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**NCERT Solutions for Class 11 Maths Chapter 13 Limits and Derivatives **are provided here.** **This Class 11 NCERT syllabus introduces an important area of mathematics called calculus. This is a branch of mathematics which deal with the study of change in the value of a function as the points in the domain change. In this article, you will get limits and derivatives class 11 NCERT solutions that are prepared by highly qualified teachers keeping in mind latest syllabus of CBSE 2023, simple and provide step by step solution to each problem. Students can get all NCERT solutions at one place and practice them to develop indepth understanding of the concepts.

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This Story also Contains

- Limits and Derivatives Class 11 Questions And Answers
- Limits and Derivatives Class 11 Questions And Answers PDF Free Download
- Limits and Derivatives Class 11 Solutions - Important Formulae
- Limits and Derivatives Class 11 NCERT Solutions (Intext Questions and Exercise)
- limits and derivatives ncert solutions - Topics
- NCERT Solutions for Class 11 Mathematics - Chapter Wise
- Key Features Of Limits And Derivatives Class 11 Solutions
- NCERT Solutions for Class 11- Subject Wise
- NCERT Books and NCERT Syllabus

In class 11 maths chapter 13 question answer, you will get questions related to all the above topics. This chapter is very important for both class 11 final examination and various competitive exams like JEE Main, JEE Advanced, VITEEE, BITSAT, etc. There are 43 questions in 2 exercises limits and derivatives class 11. The first exercise of this chapter deals with problems on limits and the second exercise deals with problems on derivatives. Students can find all NCERT solution for class 11 at one pace for hare and practice them.

**Also Read :**

- NCERT Exemplar Solutions For Class 11 Mathematics Chapter Limits And Derivatives
- Limits And Derivatives Class 11 NCERT Chapter Notes

**Limits:**

The limit of a function f(x) as x approaches a, denoted as lim(x→a) f(x), exists when both the left-hand limit (lim(x→a-) f(x)) and right-hand limit (lim(x→a+) f(x)) exist and are equal (lim(x→a-) f(x) = lim(x→a+) f(x)).

**Left-Hand and Right-Hand Limits:**

Left-Hand Limit: f(a-0) = lim(x→a-) f(x) = lim(h→0) f(a-h)

Right-Hand Limit: f(a+0) = lim(x→a+) f(x) = lim(h→0) f(a+h)

**Properties of Limits:**

If lim(x→a) f(x) and lim(x→a) g(x) both exist:

Sum Rule: lim(x→a) [f(x) ± g(x)] = lim(x→a) f(x) ± lim(x→a) g(x)

Constant Rule: lim(x→a) kf(x) = k lim(x→a) f(x)

Product Rule: lim(x→a) [f(x) * g(x)] = lim(x→a) f(x) * lim(x→a) g(x)

Quotient Rule: lim(x→a) [f(x)/g(x)] = [lim(x→a) f(x)] / [lim(x→a) g(x)] (provided lim(x→a) g(x) ≠ 0)

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Download EBook**Standard Limits:**

lim(x→a) [(x

^{n}- a^{n})/(x - a)] = na^{(n-1)}lim(x→0) [(sin(x))/x] = 1

lim(x→0) [(tan(x))/x] = 1

lim(x→0) [(a

^{x}- 1)/x] = ln(a)lim(x→0) [(e

^{x}- 1)/x] = 1lim(x→0) [(ln(1+x))/x] = 1

**Derivatives:**

The derivative of a function f at a point x, denoted as f'(x), is defined as:

f'(x) = lim(h→0) [(f(x+h) - f(x))/h]

**Properties of Derivatives:**

If f(x) and g(x) have derivatives in a common domain:c

Sum Rule: [d/dx (f(x) + g(x))] = [d/dx (f(x))] + [d/dx (g(x))]

Difference Rule: [d/dx (f(x) - g(x))] = [d/dx (f(x))] - [d/dx (g(x))]

Product Rule: [d/dx (f(x) * g(x))] = [d/dx f(x)] * g(x) + f(x) * [d/dx g(x)]

Quotient Rule: [d/dx (f(x)/g(x))] = ([d/dx f(x)] * g(x) - f(x) * [d/dx g(x)]) / [g(x)]

^{2}

**Standard Derivatives:**

[d/dx (x^n)] = n * x

^{(n-1)}[d/dx (sin(x))] = cos(x)

[d/dx (cos(x))] = -sin(x)

[d/dx (tan(x))] = sec

^{2}(x)[d/dx (cot(x))] = -csc

^{2}(x)[d/dx (sec(x))] = sec(x) * tan(x)

[d/dx (csc(x))] = -csc(x) * cot(x)

[d/dx (a^x)] = a

^{x}* ln(a)[d/dx (e^x)] = e

^{x}[d/dx (ln(x))] = 1/x

Free download **NCERT Solutions for Class 11 Maths Chapter 13 Limits and Derivatives **for CBSE Exam.

