NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation 2021

NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation

Vishal kumarUpdated on 06 Dec 2025, 07:30 PM IST

Have you ever questioned why things never fail to fall on the ground or why some things float on water, yet others sink? Class 9 science chapter 10: Gravitation, makes you study these wonderful concepts. This chapter describes the mechanism of gravity and the distinction between mass and weight, as well as such concepts as free fall and buoyancy in a simple manner.

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NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation: MCQ
NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation: Short Answer
NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation: Long Answer
NCERT Exemplar Solutions Class 9 Science Chapter 10 Gravitation: Important Concepts and Formulas
Advantages of NCERT Exemplar Class 9 Science Chapter 10 Gravitation solutions
NCERT Class 9 Science Exemplar Solutions for Other Chapters:

NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation

To ensure that you understand these topics effectively, the NCERT Exemplar Solutions offers clear and reliable answers depending on the most recent CBSE syllabus. The answers to the 15 multiple-choice questions (MCQs), 7 short-answer questions, and 4 long-answer questions in the NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation are well explained. Taking these questions regularly enhances your problem-solving abilities, makes you get the concepts well and also be familiar with the exam-type questions. These are also the best examples in NCERT Exemplar Class 9 Solutions Science Chapter 10 Gravitation that can be revised after a very short period of time before your examinations, and are also very helpful in securing good grades in your Class 9 science exams.

NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation: MCQ

Chapter 10 Gravitation Multiple Choice Questions (MCQs) assist students in assessing their knowledge of concepts such as gravity, free fall, mass, weight, pressure, and buoyancy. The conceptual clarity and confidence in CBSE Class 9 Science tests are gained through practising these MCQs.

Question:1

Two objects of different masses falling freely near the surface of moon would
(a) have same velocities at any instant
(b) have different accelerations
(c) experience forces of the same magnitude
(d) undergo a change in their inertia

Answer: A

When a body is dropped near the surface of the Moon, it would be attracted by the Moon’s gravitational force.
The gravitational force on any body will be equal to the product of the mass of the body and the acceleration due to gravity on the Moon.
Two bodies of different masses will experience different forces on the moon.
However, their acceleration will be the same by using Newton’s second law,
$a=\frac{F}{M}$
As both bodies are starting from rest and have the same acceleration, their velocities at any instant will be the same.
v = u + at
u = 0 therefore, v = at.
Hence, the correct answer to this question will be option A.

Question:2

The value of acceleration due to gravity
(a) is same on equator and poles
(b) is least on poles
(c) is least on the equator
(d) increases from pole to equator

Answer:

Ans. C
By the universal law of gravitation, we know that the acceleration due to gravity will be inversely proportional to the square of the distance of a point from the centre of the Earth.
$F=\frac{Gm_{1}m_{2}}{r^{2}}$
The surface near the pole is closer to the centre of Earth than the distance between the centre of the Earth and the equatorial surface.
Therefore, the acceleration due to gravity will be minimum at the equator.
Due to the rotation of Earth, the acceleration of gravity further decreases at the surface of equator.
Hence, the correct answer to this question will be option C

Question:3

The gravitational force between two objects is F. If masses of both objects are halved without changing distance between them, then the gravitational force would become
(a) $\frac{F}{4}$
(b) $\frac{F}{2}$
(c) F
(d) 2 F

Answer:

Ans. A
By the universal law of gravitation, we know that the force between two particles kept at a fixed separation will be proportional to the product of their masses.
$F=\frac{Gm_{1}m_{2}}{r^{2}}\\ \Rightarrow F \propto \: m_{1}m_{2}$
If the masses of both the blocks are halved, then the net force of gravitation between them will become one-fourth of the original force.
Hence, the correct option for this question is option A.

