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NCERT exemplar Class 9 Maths solutions chapter 11 provides the student with hands-on experience on geometry box instruments and drawing some geometrical figure using it. Geometrical construction plays an essential role in engineering design. At Careers 360, highly skilled subject experts have prepared these NCERT exemplar Class 9 Maths chapter 11 solutions to develop an organised learning flow for the students practicing NCERT Class 9 Maths Book. These NCERT exemplar Class 9 Maths chapter 11 solutions develop a better understanding of the concept of construction as they are detailed and expressive. The syllabus put forward by CBSE for Class 9 has been incorporated in the NCERT exemplar Class 9 Maths solutions chapter 11.
Also, read - NCERT Solutions for Class 9 Maths
Question:1
With the help of a ruler and a compass, it is not possible to construct an angle of :
(A) (B) (C) (D)
Answer:
As we know that with the help of a ruler and a compass we can construct angles which are bisectors of other angles.Question:2
The construction of a triangle ABC, given that BC = 6 cm, is not possible when difference of AB and AC is equal to:
(A) 6.9 cm (B) 5.2 cm
(C) 5.0 cm (D) 4.0 cm
Answer:
(A) 6.9 cmQuestion:3
The construction of a triangle ABC, given that BC = 3 cm, is possible when difference of AB and AC is equal to :
(A) 3.2 cm (B) 3.1 cm
(C) 3 cm (D) 2.8 cm
Answer:
(D) 2.8 cmQuestion:1
Write True or False. Give reasons for your answer:
An angle of can be constructed.
Answer:
TrueQuestion:2
Write True or False. Give reasons for your answer:
An angle of can be constructed.
Answer:
FalseQuestion:3
Write True or False. Give reasons for your answer:
A triangle ABC can be constructed in which AB = 5 cm, and BC + AC = 5 cm.
Answer:
AnswerQuestion:4
Write True or False. Give reasons for your answer:
A triangle ABC can be constructed in which BC = 6 cm, and AC – AB = 4 cm.
Answer:
TrueQuestion:5
Write True or False. Give reasons for your answer:
A triangle ABC can be constructed in which and AB + BC + AC = 10 cm.
Answer:
FalseQuestion:6
Write True or False. Give reasons for your answer:
A triangle ABC can be constructed in which and AB + BC + AC = 12 cm.
Answer:
Given : , AB + BC + AC = 12 cm.Question:1
Draw an angle of with the help of a protractor and bisect it. Measure each angle.
Answer:
Question:2
Answer:
Question:3
Draw an angle of with the help of a protractor. Then construct angles of
(i) (ii) and (iii) .
Answer:
Question:4
Answer:
Question:5
Construct a triangle ABC in which BC = 5 cm, and AC + AB = 7.5 cm.
Answer:
Question:6
Construct a square of side 3 cm.
Answer:
Given : side = 3 cmQuestion:7
Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm.
Answer:
Given : adjacent sides are of lengths 5 cm and 3.5 cm.Question:8
Construct a rhombus whose side is of length 3.4 cm and one of its angles is .
Answer:
Given : Side = 3.4 cm, Angle =
Steps of Construction :
Question:1
Construct the following and give justification :
A triangle if its perimeter is 10.4 cm and two angles are and .
Answer:
Steps of Construction :Question:2
Construct the following and give justification :
A triangle PQR given that QR = 3cm, and QP – PR = 2 cm.
Answer:
Question:3
Construct the following and give justification :
A right triangle when one side is 3.5 cm and the sum of other sides and the hypotenuse is 5.5 cm.
Answer:
Given : Side = 3.5 cm, sum of other side and hypotenuse = 5.5 cmQuestion:4
Construct the following and give justification :
An equilateral triangle if its altitude is 3.2 cm.
Answer:
Given : An equilateral triangle with Altitude : 3.2 cmThe chapter on Constructions covers the following topics through NCERT exemplar Class 9 Maths solutions chapter 11::
These Class 9 Maths NCERT exemplar chapter 11 solutions provide a hands-on experience to students with geometrical instruments like scale, compass, protractor, et cetera. Geometrical construction is a compelling mathematical branch. However, it is not directly used in higher-level mathematics or engineering entrance examinations, but its knowledge will be instrumental in engineering design and architecture. Students of Class 9 can use these solutions as reference material to better study construction-based practice problems. These Class 9 Maths NCERT exemplar solutions chapter 11 Construction provides ample questions to understand the concept better and elaborate solutions to clarify the doubts.
NCERT exemplar Class 9 Maths solutions chapter 11 pdf download will be made available soon so that students can use NCERT exemplar Class 9 Maths solutions chapter 11 offline. Also, students can use the page download option.
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 |
No, we cannot draw a unique triangle by knowing only interior angles. We can draw similar triangles having same interior angles. Therefore, there will be multiple triangles having same interior angles.
Yes, we can divide any line segment in three equal parts by construction. For this refer NCERT exemplar Class 9 Maths solutions chapter 11 pdf download.
Yes, we can do that. From NCERT exemplar Class 9 Maths solutions chapter 11 pdf download, you can learn to draw angular bisector of any angle. Once you learn to draw angle bisector, then attempt drawing bisectors of these two half angles.
Thus, you will get four equal parts of any angle.
No, we cannot construct a triangle with the sides given. We know that some of two sides must be more than the third side in any triangle, which is not true in the given case.
Therefore, it is impossible to draw a triangle with these three sides
Generally, you can expect 1 question, which can be either long-short answer type or long answer-type question from Constructions in the final examination. NCERT exemplar Class 9 Maths solutions chapter 11 consists of a step-by-step solution to each construction problem, and a thorough understanding of these solutions can lead to higher marks in the examination.
Application Date:31 May,2024 - 15 June,2024
Application Date:31 May,2024 - 15 June,2024
Application Date:01 June,2024 - 15 June,2024
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