NCERT Solutions for Exercise 1.6 Class 11 Maths Chapter 1

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NCERT Solutions for Exercise 1.6 Class 11 Maths Chapter 1 - Sets

Edited By Vishal kumar | Updated on Nov 02, 2023 07:03 AM IST

NCERT Solutions for Class 11 Maths Chapter 1 - Sets Exercise 1.6- Download Free PDF

NCERT Solutions for Class 11 Maths Chapter 1: Sets Exercise 1.6- In NCERT Solutions for Class 11 Maths Chapter 1 exercise 1.6 you will learn about the practical problems on union and intersection of two sets. Class 11th Maths Chapter 1 Exercise 1.6 is all about the applications of the union of two sets, the intersection of two sets, and applications of Venn's diagram. You should try to solve all the problems given in the Class 11 Maths ch 1 ex 1.6 on your own. These problems are related to our daily life problems which you must solve to get clarity. You may not be able to solve these NCERT problems at first, Class 11 Maths Chapter 1 exercise 1.6 solutions are here to help you. This NCERT book ex 1.6 class 11 is not only important for this chapter but formulae derived in this exercise will be used in the upcoming chapter probability. If you are looking for NCERT Solutions, click on the given link where you will find the detailed NCERT Solutions for Classes 6 to 12 in one place.

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NCERT Solutions for Class 11 Maths Chapter 1 - Sets Exercise 1.6- Download Free PDF
NCERT Solutions for Class 11 Maths Chapter 1 – Sets Exercise 1.6
Access Sets Class 11 Chapter 1 Exercise: 1.6
Question:1 If X and Y are two sets such that n ( X ) = 17, n ( Y ) = 23 and n ( X Y ) = 38, find n ( X Y ).
More About NCERT Solutions for Class 11 Maths Chapter 1 Exercise 1.6:-
Benefits of NCERT Solutions for Class 11 Maths Chapter 1 Exercise 1.6:-
Key Features of 11th Class Maths Exercise 1.6 Answers
NCERT Solutions of Class 11 Subject Wise
Subject Wise NCERT Exampler Solutions

NCERT Solutions for Exercise 1.6 Class 11 Maths Chapter 1 - Sets

The provided class 11 maths ex 1.6 solution are designed to facilitate students in grasping fundamental concepts effectively. With the detailed, step-by-step solutions offered by Careers360, achieving success in final exams becomes a straightforward endeavour. You can access the NCERT Class 11 Maths Solutions Chapter 1 Exercise 1.6 in PDF format via the link provided. Additionally, the PDF version is readily accessible for your convenience.

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NCERT Solutions for Class 11 Maths Chapter 1 – Sets Exercise 1.6

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Access Sets Class 11 Chapter 1 Exercise: 1.6

Question:1 If X and Y are two sets such that n ( X ) = 17, n ( Y ) = 23 and n ( X $\cup$ Y ) = 38, find n ( X $\cap$ Y ).

Answer:

n( X ) = 17, n( Y ) = 23 and n( X $\cup$ Y ) = 38

n( X $\cup$ Y ) = n( X ) + n( Y ) - n ( X $\cap$ Y )

38 = 17 + 23 - n ( X $\cap$ Y )

n ( X $\cap$ Y ) = 40 - 38

n ( X $\cap$ Y ) = 2.

Question:2 If X and Y are two sets such that X $\cup$ Y has 18 elements, X has 8 elements and Y has 15 elements ; how many elements does X $\cap$ Y have?

Answer:

n( X $\cup$ Y ) = 18

n(X) = 8

n(Y) = 15

n( X $\cup$ Y ) = n(X) + n(Y) - n(X $\cap$ Y)

n(X $\cap$ Y) = 8 + 15 - 18

n(X $\cap$ Y) = 5

Question:3 In a group of 400 people, 250 can speak Hindi and 200 can speak English. How many people can speak both Hindi and English?

Answer:

Hindi speaking = 250 = n(A)

English speakind = 200 = n(B)

Group of people = 400 = n(A $\cup$ B)

People speaking both Hindi and English = n(A $\cap$ B)

n(A $\cup$ B) = n(A) + n(B) - n(A $\cap$ B)

n(A $\cap$ B) = 250 + 200 - 400

n(A $\cap$ B) = 450 - 400

n(A $\cap$ B) = 50

Thus,50 people speak hindi and english both.

Question:4 If S and T are two sets such that S has 21 elements, T has 32 elements, and S $\cap$ T has 11 elements, how many elements does S $\cup$ T have?

