Have you ever wondered why a football would run faster when you kick it, why it would run slower gradually or how a car can alter its direction when you turn the steering wheel? All these observations in daily life are discussed in Chapter 8 of Science Class 9 - Force and Laws of Motion, which is the first to present students with the basics of force, motion, and laws of Newton. The chapter provides the background of mechanics and assists the students in correlating the classroom material with real-life experiences.
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NCERT Solutions for Class 9 Science Chapter 8 - Force and Laws of Motion offer well-structured, correct and step-by-step solutions that are set out by subject experts. The solutions simplify, make learning fast and exam-oriented, so that students can enhance their theoretical and numerical problem-solving ability. In-text Question, Exercise Question, HOTS (Higher Order Thinking Skills) and problem-based on application will also be covered and all the answers will be in accordance with the latest CBSE syllabus and exam pattern (2025-26). Using these NCERT Solutions for Class 9 Science Chapter 8 - Force and Laws of Motion, the students will be able to conceptualize the First, Second and Third Laws of Motion as stated by Newton with examples, learn good problem solving skills, doing derivations and numericals, make fast and brief revisions using brief explanations and diagrams, use science to solve real world problems to memorize better. With Force and Laws of Motion NCERT Solutions, students would be able to study the subject well, prevent errors and score more points in exams, as well as establish a good foundation to further education and competitive examinations.
The Class 9 Science Chapter 8 - Force and Laws of Motion question answers provide a well-organised step-by-step solution to all questions of the textbook, and students find it easy to understand the laws of Newton and how to apply them in real-life situations. These solutions are created by the same experts in the subject as in accordance with the current CBSE syllabus, which makes them very useful in preparing exams, in doing daily homework and in a quick revision. Through these solutions, students would be in a position to reinforce their knowledge of the vital concepts of force, inertia, momentum, and the three laws of motion, thus performing better on exams. To be able to study at any time, anywhere, you will find it more convenient to download the free PDF of Force and Laws of Motion Class 9 question answers.
The Force and Laws of Motion NCERT Solutions (In-text Questions) will give proper and in-depth responses to all questions inquired in the textbook. These are solutions to make students grasp vital ideas such as the laws of motion, force, inertia and momentum of Newton in a straightforward and ordered manner. These in-text question answers allow the students to enhance their conceptual clarity, enhance their skills of solving problems and be in a good position to pass exams.
Q1. Which of the following has more inertia:
(a) a rubber ball and a stone of the same size?
(c) a five-rupee coin and a one-rupee coin?
Answer:
We know that inertia is defined by the mass of the body. So the body has more mass/weight will have more inertia.
(a) In the case of a rubber ball and a stone of the same size, the stone will have greater mass, so its inertia will be greater compared to a rubber ball.
(b) The train has much more mass as compared to the bicycle, so the inertia of the train is larger.
(c) A five-rupee coin has more weight than a rupee coin, so the inertia of five five-rupee coins is more.
Q2. In the following example, try to identify the number of times the velocity of the ball changes:
Also, identify the agent supplying the force in each case.
Answer:
Velocity has both magnitude and direction. Thus change in any of the magnitude or direction results in a change in velocity.
In the given case, when the player kicks the ball to another player, the direction of the ball is changed, thus the velocity is changed.
The second player then pushes the ball in a forward direction, sothe velocity changes. Then the goalkeeper brings the ball to rest, hence velocity changes (magnitude is changed). After that, he kicks the ball, thus increasing the speed and direction is opposite, hence the velocity changes again.
The agent of the supplying force is the 1st player, the 2nd player, goalkeeper, respectively.
Q3. Explain why some of the leaves may get detached from a tree if we vigorously shake its branch.
Answer:
This can be explained with the help of the concept of inertia. When the tree is at rest, its leaves are also at rest. But when we bring the tree in motion by means of shaking it, due to the inertia of the leaves, they still tend to be at rest. Thus force is acting on leaves vigorously with a changing direction rapidly. This results in the detachment of leaves from the tree.
