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NCERT Solutions for Class 10 Science Chapter 2 Acids, Bases and Salt: Students must know that NCERT Acids, Bases, and Salts, Class 10 Science, chapter 2 Solutions is an important chapter from which 3 marks or 5 marks questions may be asked. In these NCERT solutions for Acids Bases and Salts Class 10 Science chapter 2, you will come to know the answers and step wise solutions to the questions asked in NCERT Class 10 Science books. If you want to score well in board exams then NCERT solutions for Class 10 Science will give you proper knowledge of the concepts, equations, and formulas. Read below to get exercise and question-wise NCERT solutions Class 10 Science chapter 2.
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Suggested: NCERT Class 10 Science: Chapterwise Important Formulas, Diagrams, and Points
NCERT Solutions For Class 10 Science Chapter 2 Acids And Bases are available in this article. The Chapter-wise NCERT solutions for class 10 science have been updated as per the latest CBSE Science class 10 syllabus and guidelines. If you want to perform well in Science for the Class 10 board exams as well as the JEE and NEET, you must have a thorough understanding of the theories, practice with the reactions, equations, and formulas, and answer questions from the NCERT Chemistry books.
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Three to four questions are always drawn from this chapter for the Class 10 exam. As more questions from chapter 2 science class 10 will likely result in a perfect score, it is also one of the more crucial chapters. Therefore, it is advised that students use these NCERT Solutions for Class 10 Science to practice all of the Class 10 Science Chapter 2 question answer. In previous year's question papers, practical- and subjective-based multiple-choice questions were frequently asked. Student can access NCERT Solutions for Class 10 - Subject wise Solutions for other subjects.
Also read,
Chapter 2 Chemistry Class 10
Topic : Introduction
Answer: Litmus is a common indicator that is used to identify acid and base. The colour of litmus paper turns to blue indicates that the chemical is a base. If there is no change in colour, then the chemical is either acidic or neutral.
First marks the three test tubes as A, B, and C.
Now,
(i) First of all, put the red litmus paper in each test tube one by one. The test tube in which red litmus paper will turn blue indicates the solution of that test tube is basic/Alkaline in nature.
(ii) Now remaining two are either acidic or neutral. Now mix a drop of the basic solution with a drop of each of the remaining two solutions separately and then the nature of the drops of the mixtures is checked. If the colour of the red litmus turns blue, then the second solution is neutral and if there is no change in colour, then the second solution is acidic. This is because acidic and basic solutions neutralize each other.
NCERT solutions for class 10 science chapter 2 Acids, Bases and Salts
Q.1 Why should curd and sour substances not be kept in brass and copper vessels?
Answer: Curd and sour substances not be kept in brass and copper vessels because curd and other sour substances contain acids.
Therefore, when they are kept in brass and copper vessels, the metal reacts with the acid to liberate hydrogen gas and harmful products, thereby may spoil the food.
Answer: Hydrogen gas is usually liberated when an acid reacts with a metal.
When zinc granules react with dilute sulphuric acid, then the bubbles of the soap solution are formed. These soap bubbles contain hydrogen gas and a zinc sulphate solution is formed.
The evolved hydrogen gas can be tested by taking a burning candle near a soap solution containing hydrogen gas. If the candle burns with a pop sound, it confirms the evolution of hydrogen gas.
Answer: During the chemical reaction, the evolved gas extinguishes a burning candle which means the gas is carbon dioxide.
Since, one of the compounds formed during this reaction is calcium chloride and carbon dioxide is formed when dilute hydrochloric acid reacts with a metal carbonate (or metal hydrogen carbonate) producing effervescence it means the metal compound is calcium carbonate (It cannot be calcium hydrogen carbonate because calcium hydrogen carbonate is found only in solution, it is also unstable to exist as a solid). Hence, the compound A is calcium carbonate.
The chemical reaction is written as follows:
NCERT solutions for class 10 science chapter 2 Acids And Bases
Answer:
Acids form hydrogen ions [ (aq) ions] in its aqueous solution which is responsible for their acidic characters. form hydrogen ions in aqueous solution hence, they show acidic characters in aqueous solution.
The reaction of HCL is as follows:
While solutions of compounds like alcohol and glucose do not form hydrogen ions in the solution, hence, they do not show acidic character.
Q.2 Why does an aqueous solution of acid conduct electricity?