**Limits and derivatives class 11 questions and answers - Exercise: 13.1** ** **

**Question:1 ** Evaluate the following limits

** Answer: **

Answer

** Question:6 ** Evaluate the following limits

** Answer: **

The limit

Lets put

since we have changed the function, its limit will also change,

so

So our function have became

Now As we know the property

Hence,

** Question:8 ** Evaluate the following limits

** Answer: **

The limit

At x = 2 both numerator and denominator becomes zero, so lets factorise the function

Now we can put the limit directly, so

** Question:10 ** Evaluate the following limits

** Answer: **

The limit

Here on directly putting limit , both numerator and the deniminator becomes zero so we factorize the function and then put the limit.

** (Answer) **

** Question:11 ** Evaluate the following limits

** Answer: **

The limit:

Since Denominator is not zero on directly putting the limit, we can directly put the limits, so,

** (Answer) **

** Question:12 ** Evaluate the following limits

** Answer: **

Here, since denominator becomes zero on putting the limit directly, so we first simplify the function and then put the limit,

** (Answer) **

** Question:13 ** Evaluate the following limits

** Answer: **

The limit

Here on directly putting the limits, the function becomes form. so we try to make the function in the form of . so,

As

** (Answer) **

** Question:14 ** Evaluate the following limits

** Answer: **

The limit,

On putting the limit directly, the function takes the zero by zero form So,we convert it in the form of .and then put the limit,

** (Answer) **

** Question:16 ** Evaluate the following limits

** Answer: **

The limit

the function behaves well on directly putting the limit,so we put the limit directly. So.

** (Answer) **

** Question:17 ** Evaluate the following limits

** Answer: **

The limit:

The function takes the zero by zero form when the limit is put directly, so we simplify the function and then put the limit

** (Answer) **

** Question:18 ** Evaluate the following limits

** Answer: **

The function takes the form zero by zero when we put the limit directly in the function,. since function consist of sin function and cos function, we try to make the function in the form of as we know that it tends to 1 when x tends to 0.

So,

** (Answer) **

** Question:19 ** Evaluate the following limits

** Answer: **

As function doesn't create any abnormality on putting the limit directly,we can put limit directly. So,

. ** (Answer) **

** Question:20 ** Evaluate the following limits

** Answer: **

The function takes the zero by zero form when we put the limit into the function directly, so we try to eliminate this case by simplifying the function. So

** (Answer) **

** Question:21 ** Evaluate the following limits

** Answer: **

On putting the limit directly the function takes infinity by infinity form, So we simplify the function and then put the limit

** (Answer) **

** Question:22 ** Evaluate the following limits

** Answer: **

The function takes zero by zero form when the limit is put directly, so we simplify the function and then put the limits,

So

Let's put

Since we are changing the variable, limit will also change.

as

So function in new variable becomes,

As we know tha property

** (Answer) **

** Question:23 ** Find

** Answer: **

Given Function

Now,

Limit at x = 0 :

:

Hence limit at x = 0 is 3.

Limit at x = 1

Hence limit at x = 1 is 6.

** Question:24 ** Find

** Answer: **

Limit at

Limit at

As we can see that Limit at is not equal to Limit at ,The limit of this function at x = 1 does not exists.

** Question:25 ** Evaluate

** Answer: **

The right-hand Limit or Limit at

The left-hand limit or Limit at

Since Left-hand limit and right-hand limit are not equal, The limit of this function at x = 0 does not exists.

** Question:26 ** Evaluate

** Answer: **

The right-hand Limit or Limit at

The left-hand limit or Limit at

Since Left-hand limit and right-hand limit are not equal, The limit of this function at x = 0 does not exists.

** Question:27 ** Find

** Answer: **

The right-hand Limit or Limit at

The left-hand limit or Limit at

Since Left-hand limit and right-hand limit are equal, The limit of this function at x = 5 is 0.