Answer:
In the situation of a moving bus, the passengers are also in motion along with the bus. Now, when the brakes are applied, the bus comes to rest, but due to the inertia of the passengers, they still tend to move in the forward direction. Thus, they move in the forward direction after applying the brakes.
Now that the bus is resting, the passengers are also at rest. The inertia tends them to be at rest. That's why when the bus accelerates, they move in a backwards direction.
Q1. If action is always equal to the reaction, explain how a horse can pull a cart.
Answer:
For motion, the horse applies force on the ground, and thus the frictional force of the ground pushes the horse forward (action-reaction pair). Thus horse applies force on the cart and the cart applies backwards force on the hors,e but due to an unbalanced force, the horse moves in the forward direction.
Answer:
This can be explained with the help of Newton's third law of motion (action-reaction pair). When the velocity of water is more i.e., water is coming out with a higher force thus the reaction force on the hose is also large. This makes it difficult for a fireman to hold the hose.
Answer:
Here we will use conservation of momentum :
Initial momentum of system ( rifle + bullet ) = Final momentum of system
or
or
or
The negative sign shows that the velocity is opposite to that of the bullet. This is because the force on the rifle will be opposite to the bullet (action-reaction pair).
Answer:
In this question, we will use conservation of momentum :
Initial momentum = Final momentum
or
or
or
Hence, the required velocity is 1.165 m/s.
The exercise questions that are answered at the end of this chapter facilitate students in realising how the laws of Newton's motion, conservation of momentum, and effects of force can be applied in a single clear way. These solutions empower the problem-solving capabilities and also adequately prepare students towards examinations.
Answer:
When a net zero external unbalanced force is applied and the object is in motion, then there will be a condition in which its motion is unopposed by any external force. Then, as a result object will continue to remain in motion. The velocity, in this case, will be constant and in a particular direction.
Q 2. When a carpet is beaten with a stick, dust comes out of it. Explain.
Answer:
During beating the carpet, we bring it into motion. But the dust particles have a tendency to be at rest, so they resist the motion. This is why they come out of the carpet. The factor responsible for this is inertia.
Q 3. Why is it advised to tie any luggage kept on the roof of a bus with a rope?
Answer:
This is because the luggage has some mass, so the inertia. When the bus is in motion, the luggage is also in motion. But when the bus stops suddenly, the luggage still tends to move with the same velocity due to inertia. Thus, it may fall down. Similarly, when the bus starts from rest, the luggage tends to be at rest thus it is pushed in a backward direction.
(a) the batsman did not hit the ball hard enough.
(b) velocity is proportional to the force exerted on the ball.
(c) there is a force on the ball opposing the motion.
(d) there is no unbalanced force on the ball, so the ball would want to come to rest
Answer:
The frictional force present between the ground and the ball acts in the opposite direction to the motion of the ball. Thus, balls stop after travelling a few distances.
Hence option (c) is correct.
Answer:
From the equations of motion, we can write :
or
or
And the force acting on the truck is given by :
Answer:
By the equation of motion, we know that,
or
or
The acceleration is negative. This implies that the force is opposing the motion.
The force is given by :
or
Hence, the frictional force between the stone and the ice is 4 N.
Answer:
The net accelerating force is given by :
Net accelerating force = Force by engine - Frictional force
Answer:
We know that the force is given by :
or
or
Thus acceleration of the train is
Answer:
By Newton's law of motion, we have :
and
or
Thus the retarding force required is 2550 N in the direction opposite to the motion of the vehicle
Q 9. What is the momentum of an object of mass m, moving with a velocity v?
Answer:
We know that the momentum of a body is given by:-
Momentum = Mass
Thus we have :
Hence option (d) is correct.