Answer:
Acids dissociate in aqueous solutions to form ions. Like hydrogen ions ( ) or hydronium ions ( ) and the presence of these ions in an aqueous solution of acid are responsible for conducting electricity.
Q.3 Why does dry HCl gas not change the colour of the dry litmus paper?
Answer:
The colour of litmus paper changes only in the presence of ions like hydrogen ( ) or hydronium ( ) ions. Dry HCl does not contain ( ) or ( ) ions. It can produce these ions only in the form of an aqueous solution.
Hence, because of that dry HCl gas does not change the colour of dry litmus paper.
Answer:
The process of dissolving an acid in water is highly exothermic in which a large amount of heat is evolved. It is always recommended that acid should slowly be added to water because evolved heat is easily absorbed by a large amount of water.
If it is done the other way, then it is possible that because of the large amount of heat generated, the mixture splashes out and causes burns,
Answer:
When the solution of an acid is diluted, the concentration of hydronium ions per unit volume decreases.
That means, the strength of the acid decreases.
Answer:
The concentration of hydroxide ions would increase when excess base is dissolved in a solution of sodium hydroxide .
NCERT solutions for class 10 science chapter 2 Acids, Bases and Salts
Answer:
The pH value of less than 7 indicates an acidic solution while greater than 7 indicates a basic solution. The pH value of a neutral solution is 7. And the acidic solution has more hydrogen ion concentration.
Therefore, solution A with pH = 6 is acidic and has more hydrogen ion concentration than solution B with pH = 8 which is basic.
Q.2 What effect does the concentration of H + (aq) ions have on the nature of the solution?
Answer:
Concentration of (aq) can have a varied effect on the nature of the solution.When we increase the concentration of ions in the solution, the solution becomes more acidic, while when we decrease the concentration of ions in the solution, the basicity of the solution increases.
Q.3 Do basic solutions also have H + (aq) ions? If yes, then why are these basic?
Answer:
Yes, the basic solution also has H+(aq) ions. However, they are basic because the concentration of hydrogen ions in them is less as compared to the concentration of hydroxide ions that makes the solution basic.
Answer:
Quicklime, slaked lime and chalk are basic in nature. When they react with acids, the neutralization reaction takes place.
Therefore, If the soil is acidic and improper for cultivation, then to increase the basicity of soil, the farmer would treat the soil with quicklime or slaked lime or chalk
NCERT solutions for class 10 science chapter 2 Acids, Bases, and Salts
Q.1 What is the common name of the compound ?
Answer:
The common name of the compound is bleaching powder.
Q.2 Name the substance which on treatment with chlorine yields bleaching powder .
Answer:
Calcium hydroxide on treatment with chlorine yields bleaching powder.
Q.3 Name the sodium compound which is used for softening hard water.
Answer:
Washing soda is used for softening hard water.
Answer:
When a solution of sodium hydrogen carbonate (sodium hydrogen carbonate) is heated, it undergoes decomposition reaction to form sodium carbonate and water, and carbon dioxide gas is liberated.
The equation of the reaction involved is:
Q.5 Write an equation to show the reaction between the Plaster of Paris and water .
Answer :
The chemical equation for the reaction of Plaster of Paris and water can be represented as
All questions from the chapter-end exercise have been covered in these Class 10 Science Chapter 2 Exercise Solutions:
Q.1 A solution turns red litmus blue, its pH is likely to be
(a) 1 (b) 4 (c) 5 (d) 10
Answer:
(d) As we have lean bases turn red litmus blue. The basic solution has a pH value of more than 7. Since the solution turns red litmus blue, therefore its pH is likely to be > 7 i.e. 10.
(a) NaCl (b) HCl (c) LiCl (d) KCl
Answer:
(b) The solution contains HCI reacts with crushed egg-shells to give a gas that turns lime-water milky.
(a) 4 mL (b) 8 mL (c) 12 mL (d) 16 mL
Answer:
It is given that
10ml of NaOH neutralizes 8ml Solution of HCl
1 ml of NaOH neutralizes = Solution of HCl
Therefore, 20 ml of NaOH will neutralise= solution of HCL
Therefore, 16 ml of HCl solution will be required to neutralize the 20 ml of NaOH.
The correct answer is (d)
Q.4 Which one of the following types of medicines are used for treating indigestion?
