NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

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NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salt: Students must know that NCERT Acids, Bases, and Salts, Class 10 Science, chapter 2 Solutions is an important chapter from which 3 marks or 5 marks questions may be asked. In these NCERT solutions for Acids Bases and Salts Class 10 Science chapter 2, you will come to know the answers and step wise solutions to the questions asked in NCERT Class 10 Science books. If you want to score well in board exams then NCERT solutions for Class 10 Science will give you proper knowledge of the concepts, equations, and formulas. Read below to get exercise and question-wise NCERT solutions Class 10 Science chapter 2.

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NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

NCERT Solutions For Class 10 Science Chapter 2 Acids And Bases are available in this article. The Chapter-wise NCERT solutions for class 10 science have been updated as per the latest CBSE Science class 10 syllabus and guidelines. If you want to perform well in Science for the Class 10 board exams as well as the JEE and NEET, you must have a thorough understanding of the theories, practice with the reactions, equations, and formulas, and answer questions from the NCERT Chemistry books.

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Three to four questions are always drawn from this chapter for the Class 10 exam. As more questions from chapter 2 science class 10 will likely result in a perfect score, it is also one of the more crucial chapters. Therefore, it is advised that students use these NCERT Solutions for Class 10 Science to practice all of the Class 10 Science Chapter 2 question answer. In previous year's question papers, practical- and subjective-based multiple-choice questions were frequently asked. Student can access NCERT Solutions for Class 10 - Subject wise Solutions for other subjects.

NCERT Solutions for Class 10 Science Chapter 2 Acid Bases and Salts

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NCERT Solutions for Class 10 Science Chapter 2 - Acid Bases and Salts (In-Text Questions and Exercise)

Chapter 2 Chemistry Class 10

Topic : Introduction

Q 1. You have been provided with three test tubes. One of them contains distilled water and the other two contain an acidic solution and a basic solution, respectively. If you are given only red litmus paper, how will you identify the contents of each test tube?

Answer: Litmus is a common indicator that is used to identify acid and base. The colour of litmus paper turns to blue indicates that the chemical is a base. If there is no change in colour, then the chemical is either acidic or neutral.
First marks the three test tubes as A, B, and C.
Now,

(i) First of all, put the red litmus paper in each test tube one by one. The test tube in which red litmus paper will turn blue indicates the solution of that test tube is basic/Alkaline in nature.

(ii) Now remaining two are either acidic or neutral. Now mix a drop of the basic solution with a drop of each of the remaining two solutions separately and then the nature of the drops of the mixtures is checked. If the colour of the red litmus turns blue, then the second solution is neutral and if there is no change in colour, then the second solution is acidic. This is because acidic and basic solutions neutralize each other.

NCERT solutions for class 10 science chapter 2 Acids, Bases and Salts

Topic 2.1 - Understanding the chemical properties of acids and bases

Q.1 Why should curd and sour substances not be kept in brass and copper vessels?

Answer: Curd and sour substances not be kept in brass and copper vessels because curd and other sour substances contain acids.
Therefore, when they are kept in brass and copper vessels, the metal reacts with the acid to liberate hydrogen gas and harmful products, thereby may spoil the food.

Q2 Which gas is usually liberated when an acid reacts with a metal? Illustrate with an example. How will you test for the presence of this gas?

Answer: Hydrogen gas is usually liberated when an acid reacts with a metal.
When zinc granules react with dilute sulphuric acid, then the bubbles of the soap solution are formed. These soap bubbles contain hydrogen gas and a zinc sulphate solution is formed.

$Zn +2 H_2SO_4\Rightarrow Zn(SO_4)_2+2H_2$

The evolved hydrogen gas can be tested by taking a burning candle near a soap solution containing hydrogen gas. If the candle burns with a pop sound, it confirms the evolution of hydrogen gas.

Q.3 Metal compound A reacts with dilute hydrochloric acid to produce effervescence. The gas evolved extinguishes a burning candle. Write a balanced chemical equation for the reaction if one of the compounds formed is calcium chloride.