** Question:28 ** Suppose

f (x) = f (1) what are possible values of a and b?

** Answer: **

Given,

And

Since the limit exists,

left-hand limit = Right-hand limit = f(1).

Left-hand limit = f(1)

Right-hand limit

From both equations, we get that,

and

Hence the possible value of a and b are 0 and 4 respectively.

** Question:29 ** Let a1, a2, . . ., an be fixed real numbers and define a function What is f (x) ? For some , compute l

** Answer: **

Given,

Now,

Hence

,

Now,

Hence

.

** Question:30 ** If For what value (s) of a does exists ?

** Answer: **

Limit at x = a exists when the right-hand limit is equal to the left-hand limit. So,

Case 1: when a = 0

The right-hand Limit or Limit at

The left-hand limit or Limit at

Since Left-hand limit and right-hand limit are not equal, The limit of this function at x = 0 does not exists.

Case 2: When a < 0

The right-hand Limit or Limit at

The left-hand limit or Limit at

Since LHL = RHL, Limit exists at x = a and is equal to a-1.

Case 3: When a > 0

The right-hand Limit or Limit at

The left-hand limit or Limit at

Since LHL = RHL, Limit exists at x = a and is equal to a+1

Hence,

The limit exists at all points except at x=0.

** Question:32 ** If

** Answer: **

Given,

Case 1: Limit at x = 0

The right-hand Limit or Limit at

The left-hand limit or Limit at

Hence Limit will exist at x = 0 when m = n .

Case 2: Limit at x = 1

The right-hand Limit or Limit at

The left-hand limit or Limit at

Hence Limit at 1 exists at all integers.

** C lass 11 maths chapter 13 NCERT solutions - Exercise: 13.2 **

** Question:1 ** Find the derivative of

** Answer: **

F(x)=

Now, As we know, The derivative of any function at x is

The derivative of f(x) at x = 10:

** Question:2 ** Find the derivative of x at x = 1.

** Answer: **

Given

f(x)= x

Now, As we know, The derivative of any function at x is

The derivative of f(x) at x = 1:

** (Answer) **

** Question:3 ** Find the derivative of 99x at x = l00.

** Answer: **

f(x)= 99x

Now, As we know, The derivative of any function at x is

The derivative of f(x) at x = 100:

** Question:4 (i) ** Find the derivative of the following functions from first principle.

** Answer: **

Given

f(x)=

Now, As we know, The derivative of any function at x is

** Question:4.(ii) ** Find the derivative of the following function from first principle.

** Answer: **

f(x)=

Now, As we know, The derivative of any function at x is

** (Answer) **

** Question:4(iii) ** Find the derivative of the following functions from first principle.

** Answer: **

f(x)=

Now, As we know, The derivative of any function at x is

** (Answer) **

** Question:4(iv) ** Find the derivative of the following functions from first principle.

** Answer: **

Given:

Now, As we know, The derivative of any function at x is

** Question:5 ** For the function Prove that f '(1) =100 f '(0).

** Answer: **

As we know, the property,

applying that property we get

Now.

So,

Here

Hence Proved.

** Question:6 ** Find the derivative of for some fixed real number a.

** Answer: **

Given

As we know, the property,

applying that property we get

** Question:7(i) ** For some constants a and b, find the derivative of

** Answer: **

Given

As we know, the property,

and the property

applying that property we get

** Question:7(ii) ** For some constants a and b, find the derivative of

** Answer: **

Given

As we know, the property,

and the property

applying those properties we get

** Question:7(iii) ** For some constants a and b, find the derivative of

** Answer: **

Given,

Now As we know the quotient rule of derivative,

So applying this rule, we get

Hence

** Question:8 ** Find the derivative of for some constant a.

** Answer: **

Given,

Now As we know the quotient rule of derivative,

So applying this rule, we get

Hence

** Question:9(i) ** Find the derivative of

** Answer: **

Given:

As we know, the property,

and the property

applying that property we get

** Question:9(ii) ** Find the derivative of

** Answer: **

Given.

