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Consider a classroom where some students enjoy playing chess, while a few others enjoy playing ludo, and a few of the students are equally interested in both sports. If someone is asked to find out how many students play only chess or only ludo, which method would be used to solve this problem? The answer would be the Venn diagram method, which uses simple shapes like circles in a rectangle to organize the information provided and helps solve such questions. The circles in the Venn diagram show different sets available, and the rectangle represents the universal set. In this case, the universal set is the collection of all the students in the class we are referring to. The visual approach of solving such questions makes it simpler to analyse the data and solve complex patterns.
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JEE Main Scholarship Test Kit (Class 11): Narayana | Physics Wallah | Aakash | Unacademy
Suggested: JEE Main: high scoring chapters | Past 10 year's papers
In this exercise 1.4 of Class 11 Maths Chapter 1 of the NCERT, you will learn how to use Venn Diagrams to represent various data sets provided in the questions and further solve with the help of techniques such as union, intersection and difference of sets. The NCERT solutions discuss step-by-step methodology to apply these techniques effectively. The Venn diagram method is important for other chapters as well, such as relations, functions and probability. If you are looking for NCERT Solutions, you can click on the given link to get NCERT solutions for Classes 6 to 12.
Question 1:(i) Find the union of each of the following pairs of sets :
X = {1, 3, 5} Y = {1, 2, 3}
Answer:
Union of X and Y is X
Question:1(ii) Find the union of each of the following pairs of sets :
A = [ a, e, i, o, u} B = {a, b, c}
Answer:
Union of A and B is A
Question 1:(iii) Find the union of each of the following pairs of sets :
A = {x : x is a natural number and multiple of 3} B = {x : x is a natural number less than 6}
Answer:
Here ,
A = {3,6,9,12,15,18,............}
B = {1,2,3,4,5,6}
Union of A and B is A
A
Question 1:(iv) Find the union of each of the following pairs of sets :
A = {x : x is a natural number and 1
B = {x : x is a natural number and 6
Answer:
Here,
A = {2,3,4,5,6}
B = {7,8,9}
A
or it can be written as A
Question 1:(v) Find the union of each of the following pairs of sets :
A = {1, 2, 3} B =
Answer:
Here,
A union B is A
A
Question 2: Let A = { a, b }, B = {a, b, c}. Is A
Answer:
Here,
We can see elements of A lie in set B.
Hence, A
And, A
Question 3: If A and B are two sets such that A
Answer:
If A is subset of B then A
Question 4:(i) If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8 }and D = { 7, 8, 9, 10 }; find
A
Answer:
Here,
A = {1, 2, 3, 4}
B = {3, 4, 5, 6}
The union of the set can be written as follows
A
Question 4:(ii) If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8 }and D = { 7, 8, 9, 10 }; find
A
Answer:
Here,
A = {1, 2, 3, 4}
C = {5, 6, 7, 8 }
The union can be written as follows
A
Question 4:(iii) If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8 }and D = { 7, 8, 9, 10 }; find
B
Answer:
Here,
B = {3, 4, 5, 6},
C = {5, 6, 7, 8 }
The union of the given sets are
B
Question 4:(iv) If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8 }and D = { 7, 8, 9, 10 }; find
B
Answer:
Here,
B = {3, 4, 5, 6}
D = { 7, 8, 9, 10 }
B
Question 4:(v) If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8 }and D = { 7, 8, 9, 10 }; find
A
Answer:
Here,
A = {1, 2, 3, 4},
B = {3, 4, 5, 6},
C = {5, 6, 7, 8 }
The union can be written as
A
Question 4:(vi) If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8 }and D = { 7, 8, 9, 10 }; find
A
Answer:
Here,
A = {1, 2, 3, 4},
B = {3, 4, 5, 6}
D = { 7, 8, 9, 10 }
The union can be written as
A
Question 4:(vii) If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8 }and D = { 7, 8, 9, 10 }; find
B
Answer:
Here,B = {3, 4, 5, 6},
C = {5, 6, 7, 8 } and
D = { 7, 8, 9, 10 }
The union can be written as
B
Question 5: Find the intersection of each pair of sets of question 1 above
(i) X = {1, 3, 5} Y = {1, 2, 3}
(ii) A = [ a, e, i, o, u} B = {a, b, c}
(iii) A = {x : x is a natural number and multiple of 3} B = {x : x is a natural number less than 6}
(iv) A = {x : x is a natural number and 1
(v) A = {1, 2, 3}, B =
Answer:
(i) X = {1, 3, 5} Y = {1, 2, 3}
X
(ii) A = [ a, e, i, o, u} B = {a, b, c}
A
(iii) A = {x : x is a natural number and multiple of 3} B = {x : x is a natural number less than 6}
A = {3,6,9,12,15.......} B = {1,2,3,4,5}
A
(iv)A = {x : x is a natural number and 1
A = {2,3,4,5,6} B = {7,8,9}
A
(v) A = {1, 2, 3}, B =
A
Question 6: If A = { 3, 5, 7, 9, 11 }, B = {7, 9, 11, 13}, C = {11, 13, 15}and D = {15, 17}; find
(i) A
(iii) A
(v) B
(vii) A
(ix) ( A
Answer:
Here, A = { 3, 5, 7, 9, 11 }, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}
(i) A
(ii) B
(iii) A
(iv) A
(v) B
(i) A
(ii) A
(iii) A
(iv) B
(v) B
(vi) C
Answer:
Here, A = {1,2,3,4,5,6...........}
B = {2,4,6,8,10...........}
C = {1,3,5,7,9,11,...........}
D = {2,3,5,7,11,13,17,......}
(i) A
(ii) A
(iii) A
(iv) B
(v) B
(vi) C
Question 8:(i) Which of the following pairs of sets are disjoint
{1, 2, 3, 4} and {x : x is a natural number and 4
Answer:
Here, {1, 2, 3, 4} and {4,5,6}
{1, 2, 3, 4}
Hence,it is not a disjoint set.
Question 8:(ii) Which of the following pairs of sets are disjoint
{ a, e, i, o, u } and { c, d, e, f }
Answer:
Here, { a, e, i, o, u } and { c, d, e, f }
{ a, e, i, o, u }
Hence,it is not disjoint set.
Question 8:(iii) Which of the following pairs of sets are disjoint
{x : x is an even integer } and {x : x is an odd integer}
Answer:
Here, {x : x is an even integer } and {x : x is an odd integer}
{2,4,6,8,10,..........} and {1,3,5,7,9,11,.....}
{2,4,6,8,10,..........}
Hence,it is disjoint set.
(i) A – B (ii) A – C (iii) A – D (iv) B – A (v) C – A (vi) D – A
(vii) B – C (viii) B – D (ix) C – B (x) D – B (xi) C – D (xii) D – C
Answer:
A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 }, C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {5, 10, 15, 20 }
The given operations are done as follows
(i) A – B = {3,6,9,15,18,21} (vii) B – C = {20}
(ii) A – C = {3,9,15,18,21} (viii) B – D = {4,8,12,16}
(iii) A – D = {3,6,9,12,18,21} (ix) C – B = {2,6,10,14}
(iv) B – A = {4,8,16,20} (x) D – B = {5,10,15}
(v) C – A = {2,4,8,10,14,16} (xi) C – D = {2,4,6,8,12,14,16}
(vi) D – A = {5,10,20} (xii) D – C = {5,15,20}
Question 10: If X= { a, b, c, d } and Y = { f, b, d, g}, find
(i) X – Y
(ii) Y – X
(iii) X
Answer:
X= { a, b, c, d } and Y = { f, b, d, g}
(i) X – Y = {a,c}
(ii) Y – X = {f,g}
(iii) X
Question 11: If R is the set of real numbers and Q is the set of rational numbers, then what is R – Q?