Answer: During the chemical reaction, the evolved gas extinguishes a burning candle which means the gas is carbon dioxide.

Since, one of the compounds formed during this reaction is calcium chloride and carbon dioxide is formed when dilute hydrochloric acid reacts with a metal carbonate (or metal hydrogen carbonate) producing effervescence it means the metal compound is calcium carbonate (It cannot be calcium hydrogen carbonate because calcium hydrogen carbonate is found only in solution, it is also unstable to exist as a solid). Hence, the compound A is calcium carbonate.

The chemical reaction is written as follows:

$CaCO_3+2HCL_{(aq)}\rightarrow CaCL_{2(aq)}+CO_{2(g)}+H_2O_{(l)}$

NCERT solutions for class 10 science chapter 2 Acids And Bases

Topic 2.2 What do all acids and all bases have in common?

Q.1 Why do HCl, HNO ₃ , etc., show acidic characters in aqueous solutions while solutions of compounds like alcohol and glucose do not show acidic character?

Answer:

Acids form hydrogen ions [ $H^+$ (aq) ions] in its aqueous solution which is responsible for their acidic characters. $HCl \ and \ HNO_3$ form hydrogen ions in aqueous solution hence, they show acidic characters in aqueous solution.

The reaction of HCL is as follows:
$HCl_{(aq)}\rightarrow H^++Cl^-$
$H^++H_2O\rightarrow H_3O^+$

While solutions of compounds like alcohol and glucose do not form hydrogen ions in the solution, hence, they do not show acidic character.

Q.2 Why does an aqueous solution of acid conduct electricity?

Answer:

Acids dissociate in aqueous solutions to form ions. Like hydrogen ions ( $H^+$ ) or hydronium ions ( $H_3O^+$ ) and the presence of these ions in an aqueous solution of acid are responsible for conducting electricity.

Q.3 Why does dry HCl gas not change the colour of the dry litmus paper?

Answer:

The colour of litmus paper changes only in the presence of ions like hydrogen ( $H^+$ ) or hydronium ( $H_3O^+$ ) ions. Dry HCl does not contain ( $H^+$ ) or ( $H_3O^+$ ) ions. It can produce these ions only in the form of an aqueous solution.

Hence, because of that dry HCl gas does not change the colour of dry litmus paper.

Q.4 While diluting an acid, why is it recommended that the acid should be added to water and not water to the acid?

Answer:

The process of dissolving an acid in water is highly exothermic in which a large amount of heat is evolved. It is always recommended that acid should slowly be added to water because evolved heat is easily absorbed by a large amount of water.

If it is done the other way, then it is possible that because of the large amount of heat generated, the mixture splashes out and causes burns,

Q.5 How is the concentration of hydronium ions (H ₃ O ⁺ ) affected when a solution of an acid is diluted?

Answer:

When the solution of an acid is diluted, the concentration of hydronium ions $(H_3O^+)$ per unit volume decreases.

That means, the strength of the acid decreases.

Q.6 How is the concentration of hydroxide ions $(OH^-)$ affected when excess base is dissolved in a solution of sodium hydroxide?

Answer:

The concentration of hydroxide ions $\left (OH^{-} \right )$ would increase when excess base is dissolved in a solution of sodium hydroxide .

NCERT solutions for class 10 science chapter 2 Acids, Bases and Salts

Topic 2.3 How strong are acid or base solutions

Q. 1 You have two solutions, A and B. The pH of solution A is 6 and the pH of solution B is 8. Which solution has more hydrogen ion concentration? Which of this is acidic and which one is basic?

Answer:

The pH value of less than 7 indicates an acidic solution while greater than 7 indicates a basic solution. The pH value of a neutral solution is 7. And the acidic solution has more hydrogen ion concentration.

Therefore, solution A with pH = 6 is acidic and has more hydrogen ion concentration than solution B with pH = 8 which is basic.

Q.2 What effect does the concentration of H ⁺ (aq) ions have on the nature of the solution?

