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NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

Edited By Shivani Poonia | Updated on Jun 22, 2025 06:57 PM IST | #CBSE Class 10th
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CBSE Class 10th  Exam Date : 10 Jul' 2025 - 15 Jul' 2025

Can you imagine the taste of food without salt? Food without salt is tasteless, and it becomes difficult for us to eat. Just like this, we encounter Acids, Bases, and salts in our daily life, like the stain of turmeric on a white cloth. If soap is spilled on that stain, then the color of the yellow stain is converted into reddish-brown. Acids, Bases, and Salts are essential in nature as well as in industry.

This Story also Contains
  1. Download PDF of NCERT Solutions for Class 10 Science Chapter 2
  2. NCERT Solutions for Class 10 Science Chapter 2 (In-Text Questions)
  3. NCERT Solutions for Class 10 Science Chapter 2 (Exercise Questions with Answers)
  4. Practice Questions for Class 10 Science Chapter 2
  5. Approach to Solve Questions of Class 10 Science Chapter 2
  6. Topics and Subtopics Covered in the NCERT Textbook
  7. NCERT Class 10 Science Chapter 2: Important Reactions And E-Book
  8. NCERT Solutions for Class 10 Science Chapter-wise
  9. NCERT Books and NCERT Syllabus
NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts
NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salts

This chapter explains the chemical nature of Acids, Bases, and Salts, and how they react with elements like metals and non-metals and with each other. It also explains some astonishing phenomena like a change of color of litmus papers, from red to blue when bases are present, and blue to red when acids are present, and no change in color if the substance is neutral.

NCERT solutions for Class 10 Science Chapter 2 will offer a systematic and structured approach for the exercise problems in the NCERT textbook to prepare well for your exams by providing comprehensive and detailed solutions to all the exercise questions in the NCERT textbook. Our subject matter expert prepares these NCERT Solutions for Class 10, which also serve as a valuable resource for students to enhance their performance in board exams and establish a strong foundation for various competitive exams like JEE and NEET.

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Download PDF of NCERT Solutions for Class 10 Science Chapter 2

Students looking for Class 10 Science Chapter 2 exercise solutions can download the PDF from the link below. In this PDF, students will get the detailed solutions with in-text questions.

Download Solution PDF

NCERT Solutions for Class 10 Science Chapter 2 (In-Text Questions)

To develop an understanding of the concept, In-text questions from the chapter 2 acid bases and salts class 10 solutions are important. At first, we are covering the in-text Class 10 Science Chapter 2 question answer, later we are covering the NCERT Class 10 Science Chapter 2 exercise solutions.

Topic: Introduction Page no-18

Question 1. You have been provided with three test tubes. One of them contains distilled water and the other two contain an acidic solution and a basic solution, respectively. If you are given only red litmus paper, how will you identify the contents of each test tube?

Answer:

Litmus is a common indicator that is used to identify acid and base. The colour of litmus paper turns to blue indicates that the chemical is a base. If there is no change in colour, then the chemical is either acidic or neutral.
First marks the three test tubes as A, B, and C.
Now,

(i) First of all, put the red litmus paper in each test tube one by one. The test tube in which red litmus paper will turn blue indicates the solution of that test tube is basic/Alkaline in nature.

(ii) Now remaining two are either acidic or neutral. Now mix a drop of the basic solution with a drop of each of the remaining two solutions separately and then the nature of the drops of the mixtures is checked. If the colour of the red litmus turns blue, then the second solution is neutral and if there is no change in colour, then the second solution is acidic. This is because acidic and basic solutions neutralize each other.

Topic 2.1 - Understanding the chemical properties of acids and bases. Page no-18

Question.1 Why should curd and sour substances not be kept in brass and copper vessels?

Answer:

Curd and sour substances not be kept in brass and copper vessels because curd and other sour substances contain acids.
Therefore, when they are kept in brass and copper vessels, the metal reacts with the acid to liberate hydrogen gas and harmful products, thereby may spoil the food.

Question.2 Which gas is usually liberated when an acid reacts with a metal? Illustrate with an example. How will you test for the presence of this gas?

Answer:

Hydrogen gas is usually liberated when an acid reacts with a metal.
When zinc granules react with dilute sulphuric acid, then the bubbles of the soap solution are formed. These soap bubbles contain hydrogen gas and a zinc sulphate solution is formed.