Question:4

A boy is whirling a stone tied with a string in a horizontal circular path. If the string breaks, the stone
(a) will continue to move in the circular path
(b) will move along a straight line towards the centre of the circular path
(c) will move along a straight line tangential to the circular path
(d) will move along a straight line perpendicular to the circular path away from the boy

Answer:

Ans. C
If the boy is whirling a stone tied with a string in a horizontal circular path, the force of the string is changing the direction of velocity. This force is called the Centripetal force.
If the string breaks, there will be no force to change the direction of velocity.
Therefore, the particle will move on a straight line, tangent to the circle with the speed it had just before the breaking of the string.

Question:5

An object is put one by one in three liquids having different densities. The object floats with 1/9, 2/11 and 3/7 parts of their volumes outside the liquid surface in liquids of densities d₁, d₂ and d₃ respectively. Which of the following statement is correct?
(a) d₁ > d₂ > d₃
(b) d₁ > d₂ < d₃
(c) d₁< d₂ > d₃
(d) d₁< d₂ < d₃

Answer:

Ans. D
If an object is floating in liquid, that means the force of buoyancy is equal to the object's weight.
F_b=mg
The weight of the object in all three liquids will be the same; hence, the force of buoyancy by all three liquids will be the same.
The force of buoyancy in any liquid is equal to the weight of displaced fluid.
F_b=dV_g
Therefore, the weight of displaced fluid will be the same in all three cases.
The weight of displaced fluid will be proportional to the mass of displaced fluid.
Therefore, the mass of displaced liquid will be the same in all three cases.
We know that mass is equal to the product of density and volume of displaced liquid.
Therefore, density will be inversely proportional to displaced liquid volume.
In the first case, the displaced volume is the most, hence the density will be the least.
In the third case, the displaced volume is the least, hence density will be the most.
So, the correct option for this question is option D.

Question:6

In the relation $F= \frac{GmM}{d^{2}}$, the quantity G
(a) depends on the value of g at the place of observation
(b) is used only when the earth is one of the two masses
(c) is greatest at the surface of the earth
(d) is universal constant of nature

Answer:

D
According to the universal law of gravitation, gravitational force is proportional to the product of masses and inversely proportional to the square of the distance between them.
$F= \frac{Gm_{1}m_{2}}{r^{2}}$
G is the universal gravitational constant, which does not depend on any other physical quantity.
The correct answer is option D.

Question:7

Law of gravitation gives the gravitational force between
(a) the earth and a point mass only
(b) the earth and Sun only
(c) any two bodies having some mass
(d) two charged bodies only

Answer:

C
Gravitational force is a fundamental force, and it comes because of the property of mass.
According to Newton’s gravitational law, any two bodies having mass will attract each other by gravitational force.
Gravitational force is given as:
$F= \frac{Gm_{1}m_{2}}{r^{2}}$
Hence, the correct answer is option C

Question:8

The value of quantity G in the law of gravitation
(a) depends on mass of earth only
(b) depends on radius of earth only
(c) depends on both mass and radius of the earth
(d) is independent of mass and radius of the earth

Answer:

D Gravitational force is a fundamental force, and it comes because of the property of mass.
According to Newton’s gravitational law, any two bodies having mass will attract each other by gravitational force.
According to the universal law of gravitation, gravitational force is proportional to the product of masses and inversely proportional to the square of the distance between them.
Gravitational force is given as:
$F= \frac{Gm_{1}m_{2}}{r^{2}}$
G is the universal gravitational constant, which does not depend on any other physical quantity.
G is independent of the mass and radius of the Earth.
The correct answer to this question is option D.

Question:9

Two particles are placed at some distance. If the mass of each of the two particles is doubled, keeping the distance between them unchanged, the value of gravitational force between them will be
(a) $\frac{1}{4}$times (b) 4 times (c) $\frac{1}{2}$ times (d) unchanged

Answer:

B
By the universal law of gravitation, we know that the force between two particles kept at a fixed separation will be proportional to the product of their masses.
$F= \frac{Gm_{1}m_{2}}{r^{2}}\\ \Rightarrow F\: \propto \: m_{1}m_{2}$
If the masses of both blocks are doubled, then the net force of gravitation between them will become four times the original force.
Hence, the correct answer to this question is option B.