Answer:

Concentration of $H^+$ (aq) can have a varied effect on the nature of the solution.When we increase the concentration of $H^+$ ions in the solution, the solution becomes more acidic, while when we decrease the concentration of $H^+$ ions in the solution, the basicity of the solution increases.

Q.3 Do basic solutions also have H ⁺ (aq) ions? If yes, then why are these basic?

Answer:

Yes, the basic solution also has H+(aq) ions. However, they are basic because the concentration of hydrogen ions in them is less as compared to the concentration of hydroxide ions $[OH^- ions]$ that makes the solution basic.

Q.4 Under what soil condition do you think a farmer would treat the soil of his fields with quick lime (calcium oxide) or slaked lime (calcium hydroxide) or chalk (calcium carbonate)?

Answer:

Quicklime, slaked lime and chalk are basic in nature. When they react with acids, the neutralization reaction takes place.

Therefore, If the soil is acidic and improper for cultivation, then to increase the basicity of soil, the farmer would treat the soil with quicklime or slaked lime or chalk

NCERT solutions for class 10 science chapter 2 Acids, Bases, and Salts

Topic 2.4 More about salts

Q.1 What is the common name of the compound $CaOCl_{2}$ ?

Answer:

The common name of the compound $CaOCl_{2}$ is bleaching powder.

Q.2 Name the substance which on treatment with chlorine yields bleaching powder .

Answer:

Calcium hydroxide $[Ca(OH)_2]$ on treatment with chlorine yields bleaching powder.

Q.3 Name the sodium compound which is used for softening hard water.

Answer:

Washing soda $(Na_2CO_3.10H_20)$ is used for softening hard water.

Q.4 What will happen if a solution of sodium hydrocarbonate is heated? Give the equation of the reaction involved.

Answer:

When a solution of sodium hydrogen carbonate (sodium hydrogen carbonate) is heated, it undergoes decomposition reaction to form sodium carbonate and water, and carbon dioxide gas is liberated.

The equation of the reaction involved is:

$2NaHCO_3 \xrightarrow[]{heat} Na_2CO_3+H_2O+CO_2$

Q.5 Write an equation to show the reaction between the Plaster of Paris and water .

Answer :

The chemical equation for the reaction of Plaster of Paris and water can be represented as $CaSO_4.\frac{1}{2}H_2O+ 1\frac{1}{2}H_2O\rightarrow CaSO_4.2H_2O$

NCERT Class 10 Science Chapter 2 Exercise Solutions

All questions from the chapter-end exercise have been covered in these Class 10 Science Chapter 2 Exercise Solutions:

Q.1 A solution turns red litmus blue, its pH is likely to be

(a) 1 (b) 4 (c) 5 (d) 10

Answer:

(d) As we have lean bases turn red litmus blue. The basic solution has a pH value of more than 7. Since the solution turns red litmus blue, therefore its pH is likely to be > 7 i.e. 10.

Q.2 A solution reacts with crushed egg-shells to give a gas that turns lime-water milky. The solution contains

(a) NaCl (b) HCl (c) LiCl (d) KCl

Answer:

(b) The solution contains HCI reacts with crushed egg-shells to give a gas that turns lime-water milky.

Q.3 10 mL of a solution of NaOH is found to be completely neutralized by 8 mL of a given solution of HCl. If we take 20 ml of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralize it will be

(a) 4 mL (b) 8 mL (c) 12 mL (d) 16 mL

Answer:

It is given that
10ml of NaOH neutralizes 8ml Solution of HCl
$\therefore$ 1 ml of NaOH neutralizes = $\frac{8}{10} = \frac{4}{5} \ ml$ Solution of HCl
Therefore, 20 ml of NaOH will neutralise= $\frac{4}{5}\times 20=16 \ ml$ solution of HCL

Therefore, 16 ml of HCl solution will be required to neutralize the 20 ml of NaOH.

The correct answer is (d)

Q.4 Which one of the following types of medicines are used for treating indigestion?

