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Have you ever put your ear to the railroad track and heard the distant rolling of an approaching train before you could actually hear its whistle? This straightforward experience demonstrates the travel of sound in varying media- a major concept in Class 9 Science Chapter 11: Sound. This chapter describes the formation of sound waves, their path through a solid, liquid and gas matric, and the properties of frequency, wavelength, amplitude and speed of sound that are responsible in giving us what we hear. These concepts are fundamental to excellent scores in the CBSE and foundation to upper‑level physics and competitive exams such as JEE and NEET where wave properties can be found in more refined ways.
Class 9 Science Notes of Chapter 11 designed by experienced teachers and contain concise summaries of topics like production of sound, longitudinal waves, echo and reverberation, ultrasound, and the functioning of human ear, important formulas (e.g.,
$v=f\lambda$) and relations for quick recap, well explained diagrams depicting waveforms, echoes and multiple reflection of sound and sample problems to improve problem-solving ability. These Class 9 Sound notes can give you a quick brush up before an exam or a more in depth understanding of the concept.
Also, students can refer,
Pressure = number of particles in the medium/volume.
More density produces more pressure and vice versa.
So, sound propagation can be seen as the propagation of variations in density or variations in pressure in the medium.
Sound waves are longitudinal:
Compressions (C) are the regions where the coins become closer while rarefactions(R) are the regions where the coils become further apart.
Sound travels in a series of compressions and rarefactions in a medium. Sound waves are longitudinal waves where the individual particles of the medium travel in a direction parallel to the direction of propagation of the disturbance. These particles are immovable and cannot travel from one place to another. They oscillate backwards and forward about their resting position. This is the property of longitudinal waves and hence sound waves are regarded as longitudinal waves.
Wavelength: It means the distance between two consecutive compressions (C) or two consecutive rarefactions (R). is the symbol for wavelength. The SI unit of wavelength is meter(m).
t is the time taken for one complete oscillation in the density of the medium. T is the symbol of the time period and its SI unit is second (s).
T= 1/f
When the vibration of the source is faster, the frequency and therefore the pitch becomes higher. High pitch represents more compressions and rarefactions passing a fixed point per unit time.
S= λν
speed = wavelength × frequency
1. The incident ray, the reflected ray and the normal lies in the same plane, that is, the reflecting surface
2. The angle of incidence is always equal to the angle of reflection.
1. The time difference(interval) between the original sound and the reflected sound must be at least 0.1 seconds.
2. The minimum distance of the reflecting surface from the source of sound must be 17.2 m.
Musical instruments like megaphone and a horn are made up of a tube whichis followed by a conical opening.
It is used in a stethoscope which is used for hearing sounds developed within the body. The sound of the patient’s heartbeat is heard by the doctor’s ears by multiple reflections of sound.
Ceilings of auditoriums are made curved aiming that sound after reflection reaches all corners of the hall.
1. These high frequencies clean spiral tubes, electronic components and several other places which are hard to reach. The objects which are needed to be cleaned are put in a cleaning solution and the ultrasonic waves are passed in the solution. Because of the high frequency of these particles, the dust particles and the dirt get removed and the object becomes clean
2. Ultrasonic vibrations are used to find cracks and flaws in metal blocks. These metal blocks are used for construction of buildings and scientific equipment. The floors or the cracks inside these are invisible from outside. It reduces the strength of the buildings and machines. Ultraviolet waves are passed through these metal blocks to cure this and the detectors function to detect the propagated waves. When any small defect is encountered these ultrasound reflects back which indicates the presence of any crack.
3. Ultrasonic waves are used in the technique of echocardiography. This technique makes the ultrasonic waves reflect from various parts of the heart and develop its image.
4. Ultrasonic waves are also used in ultrasound scanners to produce images of internal organs of the human body. It is used to detect any fault in the liver, gallbladder, uterus, etc. The technique by which the images are displayed on a monitor is called ultrasonography.
5. The ultrasonic waves are also used to break small stones formed in the kidneys or liver which get removed with the urine of the individual.
Sonar constitutes a transmitter and a detector which are installed in a boat or a ship. Ultrasonic waves are produced and transmitted by the transmitter which travel through water and strike the object on the seabed. The waves are reflected back and are sensed by the detector. The detector converts the waves into electrical signals for interpretation. The object's distance which reflects the sound wave can be measured by determining the speed of sound in water and the time period between transmission and reception of the ultrasound.
If the time interval is t, and the speed of sound is S, the total distance, 2d, travelled by the ultrasound becomes,
2d= S×t
This technique is known as echo ranging.
The Sonar technique is also used in various other determinations to calculate the depths of the sea and to detect the location of underwater hills, submarines, sunken ships, etc.
Q1: A person is listening to a tone of 500 Hz sitting at a distance of 450 m from the source of the sound. What is the time interval between successive compressions from the source?
Answer:
The time interval between successive compressions from the source is equal to the time period, and time period is the reciprocal of the frequency. Therefore, it can be calculated as follows:
T= 1/F
T= 1/500
T = 0.002 s.
Q2: A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m s−2 and speed of sound = 340 ms−1.
Answer:
Height (s) of tower = 500 m
Velocity (v) of sound = 340 m s−1
Acceleration (g) due to gravity = 10 m s−1
Initial velocity (u) of the stone = 0
Time (t1) taken by the stone to fall to tower base
As per second equation of motion:
s= ut1 + (½) g (t1)2
500 = 0 x t1 + (½) 10 (t1)2
(t1)2 = 100
t1 = 10 s
Time (t2) taken by sound to reach top from tower base = 500/340 = 1.47 s.
t = t1 + t2
t = 10 + 1.47
t = 11.47 s.
Q3: A sonar device on a submarine sends out a signal and receives an echo 10 seconds later. then what is the speed of sound in water if the distance of the object from the submarine is 7200 m?
Answer:
Time (t) taken to hear the echo = 10 s
Distance (d) of an object from submarine = 7200 m
Total distance travelled by SONAR during reception and transmission in water = 2d
Velocity (v) of sound in water = 2d/t = (2 × 7200) / 10 = 1440 ms-1
NCERT Class 9th Science Chapter 12 Notes |
NCERT Class 9th Science Chapter 14 Notes |
Studying sound helps students understand how we hear, how vibrations produce sound, and how sound is used in technology, medicine, and everyday life.
Applications include medical ultrasound, sonar in submarines, musical instruments, hearing aids, and soundproofing systems.
Yes, basic concepts from this chapter are foundational for understanding physics in higher classes and are useful in Olympiads, NTSE, and NEET foundation.
Ultrasound refers to sound waves with frequencies above 20,000 Hz. It is used in medical imaging (like sonography), cleaning delicate equipment, and detecting flaws in metals.
Yes, exposure to very loud sounds can damage hearing. Continuous exposure to noise above 85 dB can be harmful to the ears.
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