Question:10

The atmosphere is held to the earth by
(a) gravity
(b) wind
(c) clouds
(d) earth’s magnetic field

Answer:

A
The atmosphere around Earth has gases in it.
These gases have mass; hence, they are attracted by the gravitational force of Earth.
Gravitational force is given as:
$F= \frac{Gm_{1}m_{2}}{r^{2}}$
Therefore, we can say that the atmosphere is held to the Earth by its gravity.
The correct answer for this question is option A.

Question:11

The force of attraction between two unit point masses separated by a unit distance is called
(a) gravitational potential
(b) acceleration due to gravity
(c) gravitational field
(d) universal gravitational constant

Answer: D

By the universal law of gravitation, if two particles of mass m1 and m2 are kept at a separation, then the gravitational force between them will be given as:
$F= \frac{Gm_{1}m_{2}}{r^{2}}$
Here, G is the universal gravitational constant.
If both masses have unit values and their separation is also unit, then the magnitude of the force will be equal to the universal gravitational constant G.
$F= \frac{Gm_{1}m_{2}}{r^{2}}\\ $
if,$\;m_{1}=1;m_{2}=1;r=1;\\ F=G$
Hence, the correct answer to this question is option D.

Question:12

The weight of an object at the centre of the earth of radius R is
(a) zero
(b) infinite
(c) R times the weight at the surface of the Earth
(d) $\frac{1}{R^{2}}$ times the weight at surface of the earth

Answer: A

When we go towards the centre of the Earth from the surface, the acceleration due to gravity decreases.
Hence, the weight of any object decreases as we go towards the centre.
This decrease will be linear, and the weight of the body becomes zero at the centre of the Earth.
At the centre of the Earth, there will be no gravitational force.
Hence, the correct answer to this question is option A.

Question:13

An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be
(a) 2 N (b) 8 N (c) 10 N (d) 12 N

Answer: A

The weight of an object decreases when it is immersed in any fluid. This decrease in weight is caused due to buoyancy.
In any liquid, the apparent weight (decreased weight) is given as:
Apparent weight = weight in air - buoyancy force
The force of buoyancy is equal to the weight of displaced liquid.
$F_{b}=dVg$
The given question has an apparent weight equal to 8 kg, and the weight in air is equal to 10 kg.
Therefore, the weight of displaced liquid will be 2 kg.
Hence, the correct answer to this question is option A.

Question:14

A girl stands on a box having 60 cm length, 40 cm breadth and 20 cm width in three ways. In which of the following cases, pressure exerted by the brick will be
(a) maximum when length and breadth form the base
(b) maximum when breadth and width form the base
(c) maximum when width and length form the base
(d) the same in all the above three cases

Answer: B

The pressure is defined as the normal force per unit area.
The force applied by the box will be equal to the weight of the box in all orientations.
Therefore, the pressure exerted by it will be inversely proportional to the area.
To maximise the value of pressure, we have to decrease the surface area.
The least surface area will be in the case when breadth and width form the base.
The correct answer is option B.

Question:15

An apple falls from a tree because of gravitational attraction between the earth and apple. If F₁ is the magnitude of force exerted by the earth on the apple and F₂ is the magnitude of force exerted by apple on earth, then
(a) F₁ is very much greater than F₂
(b) F₂ is very much greater than F₁
(c) F₁ is only a little greater than F₂
(d) F₁ and F₂ are equal

Answer: D

Newton’s third law states that every action has an equal and opposite reaction.
If we assume gravitational attraction by Earth on the Apple as action, then Apple's gravitational attraction on the Earth will be the reaction.
As action and reaction have equal magnitude, therefore F₁and F₂ will have the same magnitude.
Hence, the correct answer to this question is option D

NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation: Short Answer

The NCERT Exemplar Chapter 10 Gravitation short-answer type questions aid the students to elaborate in concise but meaningful sentences. These questions enhance the power of logical thinking and the insight into the issues of buoyancy, the gravitational force, and free fall. Answering them frequently enhances performance in examinations.

Question:16

What is the source of centripetal force that a planet requires to revolve around the Sun? On what factors does that force depend?