(a) Antibiotic

(b) Analgesic

(d) Antiseptic

Answer:

Q.5 Write word equations and then balanced equations for the reaction taking place when –

(a) dilute sulphuric acid reacts with zinc granules.

(b) dilute hydrochloric acid reacts with magnesium ribbon.

(d) dilute hydrochloric acid reacts with iron filings.

Answer:

Balanced equations are:-

(a) $H_2SO_4_{(aq)}+Zn_{(s)}\rightarrow ZnSO_4_{(aq)}+H_2_{(g)}$

(b) $2HCl_ {(aq)} + Mg_{(s)}\rightarrow MgCl_{2 (aq)} + H_{2(g)}$

(d) $6HCl_ {(aq)} +2Fe_{ (s)} \rightarrow 2FeCl_{3(aq)} +3H_{2(g)}$

Class 10th Science Chapter 2 Question Answer

Q.6 Compounds such as alcohol and glucose also contain hydrogen but are not categorized as acids. Describe an activity to prove it.

Answer:

Take the solution of dilute hydrochloric solution and glucose. Two nails are fitted on a cork and are kept it in a 100 mL beaker. The nails are then connected to the two terminals of a 6-volt battery through a bulb and a switch. Dilute HCl is poured in the beaker and current is switched on. Now, the same experiment is performed with a glucose solution and an alcohol solution.

We will observe that the bulb glows in the HCl solution and does not glow in the glucose solution.

Because: HCl dissociate into H + (aq) and Cl -(aq) ions. These ions conduct electricity in the solution resulting in the glowing of the bulb. On the other hand, the glucose solution does not dissociate into ions. Therefore, it does not conduct electricity.

Conclusion:
From this activity, it can be concluded that all acids contain hydrogen but not all compounds containing hydrogen are acids. That is why, though compounds like alcohols and glucose contain hydrogen, they are not categorized as acids.

Q.7 Why does distilled water not conduct electricity, whereas rainwater does?

Answer: Distilled water is a pure form of water that does not contain ions. Therefore, it does not conduct electricity. Rainwater on the other hand, being an impure form of water, contains many ionic compounds such as acids and therefore it conducts electricity.

Q.8 Why do acids not show acidic behaviour in the absence of water?

Answer: Acids do not show acidic behaviour in the absence of water because acids form hydrogen ions [H ⁺ (aq) ions] in its aqueous solution which are responsible for their acidic characters and the dissociation of hydrogen ions from an acid occurs in the presence of water only.
Therefore in the absence of water, acids do not produce hydrogen ions and hence do not show acidic behaviour.

Q.9 (a) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

Neutral?

Answer: Solution with pH equal to 7 is a neutral solution. Therefore, a neutral solution is D

Q.9(b) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

Strongly alkaline?

Answer: The solution with the highest pH is strongly alkaline. Therefore, a strongly alkaline solution is C with a pH equal to 11

Q.9(c) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

Strongly acidic?

Answer: The solution with the lowest pH value is strongly acidic. Therefore, a strongly acidic solution is B with pH equal to 1

Q.9(d) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

Weakly acidic?

Answer: Solution with pH less than 7 but close to 7 is weakly acidic. Therefore, the weakly acidic solution is A with a pH equal to 4

Q.9(e) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

e) Weakly alkaline?

Answer: The solution with a pH greater than 7 but close to 7 is weakly alkaline. Therefore, a weakly alkaline solution is E with pH equal to 9

NCERT Solutions for Class 10 Science Chapter 2 Exercise Questions

Q.10 Equal lengths of magnesium ribbons are taken in test tubes A and B. Hydrochloric acid (HCl) is added to test tube A, while acetic acid $\left (CH_{3}COOH \right )$ is added to test tube B. Amount and concentration taken for both the acids are same. In which test tube will the fizzing occur more vigorously and why?

