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NCERT Exemplar Class 10 Science Solutions Chapter 3 Metals And Non Metals

NCERT Exemplar Class 10 Science Solutions Chapter 3 Metals And Non Metals

Edited By Sumit Saini | Updated on Sep 09, 2022 01:37 PM IST | #CBSE Class 10th

Chemical materials are categorized into metals and non-metals based on the difference in chemical and physical properties. The NCERT exemplar Class 10 Science solutions chapter 3 discusses the categorization mentioned above. The solutions provided for the NCERT exemplar Class 10 Science chapter 3 solutions for the practice of NCERT Class 10 Science chapter 3 problems are prepared by experts with more than 7+ years of experience in the teaching field. To build a strong foundation of the concepts of Metals and Non-metals these NCERT exemplar Class 10 Science chapter 3 solutions are appropriate.

This Story also Contains
  1. NCERT Exemplar Class 10 Science Solutions Chapter 3-MCQ
  2. NCERT Exemplar Class 10 Science Solutions Chapter 3-Short Answer
  3. Question:37
  4. NCERT Exemplar Class 10 Science Solutions Chapter 3-Long Answer
  5. NCERT Exemplar Solutions Class 10 Science Chapter 3 Important Topics:
  6. NCERT Class 10 Science Exemplar Solutions for Other Chapters:
  7. Features of NCERT Exemplar Class 10 Science Solutions Chapter 3:

The NCERT exemplar Class 10 Science solutions chapter 3 covers all the aspects within the CBSE syllabus for Class 10 chapter 3.
Also, read - NCERT Solutions for Class 10

NCERT Exemplar Class 10 Science Solutions Chapter 3-MCQ

Question:1

Which of the following property is generally not shown by metals?
(a) Electrical conduction
(b) Sonorous in nature
(c) Dullness
(d) Ductility

Ans. (c)
Properties of metals:
1. High melting point
2. Good conductors of electricity
3. Good conductors of heat
4. High density
5. Malleable
6. Ductile
7. Sonorous nature
8. Shiny (lustrous) in nature only when it is fresh. Metals lose their shine on keeping in air for a long time due to the formation of a thin layer of oxide, carbonate or sulphide on their surface.
Therefore option (C) is correct

Question:2

The ability of metals to be drawn into thin wire is known as
(a) ductility
(b) malleability
(c) sonorousity
(d) conductivity
Ans. (a)
(a)Ductility: Ability of metals to be drawn into thin wires.
(b)Malleability: Property which allows the metals to be hammered into thin sheets.
(c)Sonorousity: Property of metals due to which they make sound when hit with an object.
(d)Conductivity: Property of metals that allows heat to pass through them easily.
Therefore option (A) is correct

Question:3

Aluminium is used for making cooking utensils. Which of the following properties of aluminium are responsible for the same?
(i) Good thermal conductivity
(ii) Good electrical conductivity
(iii) Ductility
(iv) High melting point
(a) (i) and (ii)
(b) (i) and (iii)
(c) (ii) and (iii)
(d) (i) and (iv)
Ans. (d)
Aluminium is used for making cooking utensils. This is so because aluminium has good thermal conductivity, it is malleable (can be hammered into thin sheets), it has a light weight and high melting point.
Hence (i) and (iv) are correct
Therefore option (D) is correct

Question:4

Which one of the following metals do not react with cold as well as hot water?
(a) Na
(b) Ca
(c) Mg
(d) Fe
Ans. (d)
Reactivity of metals with water is based on reactivity series.
Metals like (Na, K and Ca) react with cold water.
Magnesium (Mg) reacts with hot water but Zinc (Zn) and Iron (Fe) react with steam.
Metals like lead, copper, silver and gold do not react with water (or even steam).
Red hot iron reacts with steam to form iron oxide and hydrogen.

Question:5

Which of the following oxide(s) of iron would be obtained on prolonged reaction of iron with steam?
(a) FeO
(b) Fe2O3
(c) Fe3O4
(d) Fe2O3 and Fe3O4
Ans. (c)
Iron does not react directly with cold or hot water. It forms a metal oxide when steam is passed over it. When red hot iron reacts with steam it forms iron(II,III) oxide and hydrogen gas is liberated. The reaction is reversible and is shown as follows:
3Fe\left ( s \right )+4H_{2}O\rightarrow Fe_{3}O_{4}\left ( s \right )+4H_{2}\left ( g \right )

Question:6

What happens when calcium is treated with water?
(i) It does not react with water
(ii) It reacts violently with water
(iii) It reacts less violently with water
(iv) Bubbles of hydrogen gas formed stick to the surface of calcium
(a) (i) and (iv)
(b) (ii) and (iii)
(c) (i) and (ii)
(d) (iii) and (iv)
Ans. (d)
Calcium reacts less violently with water and the bubbles of hydrogen gas produced stick to the surface of calcium. Due to which it floats over water surface.
Ca\left ( s \right )+2H_{2}O\left ( l \right )\rightarrow Ca\left ( OH \right )_{2}\left ( aq \right )+H_{2}\left ( g \right )
Much less heat is produced in this reaction due to which hydrogen gas formed does not catch fire.

Question:7

Generally metals react with acids to give salt and hydrogen gas. Which of the following acids does not give hydrogen gas on reacting with metals (except Mn and Mg)?
(a) H2SO4
(b) HCl
(c) HNO3
(d) All of these
Ans. (c)
Nitric acid (HNO3) does not give hydrogen gas on reacting with metals (except Manganese and Magnesium)
3Mn + 8HNO3 (dil.) \rightarrow 3Mn(NO3)2 + 2NO + 4H2O
Manganese react with nitric acid to produce manganese(II) nitrate, nitric oxide and water.
4Mg + 10HNO3 (dil.) \rightarrow 4Mg(NO3)2 + N2O + 5H2O
Manganese react with nitric acid to produce manganese(II) nitrate, nitric oxide and water.
4Mg + 10HNO3 (dil.) → 4Mg(NO3)2 + N2O + 5H2O
Magnesium react with nitric acid to produce nitrate magnesium, dinitrogen monoxide and water.
Nitric acid is a strong oxidizing agent so, as soon as hydrogen gas is formed in the reaction between metal and HNO3, it oxidizes this hydrogen to water.
Therefore option (C) is correct

Question:8

The composition of aqua-regia is
(a) Dil. HCl : Conc. HNO3 3 : 1
(b) Conc. HCl : Dil. HNO3 3 : 1
(c) Conc. HCl : Conc.HNO3 3 : 1
(d) Dil.HCl : Dil.HNO3 3 : 1
Ans. (c)
Aqua regia is a mixture of nitric acid and hydrochloric acid, in a molar ratio of 1:3.
So, Conc. HCI and conc. HNO3 in ratio 3 : 1 forms aqua-regia.
Aqua-regia is a highly corrosive, yellow-orange fuming liquid. It can dissolve all metals (even gold and platinum).