Zn+2H2SO4Zn(SO4)2+2H2

The evolved hydrogen gas can be tested by taking a burning candle near a soap solution containing hydrogen gas. If the candle burns with a pop sound, it confirms the evolution of hydrogen gas.

Question.3 Metal compound A reacts with dilute hydrochloric acid to produce effervescence. The gas evolved extinguishes a burning candle. Write a balanced chemical equation for the reaction if one of the compounds formed is calcium chloride.

Answer:

During the chemical reaction, the evolved gas extinguishes a burning candle which means the gas is carbon dioxide.

Since, one of the compounds formed during this reaction is calcium chloride and carbon dioxide is formed when dilute hydrochloric acid reacts with a metal carbonate (or metal hydrogen carbonate) producing effervescence it means the metal compound is calcium carbonate (It cannot be calcium hydrogen carbonate because calcium hydrogen carbonate is found only in solution, it is also unstable to exist as a solid). Hence, the compound A is calcium carbonate.

The chemical reaction is written as follows:

CaCO3+2HCl(aq)CaCl2(aq)+CO2(g)+H2O(l)

Topic 2.2 What do all acids and all bases have in common? Page no- 25

Question.1 Why do HCl, HNO 3 , etc., show acidic characters in aqueous solutions while solutions of compounds like alcohol and glucose do not show acidic character?

Answer:

Acids form hydrogen ions [ H+(aq) ions] in its aqueous solution which is responsible for their acidic characters. HCl and HNO3 form hydrogen ions in aqueous solution hence, they show acidic characters in aqueous solution.

The reaction of HCL is as follows:

HCl(aq)H++ClH++H2OH3O+

While solutions of compounds like alcohol and glucose do not form hydrogen ions in the solution, hence, they do not show acidic character.

Question.2 Why does an aqueous solution of acid conduct electricity?

Answer:

Acids dissociate in aqueous solutions to form ions. Like hydrogen ions ( H+) or hydronium ions ( H3O+) and the presence of these ions in an aqueous solution of acid are responsible for conducting electricity.

Question.3 Why does dry HCl gas not change the colour of the dry litmus paper?

Answer:

The colour of litmus paper changes only in the presence of ions like hydrogen ( H+) or hydronium ( H3O+) ions. Dry HCl does not contain ( H+) or ( H3O+) ions. It can produce these ions only in the form of an aqueous solution.

Hence, because of that dry HCl gas does not change the colour of dry litmus paper.

Question.4 While diluting an acid, why is it recommended that the acid should be added to water and not water to the acid?

Answer:

The process of dissolving an acid in water is highly exothermic in which a large amount of heat is evolved. It is always recommended that acid should slowly be added to water because evolved heat is easily absorbed by a large amount of water.

If it is done the other way, then it is possible that because of the large amount of heat generated, the mixture splashes out and causes burns,

Question.5 How is the concentration of hydronium ions (H3O+) affected when a solution of an acid is diluted?

Answer:

When the solution of an acid is diluted, the concentration of hydronium ions (H3O+)per unit volume decreases.

That means, the strength of the acid decreases.

Question.6 How is the concentration of hydroxide ions (OH) affected when excess base is dissolved in a solution of sodium hydroxide?

Answer:

The concentration of hydroxide ions (OH) would increase when excess base is dissolved in a solution of sodium hydroxide .

Topic 2.3 How strong are acid or base solutions Page no-28

Question.1 You have two solutions, A and B. The pH of solution A is 6 and the pH of solution B is 8. Which solution has more hydrogen ion concentration? Which of this is acidic and which one is basic?

Answer:

The pH value of less than 7 indicates an acidic solution while greater than 7 indicates a basic solution. The pH value of a neutral solution is 7. And the acidic solution has more hydrogen ion concentration.

Therefore, solution A with pH = 6 is acidic and has more hydrogen ion concentration than solution B with pH = 8 which is basic.

Question.2 What effect does the concentration of H + (aq) ions have on the nature of the solution?

Answer:

Concentration of H+(aq) can have a varied effect on the nature of the solution. When we increase the concentration of H+ions in the solution, the solution becomes more acidic, while when we decrease the concentration of H+ions in the solution, the basicity of the solution increases.

