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NCERT Solutions for Class 10 Science Chapter 12: Students preparing for CBSE class 10 board exams, must know that NCERT chapter 12 class 10 science is one of the most important chapters of NCERT syllabus. In this article on electricity class 10 NCERT solutions, you will get the complete question and answer of the electricity chapter topic-wise in a very easy and systemic manner.
Since CBSE class 10 is a board class it is extremely important to understand topics carefully. The Electricity class 10 solutions will help you score well in the CBSE board exam. Students are advised to go through Class 10 science chapter 12 question answer to score good marks in the Board examination. Complete the electricity class 10 NCERT syllabus at the earliest to revise it in a proper way. Refer to the NCERT Class 10th Science Notes and cover all the topics for scoring well in the exams.
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Electricity class 10 questions and answers are created by highly qualified subject matter experts in very easy-to-understand and step-by-step which ensure a student scores well in exam. The main aim of NCERT solutions is to provide comprehensive guidance to students. By presenting clear explanations, solving examples, and offering valuable insights, these class 10 science ch 12 ncert solutions assists students in strengthening their understanding of the subject.
Electricity class 10 ncert solutions include important formulas, diagrams, and a helpful eBook link, providing essential resources for comprehensive exam preparation and a better understanding of the subject. Click the eBook link to access valuable study materials and excel in your studies.
Current:
Current (I)= Charge(Q)/ Time taken(t)
Voltage:
Voltage(v)= Work Done(W) / Charge(Q)
Resistance:
R= ρl / A= V/I
Where:
ρ = Resistivity, l = length, A = Area
Ohm's Law:
V = I × R
Resistors in Series:
Rt = R1 + R2 + R3 + ...
Resistors in Parallel:
1/Rt = 1/R1 + 1/R2 + 1/R3 + ...
Download Ebook - NCERT Class 10 Science: Chapterwise Important Formulas, Diagrams, And Points
This ebook comprises crucial formulas, diagrams, and key points for each chapter, curated by experts. Utilizing this valuable resource, students can score well in less time and use it for quick revision during weekly tests and exams, ensuring better academic performance.
As science class 10 chapter 12 is crucial, all topics hold significance. However, here are some very important topics that will aid in scoring good marks in the exam:
Electric current potential
Electric resistance
Circuit diagrams
Ohm's law
The heating effect of electric current and power.
The electric current can be classified as direct current (DC) and alternating current ac (AC).
Also students can refer,
Download Class 10 electricity exercise solutions Electricity for free.
This chapter has been renumbered as Chapter 11 in accordance with the CBSE Syllabus 2023–24.
Topic:12.1
Answer:
A closed and continuous path of electric current is known as the electric circuit. It consists of electric circuit elements like battery, resistors, etc and electric devices like a switch and measuring devices like ammeters, etc.
Q.2 Define the unit of current.
Answer:
Ampere(A) is unit of current.1A is flow of 1C of charge through a wire in 1s of time.
Q.3 Calculate the number of electrons constituting one coulomb of charge.
Answer:
Given: Q=1C
We know that the charge of an electron
Thus, the number of electrons constituting one coulomb of charge is electrons.
Q.1 Name a device that helps to maintain a potential difference across a conductor.
Answer:
Battery, cell or power supply source helps to maintain a potential difference across a conductor.
Q.2 What is meant by saying that the potential difference between two points is 1 V?
Answer:
The potential difference between two points is 1 V means 1 J of work is required to move a charge of amount 1C from one point to another.
Q.3 How much energy is given to each coulomb of charge passing through a 6 V battery?
Answer:
Given : potential difference = 6V and carge =1C.
J
Thus, 6J energy is given to each coulomb of charge passing through a 6 V battery.
Q.1 On what factors does the resistance of a conductor depend?
Answer:
The resistance of a conductor depends on :
1. Cross section area of the conductor.
2.length of conductor
3.The temperature of the conductor.
4. Nature of material of the conductor.
Answer:
We know that resistance is given as
R=resistance
=resistivity
l=length of wire
A=area of cross section
Resistance is inversely proportional to the area of cross-section.
Thicker the wire more is cross-sectional area resulting in less resistance resulting in more current flow.
Answer:
By Ohm's law,
V=IR
V= potential difference
I =current
R = resistance
Now, the potential difference is reduced to half i.e.
R' = R=resistance
I' =current
Current flowing is reduced to half.
Q.4 Why are coils of electric toasters and electric irons made of an alloy rather than a pure metal?
Answer:
The resistivity of an alloy is higher than pure metal so alloy does not melt at high temperature. Thus, coils of electric toasters and electric irons made of an alloy rather than a pure metal.
Q.5 Use the data in Table 12.2 to answer the following –
(a) Which among iron and mercury is a better conductor?