Question:9

Which of the following are not ionic compounds?
(i) KCl
(ii) HCl
(iii) CCl4
(iv) NaCl
(a) (i) and (ii)
(b) (ii) and (iii)
(c) (iii) and (iv)
(d) (i) and (iii)
Ans. (b)
Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.
(i) KCl: formed by the transfer of electrons and hence ionic.
(ii) HCl: polar covalent compound (formed by sharing of electrons)
(iii) CCl4: is a non-polar covalent compound (formed by sharing of electrons)
(iv) NaCl: formed by the transfer of electrons and hence ionic.
Hence (ii) and (iii) are not ionic.
Therefore option (B) is correct

Question:10

Which one of the following properties is not generally exhibited by ionic compounds?
(a) Solubility in water
(b) Electrical conductivity in solid state
(c) High melting and boiling points
(d) Electrical conductivity in molten state

Ans. (b)
Properties of ionic compounds:


  2. Can conduct electricity in molten or aqueous state only.


  4. High melting and boiling points


  6. Most ionic compounds are soluble in water and form aqueous solutions.


  8. In solid state, these are non-conductor of electricity because of the absence of free ions.


  10. The ions are held together in fixed position by strong electrostatic force and cannot move freely.

Hence, electrical conductivity in solid state is not generally exhibited by ionic compounds.
Therefore option (B) is correct

Question:11

Which of the following metals exist in their native state in nature?
(i) Cu
(ii) Au
(iii) Zn
(iv) Ag
(a) (i) and (ii)
(b) (ii) and (iii)
(c) (ii) and (iv)
(d) (iii) and (iv)
Ans. (c)
Gold and silver (Au and Ag) are noble metals and are very less reactive, so they are usually found in free state (native state) in nature.

Question:12

Metals are refined by using different methods. Which of the following metals are refined by electrolytic refining?
(i) Au
(ii) Cu
(iii) Na
(iv) K
(a) (i) and (ii)
(b) (i) and (iii)
(c) (ii) and (iii)
(d) (iii) and (iv)
Ans. (a)
The method to be used for refining an impure metal depends on the nature of the metal as well as on the nature of impurities present in it.
Electrolytic refining is a process of refining a metal by the process of electrolysis.
Electrolytic refining is used for metals like Ag, Au, Cu, Zn, etc
Electrolytic refining of Cu: A large piece of impure copper is used as the anode with a thin strip of pure copper as the cathode. Copper(II) sulphate solution is the electrolyte.
Electrolytic refining of Au: A thin sheet of gold is made the cathode and a gold alloy is made the anode. Hydrochloric acid is used as an electrolyte.
Therefore option (A) is correct

Question:13

Silver articles become black on prolonged exposure to air. This is due to the formation of
(a) Ag3N
(b) Ag2O
(c) Ag2S
(d) Ag2S and Ag3N
Ans. (c)
Silver article become black because silver reacts with H2S gas present in air to form black coating of Ag2S.
2 Ag + O2 → Ag2O
4 Ag + 2 H2S + 2O2 → 2Ag2S + 2 H2O
Ag2O is brown in colour and of Ag2S is black.
Therefore option (C) is correct

Question:14

Galvanisation is a method of protecting iron from rusting by coating with a thin layer of:
(a) Gallium
(b) Aluminium
(c) Zinc
(d) Silver

Ans. (c)
Galvanization is a method of protecting iron from rusting by coating it with a thin layer of zinc (Zn) metal.
Therefore option (C) is correct

Question:15

Stainless steel is very useful material for our life. In stainless steel, iron is mixed with
(a) Ni and Cr
(b) Cu and Cr
(c) Ni and Cu
(d) Cu and Au
Ans. (a)
Stainless steel: Iron (Fe) is mixed with Nickel (Ni), Chromium (Cr) and Carbon (C).
It contains approximately 17% chromium, and 10% nickel and a very less amount of carbon.
Therefore option (A) is correct

Question:16

If copper is kept open in air, it slowly loses its shining brown surface and gains a green coating. It is due to the formation of
(a) CuSO4
(b) CuCO3
(c) Cu(NO3)2
(d) CuO

Ans. (b)
Copper reacts with oxygen present in air and forms a green coating on its surface due to the formation of basic copper carbonate [CuCO3 and Cu(OH)2]
The reaction is given as:
2Cu + O2 (From air) + CO2 + H2O \rightarrowCuCO3 + Cu(OH)2
Basic copper carbonate(green coating)
Therefore option (B) is correct

Question:17

Generally, metals are solid in nature. Which one of the following metals is found in liquid state at room temperature?
(a) Na
(b) Fe
(c) Cr
(d) Hg
Ans. (d)
Mercury (Hg) is the only metal which is found in liquid state at room temperature
Therefore option (D) is correct

Question:18

Which of the following metals are obtained by electrolysis of their chlorides in molten state?
(i) Na
(ii) Ca
(iii) Fe
(iv) Cu
(a) (i) and (iv)
(b) (iii) and (iv)
(c) (i) and (iii)
(d) (i) and (ii)
Ans. (d)
Sodium (Na) and calcium (Ca) being highly reactive are obtained by electrolysis of their chlorides in molten state.
During electrolysis of NaCl
NaCl\rightarrow Na^{+}\left ( l \right )+Cl^{-}\left ( l \right )
At cathode: reduction of 2Na^{+}\left ( aq \right )+e^{-}\rightarrow Na\left ( s \right )
At anode: oxidation of 2Cl^{-}\left ( aq \right )\rightarrow Cl_{2}\left ( g \right )+2e^{-}
Net Reaction: 2Na^{+}\left ( aq\right )+2Cl^{-}\left ( aq \right )\rightarrow 2Na\left ( s \right )+Cl_{2}\left ( g \right )
During electrolysis of aqueous CaCl2
We have,
At anode: 2Cl^{-}\rightarrow Cl_{2}+2e^{-}
At anode: Ca^{2+}+2e^{-}\rightarrow Ca(s)
Therefore option (D) is correct

Question:19

Generally, non-metals are not lustrous. Which of the following non metal is lustrous?
(a) Sulphur
(b) Oxygen
(c) Nitrogen
(d) Iodine

Ans. (d)
Shining metals are called lustrous.
Sulphur, oxygen, nitrogen are non-lustrous.
Iodine is a non-metal having lustrous appearance.
It has a shining surface (like that of metals).
Therefore option (D) is correct