Answer:
By Newton's third law, it is clear that the frictional force acting on the cabinet will be 200 N. (Note that the limit of frictional force depends upon the mass of the body and the coefficient of friction between the bodies. So it might be possible that if the frictional force acting is less than 200 N.
Answer :
The student is correct. The force applied by him is less than the static friction present between the tyres of the truck and the road (as the mass of the truck is large, thus the frictional force is also high). Thus the force applied by the student is balanced by the static frictional force, which is the action-reaction pair.
Answer:
The change in the momentum is given by :
or
or
In the above equation, we have taken
Answer:
By the equation of motion we know that:-
Putting values of v, u and t in the equation :
or
or
Now we have :
or
or
Hence the distance of penetration of the bullet in the block is 2.25 m.
Now, for the force we have :
or
Thus the retarding force acting on the bullet is 50 N.
Answer:
For calculating the velocity of the combined mass, we need to use the law of conservation of momentum.
or
or
or
Now, the momentum before the collision is :
or
By momentum conservation, the final momentum is also
Answer:
The momentum is given by :
Initial momentum is :
And the final momentum is :
Also, the force is defined as rate of change of momentum.
Thus
or
Hence the force exerted on the body is 50 N.
Answer:
Kiran’s observation:- The insect experiences a greater change in its velocity as the mass of the insect is much less compared to the motorcar, so it experiences a greater change in its momentum. Thus Kiran's observation is correct.
Akhtar’s observation:- We know that a motorcar has a larger velocity and has a bigger mass as compared to the insect. Also, the motorcar continues to move in the same direction even after the collision. This suggests that the change in momentum of a motorcar is very less, whereas the insect experiences a great change in its momentum.
Rahul’s observation:- The momentum gained by the insect is equal to the momentum lost by the motorcar (law of conservation of momentum). Thus his observation is also correct.
Answer :
For calculating momentum, we need the final velocity of the bell.
By equation of motion we can write :
or
or
Thus the momentum is :
or
The additional exercises that have been solved offer additional practice with Newton's laws, inertia, momentum, and balanced-unbalanced forces, and students find additional conceptual understanding. The solutions improve with the application of analytical thinking and confidence to solve higher-level questions in the exams.
Time in seconds | Distance in metre |
0 | 0 |
1 | 1 |
2 | 8 |
3 | 27 |
4 | 64 |
5 | 125 |
6 | 216 |
7 | 343 |
Answer:
From the table, the relation between time and distance can be seen.
Thus the velocity of the particle is increasing with time.
and
Hence acceleration increases linearly with time.
Time in seconds | Distance in metre |
0 | 0 |
1 | 1 |
2 | 8 |
3 | 27 |
4 | 64 |
5 | 125 |
6 | 216 |
7 | 343 |
Answer:
i)Velocity is the change in distance with time. So the velocity is increasing non uniformly, so the acceleration increases with time.
ii) Thus, the net force acting on the body is also increasing.
Answer:
From the question, it is clear that two people push the car with constant velocity. But when the third person pushes, it has some acceleration. Thus, the third person is responsible for the acceleration generated.
Force by the third person is given by :
Hence the force from each man is 240 N.
Answer:
Thus, the force is given by :
or
The negative sign implies that the force of the nail on the hammer is in the opposite direction.
Answer:
The initial and final velocities are :
and
Using the equation of motion, we can write :
or
or
Now the force is given by :
or
And the change in momentum is:
or
The Force and Laws of Motion NCERT Solutions (HOTS Questions) is created to improve the level of analysis and reasoning and is not limited to the simplistic textbook-problems. These questions of Higher Order Thinking Skills will ask students to use the laws of Newton and the concept of force in real-life scenarios and complex cases. Such HOTS questions will assist the learners to think critically, understand the chapter better, and score better during the exams.
Q1:
The pulleys and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle θ should be
Answer:
For block A,
For block B, T-mg=m(o)
(Since both the A and B blocks are similar and the tension in the strings is mg. It has zero acceleration, as the system is in equilibrium.