Question.3 Do basic solutions also have H + (aq) ions? If yes, then why are these basic?

Answer:

Yes, the basic solution also has H+(aq) ions. However, they are basic because the concentration of hydrogen ions in them is less as compared to the concentration of hydroxide ions [OHions ]that makes the solution basic.

Question.4 Under what soil condition do you think a farmer would treat the soil of his fields with quick lime (calcium oxide) or slaked lime (calcium hydroxide) or chalk (calcium carbonate)?

Answer:

Quicklime, slaked lime and chalk are basic in nature. When they react with acids, the neutralization reaction takes place.

Therefore, If the soil is acidic and improper for cultivation, then to increase the basicity of soil, the farmer would treat the soil with quicklime or slaked lime or chalk

Topic 2.4 More about salts Page no- 33

Question.1 What is the common name of the compound CaOCl2 ?

Answer:

The common name of the compound CaOCl2 is bleaching powder.

Question.2 Name the substance which on treatment with chlorine yields bleaching powder .

Answer:

Calcium hydroxide [Ca(OH)2] on treatment with chlorine yields bleaching powder.

Question.3 Name the sodium compound which is used for softening hard water.

Answer:

Washing soda (Na2CO310H20) is used for softening hard water.

Question.4 What will happen if a solution of sodium hydrocarbonate is heated? Give the equation of the reaction involved.

Answer:

When a solution of sodium hydrogen carbonate (sodium hydrogen carbonate) is heated, it undergoes decomposition reaction to form sodium carbonate and water, and carbon dioxide gas is liberated.

The equation of the reaction involved is:

2NaHCO3 heat Na2CO3+H2O+CO2

Question.5 Write an equation to show the reaction between the Plaster of Paris and water .

Answer :

The chemical equation for the reaction of Plaster of Paris and water can be represented as CaSO412H2O+112H2OCaSO42H2O

NCERT Solutions for Class 10 Science Chapter 2 (Exercise Questions with Answers)

All questions from the chapter-end exercise have been covered in these Class 10 Science Chapter 2 Exercise Solutions:

Question.1 A solution turns red litmus blue, its pH is likely to be

(a) 1

(b) 4

(c) 5

(d) 10

Answer:

(d) As we have lean bases turn red litmus blue. The basic solution has a pH value of more than 7. Since the solution turns red litmus blue, therefore its pH is likely to be > 7 i.e. 10.

Question.2 A solution reacts with crushed egg-shells to give a gas that turns lime-water milky. The solution contains

(a) NaCl

(b) HCl

(c) LiCl

(d) KCl

Answer:

(b) The solution contains HCI reacts with crushed egg-shells to give a gas that turns lime-water milky.

Question.3 10 mL of a solution of NaOH is found to be completely neutralized by 8 mL of a given solution of HCl. If we take 20 ml of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralize it will be

(a) 4 mL

(b) 8 mL

(c) 12 mL

(d) 16 mL

Answer:

It is given that
10 ml of NaOH neutralizes 8 ml Solution of HCl 1ml of NaOH neutralizes =810

=45ml Solution of HCl

Therefore, 20 ml of NaOH will neutralise =45×20=16ml solution of HCL

Therefore, 16 ml of HCl solution will be required to neutralize the 20 ml of NaOH.

The correct answer is (d)

Question.4 Which one of the following types of medicines are used for treating indigestion?

(a) Antibiotic

(b) Analgesic

(c) Antacid

(d) Antiseptic

Answer:

(c) The antacid is used for treating indigestion.

Question.5 Write word equations and then balanced equations for the reaction taking place when –

(a) dilute sulphuric acid reacts with zinc granules.

(b) dilute hydrochloric acid reacts with magnesium ribbon.

(c) dilute sulphuric acid reacts with aluminum powder.

(d) dilute hydrochloric acid reacts with iron filings.

Answer:

Balanced equations are:-
(a) H2SO4(aq)+Zn(s)ZnSO4(aq)+H2(g)
(b) 2HCl(aq)+Mg(s)MgCl2(aq)+H2(g)
(c) 3H2SO4(aq)+2Al(s)Al2(SO4)3(aq)+3H2(g)
(d) 6HCl(aq)+2Fe(s)2FeCl3(aq)+3H2(g)

Question.6 Compounds such as alcohol and glucose also contain hydrogen but are not categorized as acids. Describe an activity to prove it.