(b) Which material is the best conductor?
Answer:
Lower the value of resistivity lower will be the resistance for a material of given area and length. If resistance is law current flow will be high when a potential difference is applied across the conductor.
(a).resistivity of iron =
the resistivity of mercury =
the resistivity of mercury is more than iron so iron is a better conductor than mercury.
(b).From the table, we can observe silver has the lowest resistivity so it is the best conductor.
Answer:
The schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a resistor, an resistor, and a resistor, and a plug key, all connected in series is as shown below :
Answer:
The diagram is as shown :
Resistance of circuit =R=5+8+12=25
Potential = 6V
Now, for 12 ohm resistor, current = 0.24 A.
By Ohm's law,
The reading of the ammeter is o.24A and the voltmeter is 2.88V.
Q.1 Judge the equivalent resistance when the following are connected in parallel –
Answer:
R=Equivalent resistance
R=Equivalent resistance
Answer:
Given :
R=Equivalent resistance
By Ohm's law,
Hence, the resistance of electric iron is 31.25 and current through it is 7.04A.
Answer:
In parallel, there is no division of voltage among the appliances so the potential difference across all appliance is equal and the total effective resistance of a circuit can be reduced. Hence, connecting electrical devices in parallel with the battery is beneficial instead of connecting them in series.
Q.4 How can three resistors of resistances be connected to give a total resistance of
Answer:
(a)
R=Equivalent resistance
(b).1 Ohm
R=Equivalent resistance
Connect all the three resistors in parallel
Answer:
(a) the highest total resistance is obtained when all the resistors are connected in series
Answer :
(b) the lowest total resistance is R is obtained when all the resistors are connected in parallel.
Q. 1. Why does the cord of an electric heater not glow while the heating element does?
Answer:
The heating element of an electric heater is a resistor.
The amount of heat production is given as , .
The resistance of elements (alloys) of an electric heater is high. As current flow through this element, it becomes hot and glows red.
The resistance of cord (metal like Cu or Al)of an electric heater is low. As current flow through this element, it does not becomes hot and does not glow red.
Answer:
Given : potential difference = 50 V.
Charge = 9600 C
time = 1 hr=3600 s
So,
Q.3 An electric iron of resistance takes a current of 5 A. Calculate the heat developed in 30 s.
Answer:
Given : resistance=R= , TIME =30s , current =I=5A
Q.1 What determines the rate at which energy is delivered by a current?
Answer:
The rate at which energy is delivered by a current is power.
Power P=I ^{ 2 } R, where I is the current and R is the resistance of the circuit/ appliance. Power depends on the current drawn by the appliance and the resistance of the appliance.
Answer:
Given: I= 5 A and V= 220 V.
Power=P=VI
Time = 2hr=
The energy consumed =
Power of motor = 1100W
Energy consumed by motor = 7920000J
(a) 1/25 (b) 1/5 (c) 5 (d) 25
Answer:
Given: A piece of wire of resistance is cut into five equal parts.
Resistance of each part is .
Hence,
Thus, option D is correct.
Q. 2 . Which of the following terms does not represent electrical power in a circuit?
Answer:
We know that power = P=VI....................................1
Put , V=IR in equation 1
Pur , in equation 1,
P= power, V=potencial difference, I= current,R=resistance
P cannot be .
Thus, option B is correct.
Q. 3. An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed will be
(a) 100 W (b) 75 W (c) 50 W (d) 25 W
Answer:
Given : V=220V,P=100W
The resistance of the bulb
If bulb is operated on 110 Vand resistance is the same , the power consumed will be P'
Hence, option D is correct.
(a) 1:2 (b) 2:1 (c) 1:4 (d) 4:1
Answer:
If resistors are connected in parallel, the net resistance is given as
If resistors are connected in series, the net resistance is given as
Heat produced = H =
Thus, option C is correct.
Q. 5. How is a voltmeter connected in the circuit to measure the potential difference between two points?
Answer:
A voltmeter should be connected in parallel, to measure the potential difference between two points.
Answer:
Given : diameter=d= 0.5 mm and resistivity = = m.,resistance =R=10
Area =A
We know
If the diameter is doubled.
d=1 mm
Area =A'
We know
Hence, new resistance is of original resistance.
I (amperes) 0.5 1.0 2.0 3.0 4.0
V (volts) 1.6 3.4 6.7 10.2 13.2
Plot a graph between V and I and calculate the resistance of that resistor
Answer:
The plot between voltage and current is as shown :
The slope of the line gives resistance (R)
Answer:
Given : V=12V , I = 2.5 mA = 0.0025 A
Answer:
Total resistance =R
V = 9V
Hence, All resistors are in series so 0.67A current would flow through the resistor.