Answer: When an acid reacts with magnesium metal, hydrogen gas is produced which causes fizzing. Stronger acids having a greater number of hydrogen ions in it. Hence, fizzing will occur strongly in test tube A, in which hydrochloric acid (HCI) is added.
This is because HCI is a stronger acid as compared to $\left (CH_{3}COOH \right )$ and therefore, during the chemical reaction with magnesium metal, HCl will produce more hydrogen gas due to which fizzing will be more vigorous in test-tube A.

Q.11 Fresh milk has a pH of 6. How do you think the pH will change as it turns into curd? Explain your answer.

Answer: The pH of fresh milk is 6.
As milk turns into curd, lactic acid is formed due to which it becomes more acidic. Therefore, the pH of milk will decrease.

Q.12(a) A milkman adds a very small amount of baking soda to fresh milk.

(a) Why does he shift the pH of the fresh milk from 6 to slightly alkaline?

Answer: Fresh milk is slightly acidic in nature, The milkman shifts the pH of the fresh milk from 6 to slightly alkaline by adding little baking soda.
Because this will prevent the milk from getting sour due to lactic acid formation.

Q.12(b) A milkman adds a very small amount of baking soda to fresh milk.

(b) Why does this milk take a long time to set as curd?

Answer: Since this milk is slightly basic than usual milk, the lactic acid, formed during curdling, needs to first neutralize the alkali present in the milk.
Therefore, it takes a longer time for the curd to set.

Q. 13 The plaster of Paris should be stored in a moisture-proof container. Explain why?

Answer: Plaster of Paris should be stored in a moisture-proof container because it absorbs moisture (or water) to form a hard substance called gypsum which makes Plaster of Paris useless.

$CaSO_4.\frac{1}{2}H_2O+1\frac{1}{2}H_2O\rightarrow CaSO_4.2H_2O$

Q.14 What is a neutralization reaction? Give two examples.

Answer: A reaction in which an acid and base react with each other to give a salt and water is known as neutralization reaction. That is: Acid + Base → Salt + Water

For example:

(i) Sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl) to form sodium chloride (NaCl) and water:

$NaOH + HCl \rightarrow NaCl + H_2O$

(ii) Magnesium hydroxide reacts with hydrochloric acid to form magnesium chloride and water:

$Mg(OH)_2+2HCl \rightarrow MgCl_2+2H_2O$

Q.15 Give two important uses of washing soda and baking soda.

Answer: Uses of Washing Soda:

(i) It is used for removing the permanent hardness of the water.

(ii) It is used in glass, soap, and paper industries.

Uses of Baking Soda:

(i) It is used in soda-acid fire extinguishers.

(ii) It is used in making baking powder. Baking powder is a mixture of baking soda and a mild edible acid called tartaric acid. When baking powder is heated

or mixed in water, it releases CO₂ that makes cakes or bread fluffy.

Acids And Bases Class 10: Important Formulas and Diagrams + eBook link

Important formula from NCERT Solution for class 10 chapter 2 science are given below:

Important Reactions:

Acid + Metal → Salt + Hydrogen gas

Example: 2NaOH(aq) + Zn(s) → Na2ZnO2 (s) + H2 (g) (Sodium zincate)

Metal carbonate/Metal hydrogencarbonate + Acid → Salt + Carbon dioxide + Water

Example: NaHCO3(s) + HCl(aq) —-> NaCl(aq) + H2O(l) + CO2(g)

Base + Acid → Salt + Water

Example: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

Metal oxide + Acid → Salt + Water

When electricity is passed through an aqueous solution of sodium chloride (called brine), it decomposes to form sodium hydroxide. The process is called the chlor-alkali process because of the products formed– chlor for chlorine and alkali for sodium hydroxide.