(a) Antibiotic
(b) Analgesic
(c) Antacid
(d) Antiseptic
Answer:
(c) The antacid is used for treating indigestion.
Q.5 Write word equations and then balanced equations for the reaction taking place when –
(a) dilute sulphuric acid reacts with zinc granules.
(b) dilute hydrochloric acid reacts with magnesium ribbon.
(c) dilute sulphuric acid reacts with aluminum powder.
(d) dilute hydrochloric acid reacts with iron filings.
Answer:
Balanced equations are:-
(a)
(b)
(c)
(d)
Class 10th Science Chapter 2 Question Answer
Answer:
Take the solution of dilute hydrochloric solution and glucose. Two nails are fitted on a cork and are kept it in a 100 mL beaker. The nails are then connected to the two terminals of a 6-volt battery through a bulb and a switch. Dilute HCl is poured in the beaker and current is switched on. Now, the same experiment is performed with a glucose solution and an alcohol solution.
We will observe that the bulb glows in the HCl solution and does not glow in the glucose solution.
Because: HCl dissociate into H + (aq) and Cl -(aq) ions. These ions conduct electricity in the solution resulting in the glowing of the bulb. On the other hand, the glucose solution does not dissociate into ions. Therefore, it does not conduct electricity.
Conclusion:
From this activity, it can be concluded that all acids contain hydrogen but not all compounds containing hydrogen are acids. That is why, though compounds like alcohols and glucose contain hydrogen, they are not categorized as acids.
Q.7 Why does distilled water not conduct electricity, whereas rainwater does?
Answer: Distilled water is a pure form of water that does not contain ions. Therefore, it does not conduct electricity. Rainwater on the other hand, being an impure form of water, contains many ionic compounds such as acids and therefore it conducts electricity.
Q.8 Why do acids not show acidic behaviour in the absence of water?
Answer: Acids do not show acidic behaviour in the absence of water because acids form hydrogen ions [H + (aq) ions] in its aqueous solution which are responsible for their acidic characters and the dissociation of hydrogen ions from an acid occurs in the presence of water only.
Therefore in the absence of water, acids do not produce hydrogen ions and hence do not show acidic behaviour.
Answer: Solution with pH equal to 7 is a neutral solution. Therefore, a neutral solution is D
Answer: The solution with the highest pH is strongly alkaline. Therefore, a strongly alkaline solution is C with a pH equal to 11
Answer: The solution with the lowest pH value is strongly acidic. Therefore, a strongly acidic solution is B with pH equal to 1
Answer: Solution with pH less than 7 but close to 7 is weakly acidic. Therefore, the weakly acidic solution is A with a pH equal to 4
e) Weakly alkaline?
Answer: The solution with a pH greater than 7 but close to 7 is weakly alkaline. Therefore, a weakly alkaline solution is E with pH equal to 9
NCERT Solutions for Class 10 Science Chapter 2 Exercise Questions
Answer: When an acid reacts with magnesium metal, hydrogen gas is produced which causes fizzing. Stronger acids having a greater number of hydrogen ions in it. Hence, fizzing will occur strongly in test tube A, in which hydrochloric acid (HCI) is added.
This is because HCI is a stronger acid as compared to and therefore, during the chemical reaction with magnesium metal, HCl will produce more hydrogen gas due to which fizzing will be more vigorous in test-tube A.
Answer: The pH of fresh milk is 6.
As milk turns into curd, lactic acid is formed due to which it becomes more acidic. Therefore, the pH of milk will decrease.
Q.12(a) A milkman adds a very small amount of baking soda to fresh milk.
(a) Why does he shift the pH of the fresh milk from 6 to slightly alkaline?
Answer: Fresh milk is slightly acidic in nature, The milkman shifts the pH of the fresh milk from 6 to slightly alkaline by adding little baking soda.
Because this will prevent the milk from getting sour due to lactic acid formation.
Q.12(b) A milkman adds a very small amount of baking soda to fresh milk.
(b) Why does this milk take a long time to set as curd?
Answer: Since this milk is slightly basic than usual milk, the lactic acid, formed during curdling, needs to first neutralize the alkali present in the milk.
Therefore, it takes a longer time for the curd to set.
Q. 13 The plaster of Paris should be stored in a moisture-proof container. Explain why?
Answer: Plaster of Paris should be stored in a moisture-proof container because it absorbs moisture (or water) to form a hard substance called gypsum which makes Plaster of Paris useless.
