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NCERT Solutions for Exercise 14.1 Class 10 Maths Chapter 14 Statistics are discussed here. These NCERT solutions are created by subject matter expert at Careers360 considering the latest syllabus and pattern of CBSE 202425. Class 10 Maths ex 14.1 covers the classification of ungrouped and grouped frequency distributions. In the prior class, students should have learned how to visualise data in a variety of graphical styles, such as bar graphs, histograms, and frequency polygons. They must understand concepts like numerical representations of ungrouped data and measures of central tendencies like mean, median, and mode. In NCERT solutions Class 10 Maths chapter 14.1, students will learn to transition from ungrouped to grouped data and study all three measures: mean, median, and mode.
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Students will be introduced to new statistical concepts including cumulative frequency, cumulative frequency distribution, cumulative frequency curves, or 'ogives,' among others. We will also come across many statistical terms and their methods like class mark, direct method, assumed method for finding mean, etc. 10th class Maths exercise 14.1 answers are designed as per the students demand covering comprehensive, step by step solutions of every problem. Practice these questions and answers to command the concepts, boost confidence and in depth understanding of concepts. Students can find all exercise together using the link provided below.
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Download Free Pdf For Class 10 Maths chapter 14 exercise 14.1 Download PDF
Statistics C lass 10 Chapter 14 Statistics Exercise: 14.1
Which method did you use for finding the mean, and why?
Number of plants  Number of houses
 Classmark


02  1  1  1 
24  2  3  6 
46  1  5  5 
68  5  7  35 
810  6  9  54 
1012  2  11  22 
1214  3  13  39 
=20 
=162 
Mean,
We used the direct method in this as the values of are small.
Q2 Consider the following distribution of daily wages of 50 workers of a factory. Find the mean daily wages of the workers of the factory by using an appropriate method.
Let the assumed mean be a = 550
Daily Wages  Number of workers  Classmark



500520  12  510  40  480 
520540  14  530  20  280 
540560  8  550  0  0 
560580  6  570  20  120 
580600  10  590  40  400 
=50 
=240 
Mean,
Therefore, the mean daily wages of the workers of the factory is Rs. 545.20
Daily pocket allowance  Number of children  Classmark


1113  7  12  84 
1315  6  14  84 
1517  9  16  144 
1719  13  18  234 
1921  f  20  20f 
2123  5  22  110 
2325  4  24  96 
=44+f 
=752+20f 
Mean,
Therefore the missing f = 20
Let the assumed mean be a = 75.5
No. of heartbeats per minute  Number of women  Classmark



6568  2  66.5  9  18 
6871  4  69.5  6  24 
7174  3  72.5  3  9 
7477  8  75.5  0  0 
7780  7  78.5  3  21 
8083  4  81.5  6  24 
8386  2  84.5  9  18 
=30 
=12 
Mean,
Therefore, the mean heartbeats per minute of these women are 75.9
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Let the assumed mean be a = 57
Number of mangoes  Number of boxes  Classmark



5052  15  51  6  90 
5355  110  54  3  330 
5658  135  57  0  0 
5961  115  60  3  345 
6264  25  63  6  150 
=400 
=75 
Mean,
Therefore, the mean number of mangoes kept in a packing box is approx 57.19
Q6 The table below shows the daily expenditure on the food of 25 households in a locality. Find the mean daily expenditure on food by a suitable method.
Daily expenditure in rupees  100150  150200  200250  250300  300350 
Number of households  4  5  12  2  2 
Let the assumed mean be a = 225 and h = 50
Daily Expenditure  Number of households  Classmark




100150  4  125  100  2  8 
150200  5  175  50  1  5 
200250  12  225  0  0  0 
250300  2  275  50  1  2 
300350  2  325  100  2  4 
=25 
= 7 
Mean,
Therefore, the mean daily expenditure on food is Rs. 211
Find the mean concentration of in the air.
Class Interval  Frequency
 Classmark


0.000.04  4  0.02  0.08 
0.040.08  9  0.06  0.54 
0.080.12  9  0.10  0.90 
0.120.16  2  0.14  0.28 
0.160.20  4  0.18  0.72 
0.200.24  2  0.22  0.44 
=30 
=2.96 
Mean,
Therefore, the mean concentration of in the air is 0.099 ppm
Number of days  Number of Students  Classmark


06  11  3  33 
610  10  8  80 
1014  7  12  84 
1420  4  17  68 
2028  4  24  96 
2838  3  33  99 
3840  1  39  39 
=40 
=499 
Mean,
Therefore, the mean number of days a student was absent is 12.48 days.
Let the assumed mean be a = 75 and h = 10
Literacy rates  Number of cities  Classmark




4555  3  50  20  2  6 
5565  10  60  10  1  10 
6575  11  70  0  0  0 
7585  8  80  10  1  8 
8595  3  90  20  2  6 
= 35 
= 2 
Mean,
Therefore, the mean mean literacy rate is 69.43%
In this exercise we will now go through the definition of some basics terms like mean, median mode etc.
The mean (or average) of observations is the sum of all the observations' values divided by the total number of observations.
Where
 sum of the values of all the observations
 sum of the number of observations
In statistics, the median is the middle value of a set of data when ordered in a certain order. Data or observations might be arranged in ascending or descending order.
The mode is the observation with the greatest frequency in grouped data without class intervals.
Also Read Statistics Class 10 Notes
Also, See
To find what is the basics of statistic. Definition of mean and its formula. To learn about different methods of finding mean like Assumed mean method, step deviation method etc. Go through the ex 14.1 class 10 to command these concepts.
The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set. Practice class 10 maths ex 14.1 to command these concepts.
The class midpoint (or class mark) is a specific point in the centre of the bins (categories) in a frequency distribution table. Go through exercise 14.1 class 10 maths to get deeper understanding of concepts.
This class 10 ex 14.1 discusses the concept of mean in detail. to find mean of data use formula discussed in this exercise. mean = sum of total data / number of data
The centre of a bar in a histogram is known as class mark.
The mean of the data will also increase by 5.
The mean of the data will also increase by 5.
Hello
The Sadhu Ashram in Aligarh is located in Chhalesar . The ashram is open every day of the week, except for Thursdays . On Mondays, Wednesdays, and Saturdays, it's open from 8:00 a.m. to 7:30 p.m., while on Tuesdays and Fridays, it's open from 7:30 a.m. to 7:30 p.m. and 7:30 a.m. to 6:00 a.m., respectively . Sundays have varying hours from 7:00 a.m. to 8:30 p.m. . You can find it at Chhalesar, Aligarh  202127 .
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
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