Question:20

Which one of the following four metals would be displaced from the solution of its salts by other three metals?
(a) Mg
(b) Ag
(c) Zn
(d) Cu
Ans. (b)
We know that Ag is less reactive than Mg, Zn and Cu.
Hence Silver (Ag) metal would be displaced from the solution of its salts by other three metals.
Mg + 2 AgCl \rightarrow MgCl2 + 2 Ag
Zn + AgCl \rightarrow ZnCl2 + Ag
Cu + 2 AgCl \rightarrow CuCl2 + 2 Ag
Therefore option (B) is correct

Question:21

2 mL each of concentrated HCl, HNO3 and a mixture of concentrated HCl and concentrated HNO3 in the ratio of 3 : 1 were taken in test tubes labelled as A, B and C. A small piece of metal was put in each test tube. No change occurred in test tubes A and B but the metal got dissolved in test tube C respectively. The metal could be
(a) Al
(b) Au
(c) Cu
(d) Pt

Ans. (b)
A mixture of conc. HCl and conc. HNO3 in the ratio of 3 : 1 is known as aqua-regia. Gold (Au) dissolve in aqua-regia.
Hence both (b) is correct.

Question:22

An alloy is
(a) an element
(b) a compound
(c) a homogeneous mixture
(d) a heterogeneous mixture
Ans. (c)
An alloy is a homogeneous mixture of different metals or a metal with one or more other element.
It is done in order to give greater strength or resistance to corrosion.
Examples: Brass, Steel, amalgam etc.
Therefore option (c) is correct

Question:23

An electrolytic cell consists of
(i) positively charged cathode
(ii) negatively charged anode
(iii) positively charged anode
(iv) negatively charged cathode
(a) (i) and (ii)
(b) (iii) and (iv)
(c) (i) and (iii)
(d) (ii) ad (iv)
Ans. (b)
An electrolytic cell consists of positively charged anode and negatively charged cathode.
Anode - positively charged - attracts negative ions or anions towards it
Cathode - negatively charged - attracts positive ions or cations towards it
Hence statements (iii) and (iv) are correct
Therefore option (b) is correct

Question:24

During electrolytic refining of zinc, it gets
(a) deposited on cathode
(b) deposited on anode
(c) deposited on cathode as well as anode
(d) remains in the solution
Ans. (a)
Electrolytic refining is a process of refining a metal by the process of electrolysis.
The impure metal is made the anode and a thin strip of pure metal is made the cathode.
The pure zinc metal deposited on cathode is connected to the negative terminal of the battery.
Zn2+ ions from the solution move towards the negatively charged cathode.
Hence, Zn is deposited on the cathode.
Therefore option (a) is correct

Question:25

An element A is soft and can be cut with a knife. This is very reactive to air and cannot be kept open in air. It reacts vigorously with water. Identify the element from the following
(a) Mg
(b) Na
(c) P
(d) Ca
Ans. (b)
Given that A is soft and can be cut with a knife. This is very reactive to air and cannot be kept open in air. It reacts vigorously with water.
From the properties of the element described in the question, it can be said surely that the element is sodium (Na).
Therefore option (b) is correct

Question:26

Alloys are homogeneous mixtures of a metal with a metal or non metal. Which among the following alloys contain non-metal as one of its constituents?
(a) Brass
(b) Bronze
(c) Amalgam
(d) Steel
Ans. (d)
Alloys are homogeneous mixtures of a metal with a metal or non metal.
Steel is an alloy which contains iron (a metal) and carbon (a non-metal).
Brass is an alloy which contains copper (a metal) and zinc (a metal).
Bronze is an alloy which contains copper (a metal) and tin (a metal).
Amalgam is formed by mixing mercury (a metal) with other metal.
Therefore option (d) is correct

Question:27

Which among the following statements is incorrect for magnesium metal?
(a) It burns in oxygen with a dazzling white flame
(b) It reacts with cold water to form magnesium oxide and evolves hydrogen gas
(c) It reacts with hot water to form magnesium hydroxide and evolves hydrogen gas
(d) It reacts with steam to form magnesium hydroxide and evolves hydrogen gas
Ans. (b)
(a) When the magnesium metal burns it reacts with oxygen found in the air to form Magnesium Oxide (dazzling white flame).
2Mg\left ( s \right )+O_{2}\left ( g \right )\rightarrow 2MgO\left ( s \right )+energy
(b) Magnesium metal does not react with cold water.
(c, d) Mg reacts with hot water and steam both. The reaction is shown below:
Mg\left ( s \right )+HO_{2}\left ( hot\, or\, steam \right )\rightarrow Mg\left ( OH \right )_{2}+H_{2}\left ( g \right )
It gives magnesium hydroxide and hydrogen gas
Therefore option (b) is correct answer

Question:28

Which among the following alloys contain mercury as one of its constituents?
(a) Stainless steel
(b) Alnico
(c) Solder
(d) Zinc amalgam
Ans. (d)
(a) Stainless steel: iron and carbon
(b) Alnico: Aluminium, Nickel, Cobalt and Iron plus varying levels of Copper, Titanium and Niobium.
(c) Solder: One is a soft solder, which is an alloy of tin and lead. The other is a hard solder, which is an alloy of copper and zinc.
(d) Zinc amalgam: When mercury reacts with a zinc metal, it forms the zinc amalgam
Therefore option (d) is correct

Question:29

Reaction between X and Y, forms compound Z. X loses electron and Y gains electron. Which of the following properties is not shown by Z?
(a) Has high melting point
(b) Has low melting point
(c) Conducts electricity in molten state
(d) Occurs as solid
Ans (b)
During reaction between X and Y, the compound Z is formed.
X loses electron and Y gains electron. Hence Z is an ionic compound.
Ionic compounds:
1.Have high melting point
2.Conducts electricity in molten state
3.Usually occur as solids.
Therefore option (b) is correct

Question:30

The electronic configurations of three elements X, Y and Z are X — 2, 8; Y — 2, 8, 7 and Z — 2, 8, 2. Which of the following is correct?
(a) X is a metal
(b) Y is a metal
(c) Z is a non-metal
(d) Y is a non-metal and Z is a metal
Ans. (d)
X — 2, 8: Has a complete octet, hence it is a noble gas.
Y — 2, 8, 7: It requires one electron to complete its octet.
Hence Y is a non-metal
Z — 2, 8, 2: It has a tendency to lose two electrons to complete its octet.
Hence Z is a metal
Therefore option (d) is correct