Q.10. How many resistors (in parallel) are required to carry 5 A on a 220 V line?
Answer:
Given: V=220V and I =5A
Let x number of resistors are connected in parallel to obtain 44 Ohm equivalent resistance.
Thus,
Hence, 4 resistors of 176 Ohm are connected in parallel to obtain 44 Ohm.
Answer:
(i)
R=Equivalent resistance
(ii)
.
R=Equivalent resistance
Answer:
Given: V=220V and P=10W
Let x be the number of bulbs.
I = 5A and V=220V
For x bulbs of resistance 4680 Ohm, are connected in parallel to obtain 44 Ohm equivalent resistance.
Thus,
Hence, 110 bulbs of 4840 Ohm are connected in parallel to obtain 44 Ohm.
Q.13. A hot plate of an electric oven connected to a 220 V line has two resistance coils A and B, each of resistance, which may be used separately, in series, or in parallel. What are the currents in the three cases?
Answer:
Given : V=220V and Resistance of each coil=R =24A
When coil is used separately,current in coil is
When two coils are connected in series, net resistance is
current in coil is I'
When two coils are connected in parallel, net resistance is
current in the coil is I''
Q.14. Compare the power used in the resistor in each of the following circuits:
(i) a 6 V battery in series with and resistors
(ii) a 4 V battery in parallel with and resistors.
Answer:
i) Given: V=6V
R=1+2=3Ohm
In, a series current is constant.
So, power =P
ii) Given: V=6V , R=2 Ohm
In, parallel combination voltage in the circuit is constant.
So, power =P
Answer:
Given :
For lamp one: Power = P1=100W and V = 220V
For lamp two: Power = P2=60W and V = 220V
Thus, the net current drawn from the supply is 0.455+0.273=0.728A
Q.16. Which uses more energy, a 250 W TV set in 1 hr, or a 1200 W toaster in 10 minutes?
Answer:
For TV set :
Given : Power = 250W and time = 1 hr = 3600 seconds
Energy consumed = H=PI
For toaster :
Given : Power = 1200W and time = 10 minutes = 600 seconds
Energy consumed = H=PI
Thus, the TV set uses more energy than a toaster.
Q.17. An electric heater of resistance draws 15 A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.
Answer:
Given: R=8 Ohm ,I=15A and t= 2hr
The heat developed in the heater is H.
The rate at which heat is developed is given as
Q.18(a). Explain the following.
(a) Why is the tungsten used almost exclusively for filament of electric lamps?
Answer:
The tungsten used almost exclusively for filament of electric lamps because the melting point of tungsten is very high. The bulb glows at a very high temperature. So tungsten filament does not melt when bulb glows.
Q.18.(b) Explain the following.
Answer:
The conductors of electric heating devices, such as bread-toasters and electric irons, made of an alloy rather than a pure metal because the resistivity of the alloy is more than a pure metal. So the resistance will be hight and the heating effect will be high.
Q.18.(c) Explain the following.
(c) Why is the series arrangement not used for domestic circuits?
Answer:
If any of the elements in the circuit get damaged the entire circuit will be affected. If an element brake there will not be any current flow through the circuit. So the series circuit is not preferred in the domestic circuit.
Q.18.(d) Explain the following.
(d) How does the resistance of a wire vary with its area of cross-section?
Answer:
We know that
Thus, the resistance of a wire is inversely proportional to its area of cross-section.
Q.18.(e) Explain the following.
(e) Why are copper and aluminium wires usually employed for electricity transmission?
Answer:
Copper and aluminium wires usually employed for electricity transmission because they have low resistivity and they are good conductors of electricity.
Before moving on to the board exam, students must know the types of questions which may be asked from Electricity class 10 ncert solutions. The following types of questions are commonly found in the exam:
Very short answer type
Short answer type
Long answer type
Practical based questions
Also, check - NCERT Solutions for Class 10 Maths
Electricity class 10 solutions hold significant weightage in board exams. This chapter explores essential concepts related to electric circuits, Ohm's law, and electrical power, making it crucial for exam preparation and scoring well. Based on examination trends observed in previous years, class 10 science chapter 12 question answer is anticipated to carry a weightage of at least 8 marks in the Class 10 Science board exam. However, in the 2018 exam, the questions for this chapter totalled up to 7 marks. To strengthen your understanding of the key concepts in this chapter, make use of the ncert solutions for class 10 science chapter 12, ensuring a solid grasp of the subject matter.
To access electricity class 10 numericals with solutions - "Electricity", follow these steps:
These ncert class 10 science chapter 12 exercise solutions include not just exercise solutions but also topic-specific questions, offering thorough coverage of the chapter. By using these solutions, you will be able to confidently face questions in the CBSE board exam for Science, taking a step closer to academic success.
