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NCERT Solutions For Class 11 Biology Chapter 9 - Biomolecules

NCERT Solutions For Class 11 Biology Chapter 9 - Biomolecules

Edited By Irshad Anwar | Updated on Aug 12, 2025 12:13 PM IST

The NCERT Solutions for Class 11 Biology Chapter 9 Biomolecules explore complex biological compounds. It includes compounds such as carbohydrates, proteins, lipids, and nucleic acids. Biomolecules play an important role in various processes such as growth, development, and metabolism. With the help of the solutions, students can strengthen their understanding. They can also identify the weak areas and work on them. The NCERT Solutions build a solid foundation in the subject of biology.

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This Story also Contains
  1. Download PDF of Biomolecules Class 11 NCERT Solutions
  2. Get the Biomolecules Class 11 NCERT Solutions (Exercise Questions)
  3. Approach to Solve Class 11 Biology Chapter 9 Question Answers
  4. Important Question from Biomolecules Class 11 NCERT Solutions
  5. What Extra Should Students Study Beyond the NCERT for NEET?
  6. Chapter Wise NCERT Solutions for Class 11 Biology
NCERT Solutions For Class 11 Biology Chapter 9 - Biomolecules
NCERT Solutions For Class 11 Biology Chapter 9 Biomolecules

Class 11 Biology Chapter 9 Solutions are written in simple and easy-to-understand language by subject experts. Students can improve their conceptual clarity and perform well in exams. If students find any difficulty in understanding the concept of biomolecules, they are on the right platform. Students can also download the Biomolecules Class 11 NCERT Solutions PDF for regular practice. This not only increases their knowledge but also gain confidence to perform well in the exam.

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Download PDF of Biomolecules Class 11 NCERT Solutions

The PDF for the chapter Biomolecules can be downloaded from the link given below. PDF can be used offline anytime for quick revision or homework help. This makes it easier to understand complex topics like carbohydrates, proteins, and enzymes. NCERT Solutions for Class 11 are also useful for regular study and exam preparation.

Download PDF

Get the Biomolecules Class 11 NCERT Solutions (Exercise Questions)

The detailed solved explanations of all the questions given in the textbook are given below. Each question is answered step by step to improve understanding and clarity. Studying through the Class 11 Biology Chapter 9 question answers allows students to understand the structure clearly.

Q1. What are macromolecules? Give examples.

Answer:

The complex high molecular weight molecules separated in acid-insoluble fractions in the presence of trichloroacetic acid are referred to as macromolecules. They are polymers of a molecular weight of 10,000 daltons and above. Proteins, carbohydrates, nucleic acids, etc., are macromolecules. There are lipids in the acid-insoluble fraction, too, but they are not of high molecular weight.


Q2. Illustrate a glycosidic, peptide, and a phosphodiester bond.

Answer:

Glycosidic bond- This bond is formed between the 1st carbon atom of one monosaccharide and 4 carbon atom of a neighbouring monosaccharide unit. During the formation of this bond, a water molecule is released. A representation of a glycosidic bond is as follows

Peptide bond- This is a covalent bond formed between the carboxyl group of one amino acid and the amino group of neighbouring amino acids. A water molecule is released in the formation of a peptide bond. A representation of a peptide bond is as follows

Peptide Bond

Phosphodiester bond- It refers to the phosphate-hydroxyl linkage between two nucleotides. In this bond, the phosphate attached to the hydroxyl group at the 5' carbon of the pentose sugar is, in turn, bonded to the hydroxyl group of the 3' carbon of the pentose sugar of the next nucleotide.

 Phosphodiester bond


Q3. What is meant by the tertiary structure of proteins?

Answer:

The three-dimensional configuration of a protein that arises from repeated coiling and folding of helical and pleated polypeptide chains is termed its tertiary structure. Through repeated folding and coiling, polar side chains remain exposed, whereas non-polar amino acids are kept inside. The tertiary structure is bonded through weak bonds. The activity of a protein exists in tertiary structures.


Q4. Find and write down structures of 10 interesting small molecular weight biomolecules. Find if there is any industry that manufactures the compounds by isolation. Find out who are the buyers.