As we know, the property,

and the property

applying that property we get

** Question:9(iii) ** Find the derivative of

** Answer: **

Given

As we know, the property,

and the property

applying that property we get

** Question:9(iv) ** Find the derivative of

** Answer: **

Given

As we know, the property,

and the property

applying that property we get

** Question:9(v) ** Find the derivative of

** Answer: **

Given

As we know, the property,

and the property

applying that property we get

** Question:9(vi) ** Find the derivative of

** Answer: **

Given

As we know the quotient rule of derivative:

and the property

So applying this rule, we get

Hence

** Question:10 ** Find the derivative of from first principle.

** Answer: **

Given,

f(x)=

Now, As we know, The derivative of any function at x is

** Question:11(i) ** Find the derivative of the following functions:

** Answer: **

Given,

f(x)=

Now, As we know the product rule of derivative,

So, applying the rule here,

** Question:11(ii) ** Find the derivative of the following functions:

** Answer: **

Given

Now As we know the quotient rule of derivative,

So applying this rule, we get

** Question:11 (iii) ** Find the derivative of the following functions:

** Answer: **

Given

As we know the property

Applying the property, we get

** Question:11(iv) ** Find the derivative of the following functions:

** Answer: **

Given :

Now As we know the quotient rule of derivative,

So applying this rule, we get

** Question:11(v) ** Find the derivative of the following functions:

** Answer: **

Given,

As we know the property

Applying the property,

Now As we know the quotient rule of derivative,

So applying this rule, we get

** Question:11(vi) ** Find the derivative of the following functions:

** Answer: **

Given,

Now as we know the property

So, applying the property,

** Question:11(vii) ** Find the derivative of the following functions:

** Answer: **

Given

As we know the property

Applying this property,

**Limits and derivatives NCERT solutions ****- Miscellaneous Exercise **

** Question:1(i) ** Find the derivative of the following functions from first principle: -x

** Answer: **

Given.

f(x)=-x

Now, As we know, The derivative of any function at x is

** Question:1(ii) ** Find the derivative of the following functions from first principle:

** Answer: **

Given.

f(x)=

Now, As we know, The derivative of any function at x is

** Question:1(iii) ** Find the derivative of the following functions from first principle:

** Answer: **

Given.

Now, As we know, The derivative of any function at x is

** Question:1(iv) ** Find the derivative of the following functions from first principle:

** Answer: **

Given.

Now, As we know, The derivative of any function at x is

** Answer: **

Given

f(x)= x + a

As we know, the property,

applying that property we get

** Answer: **

Given

As we know, the property,

applying that property we get

** Answer: **

Given,

Now,

As we know, the property,

and the property

applying that property we get

** Answer: **

Given,

Now, As we know the derivative of any function

Hence, The derivative of f(x) is

Hence Derivative of the function is

.

** Answer: **

Given,

Also can be written as

Now, As we know the derivative of any function

Hence, The derivative of f(x) is

Hence Derivative of the function is

** Answer: **

Given,

Now, As we know the derivative of any such function is given by

Hence, The derivative of f(x) is

** Answer: **

Given,

Now, As we know the derivative of any function

Hence, The derivative of f(x) is

** Answer: **

Given,

Now, As we know the derivative of any function

Hence, The derivative of f(x) is

** Answer: **

Given

As we know, the property,

and the property

applying that property we get

** Answer: **

Given

It can also be written as

Now,

As we know, the property,

and the property

applying that property we get

** Answer: **

Given

Now, As we know the chain rule of derivative,

And, the property,

Also the property

applying those properties we get,

** Answer: **

Given

Now, As we know the chain rule of derivative,

And the Multiplication property of derivative,

And, the property,

Also the property

Applying those properties we get,

** Answer: **

Given,

Now, As we know the chain rule of derivative,

Applying this property we get,

** Answer: **

Given,

the Multiplication property of derivative,

Applying the property

Hence derivative of the function is .

** Answer: **

Given,

Now, As we know the derivative of any function

Hence, The derivative of f(x) is

** Answer: **

Given

Also can be written as

which further can be written as

Now,

** Answer: **

Given,

which also can be written as

Now,

As we know the derivative of such function

So, The derivative of the function is,

Which can also be written as

.

