The volume of any three-dimensional object is the space occupied within the object's boundaries. There are some different formulas for calculating the volume of different objects. Similarly, volumes of the combination of two or more objects can be determined. Because sometimes, two or more different or the same types of objects are combined to form a new shape. The volume of the combination of an object is the sum of the volume of the combined object. For example, a toy is made with a right circular cone at the top and a hemisphere at the base, then the sum of the volumes of the right circular cone and the hemisphere is the total volume of the toy.
This exercise has eight questions as per the NCERT Books that require students to visualise the shapes as described in the problem statements, then break up the figure, especially those types of figures whose volume or the formula to find its volume is known to us. So that we can very easily determine their volumes and either add them or subtract them to get the final volume of the resultant figure. 10th class Maths exercise 12.2 NCERT solutions are designed as per the students' demand, covering comprehensive, step-by-step solutions of every problem. Practice these questions and answers to command the concepts, boost confidence and in-depth understanding of concepts. Students can find all exercises together using the link provided below.
Answer:
The volume of the solid is given by :
The volume of the solid = Volume of the cone + Volume of a hemisphere
The volume of the cone :
or
or
And the volume of the hemisphere :
or
or
Hence, the volume of the solid is :
Answer:
The volume of air present = Volume of cylinder + 2 (Volume of a cone)
Now, the volume of a cylinder:
or
or
And the volume of a cone is :
or
or
Thus, the volume of air is :
or
Answer:
It is clear from the figure that gulab jamun has one cylindrical part and two hemispherical parts.
Thus, the volume of gulab jamun is = the Volume of the cylindrical part + 2 (Volume of the hemisphere )
Now, the volume of the cylinder is
or
or
And the volume of a hemisphere is :
Thus, the volume of 1 gulab jamun is
Hence the volume of 45 gulab jamun
Further, it is given that one gulab jamun contains sugar syrup up to
So, the total volume of sugar present:
Answer:
The volume of wood is given by = volume of the cuboid - the volume of four cones.
Firstly, the volume of a cuboid:
or
or
And, the volume of the cone :
Thus the volume of wood is
Answer:
According to the question :
Water spilt from the container = Volume of lead balls.
Let us assume the number of lead balls to be n.
Thus, the equation becomes :
or
or
or
Hence, the number of lead shots dropped is 100.
Answer:
The pole can be divided into one large cylinder and one small cylinder.
Thus, the volume of the pole = volume of the large cylinder + volume of the small cylinder
or
or
or
or
Now, according to the question mass of the pole is :
or
Answer:
It is clear from the question that the required volume is :
The volume of water (left) =Volume of a cylinder - Volume of solid
Now the volume of the cylinder is
or
And the volume of the solid is :
Thus, the volume of water left :
Answer:
The volume of the vessel is given by :
The volume of the vessel = Volume of sphere + Volume of the cylindrical part
Now, the volume of the sphere is :
And the volume of the cylinder is:-
Thus the volume of the vessel is
Also Read:
Also See:
Students must check the NCERT solutions for class 10 of the Mathematics and Science Subjects.
As per latest 2024 syllabus. Maths formulas, equations, & theorems of class 11 & 12th chapters
Students must check the NCERT Exemplar solutions for class 10 of the Mathematics and Science Subjects.
The core concept behind this exercise is to find the volume combination of solids. We have to remember the formula for finding the volume of cuboid, sphere, cylinder etc
Admit Card Date:06 May,2025 - 20 May,2025
Admit Card Date:06 May,2025 - 20 May,2025
Hello
Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.
1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.
2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.
3. Counseling and Seat Allocation:
After the KCET exam, you will need to participate in online counseling.
You need to select your preferred colleges and courses.
Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.
4. Required Documents :
Domicile Certificate (proof that you are a resident of Karnataka).
Income Certificate (for minority category benefits).
Marksheets (11th and 12th from the Karnataka State Board).
KCET Admit Card and Scorecard.
This process will allow you to secure a seat based on your KCET performance and your category .
check link for more details
https://medicine.careers360.com/neet-college-predictor
Hope this helps you .
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is
| Option 1)
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Option 2)
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Option 4)
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An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range
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Option 2)
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Option 4)
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A particle is projected at 600 to the horizontal with a kinetic energy . The kinetic energy at the highest point
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Option 2)
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Option 4)
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In the reaction,
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Option 2)
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Option 4)
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How many moles of magnesium phosphate, will contain 0.25 mole of oxygen atoms?
| Option 1)
0.02 |
Option 2)
3.125 × 10-2 |
| Option 3)
1.25 × 10-2 |
Option 4)
2.5 × 10-2 |
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As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
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