Answer:

When any particle performs circular motion, the centripetal force is required to change the direction of the velocity.
This force always acts towards the centre of the circle.
The centripetal force that a planet requires to revolve around the sun is given by the gravitational force between the sun and the planet.
By the universal law of gravitation, this force will be proportional to the mass of the planet and inversely proportional to the square of the separation of the planet from the sun.
The gravitational force between them will be given as:
$F= \frac{Gm_{1}m_{2}}{r^{2}}$

Question:17

On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?

Answer:

The motion in the vertical direction will not be affected by horizontal motion.
If a stone is dropped or thrown horizontally, its initial vertical speed is zero in both cases.
Both of them will experience the same acceleration due to gravity.
Hence, they will take some time to reach the ground if they are thrown from the same height.

Question:18

Suppose gravity of earth suddenly becomes zero, then in which direction will the moon begin to move if no other celestial body affects it?

Answer:

The moon revolves around the Earth.
To revolve, it requires a centripetal force, which is given by Earth’s gravitational force.
If the gravity of Earth suddenly disappeared, the force on the Moon would become zero.
In the presence of zero force, the moon will continue moving in a straight line with the same speed.
It can be understood by Newton’s first law:
“In the absence of any force, the body will move on straight with constant speed, if it is not at rest.”

Question:19

Identical packets are dropped from two aeroplanes, one above the equator and the other above the North Pole, both at height h. Assuming all conditions are identical, will those packets take same time to reach the surface of earth. Justify your answer

Answer:

The value of gravity near the equator is less than the value of gravity near the pole.
Two packets are dropped from two aeroplanes, with identical conditions from the pole and the equator.
The time to reach the surface will be inversely proportional to the square root of acceleration, which means more acceleration ensures lesser time.
Therefore, the packet near the pole will take less time.

Question:20

The weight of any person on the moon is about 1/6 times that on the earth. He can lift a mass of 15 kg on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

Answer:

It is given that the weight of any person on the moon is about 1/6^th that on Earth.
It means, acceleration due to gravity is also 1/6th on the Moon in comparison with Earth.
A person has to apply a force equal to the weight of any body to hold it.
As the gravity becomes 1/6 on the moon, its mass must be six times for the same weight.
F = mg
Therefore, the man can lift 90 kg on the surface of the Moon if he can hold 15 kg on Earth.

Question:21

Calculate the average density of the earth in terms of g, G and R.

Answer:

The weight of an object is nothing but the gravitational force of the Earth on that body.
By the universal law of gravitation, if two particles of mass m1 and m2 are kept at a separation, then the gravitational force between them will be given as:
$F= \frac{Gm_{1}m_{2}}{r^{2}}$
The weight is generally given as mg, therefore:
$mg= \frac{GM_{e}m}{R_{e}^{2}}\\ \Rightarrow g= \frac{GM_{e}}{R_{e}^{2}}\\$
If the density of Earth is d, its mass can be calculated by using the fact: mass is the product of density and volume.
$M_{e}=d \times \frac{4\pi\left ( R_{e} \right )^{3} }{3}$
By putting the value of mass:
$\begin{aligned} \Rightarrow & g=\frac{G}{R_e^2}\left(d \times \frac{4 \pi\left(R_e\right)^3}{3}\right) \\ \Rightarrow & g=\frac{G}{1}\left(d \times \frac{4 \pi\left(R_e\right)}{3}\right) \\ \Rightarrow & g=\frac{4 \pi d G\left(R_e\right)}{3} \\ \Rightarrow & d=\frac{3 g}{4 \pi G\left(R_e\right)}\end{aligned}$

Question:22

The earth is acted upon by gravitation of Sun, even though it does not fall into the Sun. Why?

Answer:

The Earth is acted upon by the gravitation force of the Sun; this gravitational force provides the needed centripetal force to the Earth.
Centripetal force is required to change the direction of the velocity of the Earth.
Because of this force, the Earth maintains its separation from the Sun; otherwise, it would move in a straight line tangent to the current orbit.
The gravitational pull of the sun forbids Earth from moving away from it.

NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation: Long Answer

These long-answer questions in Chapter 10, Gravitation, provide more detailed explanations, derivations and real-life examples. By practising them, you will strengthen your conceptual knowledge and improve the skills of answering descriptive questions in the final exam.

Question:23

How does the weight of an object vary with respect to mass and radius of the earth? In a hypothetical case, if the diameter of the earth becomes half of its present value and its mass becomes four times of its present value, then how would the weight of any object on the surface of the earth be affected?

Answer:

The weight of an object is nothing but the gravitational force of Earth on that body.
By the universal law of gravitation, if two particles of mass m1 and m2 are kept at a separation, then the gravitational force between them will be given as:
$F= \frac{Gm_{1}m_{2}}{r^{2}}$
The weight is generally given as mg; therefore,
$mg= \frac{GM_{e}m}{R_{e}^{2}}\\ \Rightarrow g=\frac{GM_{e}}{R_{e}^{2}}$
If we change the mass of Earth and its radius (Diameter), the value of g changes; hence, the weight of the object changes.
$\Rightarrow g=\frac{GM_{e}}{R_{e}^{2}}$
The new value of g will be:
$\begin{aligned} \Rightarrow & g^{\prime}=\frac{G 4 M_e}{\left(\frac{R_c}{2}\right)^2} \\ \Rightarrow & g^{\prime}=\frac{16 G M_e}{R_e^2} \\ \Rightarrow & g^{\prime}=16 g\end{aligned}$
Therefore, the weight of the body will be sixteen times.

Question:24

How does the force of attraction between the two bodies depend upon their masses and distance between them? A student thought that two bricks tied together would fall faster than a single one under the action of gravity. Do you agree with his hypothesis or not? Comment.

Answer:

By the universal law of gravitation, we know that the force between two particles kept at a fixed separation will be proportional to the product of their masses.
$F= \frac{Gm_{1}m_{2}}{r^{2}} \\ \Rightarrow F\: \propto \: m_{1}m_{2}\\ \Rightarrow F\: \propto \: \frac{1}{r^{2}}$
The weight of an object is nothing but the gravitational force of Earth on that body.

The weight is generally given as mg, therefore,
$mg= \frac{GM_{e}m}{R_{e}^{2}}\\ \Rightarrow g=\frac{GM_{e}}{R_{e}^{2}}$
Hence, the acceleration due to gravity does not depend on the mass of the object.
Whether you drop a single body or two bodies tied with a string, their acceleration under gravity will be the same in free fall.
Therefore, they will take the same time to reach the ground.
Hence, the hypothesis is wrong.

Question:25

Two objects of masses m₁ and m₂ having the same size are dropped simultaneously from heights h₁ and h₂ respectively. Find out the ratio of time they would take in reaching the ground. Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid and (ii) both of them are hollow, size remaining the same in each case? Give reason.

Answer:

The weight of an object is nothing but the gravitational force of Earth on that body.
The weight is generally given as mg, therefore,
$mg= \frac{GM_{e}m}{R_{e}^{2}}\\ \Rightarrow g=\frac{GM_{e}}{R_{e}^{2}}$
Hence, the acceleration due to gravity does not depend on the mass of the object.
If we neglect the friction force of air, mass does not depend on size either.
Whether you drop a solid body or a hollow body, their acceleration under gravity will be the same in free fall.
Therefore, they will take the same time to reach the ground.
The time to fall can be calculated using by equation of motion.
$s=ut+\frac{1}{2}at^{2}$
$ \Rightarrow h=0t+\frac{1}{2}gt^{2}$
$\Rightarrow t=\sqrt{\frac{2h}{g}}$
For the given objects, time will be:
$\Rightarrow t_{1}=\sqrt{\frac{2h_{1}}{g}}\; \; and\; \; t_{2}=\sqrt{\frac{2h_{2}}{g}}$
$\Rightarrow \frac{t_{1}}{t_{2}}=\sqrt{\frac{h_{1}}{h_2}}\;$
The ratio will not change in either case because acceleration will remain the same. In the case of free-fall, acceleration does not depend upon the mass and size of the body

Question:26

(a) A cube of side 5 cm is immersed in water and then in saturated salt solution. In which case will it experience a greater buoyant force? If each side of the cube is reduced to 4 cm and then immersed in water, what will be the effect on the buoyant force experienced by the cube as compared to the first case for water? Give reason for each case.
(b) A ball weighing 4 kg of density 4000 kgm^-3 is completely immersed in water of density 1000 kgm^-3 .Find the force of buoyancy on it.

