NCERT Solutions For Class 9 Science Chapter 5 The Fundamental Unit Of Life

NCERT Solutions For Class 9 Science Chapter 5 The Fundamental Unit Of Life

Edited By Irshad Anwar | Updated on Oct 06, 2023 08:58 PM IST

Chapter 5: Fundamental Unit Of Life | NCERT 9 Science Solutions PDF

NCERT Solutions for Class 9 Science Chapter 5 The Fundamental Unit of Life: In this article, you will learn that most mature plant cells have a large central vacuole that helps to maintain the turgidity of the cell and stores important substances, including wastes. NCERT Solutions for Class 9 are regularly updated according to the latest CBSE Board Syllabus (2023–24). The CBSE NCERT Solutions for Class 9 Science Chapter 5 The Fundamental Unit of Life, contain questions and solutions to all the topics and exercises mentioned in the chapter. The NCERT Solutions aim to help you solve difficult questions.

This Story also Contains
  1. Chapter 5: Fundamental Unit Of Life | NCERT 9 Science Solutions PDF
  2. The Fundamental Unit Of Life Class 9 Questions And Answers: Solved Exercise Solutions
  3. Science Class 9 Chapter 5: Important Formulas and Diagrams + eBook link

Through The Fundamental Unit Of Life Class 9, you will also get to know that Prokaryotic cells have no membrane-bound organelles, their chromosomes are composed of only nucleic acid, and they have only very small ribosomes as organelles. Cells in organisms divide for the growth of the body, for replacing dead cells, and for forming gametes for reproduction. Students can learn everything they need to know about the cell with NCERT Solutions for Class 9 Science Chapter 5. If you have any problems answering the questions or are not getting the correct answers, don't worry; Solutions for Class 9 Science Chapter 5 The Fundamental Unit of Life is there to help. It will give you solutions to all the questions that are mentioned in the NCERT Textbook.

NCERT Solutions for Class 9 Science are given below. Download The Fundamental Unit of Life Class 9 PDF for a better experience.

NCERT Solutions for Class 9 Science Chapter 5 – The Fundamental Unit of Life : Download PDF

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Class 9 Science Chapter 5 Question Answer : Solved In-text Questions

The Fundamental Unit of Life Class 9 questions and answers are explained in best possible way:

NCERT Class 9 Science Chapter 5 Question Answer: Topic 5.1 - What are Living Organisms made up of?

Q. 1. Who discovered cells, and how?

Answer:

Cells were discovered in 1665 by Robert Hooke. He was examining a thin slice of cork using a primitive microscope designed by himself. He saw that the structure of the cork at a microscopic level is similar to that of a honeycomb. It had several small chambers like those in a honeycomb.

These small chambers were termed as cells.

Q. 2. Why is the cell called the structural and functional unit of life?

Answer:

The cell is called the structural and functional unit of life as it is the smallest living unit which can carry out all the living processes essential for living.

Topic 5.2 What is a cell made up of? What is the structural organization of the cell?

Q. 1. How do substances like CO_{2} and water move in and out of the cell? Discuss

Answer:

CO 2 and water move in and out of the cell through the cell membrane by the process of diffusion and osmosis respectively.

Q. 2. Why is the plasma membrane called a selectively permeable membrane?

Answer:

The plasma membrane called a selectively permeable membrane because it relatively allows the movement of substances from the inside of the cell to the outside and vice-versa.

This selectivity depends on the requirements of the cell and the substances present in the surroundings of the cell.

Solutions for NCERT for Class 9 Chapter 5 The Fundamental Unit of Life

Topic 5.2.2 Cell Wall

Q. 1. Fill in the gaps in the following table illustrating differences between prokaryotic and eukaryotic cells.

Prokaryotic CellEukaryotic Cell
Size: Generally small (1-10μm)
1μm=10-6m
Size: Generally large (5-100μm)
Nuclear region: ..................................
.......................and known as......
Nuclear region: well defined and surrounded by a nuclear membrane
Chromosome: singleMore than one chromosome
Membrane-bound cell organelles absent...................................................................
...............................................................
....................................

Answer:

Prokaryotic Cell Eukaryotic Cell
1. Size generally small. 1. Size generally large.
2. Nuclear Region: Poorly defined because of the absence of cell membranes and is called the nucleoid. 2. Nuclear Region: Well defined and surrounded by a nuclear membrane.
3. Chromosome: single. 3. More than one chromosome.
4. Membrane-bound cells organelles present 4. Membrane-bound cell organelles absent.

CBSE NCERT solutions for class 9 science chapter 5 The fundamental unit of life

Topic 5.2 What is a cell made up of? What is the structural organization of the cell?

Q. 1. Can you name the two organelles we have studied that contain their own genetic material?

Answer:

Two organelles which contain their own genetic material are

1. Mitochondria

2. Plastids

Q. 2. If the organisation of a cell is destroyed due to some physical or chemical influence, what will happen?

Answer:

If the organisation of a cell is destroyed due to some physical or chemical influence it will not be able to perform the life processes essential for living and therefore would be digested by lysozymes.

