NCERT Solutions For Class 11 Biology Chapter 6 Anatomy of Flowering Plants

NCERT Solutions For Class 11 Biology Chapter 6 Anatomy of Flowering Plants

Edited By Irshad Anwar | Updated on Sep 05, 2023 09:39 PM IST

Anatomy of Flowering Plants | NCERT Solutions PDF Download

NCERT Solutions for Class 11 Biology Chapter 6 Anatomy of Flowering Plants: You will get insight to the internal structure and functional organization of higher plants in Anatomy of Flowering Plants Class 11 NCERT Solutions. The study of the internal structure of plants is called anatomy. Solutions to NCERT Class 11 Biology Chapter 6: Anatomy of Flowering Plants carry an impressive explanation of all the questions that are based on the Anatomy of Flowering Plants NCERT. You need to remember that plants have cells as their basic unit, cells are organized into tissues, and in turn, the tissues are organized into organs. The chapter Anatomy of Flowering Plants of the NCERT Solutions for Class 11 Biology will tell you about the different organs in a plant that show differences in their internal structure and it is important to know because you are going to get questions related to this in NCERT Solutions for Class 11 Biology Chapter 6 Anatomy of Flowering Plants. Within angiosperms, the monocots and dicots are also seen to be anatomically different. Internal structures also show adaptations to diverse environments. If you are looking for an answer from any other chapter even from any other class then go with NCERT Solutions, there you will get all the answers of NCERT Textbooks easily.

NCERT Solutions for Class 11 provide solutions for all subjects and give students the perfect tool for learning as well as last-minute reference. Class 11 Biology NCERT Solutions are created by a group of specialists who are highly knowledgeable in their specialized fields. Class 11 Biology Chapter 6 NCERT Solutions are available in PDF format that are easy to access, download and use offline. There are three types of tissue systems given in Ch 6 Bio Class 11 related to which you will get questions as well as answers in the solutions of Class 11 Biology Chapter 6.

  1. Epidermal
  2. Ground
  3. Vascular

After going through Anatomy of Flowering Plants NCERT Solutions, you must be able to understand all the answers to the following questions, which are mentioned below and you will be able to answer that the stinging hairs are found in epidermal layer of ?

NCERT Solutions For Class 11 Biology Anatomy of Flowering Plants - Download PDF

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NCERT Solutions for Class 11 Biology Chapter 6: Anatomy of Flowering Plants (Solved Exercise)

Class 11 Biology Chapter 6 Question Answers are explained in details with best format for easy to read and understand.

Anatomy of Flowering Plants Class 11 Questions and Answers

Q1. State the location and function of different types of meristems.

Answer:

Meristem refers to the simple tissue composed of a group of similar and immature cells which can divide and form new cells. ON the basis of position, there can be three types of meristem including apical meristem, intercalary meristem and lateral meristem. The location and function of these meristems are as follows:

Type of meristem
Location of meristem
Function of meristem
Apical meristem
It occurs at the tips of roots and shoots
It increases the length of plants
Intercalary meristem
It occurs between mature tissues especially in grasses
Intercalary meristem aids in the regeneration of grasses after they have been grazed by herbivores
Lateral meristem
It occurs on the sides of mature tissues of roots and shoots
It causes an increase in the girth of plants

Q2. Cork cambium forms tissues that form the cork. Do you agree with this statement? Explain.

Answer:

Cork cambium or phellogen is the secondary meristem that develops in the region of cortex to replace the outer epidermal cells that will provide protection to the stem and root from infections. Cork cambium is composed of thin-walled rectangular cells and it cuts off cells on both sides. The outer cells differentiate to form cork or phellem while the inner cells differentiate into secondary cortex or phelloderm. Together, the phellogen, phellem, and phelloderm constitute the periderm. The cork is impervious to water but allows gaseous exchange through the lenticels. Hence, c ork cambium forms tissues that form the cork

Q3. Explain the process of secondary growth in the stems of woody angiosperms with the help of schematic diagrams. What is its significance?