Answer:

(a) Force of buoyancy in any liquid is equal to the weight of displaced fluid.
$F_{b}=dVg$
As the cube is completely immersed, the displaced volume will be equal to the volume of the cube.
In both cases, volume and acceleration due to gravity are the same.
The force of buoyancy will be affected only by density.
The density of the saline solution will be more than the density of water, hence the force in water will be less.
If we change the side length of a cube, its volume will change.
The force of buoyancy will be changed in the same ratio as of volume.
Old volume = (5cm)³ = 125cm³
New volume = (4cm)³= 64cm³
Hence, the new force will be 64/125 times of old buoyancy force.
(b) Force of buoyancy in any liquid is equal to the weight of displaced fluid.
$F_{b}=dVg$
As the density of the solid is more than the density of water, it will sink in it. Therefore, the displaced volume will be equal to the volume of the solid.
We know that mass is the product of density and volume.

$\begin{gathered}
M=d \times V \\
V=\frac{M}{d}=\frac{4}{4000} m^3
\end{gathered}$

Now, we know the displaced volume, we can calculate the force of buoyancy.

$\begin{aligned}
& F_b=d V g \\
& \text { where } V=\frac{4}{4000} m^3 \\
& \Rightarrow F_b=1000 \times \frac{4}{4000} \times 10=10 \mathrm{~N}
\end{aligned}$

NCERT Exemplar Solutions Class 9 Science Chapter 10 Gravitation: Important Concepts and Formulas

The chapter Gravitation assists the student to learn about the way objects attract one another because of the force of gravity and the reason why everything falls down on the Earth. Mass, weight, free fall, buoyancy, and the universal law of gravitation are some of the main concepts taught to students in this topic. The numerical questions will require one to comprehend and memorise the formulas and concepts well. These are the main key concepts which are the foundation for higher classes and competitive exams.

1. Universal Law of Gravitation

Every object in the universe attracts every other object.
Formula:

$
F=\frac{G m_1 m_2}{r^2}
$

where
$F=$ gravitational force
$G=$ universal gravitational constant $\left(6.67 \times 10^{-11} \mathrm{Nm}^2 / \mathrm{kg}^2\right)$
$m_1, m_2=$ masses of objects
$r=$ distance between centers of the two objects

2. Acceleration Due to Gravity (g)

It is the acceleration produced in a body due to Earth's gravitational pull.
Formula:

$
g=\frac{G M}{R^2}
$

where
$M=$ mass of Earth
$R=$ radius of Earth

Standard value: $g=9.8 \mathrm{~m} / \mathrm{s}^2$

3. Relation Between Mass and Weight

Mass (m): Quantity of matter in a body (constant).
Weight (W): Force with which Earth attracts an object.
Formula:

$
W=m g
$

4. Free Fall

When an object falls only under gravity, it is called free fall.
Velocity during free fall:

$
v=u+g t
$

Distance travelled:

$
s=u t+\frac{1}{2} g t^2
$

5. Equation for Density

Density measures how compact matter is.
Formula:

$
\text { Density }=\frac{\text { Mass }}{\text { Volume }}=\frac{m}{V}
$

6. Buoyant Force

When an object is immersed in a fluid, it experiences an upward force called the buoyant force.
It depends on the volume of fluid displaced.

7. Archimedes’ Principle

When a body is immersed in a fluid, it loses weight equal to the fluid displaced by it.