Answer:

Take the solution of dilute hydrochloric solution and glucose. Two nails are fitted on a cork and are kept it in a 100 mL beaker. The nails are then connected to the two terminals of a 6-volt battery through a bulb and a switch. Dilute HCl is poured in the beaker and current is switched on. Now, the same experiment is performed with a glucose solution and an alcohol solution.

We will observe that the bulb glows in the HCl solution and does not glow in the glucose solution.

Because: HCl dissociate into H+ (aq) and Cl-(aq) ions. These ions conduct electricity in the solution resulting in the glowing of the bulb. On the other hand, the glucose solution does not dissociate into ions. Therefore, it does not conduct electricity.

Conclusion:
From this activity, it can be concluded that all acids contain hydrogen but not all compounds containing hydrogen are acids. That is why, though compounds like alcohols and glucose contain hydrogen, they are not categorized as acids.

Question.7 Why does distilled water not conduct electricity, whereas rainwater does?

Answer:

Distilled water is a pure form of water that does not contain ions. Therefore, it does not conduct electricity. Rainwater on the other hand, being an impure form of water, contains many ionic compounds such as acids and therefore it conducts electricity.

Question.8 Why do acids not show acidic behaviour in the absence of water?

Answer:

Acids do not show acidic behaviour in the absence of water because acids form hydrogen ions [H + (aq) ions] in its aqueous solution which are responsible for their acidic characters and the dissociation of hydrogen ions from an acid occurs in the presence of water only.
Therefore in the absence of water, acids do not produce hydrogen ions and hence do not show acidic behaviour.

Question.9 (a) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

  • Neutral?

Answer:

Solution with pH equal to 7 is a neutral solution. Therefore, a neutral solution is D

Question.9 (b) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

  • Strongly alkaline?

Answer:

The solution with the highest pH is strongly alkaline. Therefore, a strongly alkaline solution is C with a pH equal to 11

Question.9 (c) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

  • Strongly acidic?

Answer:

The solution with the lowest pH value is strongly acidic. Therefore, a strongly acidic solution is B with pH equal to 1

Question.9 (d) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

  • Weakly acidic?

Answer:

A solution with a pH less than 7 but close to 7 is weakly acidic. Therefore, the weakly acidic solution is A with a pH equal to 4

Question.9 (e) Five solutions A, B, C, D, and E, when tested with universal indicator, showed pH as 4,1,11,7 and 9, respectively. Which solution is

e) Weakly alkaline?

Answer:

The solution with a pH greater than 7 but close to 7 is weakly alkaline. Therefore, a weakly alkaline solution is E with pH equal to 9

Question.10 Equal lengths of magnesium ribbons are taken in test tubes A and B. Hydrochloric acid (HCl) is added to test tube A, while acetic acid (CH3COOH) is added to test tube B. Amount and concentration taken for both the acids are same. In which test tube will the fizzing occur more vigorously and why?

Answer:

When an acid reacts with magnesium metal, hydrogen gas is produced which causes fizzing. Stronger acids having a greater number of hydrogen ions in it. Hence, fizzing will occur strongly in test tube A, in which hydrochloric acid (HCI) is added.
This is because HCI is a stronger acid as compared to (CH3COOH) and therefore, during the chemical reaction with magnesium metal, HCl will produce more hydrogen gas due to which fizzing will be more vigorous in test-tube A.

Question.11 Fresh milk has a pH of 6. How do you think the pH will change as it turns into curd? Explain your answer.

Answer:

The pH of fresh milk is 6.
As milk turns into curd, lactic acid is formed due to which it becomes more acidic. Therefore, the pH of milk will decrease.

Question.12 (a) A milkman adds a very small amount of baking soda to fresh milk.

(a) Why does he shift the pH of the fresh milk from 6 to slightly alkaline?

Answer:

Fresh milk is slightly acidic in nature, The milkman shifts the pH of the fresh milk from 6 to slightly alkaline by adding little baking soda.
Because this will prevent the milk from getting sour due to lactic acid formation.