Q2:
The figure shows the displacement of a particle going along the X−axis as a function of time. The force acting on the particle is zero in the region
Answer:
In the given displacement-time graph, in regions AB and CD, the graph is linear i.e. velocity (slope) is uniform i.e., constant, and we know that acceleration = change in velocity/time. Since velocity is constant, so change in velocity is 0, and acceleration is 0.
From Newton's second law of motion,
And F = m × a = 0
Q3:
Two particles of mass m each are tied at the ends of a light string of length 2a. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance a from the centre P (as shown in the figure). Now, the midpoint of the string is pulled vertically upwards with a small but constant force F. As a result, the particles move towards each other on the surface. Neglecting the earth's gravitation, the magnitude of acceleration, when the separation between them becomes 2x, is :
Answer:
The acceleration of mass m is due to the force
From(i)and(ii)
Q4:
There are cars with masses of 4 kg and 10 kg, respectively, that are at rest. A car having a mass of 10 kg moves towards the east with a velocity of 5 m/s. Find the velocity of the car with a mass of 4 kg with respect to the ground.
Answer:
Given,
m1 = 4 kg
m2 = 10 kg
v1 = ?
v2 = 5 m.s-1
We know from the law of conservation of momentum that,
pinitial = 0, as the cars are at rest
pfinal = p1 + p2
pfinal = m1.v1 + m2.v2
pfinal = 4 kg.v1 + 10 kg.5 m.s-1
pi = pf
0=4 kg.v1+50 kg.m.s-1
v1 = 12.5 m.s-1
Q5:
A body of mass 300g kept at rest breaks into two parts due to internal forces. One part of mass 200 g is found to move at a speed of 12 m/s towards the east. What will be the velocity of the other part?
Answer: Before it broke, the body was at rest. The linear momentum of the body was thus
Force and Laws of Motion cover all the key topics that explain how forces affect the motion of objects, including Newton’s laws, inertia, and momentum. These topics form the foundation of classical mechanics and are essential for understanding real-world motion.
8.1 Balanced And Unbalanced Forces
8.2 First Law of Motion
8.3 Inertia And Mass
8.4 Second Law of Motion
8.4.1 Mathematical Formulation of the Second Law of Motion
8.5 Third Law of Motion
This chapter highlights the key formulas based on Force and Newton’s Laws of Motion, making it easier for students to solve numerical problems accurately. These formulas act as quick revision tools and help in building a strong foundation for higher-level physics concepts.
Where:
Where:
Where:
Class 9 Science Chapter 8 - Force and Laws of Motion describes the action of forces on the movement of objects as per Newton's laws of motion. The key elements that students should work on to effectively solve problems in this chapter include the development of a solid conceptual foundation, knowledge of real-life applications, and proper application of formulas. A systematic approach guarantees that both theory-based and numerical problems are clear in assisting students to perform well in exams.
NCERT Solutions of Class 9 Science have been organised and divided answers in chapters and assist the students in enhancing their knowledge of the key concepts in Physics, Chemistry, and Biology. These solutions, created according to the most recent CBSE syllabus, will include in-text questions, exercises, and numericals, as well as HOTS, which will allow for making the exam preparation more organised and efficient. They can be used as a sure source of revision, homework, and competitive exam preparation with detailed descriptions and step-by-step solutions.
Frequently Asked Questions (FAQs)
The study of force enables us to understand why and how things move or remain stationary. It's the basis for the study of motion and mechanics.
Due to its high inertia. Heavy bodies resist motion changes more than light bodies.
Equilibrium in forces results in no change in the movement of an object, but unbalanced forces result in a change in movement or direction.
Due to inertia, the lower body which is in contact with the bus does not move anymore, but the upper body still shows signs of movement, and the person finds himself falling forward.
Yes, if it was already uniformly moving, it will keep on moving with the same velocity. Equilibrium forces do not produce acceleration.
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