Question:31

Although metals form basic oxides, which of the following metals form an amphoteric oxide?
(a) Na
(b) Ca
(c) Al
(d) Cu
Ans. (c)
(a) Na - Sodium oxide (Na2O) is a strongly basic oxide.
It contains oxide ion, O2-, which is a very strong base and has a high tendency to combine with hydrogen ions.
(b) Ca - Calcium oxide (CaO) is basic in nature. It dissolves in water to form calcium hydroxide
(c) Al - Aluminium oxide (Al2O3) shows basic as well as acidic behavior hence it is called an amphoteric oxide.
(d) Cu - Copper(II) oxide or cupric oxide (CuO)
Copper(I) oxide or cuprous oxide (Cu2O)
Both are basic in nature
Therefore option (c) is correct

Question:32

Generally, non-metals are not conductors of electricity. Which of the following is a good conductor of electricity?
(a) Diamond
(b) Graphite
(c) Sulphur
(d) Fullerene
Ans. (b)
Graphite is a non-metal which conducts electricity.
Diamond and graphite are allotropes of Carbon (a non-metal).
A graphite crystal comprises of layers of carbon molecules or sheets of carbon particles. Each carbon atom in a graphite layer is joined to three other carbon atoms by strong covalent bonds to form flat hexagonal rings. The fourth valence electron of every carbon atom is free to move. Due to the presence of free electrons in a graphite crystal, it conducts electricity.
Therefore option (b) is correct

Question:33

Electrical wires have a coating of an insulting material. The material, generally used is
(a) Sulphur
(b) Graphite
(c) PVC
(d) All can be used
Ans. (c)
(a) Sulphur is insulating in nature. But it has a very low ignition temperature. Sulphur is also highly less ductile because it is a non-metal, which makes it difficult to give them the required shape. So it is not used as a coating material for an electric wire.
(b) Graphite: A graphite crystal comprises of layers of carbon molecules or sheets of carbon particles. Each carbon atom in a graphite layer is joined to three other carbon atoms by strong covalent bonds to form flat hexagonal rings. The fourth valence electron of every carbon atom is free to move. Due to the presence of free electrons in a graphite crystal, it conducts electricity.
So it is not used as a coating material for an electric wire.
(c) PVC or Polyvinyl chloride is an insulating substance. It does not allow electric current to pass through it. The electrical wires have a covering of PVC around them.
Therefore option (c) is correct

Question:34

Which of the following non-metals is a liquid?
(a) Carbon
(b) Bromine
(c) Phosphorus
(d) Sulphur
Ans. (b)
(a) Carbon: At room temperature it is in a solid state.
(b) Bromine: is a liquid at room temperature, solidifying at -7.2ºC.
(c) Phosphorus: is a colourless, semitransparent, soft, waxy solid at room temperature.
(d) Sulphur: At room temperature it is a solid
Therefore option (b) is correct

Question:35

Which of the following can undergo a chemical reaction?
(a) MgSO4 + Fe
(b) ZnSO4 + Fe
(c) MgSO4 + Pb
(d) CuSO4 + Fe
Ans. (d)
(a) and (b),
Fe is less reactive than Mg and Zn, so it is impossible to replace them.
No reaction takes place.
(c)
Pb is less reactive than Mg, so it is impossible to replace Mg.
No reaction takes place.
(d)
Fe is more reactive than Cu, so it replaces Cu from CuSO4
Hence reaction takes place.
Therefore option (d) is correct

Question:36

Which one of the following figures correctly describes the process of electrolytic refining?

Ans. (c)
Electrolytic refining is a process of refining a metal by the process of electrolysis.
Impure metal is made anode and is connected to the positive terminal of battery. Pure metal is made cathode and is connected to the negative terminal of the battery.
Electrolytic refining of Cu: A large piece of impure copper is used as the anode with a thin strip of pure copper as the cathode. Copper(II) sulphate solution is the electrolyte.
Cu2+ ions from the solution are deposited on the cathode while Cu from impure anode dissolves into the solution and the impurities settle down below anode as anode mud.
Therefore option (c) is correct

NCERT Exemplar Class 10 Science Solutions Chapter 3-Short Answer

Question:37

Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. Suggest how can he identify the produced gas. Write chemical equations for both the reactions.
Ans.
M is lustrous, so the element has to be a metal.
As it reacts with NaOH, it should be a very reactive metal.
Metal + Base \rightarrow Hydrogen gas
Also the metal reacts with HCl
Metal + acid \rightarrow salt + hydrogen
The divalent element M is Zn
Zn\left ( s \right )+2NaOH\left ( aq \right )\rightarrow Na_{2}ZnO_{2}\left ( aq \right )+H_{2}
Zn\left ( s \right )+2HCl\left ( aq \right )\rightarrow ZnCl_{2}\left ( aq \right )+H_{2}
The produced gas can be identified by bringing a burning match stick near the gas. The gas burns with a pop sound, hence it is hydrogen.

Question:38

During extraction of metals, electrolytic refining is used to obtain pure metals.
(a) Which material will be used as anode and cathode for refining of silver metal by this process?
(b) Suggest a suitable electrolyte also.
(c) In this electrolytic cell, where do we get pure silver after passing electric current?
Ans. (a)
Electrolytic refining is a process of refining a metal by the process of electrolysis.
Impure metal is made anode and is connected to the positive terminal of battery. Pure metal is made cathode and is connected to the negative terminal of the battery.
(a) Cathode: Thin strip of pure silver (It is connected to the negative terminal of the battery).
Anode: Impure, silver block (It is connected to the positive terminal of the battery).
(b) Electrolyte: any salt solution of silver like AgNO3 or AgCl,
but sodium argentocyanide (Na[Ag(CN)2]) is preferred.
(c) Pure metal from the electrolyte deposits on the cathode.

Question:39

Why should the metal sulphides and carbonates be converted to metal oxides in the process of extraction of metal from them?
Ans.
It is easier to obtain metals from their oxides (by reduction) than from carbonate or sulphide ores. So, before reduction the ore must be converted into metal oxide.
Calcination: method by which a carbonate ore is converted into oxide
Roasting: method by which a sulphide ore is converted into oxide
Calcination or roasting is done depending on the nature of ore
Example for calcination:
CaCO_{3}\rightarrow CaO+CO_{2}
Example for roasting:
2ZnS+3O_{2}\rightarrow 2ZnO+SO_{2}

Question:40

Generally, when metals are treated with mineral acids, hydrogen gas is liberated but when metals (except Mn and Mg), treated with HNO3, hydrogen is not liberated, why?
Ans.
Nitric acid (HNO3) is a strong oxidising agent. As soon as hydrogen gas is formed in the reaction between a metal and dilute nitric acid, the nitric acid oxidises this hydrogen to water and itself gets reduced to NO2 or NO or N2O.
Mg+2HNO_{3}\rightarrow Mg\left ( NO_{3} \right )_{2}+H_{2}
4Zn+10HNO_{3}\rightarrow 4Zn\left ( NO_{3} \right )_{2}+N_{2}O+5H_{2}O
4Sn+10HNO_{3}\rightarrow 4Sn\left ( NO_{3} \right )_{2}+NH_{4}NO_{3}+3H_{2}O
3Pb+8HNO_{3}\rightarrow 3Pb\left ( NO_{3} \right )_{2}+2NO+4H_{2}O
So, in the reaction of metals (except Mn and Mg), with dilute nitric acid, no hydrogen gas is evolved.

