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    NCERT Solutions for Exercise 14.4 Class 10 Maths Chapter 14 - Statistics

    NCERT Solutions for Exercise 14.4 Class 10 Maths Chapter 14 - Statistics

    Sumit SainiUpdated on 12 Jul 2022, 02:57 PM IST

    NCERT Solutions for Class 10 Maths exercise 14.4 - Cumulative frequency is calculated by adding all frequencies up to a certain threshold. We calculate the cumulative frequency by adding each and every frequency from the frequency distribution table given to us to the sum of its predecessor.

    This Story also Contains

    1. Benefits of NCERT Solutions for Class 10 Maths Exercise 14.4
    2. More About NCERT Solutions for Class 10 Maths Exercise 14.4
    3. Benefits of NCERT Solutions for Class 10 Maths Exercise 14.4
    4. NCERT Solutions for Class 10 Subject Wise

    In NCERT solutions for Class 10 Maths chapter 14 exercise 14.4 we are introduced to ‘ogives’. An 'ogive of the less than type' is a graph of a cumulative frequency distribution of the less than type. An ‘ogive of the more than type' is a graph depicting a cumulative frequency distribution of the more than type. The median of the grouped frequency distribution is determined by the point of intersection of the ogives of more than and less than types.

    The formula for finding the median:

    1639046081922

    Where,
    l = lower limit of median class,
    n = number of observations,
    cf = cumulative frequency of class preceding the median class,
    f = frequency of median class,
    h = class size (assuming class size to be equal).

    Along with NCERT book Class 10 Maths chapter 14 exercise 14.4, the following exercises are also present.

    Benefits of NCERT Solutions for Class 10 Maths Exercise 14.4

    Q1 The following distribution gives the daily income of 50 workers of a factory.

    1640762580356 Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

    Answer:

    Daily Income

    (Upper-Class Limit)

    Cumulative

    Frequency

    Less than 120

    12

    Less than 140

    26

    Less than 160

    34

    Less than 180

    40

    Less than 200

    50

    Now,

    Taking upper-class interval on the x-axis and their respective frequencies on the y-axis,

    1640762619994

    Q2 During the medical check-up of 35 students of a class, their weights were recorded as follows:


    1640762636273 Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula.

    Answer:

    Taking upper-class interval on the x-axis and their respective frequencies on the y-axis,

    1640762661028

    $N= 35 \implies \frac{N}{2} = 17.5$

    Marking a point on the curve whose ordinate is 17.5 gives an x-ordinate= 46.5.

    Hence, the Median of the data is 46.5

    Now,

    Weight

    (Class)

    Frequency

    Cumulative

    Frequency

    >38

    0

    0

    38-40

    3

    3

    40-42

    2

    5

    42-44

    4

    9

    44-46

    5

    14

    46-48

    14

    28

    48-50

    4

    32

    50-52

    3

    35

    $N= 35 \implies \frac{N}{2} = 17.5$
    $\therefore$ Median class = 46-48; Lower limit, l = 46;

    Cumulative frequency of preceding class, c.f. = 14; f = 14; h = 2
    $Median = l + \left (\frac{\frac{n}{2}-c.f}{f} \right ).W$
    $\\ = 46+ \left (\frac{17.5-14}{14} \right ).2 \\ \\ = 46+\frac{7}{14}$

    $= 46.5$

    Thus, the median using formula is 46.5 which verifies the result.

    Q3 The following table gives production yield per hectare of wheat of 100 farms of a village.


    1640762676580 Change the distribution to a more than type distribution, and draw its ogive.

    Answer:

    Production yield

    (Upper-Class Limit)

    Cumulative

    Frequency

    More than or equal to 50

    100

    More than or equal to 55

    98

    More than or equal to 60

    90

    More than or equal to 65

    78

    More than or equal to 70

    54

    More than or equal to 75

    16

    Now,

    Taking lower class limit on the x-axis and their respective frequencies on the y-axis,

    1640762700208

    More About NCERT Solutions for Class 10 Maths Exercise 14.4

    The modal class is the class with the highest frequency in grouped data. The following formula can be used to determine the mode. When the modal class is unique, the formula is valid for equal class intervals.

    The formula for finding the mode:

    1639046081094

    Where,
    l = lower limit of modal class
    h = class width
    f1 = frequency of the modal class
    f0 = frequency of the class preceding the modal class
    f2 = frequency of the class succeeding the modal class1639046080913

    Also Read| Statistics Class 10 Notes

    Confused between CGPA and Percentage?

    Get your results instantly with our calculator!

    💡 Conversion Formula used is: Percentage = CGPA × 9.5

    Benefits of NCERT Solutions for Class 10 Maths Exercise 14.4

    • Exercise 14.4 Class 10 Maths, gives us a concept on STATISTICS and its uses to a board-level of graphs like ogives.

    • NCERT syllabus Class 10 Maths chapter 14 exercise 14.4 teaches us about the new formula of mode and median.

    • The concepts from Class 10 Maths chapter 14 exercise 14.4 will give us a vivid image of the graphical representation of Cumulative Frequency Distribution, which is very effective if ogives are given to us in any question.

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