** Answer: **

Given,

Now, As we know the chain rule of derivative,

And, the property,

Applying those properties, we get

Hence Derivative of the given function is

** Answer: **

Given Function

Now, As we know the derivative of any function of this type is:

Hence derivative of the given function will be:

** Answer: **

Given,

Now, As we know the derivative of any function

Hence the derivative of the given function is:

** Answer: **

Given

Now, As we know, the Multiplication property of derivative,

Hence derivative of the given function is:

** Answer: **

Given

Now, As we know the product rule of derivative,

The derivative of the given function is

** Answer: **

Given,

Now As we know the Multiplication property of derivative,(the product rule)

And also the property

Applying those properties we get,

** Answer: **

Given,

And the Multiplication property of derivative,

Also the property

Applying those properties we get,

** Answer: **

Given,

Now, As we know the derivative of any function

Also the property

Applying those properties,we get

** Answer: **

Given,

Now, As we know the derivative of any function

Now, As we know the derivative of any function

Hence the derivative of the given function is

** Answer: **

Given

Now, As we know the derivative of any function

** Answer: **

Given

Now, As we know the Multiplication property of derivative,

Also the property

Applying those properties we get,

the derivative of the given function is,

** Answer: **

Given,

Now, As we know the derivative of any function

Also chain rule of derivative,

Hence the derivative of the given function is

13.1 Introduction

13.2 Intuitive Idea of Derivatives

13.3 Limits

13.4 Limits of Trigonometric Functions

13.5 Derivatives

Interested students can practice class 11 maths ch 13 question answer using following exercises.

- Limits And Derivatives NCERT Exercise 13.1 Solutions
- Limits And Derivatives NCERT Exercise 13.2 Solutions
- Limits And Derivatives Miscellaneous Solutions

Limit of a function(f) at a point is the common value of the left-hand limits and right-hand limits if they coincide.

For a function 'f' and a real number 'a'. and may not be the same (One may be defined and not the other one).

For functions 'f' and 'g' the following properties holds:

- Some of the standard limits are-

- The derivative of a function 'f' at 'a' is defined by-

- The derivative of a function 'f' at any point 'x' is defined by-

chapter-1 | |

chapter-2 | |

chapter-3 | |

chapter-4 | |

chapter-5 | |

chapter-6 | |

chapter-7 | |

chapter-8 | |

chapter-9 | |

chapter-10 | |

chapter-11 | |

chapter-12 | |

chapter-13 | Limits and Derivatives |

chapter-14 | |

chapter-15 | |

chapter-16 |

**Comprehensive coverage of concepts: **The ch 13 maths class 11 provides a thorough and comprehensive coverage of the fundamental concepts of limits and derivatives, which are essential for understanding the principles of calculus.

**Simple and easy language**: The class 11 maths limits and derivatives is written in a simple and easy-to-understand language, making it accessible to students of all levels of mathematical aptitude.

**Step-by-step explanations:** The chapter provides step-by-step explanations of the concepts, with worked-out examples and exercises that help students to master the topics covered in the chapter.

- NCERT solutions for class 11 biology
- NCERT solutions for class 11 maths
- NCERT solutions for class 11 chemistry
- NCERT solutions for Class 11 physics

**Tip-** Limits class 11 is more on the theory-based so you should understand every theorem and try to solve questions based on the theorem. Derivatives required more practice of problems. There are 30 questions in the miscellaneous exercise. You should solve miscellaneous exercises also to get command on this chapter with the help of NCERT solutions for class 11 maths chapter 13 limits and derivatives.

1. What is the effective way to study limits and derivatives class 11 NCERT solutions?

Effective way to study chapter 13 class 11 maths includes following points:

- Begin by familiarizing yourself with the basic concepts covered in the chapter.
- Understand the fundamental topics of calculus, including both differential and integral calculus.
- Memorize the essential formulas that are used in the chapter.
- Focus on learning about limits and their properties in detail.
- Master the fundamental theorem of calculus and its significance.
- To solidify your understanding of the concepts, practice problems on a regular basis.

2. What are the topics included in limits and derivatives class 11 solutions?

class11 maths ch13 includes following topics:

1. Introduction

2. Intuitive Idea of Derivatives

3. Limits

4. Limits of Trigonometric Functions

5. Derivatives

3. How does the NCERT solutions for class 11 chapter 13 maths are helpful ?

NCERT solutions for class 11 math ch 13 are helpful to the students in solving the NCERT problems as well building foundation for class 12th chapters such as differentiation, integration and many. These solutions are provided in a detailed manner which can be understood by an average student also.

4. Where can I find the complete class 11 maths NCERT solutions chapter 13?

Students can get the detailed NCERT solutions for class 11 maths here. they can practice these solutions to build concepts that lead confidence during exam and ultimately help to score well in the exam.

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