2NaCl(aq) + 2H2O(l) → 2NaOH(aq) + Cl2 (g) + H2 (g)

Bleaching Powder (CaOCl2) Formation:

Ca(OH)2 + Cl2 → CaOCl2 + H2O

Baking Soda (NaHCO3) Formation:

NaCl + H2O + CO2 + NH3 —---> NH4Cl (Ammonium chloride) + NaHCO3 (Sodium hydrogencarbonate)

Washing Soda (Na2CO3 .10H2O) Formation:

Na2CO3 (sodium carbonate) + 10 H2O —------> Na2CO3 .10H2O

Plaster of Paris:

1689942421137

For more, Download Ebook - NCERT Class 10 Science: Chapterwise Important Formulas, Diagrams, And Points

NCERT Solutions for Class 10 Science Chapter 2 Acid Bases and Salts - Topics and Subtopics

Before delving into Acid Base and Salt lass 10 question answer in more detail, let us take a quick look at the topics and subtopics covered in NCERT Solutions for Class 10 Science Chapter 2 Activities.

UNDERSTANDING THE CHEMICAL PROPERTIES OF ACIDS AND BASES

Acids and Bases in the Laboratory
How do Acids and Bases React with Metals?
How do Metal Carbonates and Metal Hydrogencarbonates React with Acids?
How do Acids and Bases React with each other?
Reaction of Metallic Oxides with Acids
Reaction of a Non-metallic Oxide with Base

WHAT DO ALL ACIDS AND ALL BASES HAVE IN COMMON?

What Happens to an Acid or a Base in a Water Solution?

HOW STRONG ARE ACID OR BASE SOLUTIONS?

Importance of pH in Everyday Life yday Life

MORE ABOUT SALTS

Family of Salts
pH of Salts
Chemicals from Common Salt
Are the Crystals of Salts really Dry?

Free download NCERT Solutions for Class 10 Science Chapter 2 Acids And Bases PDF for CBSE students who are using NCERT Books based on updated CBSE Syllabus.

NCERT Solutions for Class 10th Science - Chapter wise

Chapter No.	Chapter Name
Chapter 1	Chemical Reactions and Equations
Chapter 2	Acids, Bases, and Salts
Chapter 3	Metals and Non-metals
Chapter 4	Carbon and Its Compounds
Chapter 5	Periodic Classification of Elements
Chapter 6	Life Processes
Chapter 7	Control and Coordination
Chapter 8	How do Organisms Reproduce?
Chapter 9	Heredity and Evolution
Chapter 10	Light Reflection and Refraction
Chapter 11	The Human Eye and The Colorful World
Chapter 12	Electricity
Chapter 13	Magnetic Effects of Electric Current
Chapter 14	Sources of Energy
Chapter 15	Our Environment
Chapter 16	Sustainable Management of Natural Resources

Class 10 Chemistry Chapter 2 NCERT Solutions - Learning Outcomes

The learning outcocmes for science class 10 chapter 2 are listed below:

Through these NCERT Class 10 Science solutions chapter 2, you will get to know that the strength of an acid or an alkali can be tested by using a scale called the pH scale (0-14).
In Class 10 Science Chapter 2 NCERT solutions, you will also study when an acid reacts with a metal, hydrogen gas is evolved and a corresponding salt is formed.
You will study about the salt formation in Class 10 Science Chapter 2 question answer. A salt is formed when a base reacts with metal, along with the evolution of hydrogen gas which has a negative ion composed of the metal and oxygen.
In NCERT Class 10 Science Chapter 2 exercise solutions you will study abut the metal reactions. When an acid reacts with a metal hydrogen carbonate or metal carbonate, it gives the corresponding salt, water, and carbon dioxide gas.
You will study about water conduction in Class 10 Science Chapter 2 Solutions. Electricity in water is conducted by Acidic and basic solutions because they produce hydrogen and hydroxide ions respectively.

Benefits of NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases, and Salts:

Class 10 Science Chapter 2 pdf are easy to download for free and can accessed offline anytime anywhere.
The NCERT (CBSE) Syllabus and Books are strictly followed in the solution given for chemistry class 10 chapter 2.
These NCERT solutions Class 10 science chapter 2 works like a time saviour. Students will get the solutions for all the exercises and extra questions related to this chapter.
All the NCERT 10th class science Chapter 2 solutions are created by experienced experts.
The language of the acids bases and salts class 10 solutions is easy to understand.
The class 10 chemistry chapter 2, helps you to clear your concepts.