The ch 12 science class 10 is one of the most interesting chapters that will help in learning about electrical components and how they work. To give a better understanding of the chapter we have provided class 10 science chapter 12 question answer above. Students will learn about water, steam, and nuclear energy, etc. electricity class 10 questions and answers also include some other topics related to resistors. The main aim of NCERT solutions is to give a better knowledge of how to use the concept while answering the questions.
Current flows from the positive terminal to the negative terminal of a circuit.
A voltmeter is always connected in parallel across the circuit whereas an ammeter is always connected in series with the circuit whose current is to be measured.
Reciprocal of the resistance is known as conductance whereas reciprocal resistivity is known as conductivity.
Comprehensive Coverage: The electricity class 10 solutions encompass answers to both in-text questions and exercise questions, providing a thorough understanding of the chapter.
Numerical and Theoretical Problems: NCERT solutions for class 10 science chapter 12 address both numerical and theoretical problems, aiding students in mastering various aspects of electricity.
Step-by-Step Solutions: Numerical problems are solved methodically, listing necessary equations and steps, making it easier for students to follow and learn.
18 Questions in Exercise: Class 10 electricity ncert solutions consists of 18 questions, offering ample practice opportunities to students.
Also, Check NCERT Books and NCERT Syllabus here:
NCERT Solutions for Class 10 Science - Chapter wise
Chapter No. | Chapter Name |
Chapter 1 | Chemical Reactions and Equations |
Chapter 2 | Acids, Bases, and Salts |
Chapter 3 | Metals and Non-metals |
Chapter 4 | Carbon and its Compounds |
Chapter 5 | Periodic Classification of Elements |
Chapter 6 | Life Processes |
Chapter 7 | Control and Coordination |
Chapter 8 | How do Organisms Reproduce? |
Chapter 9 | Heredity and Evolution |
Chapter 10 | Light Reflection and Refraction |
Chapter 11 | The Human Eye and The Colorful World |
Chapter 12 | Electricity |
Chapter 13 | Magnetic Effects of Electric Current |
Chapter 14 | Sources of Energy |
Chapter 15 | Our Environment |
Chapter 16 | Sustainable Management of Natural Resources |
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 | |
Chapter 16 |
At Careers360, students have the advantage of accessing NCERT Solutions for all classes, ranging from Class 6 to 12, across all subjects. These solutions are thoughtfully curated by expert subject tutors, aligning them with the latest CBSE syllabus and guidelines. With Careers360 comprehensive NCERT Solutions, students can enhance their understanding, excel in exams, and achieve academic excellence across all levels of their education.
Class 10 Science Chapter 12 Electricity carries 6 to 8 marks.
Along with questions and concepts of class 10 chapter, practicing CBSE previous year question papers are mandatory for board exams.
Yes, it helps in higher studies if students chooses the Science stream because class 12 has current electricity chapter in syllabus.
class 10 science chapter 12 exercise solutions contains the following number of exercises and questions:
Exercise 12.1 includes 3 questions.
Exercise 12.2 consists of 3 questions.
Exercise 12.3 has 5 questions.
Exercise 12.4 comprises 2 questions.
Exercise 12.5 has 5 questions.
Exercise 12.6 contains 3 questions.
Exercise 12.7 comprises 2 questions.
Exercise 12.8 has 18 questions.
The PDF format of class 10 electricity solutions Chapter 12 provides diagrams and solutions to all questions which are present in the textbook. The answers are designed with consideration for the comprehension level of students, and they strictly align with the CBSE syllabus and exam pattern, allowing students to approach exams with confidence.
"Q" refers to the electrical charge or quantity of charge.
As per the revised CBSE Syllabus 2023-24, Chapter 12 "Electricity" has been renumbered as Chapter 10.
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Schools with ongoing admissions: Some schools, due to transfers or other reasons, might still have seats available even after the main admission rush. Reach out to the schools directly to see if they have any open seats in 10th grade.
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Focus on excelling in your current school: If you can't find a new school this year, focus on doing well in your current school. Maintain good grades and get involved in extracurricular activities. This will strengthen your application for next year if you decide to try transferring again.
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Hello aspirant,
The dates of the CBSE Class 10th and Class 12 exams are February 15–March 13, 2024 and February 15–April 2, 2024, respectively. You may obtain the CBSE exam date sheet 2024 PDF from the official CBSE website, cbse.gov.in.
To get the complete datesheet, you can visit our website by clicking on the link given below.
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Hope this information helps you.
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Thank you
Hope it helps you.
The eligibility age criteria for class 10th CBSE is 14 years of age. Since your son will be 15 years of age in 2024, he will be eligible to give the exam.
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As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
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As per latest 2024 syllabus. Chemistry formulas, equations, & laws of class 11 & 12th chapters