Answer:

The increase in girth of a plant body is called secondary growth. The tissues involved in secondary growth are vascular cambium and cork cambium. In a young stem, vascular cambium is found in the form of patches as a single layer between the xylem and phloem. During the later stage, it forms a complete ring. Soon, the cambial ring becomes active and begins to cut off new cells towards the inner and the outer sides. The cells which are cut off towards pith mature into secondary xylem while those which are cut off towards the periphery after maturation develops into secondary phloem. The cambium is most of the times more active on the inner side than on the outer. This is the reason, the amount of secondary xylem produced is more than secondary phloem. The primary and secondary phloems get gradually crushed due to the continued formation and accumulation of secondary xylem. Then at some places, the cambium forms a narrow band of parenchyma, which passes through the secondary xylem and the secondary phloem in the radial directions. These are the secondary medullary rays.

Q4. Draw illustrations to bring out the anatomical difference between

(i) Monocot root and Dicot root

Answer:

Monocot root

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Dicot root-

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Anatomy of Flowering Plants Class 11 Questions and Answers

Q5. Cut a transverse section of young stem of a plant from your school garden and observe it under the microscope.

How would you ascertain whether it is a monocot stem or a dicot stem? Give reasons.

Answer:

An unknown sample can be identified to be either dicot stem or monocot stem based on the following characteristics-

Characteristics of a dicot stem-

1. The vascular bundles are conjoint, collateral, and open, with a strip of cambium between the xylem and phloem.

2. The vascular bundles are arranged to form a ring, around the centrally-located pith

3. The ground tissue is differentiated into the collenchyma, parenchyma, endodermis, pericycle, and pith.

4. In between the vascular bundles, medullary rays are present.

Characteristics of monocot stem-

1. The hypodermis is made up of sclerenchyma.

2. The Vascular bundles are conjoint, closed and scattered.

3. Each vascular bundle is surrounded by a sclerenchymatous bundle sheath.

4. Phloem parenchyma is absent.

5. Water-containing cavities are present within the vascular bundles.

Q6. The transverse section of a plant material shows the following anatomical features -

(i) the vascular bundles are conjoint, scattered and surrounded by a sclerenchymatous bundle sheath.

What will you identify it as?

Answer:

The vascular bundles are conjoint, scattered and surrounded by a sclerenchymatous bundle sheath in monocot stem.

Q6. The transverse section of a plant material shows the following anatomical features -

(ii) phloem parenchyma is absent.

What will you identify it as?

Answer:

Phloem parenchyma is absent in monocot stem.

Q7. Why are xylem and phloem called complex tissues?

Answer:

Complex tissues are tissues made up of more than one types of cells. Since xylem and phloem are consists of different kinds of elements, they are called complex tissues. Xylem is consists of vessels, tracheid, xylem fibre and xylem parenchyma

1. Tracheids- These are elongated, thick-walled dead cells having pointed ends. These lack protoplasm

2. Vessels- These are long, tubular, and cylindrical structures that are formed from the vessel members, with each having lignified walls and large central cavities. Vessels being dead lack protoplasm.

3. Xylem fibres consist of thick walls with an almost insignificant lumen. These provide mechanical support to the plant.

4. Xylem parenchyma is made up of thin-walled parenchymatous cells that help in the storage of food materials and in the radial conduction of water

Phloem is made up of sieve tube, companion cells, phloem parenchyma and phloem fibres

1. Sieve tube- The sieve tube elements are tube-like elongated structures associated with companion cells. The end walls of sieve tube elements are perforated to form the sieve plate. Sieve tube elements are living cells containing cytoplasm and nucleus.

2. Companion cells- These cells are parenchymatous in nature and they help in maintaining the pressure gradient in the sieve tube elements.

3. Phloem parenchyma- These cells help in the storage of food and they are made up of long tapering cells, with dense cytoplasm.

4. Phloem fibres- These are made up of elongated sclerenchymatous cells with thickened walls.

Q8. What is stomatal apparatus? Explain the structure of stomata with a labelled diagram.

Answer:

Stomata are tiny pores or holes found to be present in the epidermis of leaves. The major function of these stomata is to regulate the process of transpiration and gaseous exchange. The stomatal pore remains surrounded by specialised cells called guard cells which in turn are surrounded by subsidiary cells.

The stomatal pore, guard cells and the surrounding subsidiary cells together constitute the stomatal apparatus.