Answer:

n(S) = 21

n(T) = 32

n(S $\cap$ T) = 11

n(S $\cup$ T) = n(S) + n(T) - n(S $\cap$ T)

n(S $\cup$ T) = 21 + 32 - 11

n(S $\cup$ T) = 53 - 11

n(S $\cup$ T) = 42

Hence, the set (S $\cup$ T) has 42 elements.

Question:5 If X and Y are two sets such that X has 40 elements, X $\cup$ Y has 60 elements and X $\cap$ Y has 10 elements, how many elements does Y have?

Answer:

n( X $\cup$ Y) = 60

n( X ∩ Y) = 10

n(X) = 40

n( X $\cup$ Y) = n(X) + n(Y) - n( X ∩ Y)

n(Y) = 60 - 40 + 10

n(Y) = 30

Hence,set Y has 30 elements.

Question:6 In a group of 70 people, 37 like coffee, 52 like tea and each person likes at least one of the two drinks. How many people like both coffee and tea?

Answer:

n(people like coffee) = 37

n(people like tea ) = 52

Total number of people = 70

Total number of people = n(people like coffee) + n(people like tea ) - n(people like both tea and coffee)

70 = 37 + 52 - n(people like both tea and coffee)

n(people like both tea and coffee) = 89 - 70

n(people like both tea and coffee) = 19

Hence,19 people like both coffee and tea.

Question:7 In a group of 65 people, 40 like cricket, 10 like both cricket and tennis. How many like tennis only and not cricket? How many like tennis?

Answer:

Total people = 65

n(like cricket) = 40

n(like both cricket and tennis) = 10

n(like tennis) = ?

Total people = n(like cricket) + n(like tennis) - n(like both cricket and tennis)

n(like tennis) = 65 - 40 + 10

n(like tennis) = 35

Hence,35 people like tennis.

n (people like only tennis) = n(like tennis) - n(like both cricket and tennis)

n (people like only tennis) = 35 - 10

n (people like only tennis) = 25

Hence,25 people like only tennis.

Question:8 In a committee, 50 people speak French, 20 speak Spanish and 10 speak both Spanish and French. How many speak at least one of these two languages?

Answer:

n(french) = 50

n(spanish) = 20

n(speak both french and spanish) = 10

n(speak at least one of these two languages) = n(french) + n(spanish) - n(speak both french and spanish)

n(speak at least one of these two languages) = 50 + 20 - 10

n(speak at least one of these two languages) = 70 -10

n(speak at least one of these two languages) = 60

Hence,60 people speak at least one of these two languages.

Benefits of NCERT Solutions for Class 11 Maths Chapter 1 Exercise 1.6:-

NCERT Solutions for 11th class maths exercise 1.6 answers is not only useful for this chapter but also very important to understand other chapters like probability.
Exercise 1.6 Class 11 Maths can be solved using Venn's diagram, but the formulas derived from it will be useful in other chapters also.
Class 11th Maths chapter 1 exercise 1.6 solutions can be used as a reference.

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Key Features of 11th Class Maths Exercise 1.6 Answers

Step-by-step solutions: The exercise 1.6 class 11 maths solution provides a detailed, step-by-step explanation of each problem, making it easier for students to understand the concepts.
Clarity and accuracy: The class 11 ex 1.6 answers are clear and accurate, ensuring that students can confidently prepare for their exams.
Additional resources: The availability of a downloadable PDF format makes it convenient for students to access the answers for study and revision.
Alignment with NCERT curriculum: The class 11 maths chapter 1 exercise 1.6 answers are designed to align with the NCERT curriculum, ensuring that students are well-prepared for their examinations.

Also see-

NCERT Solutions of Class 11 Subject Wise

Subject Wise NCERT Exampler Solutions

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Frequently Asked Questions (FAQs)

1. Can I get NCERT exemplar solutions for Class 11 Maths ?

Yes, click on the link to get NCERT Exemplar Solutions for Class 11 Maths.

2. Do I need to buy NCERT exempler solution book for Class 11 Maths ?

No, you don't need to buy NCERT exemplar solutions book for class 11 maths. It is available online on Careers360.

3. Can I get chemistry Class 11 NCERT exemplar solutions ?

Here you will get the NCERT Exemplar Solutions for Class 11 Chemistry.

4. If X and Y are two sets such that n ( X ) = 10, n ( Y ) = 13 and n ( X ∪ Y ) = 20, find n ( X ∩ Y ).

n ( X ∩ Y ) = n ( X ) + n ( Y ) - n ( X ∪ Y ) = 10 + 13 - 20 = 3

5. What is the weightage of Algebra in the Class 11 Maths ?

The unit Algebra has 30 marks weightage in the CBSE Class 11 Maths.

6. What is the syllabus for CBSE Class 11 Maths ?

Here you will get S yllabus for CBSE Class 11 Maths.

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