Q.14 What is a neutralization reaction? Give two examples.
Answer: A reaction in which an acid and base react with each other to give a salt and water is known as neutralization reaction. That is: Acid + Base → Salt + Water
For example:
(i) Sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl) to form sodium chloride (NaCl) and water:
(ii) Magnesium hydroxide reacts with hydrochloric acid to form magnesium chloride and water:
Q.15 Give two important uses of washing soda and baking soda.
Answer: Uses of Washing Soda:
(i) It is used for removing the permanent hardness of the water.
(ii) It is used in glass, soap, and paper industries.
Uses of Baking Soda:
(i) It is used in soda-acid fire extinguishers.
(ii) It is used in making baking powder. Baking powder is a mixture of baking soda and a mild edible acid called tartaric acid. When baking powder is heated
or mixed in water, it releases CO2 that makes cakes or bread fluffy.
Important formula from NCERT Solution for class 10 chapter 2 science are given below:
Important Reactions:
Acid + Metal → Salt + Hydrogen gas
Example: 2NaOH(aq) + Zn(s) → Na2ZnO2 (s) + H2 (g) (Sodium zincate)
Metal carbonate/Metal hydrogencarbonate + Acid → Salt + Carbon dioxide + Water
Example: NaHCO3(s) + HCl(aq) —-> NaCl(aq) + H2O(l) + CO2(g)
Base + Acid → Salt + Water
Example: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
Metal oxide + Acid → Salt + Water
When electricity is passed through an aqueous solution of sodium chloride (called brine), it decomposes to form sodium hydroxide. The process is called the chlor-alkali process because of the products formed– chlor for chlorine and alkali for sodium hydroxide.
2NaCl(aq) + 2H2O(l) → 2NaOH(aq) + Cl2 (g) + H2 (g)
Bleaching Powder (CaOCl2) Formation:
Ca(OH)2 + Cl2 → CaOCl2 + H2O
Baking Soda (NaHCO3) Formation:
NaCl + H2O + CO2 + NH3 —---> NH4Cl (Ammonium chloride) + NaHCO3 (Sodium hydrogencarbonate)
Washing Soda (Na2CO3 .10H2O) Formation:
Na2CO3 (sodium carbonate) + 10 H2O —------> Na2CO3 .10H2O
Plaster of Paris:
For more, Download Ebook - NCERT Class 10 Science: Chapterwise Important Formulas, Diagrams, And Points
Before delving into Acid Base and Salt lass 10 question answer in more detail, let us take a quick look at the topics and subtopics covered in NCERT Solutions for Class 10 Science Chapter 2 Activities.
UNDERSTANDING THE CHEMICAL PROPERTIES OF ACIDS AND BASES
WHAT DO ALL ACIDS AND ALL BASES HAVE IN COMMON?
HOW STRONG ARE ACID OR BASE SOLUTIONS?
MORE ABOUT SALTS
Free download NCERT Solutions for Class 10 Science Chapter 2 Acids And Bases PDF for CBSE students who are using NCERT Books based on updated CBSE Syllabus.
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | Acids, Bases, and Salts |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 | |
Chapter 16 |
The learning outcocmes for science class 10 chapter 2 are listed below:
Also, check
2nd chapter name is ‘Acids, Bases, and Salts’. Questions of the NCERT book helps to study the chapter well for the exam.
Sodium Hydroxide, Bleaching Powder, Baking Soda, Washing Soda and Plaster of Paris are the important topics of NCERT Class 10 Science Chapter 2 solutions.
This chapter holds the weightage of 3 or 5 marks in CBSE Board exams. More questions on the chapter Acids Bases and Salts can be practiced from previous year papers of CBSE board Science exam and the NCERT exemplar.
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
Yes, you can definitely apply for diploma courses after passing 10th CBSE. In fact, there are many diploma programs designed specifically for students who have completed their 10th grade.
Generally, passing 10th CBSE with a minimum percentage (often 50%) is the basic eligibility for diploma courses. Some institutes might have specific subject requirements depending on the diploma specialization.
There is a wide range of diploma courses available in various fields like engineering (e.g., mechanical, civil, computer science), computer applications, animation, fashion design, hospitality management, and many more.
You can pursue diplomas at various institutions like:
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