NCERT Solutions for Exercise 1.6 Class 11 Maths Chapter 1 - Sets
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Download PDFIn NCERT solutions for Class 11 Maths chapter 1 exercise 1.6 you will learn about the practical problems on union and intersection of two sets. Class 11th Maths chapter 1 exercise 1.6 is all about the applications of the union of two sets, the intersection of two sets, and applications of Venn's diagram. You should try to solve all the problems given in the Class 11 Maths ch 1 ex 1.6 on your own. These problems are related to our daily life problems which you must solve to get clarity. You may not be able to solve these NCERT problems at first, Class 11 Maths chapter 1 exercise 1.6 solutions are here help you. This NCERT book exercise is not only important for this chapter but formulae derived in this exercise will be used in the upcoming chapter probability. If you are looking for NCERT Solutions, click on the given link where you will find the detailed NCERT Solutions for Classes 6 to 12 at one place.
Mar 05, 2022
Also, see
- Sets Exercise 1.1
- Sets Exercise 1.2
- Sets Exercise 1.3
- Sets Exercise 1.4
- Sets Exercise 1.5
- Sets Miscellaneous Exercise
Sets Class 11 Chapter 1 Exercise: 1.6
Question:1 If X and Y are two sets such that n ( X ) = 17, n ( Y ) = 23 and n ( X 
Y ) = 38, find n ( X 
Y ).
Answer:
n( X ) = 17, n( Y ) = 23 and n( X Y ) = 38
n( X Y ) = n( X ) + n( Y ) - n ( X
Y )
38 = 17 + 23 - n ( X Y )
n ( X Y ) = 40 - 38
n ( X Y ) = 2.
Answer:
n( X Y ) = 18
n(X) = 8
n(Y) = 15
n( X Y ) = n(X) + n(Y) - n(X
Y)
n(X Y) = 8 + 15 - 18
n(X Y) = 5
Answer:
Hindi speaking = 250 = n(A)
English speakind = 200 = n(B)
Group of people = 400 = n(A B)
People speaking both Hindi and English = n(A B)
n(A B) = n(A) + n(B) - n(A
B)
n(A B) = 250 + 200 - 400
n(A B) = 450 - 400
n(A B) = 50
Thus,50 people speak hindi and english both.
Answer:
n(S) = 21
n(T) = 32
n(S T) = 11
n(S T) = n(S) + n(T) - n(S
T)
n(S T) = 21 + 32 - 11
n(S T) = 53 - 11
n(S T) = 42
Hence, the set (S T) has 42 elements.
Answer:
n( X Y) = 60
n( X ∩ Y) = 10
n(X) = 40
n( X Y) = n(X) + n(Y) - n( X ∩ Y)
n(Y) = 60 - 40 + 10
n(Y) = 30
Hence,set Y has 30 elements.
Answer:
n(people like coffee) = 37
n(people like tea ) = 52
Total number of people = 70
Total number of people = n(people like coffee) + n(people like tea ) - n(people like both tea and coffee)
70 = 37 + 52 - n(people like both tea and coffee)
n(people like both tea and coffee) = 89 - 70
n(people like both tea and coffee) = 19
Hence,19 people like both coffee and tea.
Answer:
Total people = 65
n(like cricket) = 40
n(like both cricket and tennis) = 10
n(like tennis) = ?
Total people = n(like cricket) + n(like tennis) - n(like both cricket and tennis)
n(like tennis) = 65 - 40 + 10
n(like tennis) = 35
Hence,35 people like tennis.
n (people like only tennis) = n(like tennis) - n(like both cricket and tennis)
n (people like only tennis) = 35 - 10
n (people like only tennis) = 25
Hence,25 people like only tennis.
Answer:
n(french) = 50
n(spanish) = 20
n(speak both french and spanish) = 10
n(speak at least one of these two languages) = n(french) + n(spanish) - n(speak both french and spanish)
n(speak at least one of these two languages) = 50 + 20 - 10
n(speak at least one of these two languages) = 70 -10
n(speak at least one of these two languages) = 60
Hence,60 people speak at least one of these two languages.
More About NCERT Solutions for Class 11 Maths Chapter 1 Exercise 1.6:-
In NCERT syllabus Class 11th Maths chapter 1 exercise 1.6, you will get eight questions based on the practical applications of union, the intersection of the set, and Venn's diagram. Before Class 11 Maths ch 1 ex 1.6 there are some solved examples given in the textbook which you can solve. Solving these examples will help you to understand the concept clearly. The last concept of this chapter is useful in solving relations and functions problems as well as in probability.
Also Read| Sets Class 11th Notes
Benefits of NCERT Solutions for Class 11 Maths Chapter 1 Exercise 1.6:-
- NCERT solutions for Class 11 Maths chapter 1 Exercise 1.6 is not only useful for this chapter but also very important to understand other chapters like probability.
- Exercise 1.6 Class 11 Maths can be solved using Venn's diagram, but the formulas derived from it will be useful in other chapters also.
- Class 11th Maths chapter 1 exercise 1.6 solutions can be used as reference.
Also see-
NCERT Solutions of Class 11 Subject Wise
Subject Wise NCERT Exampler Solutions
Happy learning!!!
Frequently Asked Question (FAQs) - NCERT Solutions for Exercise 1.6 Class 11 Maths Chapter 1 - Sets
Question: Can I get NCERT exemplar solutions for Class 11 Maths ?
Answer:
Yes, click on the link to get NCERT Exemplar Solutions for Class 11 Maths.
Question: Do I need to buy NCERT exempler solution book for Class 11 Maths ?
Answer:
No, you don't need to buy NCERT exemplar solutions book for class 11 maths. It is available online on Careers360.
Question: Can I get chemistry Class 11 NCERT exemplar solutions ?
Answer:
Here you will get the NCERT Exemplar Solutions for Class 11 Chemistry.
Question: If X and Y are two sets such that n ( X ) = 10, n ( Y ) = 13 and n ( X ∪ Y ) = 20, find n ( X ∩ Y ).
Answer:
n ( X ∩ Y ) = n ( X ) + n ( Y ) - n ( X ∪ Y ) = 10 + 13 - 20 = 3
Question: What is the weightage of Algebra in the Class 11 Maths ?
Answer:
The unit Algebra has 30 marks weightage in the CBSE Class 11 Maths.
Question: What is the syllabus for CBSE Class 11 Maths ?
Answer:
Here you will get Syllabus for CBSE Class 11 Maths.
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