Answer:

The structures of 10 small molecular weight biomolecules are as follows.

amino acid


10 small molecular weight biomolecules


These biomolecules are manufactured in biotechnology industries.

Q5. Find out and make a list of proteins used as therapeutic agents. Find other applications of proteins (e.g., Cosmetics, etc.)

Answer:

Proteins with therapeutic uses are insulin, oxytocin, ADH, thrombin, fibrinogen, renin, immunoglobulin, diastase, streptokinase, etc.

Other applications of proteins are

1. As cosmetics- Proteins such as casein are used in beauty creams, shampoos, etc.

2. Sweeteners- Thaumatin and monellin are sweet proteins.

3. Dietary supplements- Proteins can be used as dietary supplements.

Q6. Explain the composition of triglyceride.

Answer: triglyceride

A triglyceride is a chemical formed by the esterification of three molecules of fatty acids with one molecule of trihydric alcohol called glycerol. All three fatty acids of triglyceride can be similar, as in tripalmitin, or dissimilar, as in palmito-oleoistearin, dipalmitostearin, etc.

three molecules of fatty acids


Q7. Can you describe what happens when milk is converted into curd or yoghurt, from your understanding of proteins?

Answer:

Milk has a protein known as casein. When we mix a little curd into milk, the protein casein is coagulated by the action of lactic acid bacteria, and thus milk is transformed into curd. Coagulation breaks the structure of the protein casein.

Q8. Can you attempt building models of biomolecules using commercially available atomic models (Ball and Stick models).

Answer:

Yes, we can try constructing models of biomolecules with the help of commercially purchased atomic models, like ball and stick models. The stick is, in the model, taken to be a bond, and balls of varying colours are taken to be atoms.

Q9. Attempt to titrate an amino acid against a weak base and discover the number of dissociating ( ionizable ) functional groups in the amino acid.

Answer:

When we titrate an amino acid against a weak base, it dissociates into its functional groups, i.e., -COOH (carboxylic group) and -NH (amino group)

Q10. Draw the structure of the amino acid, alanine.

Answer:

The structure of the amino acid alanine is represented below:

structure of the amino acid alanine

Q11. Find out a qualitative test for proteins, fats and oils, and amino acids, and test any fruit juice, saliva, sweat, and urine for them.

Answer:

One of the qualitative tests for proteins is the xanthoproteic test. When a qualitative test for protein in urine is done using the aid of the xanthoproteic test, if a yellow precipitate is formed, then it is guaranteed that there is protein in it. The qualitative test for fats is the emulsification test.

During the emulsification test, the experimental material is first treated with ethanol and then dissolved in water. The development of an emulsion proves the existence of fats. The qualitative analysis for oils is the paper test. The material to be tested is placed on paper. The presence of oil is established when oil marks remain.

Q12. Find out how much cellulose is made by all the plants in the biosphere and compare it with how much paper is manufactured by man, and hence what the consumption of plant material by man is annually. What a loss of vegetation!

Answer:

Paper consists of wood pulp, which is predominantly composed of cellulose. Cellulose is a polymer of glucose molecules. Approximately 85 billion tonnes of cellulose are generated every year in the biosphere. Paper production requires 0.5 billion tonnes of wood. The rise in the usage of wood has caused immense loss of vegetation.

Q13. Describe the important properties of enzymes.

Answer:

Enzymes are proteinaceous substances which are capable of catalysing chemical reactions of biological origin without themselves undergoing any change. They are commonly called biocatalysts. The properties of enzymes are as follows:

1. Enzymes are proteins by nature

2. Optimum temperature- An enzyme is active within a narrow range of temperature. The temperature at which an enzyme is most active is called the optimum temperature. The enzyme activity decreased above and below this temperature.

3. Optimum pH- Every enzyme has an optimum pH at which it is maximum active. Most of the intracellular enzymes work at neutral pH.

4. Enzymes are substrate specific, i.e. one enzyme catalyses only a particular substrate. Every enzyme has specific sites called active sites for the binding of substrate.