Q. 3. Why are lysosomes known as suicide bags?

Answer:

When the cells are damaged to such an extent that they are incapable of performing certain functions which are essentials for survival, the organism tries to get rid of these cells.

For this function, the lysosomes which are membrane-bound organelles burst and release digestive enzymes called lysozymes which destruct the cell and lysosomes are therefore called suicide bags.

Q. 4. Where are proteins synthesized inside the cell?

Answer:

Inside the cells, the proteins are synthesized at sites called ribosomes.

These are very small structures made up of ribonucleic acids and proteins.

The Fundamental Unit Of Life Class 9 Questions And Answers: Solved Exercise Solutions

Class 9 Science Chapter 5 Exercise Question Answers are given below in the best possible manner, with tables and using simple language.

Q1. Make a comparison and write down ways in which plant cells are different from animal cells.

Answer:

Plant Cells Animal Cells
1. Plant cells are generally bigger than animal cells. 1. Animal cells are relatively small.
2. Plant cells have a cell wall. 2. Animal cells do not have a cell wall.
3. The nucleus is not present in the centre of the cell. 3. The nucleus is there at the center of the cell.
4. The size of the vacuole is large. 4. The size of the vacuole is small.
5. A chloroplast is present. 5. A chloroplast is absent.

Q2. How is a prokaryotic cell different from a eukaryotic cell?

Answer:

Prokaryotic Cell Eukaryotic Cell
1. A prokaryotic cell is quite small in size.
( 1 - 10 pm)
1. A eukaryotic cell is relatively larger.
(5-100 pm)
2. The nuclear region is poorly defined as the nuclear membrane is absent. 2. The nuclear membrane is present and the nuclear region is well defined.
3. Organelles are not membrane-bound. 3. Organelles are membrane-bound.
4. Only one chromosome is present. 4. More than one chromosome is present.

Q3. What would happen if the plasma membrane ruptures or breaks down?

Answer:

If the plasma membrane ruptures the cell would eventually die because the movement of substances won't be regulated.

This will cause important substances to move out of the cell and harmful substances from the environment would enter the cell.

Q4. What would happen to the life of a cell if there was no Golgi apparatus?

Answer:

Golgi apparatus stores and transports materials through vesicles.

In the absence of the Golgi apparatus, these functions would stop and this will cause the death of the cell.

Q5. Which organelle is known as the powerhouse of the cell? Why?

Answer:

Mitochondria are known as the powerhouse of the cell as mitochondria releases energy in the form of ATP which is essential for performing all the functions of the cell.

Q6. Where do the lipids and proteins constituting the cell membrane get synthesized?

Answer :

Lipids and proteins are synthesized in the endoplasmic reticulum.

In the Rough Endoplasmic Reticulum, proteins are manufactured whereas the manufacturing of lipids take place in the Smooth Endoplasmic Reticulum.

Q7. How does an Amoeba obtain its food?

Answer:

Amoeba obtains its food by the virtue of the flexibility of its shape.

Amoeba entraps the food particle around its membrane and then engulfs it within the cytoplasm. This process is called endocytosis.

Q8. What is osmosis?

Answer:

Osmosis is the movement of water from a region of low concentration of solute(high water concentration) to a region of high concentration of solute(low water concentration) through a semi-permeable membrane.

Class 9 Science Chapter 5 question answer

Q9. (i) Carry out the following osmosis experiment:

Take four peeled potato halves and scoos each one out to make potato cups. One of these potato cup should be made from a boiled potato. Put each potato cup in a trough containing water. Now,

(a) Keep cup A empty

(b) Put one teaspoon sugar in cup B

(c) Put one teaspoon salt in cup C

(d) Put one teaspoon sugar in the boiled potato cup D. Keep these for two hours. Then observe the four potato cups and answer the following:

(i) Explain why water gathers in the hollowed portion of B and C.

Answer:

(i) Due to the presence of a solute (sugar in case of B and salt in case of C), there is a concentration difference of water in the potato cup and the trough due to which osmosis takes place where the cells of the potato act as the semi-permeable membrane.

Q9. (ii) Carry out the following osmosis experiment:

Take four peeled potato halves and scoops each one out to make potato cups. One of these potato cups should be made from a boiled potato. Put each potato cup in a trough containing water. Now,

(a) Keep cup A empty

(b) Put one teaspoon sugar in cup B

(c) Put one teaspoon salt in cup C

(d) Put one teaspoon sugar in the boiled potato cup D.

Keep these for two hours. Then observe the four potato cups and answer the following:

(ii) Why is potato A necessary for this experiment?

Answer:

Potato A is absolutely necessary because it acts as the control for the experiment. Without A we will have no reference to compare the other cases with. We can see that since there is no solute in the hollow part of this potato no osmosis has taken place.

Q9.(iii) Carry out the following osmosis experiment:

Take four peeled potato halves and scoos each one out to make potato cups. One of these potato cups should be made from a boiled potato. Put each potato cup in a trough containing water. Now,

(a) Keep cup A empty

(b) Put one teaspoon sugar in cup B

(c) Put one teaspoon salt in cup C

(d) Put one teaspoon sugar in the boiled potato cup D.