8. Pressure in Fluids

Pressure at a depth in a fluid depends on density and depth.
Formula:

$
P=h \rho g
$

where
$h=$ depth
$\rho=$ density of liquid
$g$ = acceleration due to gravity

Advantages of NCERT Exemplar Class 9 Science Chapter 10 Gravitation solutions

The NCERT Exemplar Solutions Class 9 Chapter 10 Gravitation provides the students with a clear explanation of complex concepts such as the gravitational force, buoyancy and the phenomenon of the free fall. These solutions enhance the conceptual knowledge and problem-solving ability. They are also used to aid the students to familiarise themselves with the pattern of examination, as well as enhancing confidence in board and school-level examinations.

Students acquire a more profound insight into such significant concepts as mass, weight, buoyancy, and density.
Assists in enhancing accuracy and speed in solving numerical problems connected with Gravitation.
Exposes to a range of question types that are typically used in exams at school.
Solutions are best to revise because they simplify the main concepts in a simple-to-follow form.
Enhances confidence through the step-by-step provision of answers to all forms of questions, such as MCQs, short and long questions.

NCERT Class 9 Exemplar Solutions for Other Subjects:

NCERT Class 9 Science Exemplar Solutions for Other Chapters:

NCERT Class 9 Science Exemplar Solutions for other chapters provide well-structured, high-quality practice material designed to strengthen conceptual understanding and analytical skills. These solutions assist students in solving application-based and higher-level questions that usually emerge in competitive and school examinations. They simplify the complex topics by providing straightforward explanations and logical ways of learning, thus making it easier to revise.

Chapter-wise solutions

Chapter 1 Matter in our Surroundings

Chapter 2 Is Matter Around Us Pure?

Chapter 3 Atoms and Molecules

Chapter 4 Structure of the Atom

Chapter 5 The Fundamental Unit of Life

Chapter 6 Tissues

Chapter 7 Diversity in Living Organisms

Chapter 8 Motion

Chapter 9 Forces and Laws of Motion

Chapter 11 Work and Energy

Chapter 12 Sound

Chapter 13 Why do We Fall ill?

Chapter 14 Natural Resources

Chapter 15 Improvement in Food Resource

Also, read - NCERT Solutions for Class 9

Check the Solutions of Questions Given in the Book

Chapter No.	Chapter Name
Chapter 1	Matter in Our Surroundings
Chapter 2	Is Matter Around Us Pure
Chapter 3	Atoms and Molecules
Chapter 4	Structure of The Atom
Chapter 5	The Fundamental Unit of Life
Chapter 6	Tissues
Chapter 7	Motion
Chapter 8	Force and Laws of Motion
Chapter 9	Gravitation
Chapter 10	Work and Energy
Chapter 11	Sound
Chapter 12	Improvement in Food Resources

Also, Read the NCERT Solution Subject Wise

Check NCERT Notes Subject Wise

Also, check NCERT Books and NCERT Syllabus here

Frequently Asked Questions (FAQs)

Q: Where can I find NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation with answers?

You can get detailed and step-by-step Gravitation Class 9 NCERT Exemplar Solutions from Careers360 NCERT Exemplar Class 9 Science Solutions Chapter 10 Gravitation PAGE. These solutions include MCQs, short answers, long answers, and numericals explained as per the CBSE syllabus.

Q: What type of questions are covered in Class 9 Science Exemplar Chapter 10 Gravitation?

The Class 9 Science Exemplar Chapter 10 Gravitation includes multiple-choice questions (MCQs), short answer questions, long answer questions, and numerical problems to help students practice different types of questions asked in exams.

Q: What is the Universal Law of Gravitation?

It states that every object in the universe attracts every other object with a force directly proportional to their masses and inversely proportional to the square of the distance between them.

Q: Why do objects fall towards the Earth?

Due to Earth’s gravitational pull acting on them.

Q: Why should I practice Gravitation Class 9 Extra Questions and Numericals?

Practising Gravitation Class 9 Extra Questions and Numericals helps you understand key topics like universal law of gravitation, free fall, and buoyancy better. It also improves your problem-solving skills for school exams and competitive tests.

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