Question:41

Compound X and aluminium are used to join railway tracks.
(a) Identify the compound X
(b) Name the reaction
(c) Write down its reaction.
Ans.
(a) Compound X is iron oxide, Fe2O3
(b) Thermite reaction
(c) The reaction that takes place is as follows
Fe_{2}O_{3}\left ( s \right )+2Al\left ( s \right )\rightarrow 2Fe\left ( l \right )+Al_{2}O_{3}\left ( s \right )+Heat

Question:42

When a metal X is treated with cold water, it gives a basic salt Y with molecular formula XOH (Molecular mass = 40) and liberates a gas Z which easily catches fire. Identify X, Y and Z and also write the reaction involved
Ans.
Sodium (Na) and potassium (K) react with cold water to form basic salt NaOH and KOH respectively.
Molecular formula = XOH
Molecular mass = 40
Let the atomic weight of metal X is x
Then, molecular mass of BOH = x + 16 + 1= 40 (Given)
x = 40 – 17 = 23
Thus, metal X is sodium (Na)
Sodium reacts with water as
2Na+2H_{2}O\rightarrow 2NaOH+H_{2}
Sodium (Na) liberates hydrogen gas (Z) on reaction with cold water.
So, Y is NaOH (sodium hydroxide)
Z Is H2 (hydrogen gas).

Question:43

A non-metal X exists in two different forms Y and Z. Y is the hardest natural substance, whereas Z is a good conductor of electricity. Identify X, Y and Z
Ans.
X exists in two different forms Y and Z
Y is the hardest natural substance, whereas Z is a good conductor of electricity
We know that diamond is the hardest natural substance, hence Y is diamond.
Now carbon (C) exists in two different forms called the allotropes of carbon. These allotropes are diamond and graphite. So X is carbon.
Z is graphite which is a good conductor of electricity.
X: Carbon
Y: Diamond
Z: Graphite

Question:44

The following reaction takes place when aluminium powder is heated with MnO2
3MnO_{2}\left ( s \right )+4Al\left ( s \right )\rightarrow 3Mn\left ( l \right )+2Al_{2}O_{3}\left ( l \right )+Heat
(a) Is aluminium getting reduced?
(b) Is MnO2 getting oxidised?
Ans.
Oxidation is the loss of electrons and reduction is the gain of electrons.
In the reaction:
3MnO_{2}\left ( s \right )+4Al\left ( s \right )\rightarrow 3Mn\left ( l \right )+2Al_{2}O_{3}\left ( l \right )+Heat
(a) Aluminium is getting oxidised because there is an addition of oxygen
(b) MnO2 is getting reduced because there is removal of oxygen.

Question:45

What are the constituents of solder alloy? Which property of solder makes it suitable for welding electrical wires?
Ans.
One is a soft solder, which is an alloy of tin and lead. The other is a hard solder, which is an alloy of copper and zinc.
Most commonly used solder is the soft solder: an alloy of lead (Pb) and tin (Sn).
It contains 50% lead and 50% tin.
Solder is suitable for welding electrical wires because it has a low melting point. Hence, it is used for soldering (or welding) electrical wires together.

Question:46

A metal A, which is used in thermite process, when heated with oxygen gives an oxide B, which is amphoteric in nature. Identify A and B. Write down the reactions of oxide B with HCl and NaOH
Ans.
Thermite Reaction:
4Al+3O_{2}\rightarrow 2Al_{2}O_{3}\left ( s \right )
Metal A is aluminum (Al) which is used in thermite process.
Al reacts with oxygen to form aluminum oxide Al­2O3which is amphoteric in nature. So B is Al­2O3
(i) Al_{2}O_{3}\left ( s \right )+6HCl\left ( aq \right )\rightarrow 2AlCl_{3}\left ( aq \right )+3H_{2}O\left ( l \right )
(ii) Al_{2}O_{3}\left ( s \right )+2NaOH\left ( aq \right )\rightarrow 2NaAlO_{2}\left ( aq \right )+H_{2}O\left ( l \right )

Question:47

A metal that exists as a liquid at room temperature is obtained by heating its sulphide in the presence of air. Identify the metal and its ore and give the reaction involved.
Ans.
The only metal that exists as a liquid at room temperature is mercury (Hg).
Mercury is obtained from the sulphide ore called cinnabar (HgS).
The reaction:
Heating

HgS + O_2\rightarrow Hg+SO_2

Question:48

Give the formulae of the stable binary compounds that would be formed by the combination of following pairs of elements.
(a) Mg and N2
(b) Li and O2
(c) Al and Cl2
(d) K and O2
Ans.
(a)Mg3N2 Magnesium nitride
(b) Li2O Lithium oxide
(c) AICI3 Aluminium chloride
(d) K2O Potassium oxide

Question:49

What happens when
(a) ZnCO3 is heated in the absence of oxygen?
(b) a mixture of Cu2O and Cu2S is heated
Ans
(a) Calcination takes place
ZnCO_{3}\left ( s \right )\rightarrow ZnO\left ( s \right )+CO_{2}\left ( g \right )
When ZnCO3 is heated in the absence of oxygen, Zinc oxide and carbon dioxide are produced.
(b) Roasting takes place
2Cu_{2}O\left ( s \right )+Cu_{2}S\left ( s \right )\rightarrow 6Cu\left ( s \right )+SO_{2}\left ( g \right )
When a mixture of Cu2O and Cu2S is heated, copper metal and sulphur dioxide gas are produced

Question:50

A non-metal A is an important constituent of our food and forms two oxides B and C. Oxide B is toxic whereas C causes global warming
(a) Identify A, B and C
(b) To which Group of Periodic Table does A belong?
Ans.
(a) Non-metal A is carbon.
Two oxides are carbon monoxide and carbon dioxide.
Oxide B is toxic whereas C causes global warming
So B is carbon monoxide (CO) and C is carbon dioxide (CO2)
(b) Atomic weight of C = 6
Electronic configuration of C is 2, 4.
It is present in 14th group (10 + valence electrons), i.e., IV A of the periodic table.