Question.12 (b) A milkman adds a very small amount of baking soda to fresh milk.

(b) Why does this milk take a long time to set as curd?

Answer:

Since this milk is slightly basic than usual milk, the lactic acid, formed during curdling, needs to first neutralize the alkali present in the milk.
Therefore, it takes a longer time for the curd to set.

Question. 13 The plaster of Paris should be stored in a moisture-proof container. Explain why?

Answer:

Plaster of Paris should be stored in a moisture-proof container because it absorbs moisture (or water) to form a hard substance called gypsum which makes Plaster of Paris useless.
CaSO412H2O+112H2OCaSO42H2O

Question.14 What is a neutralization reaction? Give two examples.

Answer:

A reaction in which an acid and base react with each other to give a salt and water is known as neutralization reaction. That is: Acid + Base → Salt + Water

For example:

(i) Sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl) to form sodium chloride (NaCl) and water:

NaOH+HClNaCl+H2O

(ii) Magnesium hydroxide reacts with hydrochloric acid to form magnesium chloride and water:

Mg(OH)2+2HClMgCl2+2H2O

Question.15 Give two important uses of washing soda and baking soda.

Answer:

Uses of Washing Soda:

(i) It is used for removing the permanent hardness of the water.

(ii) It is used in glass, soap, and paper industries.

Uses of Baking Soda:

(i) It is used in soda-acid fire extinguishers.

(ii) It is used in making baking powder. Baking powder is a mixture of baking soda and a mild edible acid called tartaric acid. When baking powder is heated

Or mixed in water, it releases CO2 that makes cakes or bread fluffy.

Practice Questions for Class 10 Science Chapter 2

Question 1. What are acids and bases? Give two examples of each?

Answer:

Acids: These substances release H+ ions in aqueous solutions.

Examples: HCl, H2SO4.

Bases: These substances release OH- ions in aqueous solutions.

Examples: NaOH, Ca(OH)2.

Question 2. Why is it important to maintain the pH of soil?

Answer:
Plants need a specific pH range to grow. If the soil is too acidic or basic, nutrients become unavailable, and plant growth is affected. So, maintaining the pH ensures proper nutrient absorption and fruther growth of the plant.

Question 3. What is the pH range of acidic, Basic, and neutral solution?

Answer:

The pH range of acidic, Basic, and neutral solution:

Acidic solution: pH less than 7.

Basic solution: pH greater than 7.

Neutral solution: pH equal to 7.

Approach to Solve Questions of Class 10 Science Chapter 2

Students can follow the strategy given below to solve the Class 10 science question more effectively and attractively, which can help them to score good marks in their exams.

1) The first step to solve any question is to understand the basics:

  • Understanding of the basic concepts like the pH scale, types of acids and bases, neutralisation reaction, indicators, etc.
  • Students can use visuals, like flowcharts and diagrams, for proper understanding of concepts like acid-base reactions, salt formation, etc.

2) Read the chapter thoroughly from the NCERT textbook, be extra careful while reading definitions, equations, and examples.

3) To get command over questions, solve all the in-text and end-of-chapter questions of the NCERT textbook.

4) Revise important reactions like neutralisation and acid-base titration again and again.

5) Try to memorise important equations and reactions like:

  • Common acid and base reactions.
  • Balanced chemical equations.

6) Revise concepts again and again and practice questions as much as you can. As practice makes a man perfect.

Topics and Subtopics Covered in the NCERT Textbook

Topics and subtopics covered in the NCERT for Class 10 Science Chapter 2 are given below. A basic understanding of these topics helps students to solve complex problems easily.

2.1 Understanding the Chemical Properties of Acids and Bases

2.1.1 Acids and Bases in the Laboratory

2.1.2 How do Acids and Bases React with Metals?

2.1.3 How do Metal Carbonates and Metal Hydrogencarbonates React with Acids?

2.1.4 How do Acids and Bases React with each other?

2.1.5 Reaction of Metallic Oxides with Acids

2.1.6 Reaction of a Non-metallic Oxide with Base

2.2 What do All Acids and All Bases Have in Common

2.2.1 What Happens to an Acid or a Base in a Water Solution?

2.3 How Strong are Acid or Base Solutions?

2.3.1 Importance of pH in Everyday Life

2.4 More About Salts

2.4.1 Family of Salts

2.4.2 pH of Salts

2.4.3 Chemicals from Common Salt

2.4.4 Are the Crystals of Salts really Dry?

NCERT Class 10 Science Chapter 2: Important Reactions And E-Book

Important formulas from the NCERT Solution for class 10, chapter 2, science are given below:

