}{dx^2} = \cos 3x + \sin 3x$
$\Rightarrow \frac{d^2y}{dx^2}- \cos 3x - \sin 3x = 0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{''}\left ( \frac{d^2y}{dx^2} \right )$
Therefore, order of given differential equation $\frac{d^2y}{dx^2}- \cos 3x - \sin 3x = 0$ is 2
Now, the given differential equation is a polynomial equation in it's dervatives $\frac{d^2y}{dx^2}$ and power raised to $\frac{d^2y}{dx^2}$ is 1
Therefore, it's degree is 1
Answer:
Given function is
$(y''')^2 + (y'')^3 + (y')^4 + y^5= 0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{'''}$
Therefore, order of given differential equation $(y''')^2 + (y'')^3 + (y')^4 + y^5= 0$ is 3
Now, the given differential equation is a polynomial equation in it's dervatives $y^{'''} , y^{''} \ and \ y^{'}$ and power raised to $y^{'''}$ is 2
Therefore, it's degree is 2
Question:7 Determine order and degree (if defined) of differential equation
Answer:
Given function is
$y''' + 2y'' + y' =0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{'''}$
Therefore, order of given differential equation $y''' + 2y'' + y' =0$ is 3
Now, the given differential equation is a polynomial equation in it's dervatives $y^{'''} , y^{''} \ and \ y^{'}$ and power raised to $y^{'''}$ is 1
Therefore, it's degree is 1
Question:8 Determine order and degree (if defined) of differential equation
Answer:
Given function is
$y' + y = e^x$
$\Rightarrow$ $y^{'}+y-e^x=0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{'}$
Therefore, order of given differential equation $y^{'}+y-e^x=0$ is 1
Now, the given differential equation is a polynomial equation in it's dervatives $y^{'}$ and power raised to $y^{'}$ is 1
Therefore, it's degree is 1
Question:9 Determine order and degree (if defined) of differential equation
Answer:
Given function is
$y'' + (y')^2 + 2y = 0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{''}$
Therefore, order of given differential equation $y'' + (y')^2 + 2y = 0$ is 2
Now, the given differential equation is a polynomial equation in it's dervatives $y^{''} \ and \ y^{'}$ and power raised to $y^{''}$ is 1
Therefore, it's degree is 1
Question:10 Determine order and degree (if defined) of differential equation
Answer:
Given function is
$y'' + 2y' + \sin y = 0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{''}$
Therefore, order of given differential equation $y'' + 2y' + \sin y = 0$ is 2
Now, the given differential equation is a polynomial equation in it's dervatives $y^{''} \ and \ y^{'}$ and power raised to $y^{''}$ is 1
Therefore, it's degree is 1
(A) 3
(B) 2
(C) 1
(D) not defined
Answer:
Given function is
$\left(\frac{d^2y}{dx^2} \right )^3 + \left(\frac{dy}{dx} \right )^2 + \sin\left(\frac{dy}{dx}\right ) + 1= 0$
We can rewrite it as
$(y^{''})^3+(y^{'})^2+\sin y^{'}+1=0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{''}$
Therefore, order of given differential equation $\left(\frac{d^2y}{dx^2} \right )^3 + \left(\frac{dy}{dx} \right )^2 + \sin\left(\frac{dy}{dx}\right ) + 1= 0$ is 2
Now, the given differential equation is a not polynomial equation in it's dervatives
Therefore, it's degree is not defined
Therefore, answer is (D)
Question:12 The order of the differential equation $2x^2\frac{d^2y}{dx^2} - 3\frac{dy}{dx} + y = 0$ is
(A) 2
(B) 1
(C) 0
(D) Not Defined
Answer:
Given function is
$2x^2\frac{d^2y}{dx^2} - 3\frac{dy}{dx} + y = 0$
We can rewrite it as
$2x.y^{''}-3y^{'}+y=0$
Now, it is clear from the above that, the highest order derivative present in differential equation is $y^{''}$
Therefore, order of given differential equation $2x^2\frac{d^2y}{dx^2} - 3\frac{dy}{dx} + y = 0$ is 2
Therefore, answer is (A)
Also check -
Topic | Description | Example |
Differential Equation | An equation that contains derivatives of a function. | $\frac{d y}{d x}+y=e^x$ |
Order of a Differential Equation | The highest order of the derivatives in the equation. | $\begin{aligned} & \frac{d^2 y}{d x^2}+3 \frac{d y}{d x}=0 \\ & \text { Order }=2\end{aligned}$ |
Degree of a Differential Equation | Power of the highest order derivative (after eliminating roots/fractions) | $ |
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Frequently Asked Questions (FAQs)
The concepts of order and degree of differential equations are covered in the Class 12 Maths chapter 9 exercise 9.1.
One solved example is given in the NCERT book before exercise 9.1 Class 12 Maths.
12 questions and their answers are given in the NCERT solutions for Class 12 Maths chapter 9 exercise 9.1
7 exercises. In which one is miscellaneous exercises.
Miscellaneous exercise covers question from whole chapter and exercise questions covers topics discussed in that particular area.
Yes, Students can expect questions from this part for JEE Mains.
Yes, these solutions of exercise 9.1 are prepared by expert faculty and are reviewed.
It is necessary to get clarity over the topics degree and order of a differential equation. NCERT Solutions for Class 12 Maths chapter 9 exercise 9.1 helps for the same.
On Question asked by student community
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