Also, check

Also Check NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. What is the name of Class 10 Science 2nd Chapter?

2nd chapter name is ‘Acids, Bases, and Salts’. Questions of the NCERT book helps to study the chapter well for the exam.

2. What are the important topics of Class 10 Science Chapter 2 Acids, Bases, and Salts?

Sodium Hydroxide, Bleaching Powder, Baking Soda, Washing Soda and Plaster of Paris are the important topics of NCERT Class 10 Science Chapter 2 solutions.

3. What is the weightage of chapter Acids, Bases, and Salts in CBSE Class 10 board final exam?

This chapter holds the weightage of 3 or 5 marks in CBSE Board exams. More questions on the chapter Acids Bases and Salts can be practiced from previous year papers of CBSE board Science exam and the NCERT exemplar.

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Questions related to CBSE Class 10th

Have a question related to CBSE Class 10th ?

sadhu ashram ramgart road aligarh

If you're looking for directions or steps to reach Sadhu Ashram on Ramgart Road in Aligarh, here’s how you can get there:

Steps to Reach Sadhu Ashram, Ramgart Road, Aligarh:

Starting Point:
- Determine your starting point in Aligarh or the nearby area.
Use Google Maps:
- Open Google Maps on your phone or computer.
- Enter "Sadhu Ashram, Ramgart Road, Aligarh" as your destination.
- Follow the navigation instructions provided by Google Maps.
By Local Transport:
- Auto-rickshaw/Taxi: Hire an auto-rickshaw or taxi and inform the driver about your destination. Most local drivers should be familiar with Sadhu Ashram.
- Bus: Check if there are any local buses that operate on Ramgart Road. Ask the bus conductor if the bus stops near Sadhu Ashram.
Landmarks to Look For:
- As you approach Ramgart Road, look for local landmarks that might help you confirm you’re on the right path, such as known shops, temples, or schools nearby.
Ask for Directions:
- If you're unsure, ask locals for directions to Sadhu Ashram on Ramgart Road. It's a known location in the area.
Final Destination:
- Once you reach Ramgart Road, Sadhu Ashram should be easy to spot. Look for any signage or ask nearby people to guide you to the exact location.

If you need detailed directions from a specific location or more information about Sadhu Ashram, feel free to ask

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sai raja 01 September,2024

show the previous year exams ?

Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.

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SWETCHCHA MISKA 10 July,2024

as an icse student in class 10 is above 80 percent good enough to get into commerce in 11th cbse

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

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Manasvini Gupta 23 July,2024

i had cleared 10th from cbse in 2022 2 years ago now i wish to apply for 12th as private candidate in 2025. can i do so?

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

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Ashvadha 03 July,2024

i had cleared 10th in 2022 from cbse can i apply for 12th as private candidate this year?

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.

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sadafreen356 03 July,2024

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Central Board of Secondary Education Class 10th Examination

Applications Open

Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

Option 1) less than 3	Option 2) more than 3 but less than 6
Option 3) more than 6 but less than 9	Option 4) more than 9

NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

Pearson | PTE

NCERT Solutions for Class 10 Science Chapter 2 Acid Bases and Salts

NCERT Solutions for Class 10 Science Chapter 2 - Acid Bases and Salts (In-Text Questions and Exercise)

Topic 2.1 - Understanding the chemical properties of acids and bases

Topic 2.2 What do all acids and all bases have in common?

Topic 2.3 How strong are acid or base solutions

Topic 2.4 More about salts

NCERT Class 10 Science Chapter 2 Exercise Solutions

Acids And Bases Class 10: Important Formulas and Diagrams + eBook link

NCERT Solutions for Class 10 Science Chapter 2 Acid Bases and Salts - Topics and Subtopics

NCERT Solutions for Class 10th Science - Chapter wise

Class 10 Chemistry Chapter 2 NCERT Solutions - Learning Outcomes

Benefits of NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases, and Salts:

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