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Have you ever ridden your bicycle up a hill and compare how much more you have to peddle it up, to when going down the road or when the road is flat? The daily experience is a beautiful illustration of the principle of work and energy the harder you attempt something, the more work you are doing and some of the energy is being transported. This is precisely what Chapter 10: Work, Power, and Energy in Class 9 Science is all about. The chapter gives the student some basic physical knowledge of work, the definition of energy along with a relation of power and the rate at which work is performed. No matter whether you are studying towards your CBSE school exam or paving the way to your next entry-level exams like JEE or NEET, this chapter is an essential part of mastering how forces and energy interact with each other in the world around us.
The Class 9 Science Notes Chapter 10 provide a Class 9 student with the overview of the whole chapter. These include the concepts of importance such as work, power, energy, kinetic and potential energy, basic and clear explanation of significant formulas and definitions, labeled diagrams to strengthen understanding and Practice questions to test your learning. How to calculate work done, various types of energy and the principle of conservation of energy which plays a very critical role and recurs frequently in physics over the higher classes will also be discussed in the Class 9 Science chapter 10 notes. To have a better picture of learning, these notes work most optimally with NCERT Solutions to Class 9 Chapter 10 that would show all the solutions to in-text and back-exercise questions step-by-step.
Also, students can refer,
Work is done on an object when it is displaced by the action of a force.
Work done = force x displacement
W= Fs {F=force acting on the object, s= displacement caused due to F, W= work done on the object}
W= Fs
From the equation of motion if a is the constant acceleration on a body;
v2-u2=2as
Rearranging the above equation gives
s=(v2-u2)/2a
Since, F=ma, work done can be written as,
W= ma x (v2-u2)/2a
Simplifying the above equation,
W= m(v2-u2)/2
If the object starts at rest, its initial velocity (u) =0
W= mv2/2
Since all work done on the object results in an increase in its kinetic energy,
Kinetic energy= Ek = mv2/2
where Ek= Kinetic energy of the object
m = mass of the object
v= velocity at which the object is moving
When an object is raised to a greater height, its energy increases. This is because work is done on it as it is being raised against gravity. The gravitational potential energy is the energy present in such an item. The work done in elevating an object from the ground to a point above the ground is defined as the gravitational potential energy of that object.
Displacement of the object is its change in elevation=h, the force required for this action is mg, where m is the mass of that object is g is the acceleration due to gravity.
W= Force x displacement
W= mg x h
W= mgh
Since all work done on the object results in an increase in its potential energy,
Potential energy = EP = mgh
mgh + mv2/2 = constant, mechanical energy is constant
P=w/t
Q1: Which of the following are example of mechanical energy -
1.Kinetic energy, 2.chemical energy, 3.electrical energy, 4.heat energy, 5.Potential energy
Answer:
Mechanical energy is the sum of potential energy and kinetic energy. It is the macroscopic energy associated with a system.
Q2: A ball of mass 1 kg is thrown vertically upward with velocity 2 m/s. then what is the total energy of the ball when it reaches the highest point? (Assume potential energy of a body at the ground is zero)
Answer:
- Kinetic Energy
-
- KE = 2 Joules
Total energy at any point:
- The total energy of the ball is the sum of its kinetic and potential energy.
- At the highest point, the ball's velocity is zero, so its kinetic energy is zero.
- The total energy at the highest point is equal to the initial kinetic energy, which is 2 Joules.
Therefore, the total energy of the ball at the highest point is 2 Joules.
Q3: If acceleration due to gravity is 10 m/s2, what will be the potential energy of a body of mass 10 kg kept at a height of 2 m? (Assume potential energy of a body at the ground is zero)
Answer:
The potential energy of a body is calculated by using the formula :
Potential energy = m × g × h=10*2*10=200J
NCERT Class 9th Science Chapter 11 Notes |
NCERT Class 9th Science Chapter 14 Notes |
In physics, work is said to be done when a force is applied on an object and the object moves in the direction of the applied force.
It states that energy can neither be created nor destroyed; it only changes from one form to another. The total energy of an isolated system remains constant.
Work is the process of energy transfer when a force moves an object, whereas energy is the capacity to do work.
Main types include kinetic energy (energy due to motion) and potential energy (energy due to position or configuration).
In a fan: electrical energy → mechanical energy
In a torch: chemical energy → electrical energy → light energy
In a hydroelectric plant: potential energy → kinetic energy → electrical energy
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