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The gaseous exchange is maintained by guard cells. In dicots, guard cells are bean-shaped while in monocots, guard cells are dumbell shaped.

Anatomy of Flowering Plants Questions and Answers NCERT

Q9. Name the three basic tissue systems in the flowering plants. Give the tissue names under each system.

Answer:

The three basic tissue systems in the flowering plants include epidermal tissue system, ground tissue system and vascular tissue system.

1. Epidermal tissue system- It forms the outermost covering of whole plant body. It consists of tissues like epidermis, stomata, epidermal appendages (trichomes and hairs) etc.

2. Ground tissue system- All the tissue between the epidermis and vascular bundle forms the ground tissues. It consists of simple permanent tissues like parenchyma, sclerenchyma, collenchyma, mesophyll etc. It includes pericycle, cortex, pith and medullary rays

3. Vascular tissue system- The vascular tissue system consists of complex tissues, xylem and phloem that together form vascular bundles.

Q10. How is the study of plant anatomy useful to us?

Answer:

The study of plant anatomy useful to us in the following ways

1. The study of anatomy helps to know the structures of plants that can be of commercial value. For example, jute, flax etc.

2. Study of anatomy can help in knowing the age of trees

3. By knowing the anatomical details, we can identify the unknown plant samples.

4. Anatomy may also help in understanding the structural adaptations of plants with respect to diverse environmental conditions.

Q12. Describe the internal structure of a dorsiventral leaf with the help of labelled diagrams.

Answer:

The internal structure of a dorsiventral leaf-

The leaf lamina of a dorsiventral leaf has 3 parts: epidermis, mesophyll and vascular system.

1. Epidermis- The epidermis is two layered. The upper epidermis is called the adaxial epidermis and the lower one is called abaxial epidermis. More number of stomata are present on the abaxial epidermis.

2. Mesophyll- Inner to epidermis, mesophyll tissue is present. There are two types of cells in the mesophyll i.e. palisade parenchyma and spongy parenchyma. The palisade parenchyma is placed adaxially while the spongy parenchyma is situated below the palisade parenchyma and extends to the lower epidermis. There are numerous large spaces and air cavities between the cells of spongy parenchyma.

3. Vascular system- The vascular bundles are surrounded by a layer of thick-walled bundle sheath cells. They are conjoint and closed.

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Q13. What is periderm? How does periderm formation take place in the dicot stems?

Answer:

The periderm refers to the collective term used to signify phellogen, phellem, and phelloderm in a plant stem. Periderm formation in plants, mainly occurs to replace the existing epidermis.

Formation of periderm

The formation of periderm occurs during secondary growth. During this process, to replace the broken outer epidermal layer and the cortical layer, the cells of the cortex turn meristematic. As a result of this, cork cambium or phellogen is formed. The phellogen is composed of thin-walled, narrow and rectangular cells. Later on, the phellogen cuts off cells on its either side. The cells of the outer side give rise to the phellem or cork which due to the deposition of suberin in its cell wall is impervious to water. Similarly, the inner side forms secondary cortex or phelloderm which is mainly parenchymatous in nature.

Important Topics of NCERT Solutions for Class 11 Biology Chapter 6 Anatomy of Flowering Plants

Important topics covered in the Chapter 6 Biology Class 11 NCERT Solutions are listed below:

6.1 The Tissues

6.1.1 Meristematic Tissues

6.1.2 Permanent Tissues

6.1.2.1 Simple Tissues

6.1.2.2 Complex Tissues

6.2 The Tissue System

6.2.1 Epidermal Tissue System

6.2.2 The Ground Tissue System

6.2.3 The Vascular Tissue System

6.3 Anatomy of Dicotyledonous and Monocotyledonous Plants

6.3.1 Dicotyledonous Root

6.3.2 Monocotyledonous Root

6.3.3 Dicotyledonous Stem

6.3.4 Monocotyledonous Stem

6.3.5 Dorsiventral (Dicotyledonous) Leaf

6.3.6 Isobilateral (Monocotyledonous) Leaf

6.4 Secondary Growth

6.4.1 Vascular Cambium

6.4.1.1 Formation of cambial ring

6.4.1.2 Activity of the cambial ring

6.4.1.3 Springwood and autumn wood

6.4.1.4 Heartwood and sapwood

6.4.2 Cork Cambium

6.4.3 Secondary Growth in Roots

In Anatomy of Flowering Plants NCERT, monocotyledonous and dicotyledonous plants show marked variation in their internal structures. They differ in type, number and location of vascular bundles and based on this you will get questions along with their answers in CBSE NCERT Solutions Class 11 Biology Chapter 6. The secondary growth occurs in most of the dicotyledonous roots and stems and it increases the girth (diameter) of the organs by the activity of the vascular cambium and the cork cambium. Go through these topics before practicing Anatomy of Flowering Plants Questions and Answers NCERT.

Highlights of NCERT Solutions Class 11 Biology Anatomy of Flowering Plants

Highlights for Biology Class 11 Chapter 6 are given below:

  • The solution given in the Anatomy of Flowering Plants NCERT PDF is written in the best possible way using simple language that makes solutions easier to read and understand.
  • In the Class 11 Biology Chapter 6 Question Answers, points are used to frame answers to help understand quickly.
  • Anatomy of Flowering Plants Questions and Answers PDF is derived from the textbook by the subject expert.
  • Class 11 biology Anatomy of Flowering Plants NCERT Solutions are as per the latest CBSE Syllabus and guidelines.
  • Anatomy of Flowering Plants Class 11 PDF links are readily available and easily accessible for free.
  • Important topics are listed in the Anatomy of Flowering Plants Class 11 NCERT Solutions.
  • Ch 6 Bio Class 11 is a great resource for information.
  • Anatomy of Flowering Plants NCERT will also help you to prepare for your competitive exams like NEET.
  • Chapter 6 Bio Class 11 NCERT Solutions will also boost your knowledge and interest in biology.
  • NCERT is the base of your learning and answers for Anatomy of flowering plants class 11 NCERT are easy to access.

NCERT Solutions for Class 11 Biology- Chapter Wise

NCERT Solutions for Class 11: Subject-wise

NCERT Solutions for Class 11 Biology Chapter 6 – Anatomy of Flowering Plants

If you are unable to determine these questions or facing any problem to understand Chapter 6 Biology Class 11 NCERT Solutions, then go through the book again and then try to solve all the given questions by yourself and then match it from the CBSE NCERT Solutions for Class 11 Biology Chapter 6 Anatomy of Flowering Plants, as it will help you to prepare not only for the school exam even also for other competitive exams like NEET.

Check the NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. What are the epidermal tissue systems made up of as given in class 11 biology chapter 6?
  1. epidermal cells  
  2. stomata  
  3. epidermal appendages 
2. What are the benefits of NCERT solutions for biology class 11 chapter 6 ?
  • NCERT is the base of your learning.  
  • You will get all the answers to ch 6 bio class 11  and it will help you to score good marks in the exam.  
  • NCERT solutions for class 11 biology chapter 6 anatomy of flowering plants will also help you in your 12th board exam.  
  • Anatomy of flowering plants class 11 ncert pdf will also boost your knowledge.  
  • CBSE   NCERT solutions for class 11 biology chapter 6 anatomy of flowering plants will also help you with competitive exams like NEET. 
  • To score well in the examination, follow the NCERT syllabus and solve the exercise given in the NCERT Book. To practice more problems, students must refer to NCERT Exemplar.

3. What are the important topics of NCERT solutions for biology class 11 chapter 6 ?

The important topics of class 11 biology chapter 6:  

  • The Tissues
  • Meristematic Tissues  
  • Permanent Tissues  
  • Epidermal Tissue System  
  • The Ground Tissue System  
  • The Vascular Tissue System  
  • Anatomy of Dicotyledonous and Monocotyledonous Plants  
  • Secondary Growth  
  • Vascular Cambium  
  • Cork Cambium 
  • Secondary Growth in Roots 
4. What are the function of meristem given in anatomy of flowering plants class 11 ncert pdf ?
  • It increases the length of plants.
  • Intercalary meristem aids in the regeneration of grasses after they have been grazed by herbivores.
  • It causes an increase in the girth of plants.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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