Question:51

Give two examples each of the metals that are good conductors and poor conductors of heat respectively.
Ans.
Good conductors: Silver, Bronze, Iron and copper. (All metals are good conductors of electricity)
Poor conductors: Lead and mercury.

Question:52

Name one metal and one non-metal that exist in liquid state at room temperature. Also name two metals having melting point less than 310 K (37°C)
Ans.
The only metal that exists as a liquid at room temperature is mercury (Hg).
Non-metal which exists in liquid state at room temperature is bromine (Br).
Two metals having melting point less than 310 K (37°C) are caesium (Cs) with melting point 28.5°C and gallium (Ga) with melting point 30°C

Question:53

An element A reacts with water to form a compound B which is used in white washing. The compound B on heating forms an oxide C which on treatment with water gives back B. Identify A, B and C and give the reactions involved.
Answer:

Element A is calcium (Ca). When it reacts with water, it forms calcium hydroxide.
Ca+H_{2}O\rightarrow Ca\left ( OH \right )_{2}+H_{2}
Thus, compound B is calcium hydroxide [Ca(OH)2], which on heating gives CaO.
Ca\left ( OH \right )_{2}\rightarrow CaO+H_{2}O
Thus, C is calcium oxide (CaO)
Hence the answer is:
A: Calcium
B: Ca(OH)2
C: CaO

Question:54

An alkali metal A gives a compound B (molecular mass = 40) on reacting with water. The compound B gives a soluble compound C on treatment with aluminium oxide. Identify A, B and C and give the reaction involved.
Answer:

Let, the atomic weight of alkali metal A is x. When it reacts with water it forms a compound B having molecular mass 40.
Let, the reaction is
2A+2H_{2}O\rightarrow 2AOH+H_{2}
Molecular mass of B = x + 16 + 1 = 40
x = 40 - 17 = 23
Hence A is Sodium (Na)
The reaction involved is:
2Na+2H_{2}O\rightarrow 2NaOH+H_{2}
So, compound B is sodium hydroxide (NaOH)
Sodium hydroxide reacts with aluminium oxide (Al2O3) to give sodium aluminate (NaAIO2)
Thus, C is sodium aluminate NaAIO2
The reaction involved is:
Al_{2}O_{3}+2NaOH\rightarrow 2NaAlO_{2}+H_{2}O

Question:55

Give the reaction involved during extraction of zinc from its ore by
(a) roasting of zinc ore
(b) calcination of zinc ore
Answer:

Roasting: method by which a sulphide ore is converted into oxide
Calcination: method by which a carbonate ore is converted into oxide
(a) Roasting of zinc ore: Sulphide ore of zinc is ZnS (zinc blende)
2ZnS\left ( s \right )+3O_{2}\rightarrow 2ZnO\left ( s \right )+2SO_{2}
ZnO is then reduced to zinc by heating with coke (carbon)
ZnO\left ( s \right )+C\left ( s \right )\rightarrow Zn\left ( s \right )+CO\left ( g \right )
(b) Calcination of zinc ore: Carbonate ore of Zinc is calamine ZnCO3
ZnCO_{3}\left ( s \right )\rightarrow ZnO\left ( s \right )+CO_{2}\left ( g \right )
ZnO is then reduced to zinc by heating with coke (carbon)
ZnO\left ( s \right )+C\left ( s \right )\rightarrow Zn\left ( s \right )+CO\left ( g \right )

Question:56

A metal M does not liberate hydrogen from acids but reacts with oxygen to give a black colour product. Identify M and black coloured product and also explain the reaction of M with oxygen.
Answer:

Metal M is Cu as Cu is less reactive than hydrogen. So, it does not react with acids to release hydrogen.
Cu\left ( s \right )+HCl\rightarrow No reaction
Copper metal does not burn in air even on strong heating.
Copper reacts with the oxygen on prolonged heating to form a black substance, i.e., copper (Il) oxide.
2Cu\left ( s \right )+O_{2}\left ( g \right )\rightarrow CuO\left ( s \right )

Question:57

An element forms an oxide A2O3 which is acidic in nature. Identify A as a metal or non-metal.
Answer:

Oxides of non-metals are acidic in nature
Oxides of metals are basic in nature
Given that the element A forms an acidic oxide, therefore, A is a non-metal.
Also, it forms an oxide A2O3 so it should have 3 valence electrons, i.e., +3 charge,
Therefore, electronic configuration is 2, 3
Hence, A is boron and its oxide is B2O3.

Question:58

A solution of CuSO4 was kept in an iron pot. After few days the iron pot was found to have a number of holes in it. Explain the reason in terms of reactivity. Write the equation of the reaction involved.
Answer:

Iron displaces copper from copper sulphate solution as it is a more reactive metal than copper. The reaction is as follows:
Fe\left ( s \right )+CuSO_{4}\rightarrow FeSO_{4}+Cu
A portion of the iron pot gets dissolved and cause holes in this process.
Iron taking part in this reaction, produces holes at places where iron metal has reacted to form iron (Il) sulphate.

NCERT Exemplar Class 10 Science Solutions Chapter 3-Long Answer

Question:59

A non-metal A which is the largest constituent of air, when heated with H2 in 1:3 ratio in the presence of catalyst (Fe) gives a gas B. On heating with O2 it gives an oxide C. If this oxide is passed into water in the presence of air it gives an acid D which acts as a strong oxidising agent.
(a) Identify A, B, C and D
(b) To which group of periodic table does this non-metal belong
Answer:

(a) A is the largest constituent of air so A is nitrogen gas.
Now, when N2 is heated with H2 in 1:3 ratio in presence of catalyst Fe, ammonia is formed. The reaction is as follows:
N_{2}+H_{2}\rightarrow NH_{3}
Thus, B is ammonia gas.
Now it is given that On heating with O2, B gives an oxide C.
Ammonia, when heated with oxygen forms nitric oxide (NO).
4NH_{3}+5O_{2}\left ( g \right )\rightarrow 4NO\left ( g \right )+6H_{2}O\left ( g \right )
NO further gets oxidised to NO2 by oxygen present in the air. The reaction is as follows:
2NO\left ( g \right )+O_{2}\left ( g \right )\rightarrow 2NO_{2}\left ( g \right )
Thus, C is NO2 (nitrogen dioxide)
Now it is given in the question that this oxide is passed into water in the presence of air (O2). The reaction will be:
4NO_{2}+2H_{2}O+O_{2}\rightarrow 4HNO_{3}
Hence nitric acid (HNO3) is produced which is a strong oxidising agent.
Thus, D is nitric acid (HNO3)
(b) The non-metal nitrogen has atomic number 7.
Its electronic configuration is 2, 5.
It belongs to group 15 or VA because N has 5 valence electrons.