Important Reactions:

Acid + Metal → Salt + Hydrogen gas

Example: 2NaOH(aq) + Zn(s) → Na2ZnO2 (s) + H2 (g) (Sodium zincate)

Metal carbonate/Metal hydrogencarbonate + Acid → Salt + Carbon dioxide + Water

Example: NaHCO3(s) + HCl(aq) —-> NaCl(aq) + H2O(l) + CO2(g)

Base + Acid → Salt + Water

Example: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

Metal oxide + Acid → Salt + Water

When electricity is passed through an aqueous solution of sodium chloride (called brine), it decomposes to form sodium hydroxide. The process is called the chlor-alkali process because of the products formed– chlor for chlorine and alkali for sodium hydroxide.

2NaCl(aq) + 2H2O(l) → 2NaOH(aq) + Cl2 (g) + H2 (g)

Bleaching Powder (CaOCl2) Formation:

Ca(OH)2 + Cl2 → CaOCl2 + H2O

Baking Soda (NaHCO3) Formation:

NaCl + H2O + CO2 + NH3 —---> NH4Cl (Ammonium chloride) + NaHCO3 (Sodium hydrogen carbonate)

Washing Soda (Na2CO3 .10H2O) Formation:

Na2CO3 (sodium carbonate) + 10 H2O —------> Na2CO3.10H2O

Plaster of Paris:

CaSO412H2O


Preparation:

CaSO42H2O Gypsum  Heat CaSO4 Plaster of Paris 12H2O+112H2O

To download the E-Book click on the link given below


NCERT Solutions for Class 10 Science Chapter-wise

Class 10 NCERT chapter-wise solutions are given below:

NCERT Books and NCERT Syllabus

The NCERT books and syllabus links for class 10 are given below:

Also Read:

NCERT solutions for Class 10 Maths

Frequently Asked Questions (FAQs)

1. What are acids and bases?
  • Acids: Substances that donate hydrogen ions (H+) when dissolved in water. They generally have a sour taste, and can corrode metals. Acids turn blue litmus paper red.
  • Bases: Substances that accept hydrogen ions (H+) or donate hydroxide ions (OH-) when dissolved in water. They generally have a bitter taste, and feel slippery. Bases turn red litmus paper blue.
2. What is the pH scale?

It is a logarithmic scale which is used to specify the acidity or basicity of an aqueous solution. Range of pH scale is from 0 to 14.

  • pH < 7 : Acidic
  • pH = 7: Neutral
  • pH > 7: Basic
3. What are some common examples of salts?

Some common examples of salts include:

  • Sodium chloride (NaCl): Table salt.
  • Potassium chloride (KCl): Used in fertilizers.
  • Calcium carbonate (CaCO3): Found in limestone and in marble.
  • Magnesium sulfate (MgSO4 ): Used in bath salts.
4. What are indicators?

Indicators are substances that change the color depending on the pH of the solution. They are generally used to determine whether a solution is acidic, basic, or neutral. Common examples of indicators litmus paper, phenolphthalein, and methyl orange.

5. Why are strong acids more reactive than weak acids?

Strong acids are more reactive than weak acids because they release a much higher concentration of H+ ions into the solution.

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Questions related to CBSE Class 10th

Have a question related to CBSE Class 10th ?

Hello

Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.

1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.

2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.

3. Counseling and Seat Allocation:

After the KCET exam, you will need to participate in online counseling.

You need to select your preferred colleges and courses.

Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.

4. Required Documents :

Domicile Certificate (proof that you are a resident of Karnataka).

Income Certificate (for minority category benefits).

Marksheets (11th and 12th from the Karnataka State Board).

KCET Admit Card and Scorecard.

This process will allow you to secure a seat based on your KCET performance and your category .

check link for more details

https://medicine.careers360.com/neet-college-predictor

Hope this helps you .

Hello Aspirant,  Hope your doing great,  your question was incomplete and regarding  what exam your asking.

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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