5. Only a small quantity of the enzyme is capable of forming the desired product

6. Enzyme activity is sensitive to certain chemicals called inhibitors or modulators.

Check the NCERT Books and NCERT Syllabus here:

Approach to Solve Class 11 Biology Chapter 9 Question Answers

To answer Biomolecules questions effectively, students can follow the simple steps given below:

  • Study the formation of chemicals in living organisms, for example, carbon, hydrogen, and oxygen.

  • Understand biomacromolecules such as proteins, nucleic acids, and polysaccharides. All the concepts are well-explained in the Class 11 Biology Chapter 9 Solutions.

  • Note down primary and secondary metabolites and their role in metabolism. Make a comparison table using the Biomolecules Class 11 NCERT Solutions PDF.

  • Learn concepts such as the formation of an enzyme, its function, and the determinants of enzyme activity.

  • Practice questions given in the NCERT Solutions Class 11 Biology to understand the biochemical reactions.

NCERT Solutions for Class 11: Subject-wise

Important Question from Biomolecules Class 11 NCERT Solutions

This chapter explains the structure and functions of biomolecules like carbohydrates, proteins, and nucleic acids. Given below is a question from this chapter, along with the answer. To score well, it is important to practice the questions given in the Biomolecules Class 11 NCERT Solutions.

Question: What type of bond joins monosaccharides in polysaccharides?

a. Peptide bond

b. Glycosidic bond

c. Phosphodiester bond

d. Hydrogen bond

Answer: The correct answer is option (b), Glycosidic bond

Explanation: Glycosidic bonds are the chemical connections between monosaccharide units in polysaccharides. Peptide bonds connect amino acids in proteins, phosphodiester bonds connect nucleotides in DNA and RNA, and hydrogen bonds are weaker interactions that stabilise the structure of molecules.

What Extra Should Students Study Beyond the NCERT for NEET?

Here is a table for all the topics from the chapter, which students have to study beyond the NCERT for NEET. Students can also go through the Class 11 Biology Chapter 9 Solutions to gain clarity.

Chapter Wise NCERT Solutions for Class 11 Biology

Below are the chapter-wise solutions:


Frequently Asked Questions (FAQs)

1. What are the different types of structures of biomacromolecules given biomolecules ncert biology?

The different types of structures of biomacromolecules given in the NCERT Solutions for Class 11 Biology Chapter 9 Biomolecules are: 

  • primary  
  • secondary  
  • tertiary and  
  • quaternary 
2. What are the important topics of ch 9 bio class 11?

The important topics of NCERT Solutions for Class 11 Biology Chapter 9 Biomolecules are: 

  • Primary and Secondary Metabolites  
  • Biomacromolecules  
  • Proteins  
  • Polysaccharides  
  • Nucleic Acids  
  • Structure of Proteins  
  • Nature of Bond Linking Monomers in a Polymer  
  • Metabolic Basis for Living  
  • The Living State  
  • Enzymes 
3. List the characteristics of the enzymes discussed in Chapter 9 of the NCERT Solutions for Class 11 Biology.

The properties of enzymes covered in the NCERT Solutions for Class 11 Biology Chapter 9 Biomolecules are: 

  • The enzymes are complex macromolecules with a higher molecular weight.
  • The enzymes help break down larger molecules into simpler molecules by catalyzing the biochemical reactions occurring within the cell.
  • Enzymes can only speed up a reaction.
  • Enzymes are action-specific.
  • At a pH level between 6 and 8, enzyme activity peaks.
4. What is the structure and function of nucleic acids in Class 11?

Nucleic acids (DNA and RNA) are nucleotide polymers, composed of a sugar, phosphate group, and nitrogenous base (A, T/U, G, C). DNA is double-helix, whereas RNA is typically single-stranded. They carry and transfer genetic information, with DNA coordinating protein synthesis and RNA helping in transcription and translation. Their structure allows replication, gene expression, and heredity in living things.

5. What is the role of vitamins in biomolecules?

Vitamins serve as coenzymes or coenzyme precursors, facilitating enzymatic reactions during metabolism. Vitamins assist in energy production, immune function, cell growth, and repair. Vitamins are either water-soluble (B-complex, C) or fat-soluble (A, D, E, K), with each having a unique biochemical function.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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