Question:60

Give the steps involved in the extraction of metals of low and medium reactivity from their respective sulphide ores.
Answer:

Extraction of metals of low and medium reactivity:
1.Roasting: a respective sulphide ore is heated in air. So, metal oxide is formed.
2.Heating of metal oxide to obtain the metal
Mercury has low reactivity.
We can see the entire process for mercury (Hg) as follows:
(i) Roasting: Metal sulphide is converted into metal oxide by heating the ore strongly in the presence of excess of air.
2HgS+3O_{2}\rightarrow 2HgO+2SO_{2} (Metal oxide is formed)
(ii) Reduction: Metal oxide is then reduced to metal by heating it.
2HgO\rightarrow 2Hg+O_{2}
Hence mercury is extracted.
Similarly, we can see for zinc (medium reactivity).
Roasting: 2ZnS+3O_{2}\rightarrow 2ZnO+2SO_{2}
Reduction:ZnO+C\rightarrow Zn+CO

Question:61

Explain the following
(a) Reactivity of Al decreases if it is dipped in HNO3
(b) Carbon cannot reduce the oxides of Na or Mg
(c) NaCl is not a conductor of electricity in solid state whereas it does conduct electricity in aqueous solution as well as in molten state
(d) Iron articles are galvanised.
(e) Metals like Na, K, Ca and Mg are never found in their free state in nature.
Answer:

(a) Nitric acid (HNO3) is a strong oxidizing agent. When aluminium (Al) is dipped in HNO3, an oxide layer of aluminium (Al2O3) is formed on the surface of the metal, which prevents it from further reaction. Thus, reactivity of Al decreases.
(b) Affinity of Na, Mg with oxygen is higher than that of carbon. This is because Na, Mg metals are quite reactive and present towards the top of the reactivity series. Therefore, their oxides (Na2O, MgO) are stable. Very high temperature is required to reduce them with carbon, and at that temperature they will form their corresponding carbides. Hence, their oxides cannot be reduced by carbon
(c) NaCl is not a conductor of electricity in solid state whereas it does conduct electricity in aqueous solution as well as in molten state. Ions of NaCl are free to move in aqueous solution to carry the charge. But in dry or solid state, ions of NaCl cannot move to carry the charge in as they are fixed. Hence, NaCl conducts electricity in molten state.
(d) Galvanization is a method of protecting iron from rusting by coating it with a thin layer of zinc (Zn) metal.
A thin layer of zinc is formed over the iron articles by dipping them in molten zinc. As zinc is more reactive than iron, this prevents iron from corrosion
(e) Metals like Na, K, Ca and Mg are never found in their free state in nature because these metals are quite reactive so they cannot exist in free state and hence, they are found in nature in the form of their compounds.

Question:62

(i) Given below are the steps for extraction of copper from its ore. Write the reaction involved.
(a) Roasting of copper (1) sulphide
(b) Reduction of copper (1) oxide with copper (1) sulphide.
(c) Electrolytic refining
(ii) Draw a neat and well labelled diagram for electrolytic refining of copper

Ans.
(i) 2Cu_{2}S\left ( s \right )+3O_{2}\left ( g \right )\rightarrow Cu_{2}O\left ( s \right )+2SO_{2}\left ( g \right )
(ii) 2Cu_{2}O\left ( s \right )+Cu_{2}S\left ( s \right )\rightarrow 6Cu\left ( s \right )+SO_{2}\left ( g \right )
(iii) Electrolytic refining: Electrolytic refining is a process of refining a metal by the process of electrolysis.
A thick block of the impure metal is made anode (+ ve)
A thin strip of pure metal is made cathode (- ve)
CuSO4 solution is taken as electrolyte.
At cathode: Cu^{2+}\left ( aq \right )+2e^{-}\rightarrow Cu
At anode Cu\left ( s \right )\rightarrow Cu^{2+}\left ( aq \right )+2e^{-}
(b)

Question:63

Of the three metals X, Y and Z. X reacts with cold water, Y with hot water and Z with steam only. Identify X, Y and Z and also arrange them in order of increasing reactivity.
Answer:

X is sodium or potassium (Na or K) as it reacts with cold water.
Na or K reacts violently with cold water.
2Na+2H_{2}O\rightarrow 2NaOH+H_{2}
2K+2H_{2}O\rightarrow 2KOH+H_{2}
Y is magnesium (Mg) as it reacts with hot water.
Mg+2H_{2}O\rightarrow Mg\left ( OH \right )_{2}+H_{2}
Z is iron (Fe)
3Fe+4H_{2}O\rightarrow Fe_{3}O_{4}+4H_{2}
Order of reactivity
Z < Y< X
Or, Fe < Mg < Na (or) K

Question:64

An element A burns with golden flame in air. It reacts with another element B, atomic number 17 to give a product C. An aqueous solution of product C on electrolysis gives a compound D and liberates hydrogen. Identify A, B, C and D. Also write down the equations for the reactions involved.

Answer:

An element A burns with golden flame in air. So, A is sodium (Na) because it burns with golden flame in air.
Atomic number of B is given as 17 so B is chlorine (Cl).
When Sodium reacts with Chlorine, sodium chloride (NaCl) is formed. Hence, C is sodium chloride (NaCl)
2Na\left ( s \right )+Cl_{2}\left ( g \right )\rightarrow 2NaCl\left ( s \right )
Now it is given that an aqueous solution of product C on electrolysis gives a compound D and liberates hydrogen
Aqueous solution of NaCl, on electrolysis gives sodium hydroxide.
Electrolysis Reaction:
The reaction at the cathode is:
H_{2}O\left ( l \right )+2e^{-}\rightarrow H_{2}\left ( g \right )+2OH^{-}
The reaction at the anode is:
Cl^{-}\rightarrow \frac{1}{2}Cl_{2}\left ( g \right )+1e^{-}
The overall reaction is:
2NaCl\left ( aq \right )+2H_{2}O\left ( l \right )\rightarrow 2NaOH\left ( aq \right )+Cl_{2}\left ( g \right )+H_{2}\left ( g \right )
Thus, D is sodium hydroxide (NaOH)

Question:65

Two ores A and B were taken. On heating ore A gives CO2 whereas, ore B gives SO2. What steps will you take to convert them into metals?
Answer:

We will use the following definitions:
1.Calcination: method by which a carbonate ore is converted into oxide
2.Roasting: method by which a sulphide ore is converted into oxide
3.Reduction (to convert metal oxide to metal
Given that ore A gives CO2 on heating, so it must be a carbonate of moderately reactive metal like Zn.
Also given, B gives SO2, so B must be a sulphide ore, e.g., Cu2S, ZnS, HgS, etc.
A will be first subjected to calcination followed by reduction
ZnCO_{3}\rightarrow ZnO+CO_{2} (calcination)
To convert it into metal treat it with carbon
ZnO+C\rightarrow Zn+CO (reduction)
B will be subjected to roasting followed by reduction
2ZnS+3O_{2}\rightarrow 2ZnO+2SO_{2} (roasting)
2Cu_{2}S+3O_{2}\rightarrow 2Cu_{2}O+2SO_{2} (roasting)
2HgS+3O_{2}\rightarrow 2HgO+2SO_{2} (roasting)
Metal is obtained from these oxides either by using reducing agent like C or by auto reduction
ZnO+C\rightarrow Zn+CO (reduction)
Cu_{2}S+2Cu_{2}O\rightarrow 6Cu+SO_{2} (reduction)

NCERT Exemplar Solutions Class 10 Science Chapter 3 Important Topics:

NCERT exemplar Class 10 Science solutions chapter 3 covers the topics:

  • Differences in metals and non-metals based on their chemical and physical properties.
  • Properties of metals such as ductility, malleability, and conductivity
  • NCERT exemplar Class 10 Science solutions chapter 2 discusses the reaction of metals with oxygen and gives hydrogen gas with some exceptions.

NCERT Class 10 Exemplar Solutions for Other Subjects:

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NCERT Class 10 Science Exemplar Solutions for Other Chapters:

Features of NCERT Exemplar Class 10 Science Solutions Chapter 3:

In this Class 10 Science NCERT exemplar chapter 3 solutions, students will learn about exceptional properties which some metals and non-metals show. These solutions will act as a quality reference material to enhance the learnings of Metals and Non-metals based practice problems. Referring to the Class 10 Science NCERT exemplar solutions chapter 3, students will find it easy to solve the questions given in CBSE as well as reference books such as NCERT Class 10 Science, S.Chand by Lakhmir Singh and Manjit Kaur, Chemistry question bank et cetera.

An interesting feature of these solutions equips the students with the functionality of viewing or downloading the pdf files via the feature NCERT exemplar Class 10 Science solutions chapter 3 pdf download which will be provided shortly.

Check NCERT Solutions for questions given in the book

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Frequently Asked Questions (FAQs)

1. Q1. Are all metals solid?

A1. No, generally metals are solids but some metals show exception, and they are found in liquid form and also known as liquid metals.

Example: Mercury, Caesium, Rubidium, Francium

2. Q2. Is there any metal that does not conduct electricity?

A2. Generally, Metals conduct electricity but there are few conductors which show very weak conductivity.

Example: Stainless steel

3. Q3. Why nonmetals do not conduct electricity?

A3. Generally, non-metals have covalent bonds and do not have free electrons. We know that free electrons are charge carriers; therefore, in absence of free electrons, these non-metals are non-conductor.

4. Q4. Give an example of a non-metal that conducts heat?

A4. Graphite is an exception among non-metals which can conduct heat as well as electricity.

5. Q5. Which substance is the hardest known substance?

A5. Diamond is the hardest known substance and it is non-metal.

6. Q6. Is the chapter Metals and Non-metals of high weightage in the board examination?

A6. The chapter Metals and Non-metals is of extreme importance in the context of the board examination as it accounts for atlease 8-10% of the total marks of the paper. NCERT exemplar Class 10 Science solutions chapter 3 provides detailed solutions to all the problems related to this chapter.

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Questions related to CBSE Class 10th

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sadhu ashram ramgart road aligarh

If you're looking for directions or steps to reach Sadhu Ashram on Ramgart Road in Aligarh, here’s how you can get there:

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  1. Starting Point:

    • Determine your starting point in Aligarh or the nearby area.

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    • Open Google Maps on your phone or computer.
    • Enter "Sadhu Ashram, Ramgart Road, Aligarh" as your destination.
    • Follow the navigation instructions provided by Google Maps.

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    • Auto-rickshaw/Taxi: Hire an auto-rickshaw or taxi and inform the driver about your destination. Most local drivers should be familiar with Sadhu Ashram.
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    • As you approach Ramgart Road, look for local landmarks that might help you confirm you’re on the right path, such as known shops, temples, or schools nearby.

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If you need detailed directions from a specific location or more information about Sadhu Ashram, feel free to ask

Read Complete Answer
sai raja 01 September,2024
show the previous year exams ?

Hello Aspirant,  Hope your doing great,  your question was incomplete and regarding  what exam your asking.

Read Complete Answer
SWETCHCHA MISKA 10 July,2024
as an icse student in class 10 is above 80 percent good enough to get into commerce in 11th cbse

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

Read Complete Answer
Manasvini Gupta 23 July,2024
i had cleared 10th from cbse in 2022 2 years ago now i wish to apply for 12th as private candidate in 2025. can i do so?

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

Read Complete Answer
Ashvadha 03 July,2024
i had cleared 10th in 2022 from cbse can i apply for 12th as private candidate this year?

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.

Read Complete Answer
sadafreen356 03 July,2024
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Popular CBSE Class 10th Questions

A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

 Option 2)

0.16\; J
Option 3)

1.00\; J

 Option 4)

0.67\; J
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A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

 Option 2)

 6.45×10−3 kg
Option 3)

 9.89×10−3 kg

 Option 4)

12.89×10−3 kg

 
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An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

 Option 2)

200 \, \, J - 500 \, \, J
Option 3)

2\times 10^{5}J-3\times 10^{5}J

 Option 4)

20,000 \, \, J - 50,000 \, \, J
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A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

 Option 2)

\; K\;
Option 3)

zero\;

 Option 4)

K/4
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In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

 Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced
Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

 Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .
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How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

 Option 2)

3.125 × 10-2
Option 3)

1.25 × 10-2

 Option 4)

2.5 × 10-2
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If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

 Option 2)

increase two fold
Option 3)

remain unchanged

 Option 4)

be a function of the molecular mass of the substance.
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With increase of temperature, which of these changes?

Option 1)

Molality

 Option 2)

Weight fraction of solute
Option 3)

Fraction of solute present in water

 Option 4)

Mole fraction.
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Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

 Option 2)

6.023 × 1022
Option 3)

half that in 8 g He

 Option 4)

558.5 × 6.023 × 1023
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A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

 Option 2)

more than 3 but less than 6
Option 3)

more than 6 but less than 9

 Option 4)

more than 9
Read More

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