Answer:
R = set of real numbers.
Q = set of rational numbers.
R - Q = set of irrational numbers.
Question 12:(i) State whether each of the following statement is true or false. Justify your answer.
{ 2, 3, 4, 5 } and { 3, 6} are disjoint sets.
Answer:
Here,
{ 2, 3, 4, 5 } and { 3, 6}
{ 2, 3, 4, 5 }
Hence,these are not disjoint sets.
So,false.
Question 12:(ii) State whether each of the following statement is true or false. Justify your answer.
{ a, e, i, o, u } and { a, b, c, d }are disjoint sets
Answer:
Here, { a, e, i, o, u } and { a, b, c, d }
{ a, e, i, o, u }
Hence,these are not disjoint sets.
So, statement is false.
Question 12:(iii) State whether each of the following statement is true or false. Justify your answer.
{ 2, 6, 10, 14 } and { 3, 7, 11, 15} are disjoint sets.
Answer:
Here,
{ 2, 6, 10, 14 } and { 3, 7, 11, 15}
{ 2, 6, 10, 14 }
Hence, these are disjoint sets.
So,given statement is true.
Question 12:(iv) State whether each of the following statement is true or false. Justify your answer.
{ 2, 6, 10 } and { 3, 7, 11} are disjoint sets.
Answer:
Here,
{ 2, 6, 10 } and { 3, 7, 11}
{ 2, 6, 10 }
Hence,these are disjoint sets.
So,statement is true.
Also Read
1. Union of Sets (∪)
The union of sets is an important topic of this exercise. The union of two or more sets is a set which contains all distinct elements from the sets involved in the discussion. Hence, it can be said that it combines elements from all sets without duplication. It is represented by A∪B for union of sets A and B.
2. Venn Diagrams
Venn diagrams are a representation where we use overlapping circles to represent sets and their relationships as per the information provided in the problems. Venn diagrams help in understanding operations like union, intersection, and difference clearly. Each region of the diagram is related to different combinations of membership.
3. Operations on Sets
There are various operations on sets which help us solve various complex problems related to sets. Set operations include union, intersection, and difference. These operations are used to compare and combine various sets. Further, these operations help in solving problems related to groupings and logical relationships among data, and each operation follows specific mathematical rules. Let's discuss some of the operations:
3.1 Union of Sets
Union is the set of all elements that belong to at least one of the sets. It's used to find the total collection of unique elements when sets are combined.
Example: A={1,2},B={2,3}
⇒A∪B={1,2,3}
3.2. Intersection of Sets (∩)
The intersection of sets consists of elements common to all involved sets. It highlights shared data or values between sets.
Example: A∩B={x:x∈A and x∈B}
3.3 Difference of Sets (−)
The difference of sets (A − B) includes elements that are only in the first set and not in the second. It’s useful to identify exclusive elements from a group.
Example: A={1,2,3},B={2,3}⇒A−B={1}
Also Read
Follow the links to get your hands on subject-wise NCERT textbooks and exemplar solutions to ace your exam preparation.
NCERT Solutions for Class 11 Maths |
NCERT Solutions for Class 11 Physics |
NCERT Solutions for Class 11 Chemistry |
NCERT Solutions for Class 11 Biology |
The union of set A and set B is a set that contains all the elements from set A as well as all the elements from set B.
The intersection of set A and set B is a set that contains the common elements from set A and set B.
A = { 1,2,4,6}
B={2,1,6,7}
A U B = { 1,2,4,6,7}
A = { 1,2,4,6}
B={2,1,6,7}
A ∩ B = { 1,2,6}
A = { 1,2,4,6}
B={2,1,6,7}
A - B = { 4}
A = { 1,2,4,6}
B={2,1,6,7}
B - A = { 7 }
U ∩ A = A
Yes, A ∪ B = B ∪ A (Commutative law)
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