Work and Energy Class 9th Notes - Free NCERT Class 9 Science Chapter 11 Notes - Download PDF

Work and Energy Class 9th Notes - Free NCERT Class 9 Science Chapter 11 Notes - Download PDF

Edited By Vishal kumar | Updated on Mar 20, 2024 10:21 AM IST

CBSE Class 9 Work and Energy Notes - Download Free PDF

Welcome to our complete collection of Class 9 Science notes, which focuses on Chapter 11: Work, Power, and Energy. This meticulously crafted work and energy class 9 notes condenses the key concepts, important points, and essential diagrams from CBSE's Class 9 Science textbook, specifically Chapter 11. This chapter is critical for students using the NCERT Textbook to navigate the complexities of science. It teaches fundamental principles about work, power, and energy. Whether you need a quick review before an exam or want to gain a better understanding of the subject, these class 9 physics chapter 11 notes will help you along your academic journey.

This Story also Contains
  1. CBSE Class 9 Work and Energy Notes - Download Free PDF
  2. NCERT Class 9 Chapter 11 Notes
  3. Work
  4. Energy
  5. Potential energy
  6. Law of conservation of energy
  7. Rate of doing work
  8. Significance of NCERT notes for class 9 Science chapter 11
  9. NCERT solutions of class 9 subject-wise
  10. NCERT Class 9 Exemplar Solutions for Other Subjects:

Our CBSE class 9 physics ch 11 notes offer a structured approach to learning, with CBSE Key Notes, Revision Notes, Short Key Notes, and illustrative images and diagrams. We hope to make it easier to memorise and comprehend the subject matter by consolidating all relevant information in one place.

Furthermore, to supplement your understanding, we recommend that you read NCERT Solutions for Class 9 Science Chapter 11: Work, Power, and Energy to ensure a thorough understanding of the concepts covered. Download our PDF of work and energy notes class 9 for an easy revision experience, and start your journey to mastering this fundamental aspect of science education.

Also, students can refer,

NCERT Class 9 Chapter 11 Notes

Work

Not much ‘work’ despite working hard

Performing physical or mental jobs is not considered work concerning this chapter.

The scientific concept of work-

Work is done on an object when it is displaced by the action of a force.

Work done by a constant force

Work done = force x displacement

W= Fs {F=force acting on the object, s= displacement caused due to F, W= work done on the object}

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Work done by a constant force can be given by the multiplication of the magnitude of the force and the distance moved in the direction of that force. The SI unit of work done is ‘Nm’ (Newton metre) or ‘J’ (joule). When 1 N of force is applied to displace an object by 1m, 1 J of work is said to be done.

Work done could be either positive (force applied is in the direction of displacement) or negative (force applied is opposite to the direction of object’s displacement).

Energy

The Sun is the ultimate source of energy for sustaining life on Earth. Energy is defined as the capacity to do work. The object which performs work will lose energy, whereas the object on which work is being performed will gain energy. Transfer of energy happens when an object having energy starts to exert force on the other object. Energy has the same SI unit as of work i.e., joule (J), this is because energy is measured as the capacity to perform work. 1J work requires an input of 1J energy.

1 kJ= 1000J

Forms of energy

Energy can exist in the form of mechanical energy (potential energy + kinetic energy), heat energy, sound energy, chemical energy, and light energy and these forms of energy are interconvertible.

Kinetic energy

It is the energy possessed by an object due to its motion, it is directly proportional to the mass of an object and is proportional to the square of the object’s velocity.

Let there be an object of mass ‘m’, travelling with initial velocity ’u’. If a force ‘F’ acts on it to cause a displacement ‘s’, then its final velocity changes to ‘v’, and work done in it is ‘W’

W= Fs

From the equation of motion if a is the constant acceleration on a body;

v2-u2=2as

Rearranging the above equation gives

s=(v2-u2)/2a

Since, F=ma, work done can be written as,

W= ma x (v2-u2)/2a

Simplifying the above equation,

W= m(v2-u2)/2

If the object starts at rest, its initial velocity (u) =0

W= mv2/2

Since all work done on the object results in an increase in its kinetic energy,

Kinetic energy= Ek = mv2/2

where Ek= Kinetic energy of the object

m = mass of the object

v= velocity at which the object is moving

Potential energy

Potential energy can be defined as the energy possessed by an object by the virtue of its position or configuration.

The potential energy of an object at a height

When an object is raised to a greater height, its energy increases. This is because work is done on it as it is being raised against gravity. The gravitational potential energy is the energy present in such an item. The work done in elevating an object from the ground to a point above the ground is defined as the gravitational potential energy of that object.

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Displacement of the object is its change in elevation=h, the force required for this action is mg, where m is the mass of that object is g is the acceleration due to gravity.

W= Force x displacement

W= mg x h

W= mgh

Since all work done on the object results in an increase in its potential energy,

Potential energy = EP = mgh

Law of conservation of energy

It is only possible to transform energy from one form to another; it cannot be created or destroyed. Before and after the transition, the total energy of the system is the same. When an object of mass ‘m’ falls from height ‘h’ to the ground (h=0), its potential energy EP = mgh gets converted to kinetic energy EK = mv2/2, no energy is lost in this process.

mgh + mv2/2 = constant, mechanical energy is constant

Rate of doing work

Power is defined as the rate of doing work or the rate of transfer of energy.

Power = work/time

P=w/t

SI unit of power is Watt (W)

1W= 1 Js-1

Average power is the total work divided by the total consumed time to perform that work.

Commercial unit of energy

Since a joule is very small, a larger unit kilowatt-hour (kW h) is used in commercial applications.

1 kW h is defined as the energy that is utilized in one hour at the rate of 1000 Js-1 (or 1 kW).

1 kW h = 3.6 x 106 J

1 unit of electricity consumed equals 1 kWh

Significance of NCERT notes for class 9 Science chapter 11

Comprehensive Revision: The NCERT work and energy class 9 notes provide a thorough overview of the chapter, assisting students with their revision efforts.

Clarity in Concepts: These class 9 physics chapter 11 notes are intended to simplify complex concepts so that students understand the main ideas and principles discussed in the chapter.

Step-by-Step Explanation: The work and energy notes class 9 provide a step-by-step explanation of various topics, allowing students to follow along and comprehend the material.

Aligned with CBSE Syllabus: As part of the CBSE Science syllabus for class 9, these notes have been meticulously crafted to cover all of the important topics and concepts outlined in the curriculum.

Non-Complex: The language used in these cbse class 9 physics ch 11 notes is straightforward and easy to understand, removing any confusion and assisting students in developing a solid foundation in the subject.

Offline Preparation: Students can download the notes in PDF format and access them offline, making it possible to prepare whenever and wherever they want.

NCERT solutions of class 9 subject-wise

NCERT Class 9 Exemplar Solutions for Other Subjects:

Class 10 Chapter Wise Notes

Frequently Asked Questions (FAQs)

1. What is the SI unit of work?

Newton metre (Nm) or Joule (J)

2. Define potential energy ?

The object's potential energy is the energy present in it as a result of its location or configuration.

3. What are the various forms of energy as in NCERT chapter 11 class 9?

Energy can exist in the form of mechanical energy (potential energy + kinetic energy), heat energy, sound energy, chemical energy, and light energy.

4. What is power?

Power is defined as the rate of doing work or the rate of transfer of energy.

Power = work/time=Fv, where F is the forve and v is the velocity

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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