Keep these for two hours. Then observe the four potato cups and answer the following:

(iii) Explain why water does not gather in the hollowed-out portions of A and D.

Answer:

Since there is no solute in the hollow part of potato A no osmosis has taken place and water does not gather in the hollowed part of A.

In the case of D even after the presence of solute osmosis does not take place. Boiling this potato has destroyed the cells and thus no semi-permeable membrane is there for osmosis to take place.

Q10. Which type of cell division is required for the growth and repair of the body and which type is involved in the formation of gametes?

Answer:

Mitosis is required for the growth and repair of the body and meiosis is involved in the formation of gametes.


NCERT Solutions for Class 9 Science - Chapter Wise

Chapter No. Chapter Name
Chapter 1 Matter in Our Surroundings
Chapter 2 Is Matter Around Us Pure
Chapter 3 Atoms and Molecules
Chapter 4 Structure of The Atom
Chapter 5 The Fundamental Unit of Life
Chapter 6 Tissues
Chapter 7 Diversity in Living Organisms
Chapter 8 Motion
Chapter 9 Force and Laws of Motion
Chapter 10 Gravitation
Chapter 11 Work and Energy
Chapter 12 Sound
Chapter 13 Why Do We Fall ill?
Chapter 14 Natural Resources
Chapter 15 Improvement in Food Resources

Science Class 9 Chapter 5: Important Formulas and Diagrams + eBook link

Did you know that some students perform better on their CBSE exams than others, even with less time? The simple explanation for this is that they each have unique learning and revision plans and strategies. Aside from the Class 9 Science Chapter 5 Exercise Question Answer, one way to shorten revision time for NCERT science is to group the most crucial formulas and points together in one location. This will enable a quick glance and an instant reminder once the concepts are understood.

Subject experts at Careers360 have compiled a list of all the important formulas for NCERT Science Class 9 in this handy ebook. This ebook will save you time and help you quickly go over every significant formula with examples that you might see in your exams.

for more details - download the ebook for class 9 sceince - Important formulas and diagrams

NCERT Solutions for Class 9 Science Chapter 5 – The Fundamental Unit of Life

Unit 2 - Organization in the Living World, which is expected to earn about 20 marks, includes the NCERT Solutions for Class 9 Science Chapter 5. Because of its significance, it is essential that you fully understand the Fundamental Unit of Life Class 9 Questions and Answers before taking the CBSE exam. These NCERT Solutions - Class 9 Chapter 5 Science Question Answers are prepared by experienced teachers to provide clarity on complex concepts and problem-solving skills.

Important Topics of NCERT Solutions for Class 9 Science Chapter 5 - The fundamental Unit of Life

Important topics and sub-topics of Science Chapter 5 Class 9 are listed below:

  • 5.1 - What Are Living Organisms Made up of?
  • 5.2 - What Is a Cell Made up Of? What Is the Structural Organisation of a Cell?
  • 5.2.1 - Plasma Membrane or Cell Membrane
  • 5.2.2 - Cell Wall
  • 5.2.3 - Nucleus
  • 5.2.4 - Cytoplasm
  • 5.2.5 - Cell Organelles
  • 5.2.5 - (i) Endoplasmic Reticulum (ER)
  • 5.2.5 - (ii) Golgi Apparatus
  • 5.2.5 - (iii) Lysosomes
  • 5.2.5 - (iv) Mitochondria
  • 5.2.5 - (v) Plastids
  • 5.2.5 - (vi) Vacuoles

Now, students can refer to the Class 9 Science Chapter 5 Exercise Question Answer to assess yourself about these topics.

Features of NCERT Solutions for Class 9 Science Chapter 5 The Fundamental Unit of Life

  • You will get the best answer in the Fundamental Unit of Life Class 9 PDF, written by our experts as per CBSE guidelines.
  • NCERT Class 9 Science Chapter 5 Question Answer helps you understand the concepts easily.
  • Students are advised to go through the NCERT Solutions for Class 9 Science Chapter 5 as it will help them score well in the exams.
  • Solutions for the fundamental unit of life are easily accessible and free.
  • Class 9 Chapter 5 Science Question Answer are easy to download and use offline.

NCERT Solutions for Class 9 - Subject Wise

NCERT Solutions for Class 9 Maths
NCERT Solutions for Class 9 Science

Also Check NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. What are the features of NCERT solutions for the fundamental unit of life class 9?

The features of NCERT solutions for class 9 science chapter 5 are: 

  • In solutions for the fundamental unit of life, you will get the best answer written by our experts as per CBSE guidelines.  
  • Solutions for fundamental unit of life help you to understand the concepts easily.  
  • Students are advised to go through the class 9 science chapter 5 question answer as it will help them to score well in the exams.  
  • Solutions for science chapter 5 class 9 are easily accessible and free.
2. How to score well in examination?

To score well in the examination, follow the NCERT syllabus and solve the exercise given in the NCERT Book. To practice more problems, students must refer to NCERT Exemplar.

3. Who discovered cell and how class 9?

British scientist Robert Hooke made the discovery of the cell in 1665. Under his own-built microscope, he looked at cells in a cork slice and saw compartments that looked like honeycombs. He named them "cells."

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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